# RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.4 (Updated For 2021-22)

RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.4: Be it your Class 7 Maths assignments or class test prep, RS Aggarwal Solutions Class 7 Maths can be the perfect choice for you. The solutions of RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.4 are credible, accuaret and well-explained, all thanks to the subject matter experts.

Download the Free PDF of RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.4 by using the download link given in the blog. To know more, read the whole blog.

## Download RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.4 PDF

RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.4

## RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.4 – Overview

In the fourth exercise of RS Aggarwal Solutions Class 7 Maths Chapter 20, there is a total of 12 questions. The emphasis of such questions is going to be on performing the calculation of the equilateral triangle and right-angle triangle.

### Right Angled Triangle

It consists of three sides namely – Base, Height, and hypotenuse. Here, the angle is 90 degrees between the height and the base. Also, the hypotenuse is the longest side here. These three things are used to develop the Pythagoras theorem. This theorem can be defined as below –

“The square of the hypotenuse side is equivalent to the sum of the squares of the base value and the height.”

### Right Angle Triangle Properties

• In the “Right Angle Triangle”, one of the angles will always be equal to 90 degrees or the right angle.
• In the “Right Angle Triangle “, the hypotenuse side is the side that is opposite to the 90 degrees angle.
• In the “Right Angle Triangle”, the hypotenuse is always on the longest side.
• In the “Right Angle Triangle”, the sum of the remaining two angles will always be equal to 90 degrees.
• In the “Right Angle Triangle”, the neighbouring sides are called the base and the perpendicular.
• In the “Right Angle Triangle”, its area is equivalent to half of the product of the right angle triangle’s neighbouring sides i.e., Area ( Right Angle Triangle ) =  ( 1 / 2 ) ( Base /  Perpendicular ).
• In the “Right Angle Triangle”, in case the perpendicular line is being made from the right angle till the hypotenuse, then in this case, it will result in the total of the three similar triangles.
• In the “Right Angle Triangle”, a circumcircle is being drawn passing via all the 3 vertices – in this case, the ‘Radius of the Same circle will be equivalent to the hypotenuse’s half-length.’

This is the complete blog on RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.4. to know more about the CBSE Class 7 Maths exam, ask in the comments.

## FAQs on RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.4

### Define a Right-Angled Triangle.

It consists of three sides namely – Base, Height, and hypotenuse. Here, the angle is 90 degrees between the height and the base.

### What is the Pythagoras Theorem?

“The square of the hypotenuse side is equivalent to the sum of the squares of the base value and the height.”

### How many questions are there in the fourth exercise of RS Aggarwal Solutions Class 7 Maths Chapter 20?

In the fourth exercise of RS Aggarwal Solutions Class 7 Maths Chapter 20, there is a total of 12 questions.

### What are the questions of the fourth exercise of RS Aggarwal Solutions Class 7 Maths Chapter 20 based on?

The emphasis of such questions is going to be on performing the calculation of the equilateral triangle and right-angle triangle.

### From where can I find the download link for the RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.4 PDF?

You can find the download link in the above blog.