**RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.2: **Class 7 Maths is made easier becuase of RS Aggarwal Solutions Class 7 Maths. Be it your class tests or assignments, RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.2 has got your back. The solutions are designed by subject matter experts for your better understanding and are as per the current CBSE Syllabus.

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## Download RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.2 PDF

RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.2

## RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.2 – Overview

The second exercise of the 20th chapter consists of 8 questions in total. All of these questions are based on the calculation of the area in between the outward and the inward fence of the rectangular field.

### Basic Formulae

- The Perimeter of the rectangle = 2 ( L + B ) units
- The Length of Rectangle = (P / 2) – w units
- The Width (w) of Rectangle = (P / 2) – L units
- The Diagonal of Rectangle = √( L2 + W2 ) units
- The Area of Rectangle = L x w sq.units
- The Length of Rectangle = A / w units
- The Width of Rectangle = A / L units
- The Area of the Square, S = S²
- The Area of the circle, C = πr²
- The Area of parallelogram = base × height
- The Area of rhombus = base × height
- The Area of trapezium = 1 / 2 ( The total sum of the parallel sides ) × ( The exact perpendicular distance between these two parallel sides )

### Perimeter

A perimeter is the total boundary of the two-dimensional shape. he units of the perimeter are, cm, m, etc.

### Formulae For Perimeter

**1. Perimeter of Rectangle –**The rectangle consists of two sides that are parallel and equal to each other. And it consists of all the angles equivalent to 90 degrees.

**2. Perimeter of Square –**The rectangle having each of its sides as equivalent to each other is said to be a square. And, the perimeter of a square, P is equal to the 4 × Side.

**3. The Perimeter of a Triangle**, denoted by P = ( x + y + z ). Here, we have devoted the symbols x, y, and z as the three sides of the triangle.

**4. Perimeter of Parallelogram –**2 ( The sum of all the sides adjacent to each other )

**5. Perimeter of Rhombus**= 4 × side

This is the complete blog on RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.2. To know more about the CBSE Class 7 Maths exam, ask in the comments.

## FAQs on RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.2

### What is the perimeter of the rhombus?

**Perimeter of Rhombus** = 4 × side

### What is the perimeter of the parallelogram?

**The perimeter of Parallelogram –** 2 ( The sum of all the sides adjacent to each other )

### What is the Area of the trapezium?

The Area of trapezium = 1 / 2 ( The total sum of the parallel sides ) × ( The exact perpendicular distance between these two parallel sides )

### How many questions will be asked in the second exercise of RS Aggarwal Solutions Class 7 Maths Chapter 20?

There is a total of 8 questions in the second exercise of RS Aggarwal Solutions Class 7 Maths Chapter 20.

### What are the questions of the second exercise of RS Aggarwal Solutions Class 7 Maths Chapter 20 based on?

All of the questions are based on the calculation of the area in between the outward and the inward fence of the rectangular field.

### From where can I find the download link for the RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.2 PDF?

You can find the download link in the above blog.

### How much does it cost to download the RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.2 PDF?

You can download it for free.

### Can I access the RS Aggarwal Solutions Class 7 Maths Chapter 20 Ex 20.2 PDF Offline?

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