# RS Aggarwal Solutions Class 9 Maths Chapter 4 Linear Equations in Two Variables (Updated For 2021-22) RS Aggarwal Solutions Class 9 Maths Chapter 4 Linear Equations in Two Variables: Class 9 Maths is made easier with the RS Aggarwal Solutions Class 9 Maths. Be it exam preparation or class assignments, RS Aggarwal Solutions Class 9 Maths Chapter 4 Linear Equations in Two Variables have got you covered. The solutions are well-writtern, well-explained and reliable.

To download the RS Aggarwal Solutions Class 9 Maths Chapter 4 Linear Equations in Two Variables Free PDF, you can use the download link given in the blog. To know more, read the whole blog.

## Download RS Aggarwal Solutions Class 9 Maths Chapter 4 Linear Equations in Two Variables PDF

RS Aggarwal Solutions Class 9 Maths Chapter 4 Linear Equations in Two Variables

## Access Solutions Of RS Aggarwal Solutions Class 9 Maths Chapter 4 Linear Equations in Two Variables

Question 1.
Solution:
(i) x = 5 is the line AB parallel to the y-axis at a distance of 5 units.
(ii) y = – 2 is the line CD parallel to x-axis at a distance of – 2 units.
(iii) x + 6 = 0 => x = – 6 is the line EF parallel to y-axis at a distance of – 6 units.
(iv) x + 7 = 0 => x = – 7 is the line PQ parallel to y-axis at a distance of – 7 units.
(v) y = 0 is the equation of x-axis. The graph of y = 0 is the line X’OX
(vi) x = 0 is the equation of y-axis.The graph of x = 0 is the line YOY’
Ans. Question 2.
Solution:
In the given equation. y = 3x
Put x = 1, then y = 3 x 1 = 3
Put x = 2, then y = 3 x 2 = 6
Put x = – 1, then y = 3 ( – 1) = – 3
Now, plot the points (1, 3), (2, 6) and ( – 1, – 3) as given the following table and join them to form a line of the given equation.
Now from x = – 2,
draw a line parallel to y-axis at a distance of x = – 2, meeting the given line at P. From P, draw, a line parallel to x-axis joining y-axis at M, which is y = – 6 Hence, y = – 6 Ans.

Question 3.
Solution:
In the given equation x + 2y – 3 = 0
=> 2y = 3 – x
y = 3x2
put x = 1,then   Question 4.
Solution:
(i) In the equation y = x
When x = 1, then y = 1
when x = 2, then y = 2
and when x = 3, then y = 3      Question 5.
Solution:
In the given equation
2x – 3y = 5   Question 6.
Solution:
In the given equation
2x + y = 6
=> y = 6 – 2x
Put x = 1, then y – 6 – 2 x 1 = 6 – 2 = 4
Put x = 2, then y = 6 – 2 x 2 = 6 – 4 = 2
Put x = 3, then y = 6 – 2 x 3 = 6 – 6 = 0  Question 7.
Solution:
In the given equation
3x + 2y = 6   This is the complete blog on the RS Aggarwal Solutions Class 9 Maths Chapter 4 Linear Equations in Two Variables. To know more about the CBSE Class 9 Maths exam, ask in the comments.