RS Aggarwal Solutions Class 9 Maths Chapter 19 Probability (Updated For 2024)

RS Aggarwal Solutions Class 9 Maths Chapter 19 Probability: Your Class 9 Maths exam preparation is incomplete by studying the RS Aggarwal Solutions Class 9 Maths. You can always rely on the RS Aggarwal Solutions Class 9 Maths Chapter 19 Probability for clearing your doubts and subject matter experts have designed well-designed solutions for you.

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RS Aggarwal Solutions Class 9 Maths Chapter 19 Probability

RS Aggarwal Solutions Class 9 Maths Chapter 19 Probability – Overview

In this chapter, you will deal with the concept of probability. The Probability of an event is a number somewhere in the range of 0 and 1, where, 0 demonstrates the event’s failure, and 1 shows certainty.

Here are the key points covered in RS Aggarwal Solutions Class 9 Maths Chapter 19 Probability.

• Experiment: Any technique that can be vastly repeated and has a very much characterized set of potential outcomes also known as sample space. An experiment is supposed to be random on the off chance that it has more than one potential result and deterministic on the off chance that it has just one.
• Trail: A trail is a specific performance of a random experiment. All possible trails that establish an all-around characterized set of possible results are by and large called an experiment or sample space.
• Experimental or Empirical Probability: It is the probability of an event dependent on the consequences of a real experiment led a few times.

It is represented as 

Probability of event P(E)=Number of possible outcomes/Total number of outcomes.

• Coin Tossing Experiment: Here the mutually independent results are the coin arrival either heads up or tail up. If the probability is one, we state that this result consistently happens with complete certainty. 

The probability of getting head P(H) =Number of results to get head n(H)/Number of possible outcomes n(S)= ½

Similarly, the probability of getting a tail P(T) = ½

• Rolling Of Dice: When a fair dice is rolled, the number that surfaces top is a number between one to six. 

The probability of getting two P(E)= Number of results to get two n(E)/Number of possible results n(S)=1/6

The result is the same for all the remaining numbers.

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