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RS Aggarwal Solutions Class 9 Maths Chapter 14 Areas of Triangles and Quadrilaterals
RS Aggarwal Solutions Class 9 Maths for Chapter 14 Areas of Triangles and Quadrilaterals – Overview
In the Chapter 14 of RS Aggarwal Solutions Class 9 Maths, you will get to know about the following topics:
 Area of different triangles and quadrilaterals
 Area of a quadrilaterals using diagonals
In this chapter, you will have to deal with two exercises:
 There are 44 questions in the first exercise that covers various concepts of finding the area of triangles and different quadrilateral figures using suitable formulae.
 In the second exercise, there are various objectivetype questions based on the concepts you have learned in the previous exercise.
 Important Formulae

The basic area of any triangle: ½ × b × h
where b is the base and h is the height of the triangle

Area of an equilateral triangle: An equilateral triangle is a triangle whose all the sides are equal.
Area of an equilateral triangle = √3/4 × a²
Height of an equilateral triangle = √3/4 × a
where a is the measure of its sides.

Area of an isosceles triangle: b/4 x √4a²b²
where a is the measure of the two equal sides and b is the measure of the base.

Area of a triangle having three different sides (Heron’s formula):
Suppose a triangle has sides measuring a, b and c.
According to Heron’s formula:
The first step includes finding the semiperimeter of the triangle:
Semiperimeter (S) = (a+b+c)
Using the above finding and implementing it in the Heron’s formula for the area of a triangle constitutes the second step.
Area = √ s (sa) (sb) (sc)
There are seven different types of quadilaterals, each having a specific formula for its area.

Parallelogram: Its opposite sides are equal and parallel to each other.
Area of a parallelogram = base × height

Rectangle: It is a parallelogram with all four angles measuring 90⁰
Area of a rectangle = length × breadth

Square: It is a rectangle whose all sides are equal
Area of a square = side²

Rhombus: It is a parallelogram whose all sides are equal.
Area of a rhombus = base × height
Area of rhombus using diagonals = (d1xd2)/2

Trapezium: A trapezium has one pair of sides parallel.
Area of trapezium = 1/2 x (a + b) × h
where a and b are the measure of two parallelsided and h is the height

Kite: It has two pairs of equal adjacent sides but unequal opposite sides.
Area of a kite = (d1xd2)/2
NOTE: Perimeter of any figure is equal to the sum of all its sides.
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FAQs on RS Aggarwal Solutions Class 9 Maths Chapter 14 Areas of Triangles and Quadrilaterals
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Is the RS Aggarwal Solutions Class 9 Maths Chapter 14 a credible source for Class 9 Maths exam preparation?
Yes, the solutions are prepared by the subject matter experts, hence credible.
How many questions are there in RS Aggarwal Solutions Class 9 Maths Chapter 14 Ex 14.1?
There are 44 questions in this exercise.
How many exercises are there in RS Aggarwal Solutions Class 9 Maths Chapter 14 Areas of Triangles and Quadrilaterals?
There are 2 exercises in this chapter.