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## Download RS Aggarwal Solutions Class 7 Maths Chapter 1 Ex 1.2 PDF

RS Aggarwal Solutions Class 7 Maths Chapter 1 Ex 1.2

## Access Solutions Of RS Aggarwal Solutions Class 7 Maths Chapter 1 Ex 1.2

**Question 1.****Solution:**

(i) 16 by 9 = 16 x 9 = 144

(ii) 18 by -6 = 18 x (-6) = -108

(iii) -36 by -11 = 36 x (-11) = -396

(iv) -28 by 14 = -28 x 14 = -392

(v) -53 by 18 = -53 x 18 = -954

(vi) -35 by 0 = -35 x 0 = 0

(vii) 0 by -23 = 0 x (-23) = 0

(viii) -16 by -12 = (-16) x (-12) = 192

(ix) -105 by -8 = -105 x (-8) = 840

(x) -36 by -50 = (-36) x (-50) = 1800

(xi) -28 by -1 = (-28) x (-1) = 28

(xii) 25 by -11 = 25 x -11 = -275

**Question 2.****Solution:**

(i) 3 x 4 x (-5) = 12 x (-5) = -60 = 60

(ii) 2 x (-5) x (-6) = (-10) x (-6) = 60

(iii) (-5) x (-8) x (-3) = 40 x (-3) = -120

(iv) (-6) x 6 x (-10) = (-36) x (-10) = 360

(v) 7 x (-8) x 3 =(-56) x 3 = -168

(vi) (-7) x (-3) x 4 = 21 x 4 = 84

**Question 3.****Solution:**

(i) (-4) x (-5) x (-8) x (-10) = (4 x 5) x (8 x 10)

{Number of negative integers is even}

= 20 x 80 = 1600

(ii) (-6) x (-5) x (-7) x (-2) x (-3)

Here number of negative integers is odd

= (-1) [6 x 5 x 7 x 2 x 3]

= (-1) (1260) = -1260

(iii) (-60) x (-10) x (-5) x (-1)

Here number of negative integers is even

= 60 x 10 x 5 x 1

= 3000

(iv) (-30) x (-20) x (-5)

Here number of negative integers is odd

= (-1) (30 x 20 x 5) = -1 x 3000 = -3000

(v) (-3) x (-3) x (-3) x …6 times

Here number of negative integers is even

= 3 x 3 x 3 x 3 x 3 x 3 = 729

(vi) (-5) x (-5) x (-5) x …5 times

Here number of negative integers is odd

= (-1) (5 x 5 x 5 x 5 x 5)

= (-1) (3125) = – 3125

(vii) (-1) x (-1) x (-1) x …200 times

Here number of negative integers is even

= 1 x 1 x 1 x 1 x 200 times = 1

(viii) (-1) x (-1) x (-1) x …171 times

Here number of negative integers is odd

= (-1) x (1 x 1 x 1 x ……… 171 times)

= -1 x 1 = -1

**Question 4.****Solution:**

Number of negative integers = 90

which is positive and 9 integers are positive

The sign of the product will be positive

**Question 5.****Solution:**

Number of negative integers = 103 which is negative

Product will be negative

**Question 6.****Solution:**

(i) (- 8) x 9 + (- 8) x 7

= (-8) {9 + 7}

= -8 x 16 = -128

(ii) 9 x (-13) + 9 x (-7)

= 9 x (-13 – 7)

= 9 x (-20) = – 180

(iii) 20 x (-16) + 20 x 14 = 20 x {-16 + 14}

= 20 x (-2)= -40

(iv) (-16) x (-15) + (-16) x (-5)

= (-16) x {-15 – 5}

= (-16) x (-20) = 320

(v) (-11) x (-15)+ (-11) x (-25)

-(-11) x {-15 – 25}

= (-11) x (-40) = -440

(vi) 10 x (-12)+ 5 x (-12)

= (-12) {10 + 5} = (-12) x 15 = -180

(vii) (-16) x (-8) + (-4) x (-8)

= (-8){-16 – 4} = (-8) x (-20) = 160

(viii) (-26) x 72 + (-26) x 28

= (-26) (72 + 28) = (-26) x 100 = -2600

**Question 7.****Solution:**

(i) (-6) x (………) = 6 ⇒ (-6) x (-1) = 6

(ii) (-18) x (………) = (-18) ⇒ (-18) x (1) = (-18)

(iii) (-8) x (-9) = (-9) x (……….) ⇒ (-8) x (-9) = (-9) x (-8) (By Commutative Law of Multiplication)

(iv) 7 x (-3) = (-3) x (……….) ⇒ 7 x (-3) = (-3) x (7) (By Commutative Law of Multiplication)

(v) {(-5) x 3} x (-6) = (………) x {3 x (-6)} ⇒ {(-5) x 3} x (-6) = (-5) x {3 x (-6)} (By Associative Law of Multiplication)

(vi) (-5) x (……….) = 0 ⇒ (-5) x (0) = 0 (By Property of Zero)

**Question 8.****Solution:**

Number of questions in a test =10

Marks awarded for every correct answer = 5

and marks deducted for every wrong answer = 2 (-2 is given)

(i) Ravi gets 4 correct and 6 incorrect answers

Total marks obtained by him = 4 x 5 – 6 x 2 = 20 – 12 = 8

(ii) Reenu gets 5 correct and 5 incorrect answers

Total marks obtained by her = 5 x 5 – 5 x 2 = 25 – 10= 15

(iii) Heena gets 2 correct and 5 incorrect answers

She gets marks = 2 x 5 – 5 x 2 = 10 – 10 = 0

**Question 9.****Solution:**

(i) True: As product of a positive and a negative integer is negative.

(ii) False: The product of two negative integers is positive.

(iii) True.

(iv) False: As multiplication of an integer and (-1) is negative.

(v) True as a x b = b x a.

(vi) True as (a x b) x c = a x (b x c)

(vii) False: It is not possible except integer 1.

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