RS Aggarwal Solutions for Class 10 Maths Chapter 14 Height and Distance | Updated For 2024

RS Aggarwal Solutions for Class 10 Maths Chapter 14 Height and Distance

RS Aggarwal Solutions for Class 10 Maths Chapter 14 Height and Distance: Subject matter experts have designed easy-to-understand solutions for RS Aggarwal Solutions for Class 10 Maths Chapter 14 Height and Distance. You can easily clear your doubts with this ultimate help guide. All the solutions of RS Aggarwal Solutions Class 10 Maths Chapter 14 are as per the current CBSE Syllabus.

You can download the RS Aggarwal Solutions Class 10 Maths Chapter 14 Height and Distance PDF for free from this blog.

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RS Aggarwal Solutions for Class 10 Maths Chapter 14 Height and Distance

 


Access The RS Aggarwal Class 8 Maths Chapter 23 Ex 23.1 Solutions

Solution 1

Let AB be the tower standing on a level ground and O be the position of the observer. Then OA = 20 m and 183527 image002OAB = 90° and 183527 image002AOB = 60°

183527 pic250

Let AB = h meters

From the right 183527 TriangleOAB, we have

183527 pict190

Hence the height of the tower is 183527 image009

Solution 2

Let OB be the length of the string from the level of ground and O be the point of the observer, then, AB = 75m and 183528 image002OAB = 90° and 183528 image002AOB = 60°, let OB = l meters.

From the right 183528 TriangleOAB, we have

183528 pic251

183528 pict191

Solution 3

 

Solution 4

  

Solution 5

  

Solution 6

  

Solution 7

  

 

  

Solution 8

Let SP be the statue and PB be the pedestal. Angles of elevation of S and P are 60° and 45° respectively.

Further suppose AB = x m, PB = h m

183538 pic261

In right 183538 image033ABS,

183538 image121

In right 183538 image033PAB,

183538 image123


Thus, height of the pedestal = 2m

Solution 9

Let AB be the unfinished tower and let AC be complete tower.

Let O be the point of observation. Then,

OA = 75 m

183700 image002AOB = 30° and 183700 image002AOC = 60°

183700 pic280

Let AB = h meters

And AC = H meters

183700 image330

Hence, the required height is 183700 pict214

Solution 10

Let AB be the tower and BC be flagpole, Let O be the point of observation.

Then, OA = 9 m, 183540 image002AOB = 30° and 183540 image002AOC = 60°

183540 pic263

From right angled 183540 TriangleBOA

183540 image134

From right angled 183540 TriangleOAC

183540 image136

Thus 183540 image138

Hence, height of the tower= 5.196 m and the height of the flagpole = 10.392 m

RS Aggarwal Solutions for Class 10 Maths Chapter 14 Height and Distance – Overview 

Chapter 14 of RS Aggarwal Solutions Class 10 Maths comes with one exercise and all the questions related to the topic of Height and Distance. 

All the topics are very well-explained in RS Aggarwal Solutions Class 10 Maths Chapter 14. The questions are explained in a step-by-step manner and are very accurate. To clear your doubts in detail, this is the perfect guide for you. 

Class 10 RS Aggarwal Solutions – Height and Distances

In this chapter, we will learn how to solve questions related to the heights of the rectangular prism and the rectangular trapezoid using Pythagoras’ theorem. Both the prisms and trapezoids are considered rectangular in this chapter, which means they are rectangles or rectangle-shaped solids. They are made of right rectangularly aligned rows of points of various lengths

Pythagoras’ Theorem:

The height of a triangle is given by the Area of the triangle: c . h . d

Where

c = the length of the hypotenuse

d = the length of the leg

h = the height of the triangle.

Access RS Aggarwal Solutions Class 10 Maths Chapter 14 Other Important Exercises

RS Aggarwal Solutions Chapter 14 Exercise 14.1

This is the complete blog on the RS Aggarwal Solutions Class 10 Maths Chapter 14. To know more about the CBSE Class 10 Maths exam, ask in the comments.

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