RS Aggarwal Solutions Class 8 Maths Chapter 9 Percentage Exercise 9.1 (2021-22) RS Aggarwal Class 8 Solutions Chapter 9 Ex 9.1: At Kopykitab, our subject experts in Mathematics have prepared RS Aggarwal Solutions Class 8 Maths Ex 9a. These are accurate and reliable answers. The aim of RS Aggarwal Class 8 Maths Chapter 9 Ex 9a is to assess a student’s understanding of basic percentage concepts.

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RS Aggarwal Class 8 Solutions Chapter 9 Ex 9.1

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Question 1.
Solution:
(i) 48% = 48100 = 1225
(ii) 220% = 220100 = 115
(iii) 2.5% = 2.5100 = 2510X100 = 140

Question 2.
Solution:
(i) 6% = 6100 = 0.06
(ii) 72% = 72100 = 0.72
(iii) 125% = 125100 = 1.25

Question 3.
Solution: Question 4.
Solution:
Ratio is 4:5 or 45
45
= 4X205X20
= 80100
= 80%

Question 5.
Solution:
125% = 125100
= 54 (dividing by 25)
Ratio = 5:4

Question 6.
Solution: We see that 15% or 320 is the largest

Question 7.
Solution:
(i) Let x% of 150
= 96  Question 8.
Solution:
623 of Rs 3600
= Rs 92 x 3600100
= Rs 162

Question 9.
Solution:
16% of a number = 72
Number = 7216%
= 72X10016
= 450

Question 10.
Solution:
Let monthly income = Rs x
Savings = 18% Question 11.
Solution:
Let total games = x
Then game which a team wins = 73
and it is 35% of total games
35% of x = 7
=> x = 7X10035 = 20
Number of total games = 20

Question 12.
Solution:
Let salary = Rs x
Increment = 20%
Total salary = x + 20% of x Question 13.
Solution:
No. of days, Sonal attended = 204 days
and her attendance = 85% of total days
85% of total days = 204
Total number of days = 204X10085
= 240 days

Question 14.
Solution:
Let B’s income = Rs. 100
Then A’s income = 20% less than B’s
= 100 – 20 = Rs. 80
Difference = 100 – 80 = 20
B’s more income that A’s = 2080 x 100
= 25%

Question 15.
Solution:
Increase in price of petrol = 10%
Let first price = Rs. 100 p.l.
Increased price = 100 + 10 = Rs. 110
Now reduction in consumption = 110 – 100= 10
Percentage reduced consumption
= 10X100110
= 10011
= 9111

Question 16.
Solution:
Present population of a town = 54000
Rate of increase = 8% annually
Population a year ago = 54000X100100+8
= 54000X100108
= 50000

Question 17.
Solution:
Depreciation in the value of machine = 20%
Present value = Rs. 160000
Then value of machine one year ago
= 160000X100100−20
= 160000X10080
= Rs 200000

Question 18.
Solution:
In an alloy,
Copper = 40%
Nickel = 32%
Zinc = 100 – (40% + 32%)
= 100 – 72 = 28%
Then mass of zinc in one kg of alloy
= 1 kg X 28%
= 1000X28100 g
= 280 gm

Question 19.
Solution:
In balance diet,
Protein = 12%
Fats = 25%
Carbohydrates = 63%
Total number of dories = 2600 Question 20.
Solution:
In gunpowder,
Nitre = 75%
Sulphur = 10%
(i) Amount of gunpowder if nitre is 9 kg
= 10075 x 9
= 12 kg
(ii) Amount of gunpowder if sulphur is 2.5kg 100
= 10010 x 2.5
= 25 kg

Question 21.
Solution:
Let C get = Rs. x  Question 22.
Solution:
24-carat gold is 100% pure
22 parts out of 24 part in 22-carat gold Question 23.
Solution:
Let present salary = Rs. 100
Increase = 25%
Increased salary = Rs. 100 + 25
= Rs. 125
To receive the original salary, amount to be decreased = Rs. 125 – 100 = Rs. 25
∴ % decrease = 25X100125 = 20%

Important Definition for RS Aggarwal Class 8 Maths Chapter 9 Ex 9.1 Solutions

• Fraction

It is a number of parts of a whole thing. It signifies how many parts of a certain size are divided into a whole thing. A fraction comprises a numerator & a denominator.

• Steps to Convert Percentage to Fraction

(I) Method One

Step 1: Divide the given percent by 100. This will give a decimal number.

Step 2: After a decimal point, count the number of digits. The digit is represented as d.

For instance: The decimal number 2.56 has two digits after the decimal point, so d = 2.

Step 3: Calculate the factor (f). This will convert the decimal number as an integer using the formula f = 10d. So, f = 102 = 100

Step 4: The decimal number must be divided & multiplied by the factor

Step 5: Find the Greatest Common Divisor of the fraction

Step 6: Simplify the fraction by dividing the numerator & denominator by the GCD value

(II) Method Two

Step 1: Divide the given percent by 100 to obtain the decimal number percent100.

Step 2: If the percent is not a whole number, then multiply each number by 10 after the decimal point.

Step 3: Simplify the fraction.

Hope given RS Aggarwal Class 8 Solutions Chapter 9 Ex 9.1 are helpful to complete your CBSE Math homework. If you have any doubts, please comment below.

RS Aggarwal Class 8 Solutions Chapter 9 Ex 9.1 – FAQs

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Is it required to remember all of the questions in Chapter 9 Exercise 9.1 of RS Aggarwal Solutions for Class 8 Maths?

Yes, all of the questions in RS Aggarwal Class 8 Solutions Chapter 9 Ex 9.1 must be learned. These questions may appear on both board exams and class tests. Students will be prepared for their board exams if they learn these questions.