RS Aggarwal Class 8 Maths Chapter 3 Ex 3.8 Solutions: This exercise deals with the topics related to the long division method to find the approximate values of square roots. The solutions assist the students to practice & learn the fundamentals as it provides all the answers to the questions from the textbook. Practicing as many times as possible enables the students to better understand the topics & also assists them in effective time management skills. This also boosts their confidence level to attain high marks in the Class 8th Maths final exam.
RS Aggarwal Class 8 Maths Chapter 3 Ex 3.8 Solutions are very helpful for the students at the time of practicing questions from this exercise. These solutions offer the students a detailed and in-depth understanding of all the questions and topics of this exercise. The students can get these solutions that are accurate & reliable & enable the students to understand this chapter in a better way.
Access RS Aggarwal Class 8 Maths Chapter 3 Solutions PDF
Download RS Aggarwal Class 8 Maths Chapter 3 Ex 3.8 Solutions
RS Aggarwal Class 8 Maths Chapter 3 Ex 3.8 Solutions
Important Definition for RS Aggarwal Class 8 Maths Chapter 3 Ex 3.8 Solutions
- Long division method to find the approximate values of square roots. The students can easily with just one click download RS Aggarwal Class 8 Maths Chapter 3 Ex 3.8 PDF free of cost & obtain the detail of each topic they needed to study. The students can also get an idea about the real exam paper pattern that assists them to understand the marking scheme as well. The students can get these solutions that are accurate & reliable & enable the students to understand this chapter in a better way.
Here is the stepwise solution for the long division method:
- Divide the digits of the number into pairs of segments begining with the digit in the units place. Then identify each pair & the remaining final digit (in case there is an odd count of digits in the number) as a segment.
- After dividing the digits into segments, begin from the leftmost segment. The largest number whose square is equal to or just less than the 1st segment is taken as the divisor & also as the quotient so that the number is the square.
- Subtract the square of the divisor from the 1st segment & bring down the next segment to the right of the remainder to attain the new dividend.
- Then, the new divisor is acquired by taking two times the previous quotient & connecting it with a suitable digit which is also taken as the next digit of the quotient, selected in such a way that the number of the new divisor & this digit is equal to or just less than the new dividend.
- Repeat steps (2), (3) & (4) till each segment have been taken up. Then, the quotient so acquired is the needed square root of the given number.
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