# RS Aggarwal Class 8 Maths Chapter 13 Ex 13.1 Solutions 2022 | Download Free PDF

RS Aggarwal Class 8 Maths Chapter 13 Ex 13.1 Solutions: This exercise covers topics related to pipes & cistern problems using some general rules. It is essential that the students should practice the problems on a regular basis which enables them to excel in their exams & improve their overall percentage too.

The solutions are presented in a precise manner so the students can effortlessly get the answers to any question available in the RS Aggarwal textbook. RS Aggarwal Class 8 Maths Chapter 13 Ex 13.1 Solutions are created as per the latest syllabus & the guidelines of CBSE that cover detailed illustrations with each answer. The students will get simplified & detailed solutions to the complex problems that enable them to understand the topics with ease.

## Download RS Aggarwal Class 8 Maths Chapter 13 Ex 13.1 Solutions

RS Aggarwal Class 8 Maths Chapter 13 Ex 13.1 Solutions

## Important Definition for RS Aggarwal Class 8 Maths Chapter 13 Ex 13.1 Solutions

• Pipes and cistern

It is another form of time & work-based questions. The questions like the time taken to fill or empty a tank, the amount of work performed for the same & similar kinds of questions may come in the exam. There are 2 main things which the students need to know about such questions:

(i) Inlet: It is a pipe that is linked to fill a tank with water. It is the positive kind of work performed.

(ii) Outlet: It is a pipe that is linked to empty the tank of water. It shows a negative kind of work performed.

• Important Formula on Pipes and Cistern
• Following are some important formulas that shall assist the students to solve the pipes and cistern based questions fast & more efficiently:
• If x hours are needed to fill up a tank, the part filled in 1 hr = 1/x
• If y hours are needed to empty the tank, the part emptied in 1 hour = 1/y
• If a pipe can fill a tank in x hours & can empty the same tank in y hours. If both the pipes are opened at the same time, the net part of the tank filled in 1 hr = {(xy) / (y – x)}, given y>x
• If a pipe can fill a tank in x hours & can empty the same tank in y hours. If both the pipes are opened at the same time, the net part of the tank filled in 1 hr = {(xy) / (x – y)}, given x>y
• Net work performed = (Sum of work performed by Inlets) – (Sum of work performed by Outlets)
• One inlet can fill the tank in x hr & the other inlet can fill the same tank in y hrs, when both the inlets are opened at the same time, the time is taken to fill the whole tank = {(xy) / (y+x)}
• If 2 pipes take x & y hours respectively to fill a tank of water & a 3rd pipe is opened which takes z hours to empty the tank, the time taken to fill the tank = {1 / (1/x) + (1/y) + (1/z)} & the net part of the tank filled in 1 hr = (1/x) + (1/y) – (1/z)

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