**RD Sharma Class 10 Solutions Chapter 14 Exercise 14.1: **A pair of mutually perpendicular lines known as coordinate axes are required to locate a point on a plane. The important things assessed in this exercise are the introduction to these rectangular coordinate axes, cartesian coordinates of a point, and quadrants. Students can use the **RD Sharma Class 10 Solutions** to clear up any doubts they have about this chapter. Students can also get the **RD Sharma Solutions for Class 10 Maths Chapter 14 Co-ordinate Geometry** Exercise 14.1 PDF by clicking on the link below.

## Download RD Sharma Class 10 Solutions Chapter 14 Exercise 14.1 Free PDF

RD Sharma Class 10 Solutions Chapter 14 Exercise 14.1

### Access answers to RD Sharma Solutions Class 10 Maths Chapter 14 Exercise 14.1- Important Question with Answers

Question 1.

On which axis do the following points lie?

(i) P (5, 0)

(ii) Q (0 – 2)

(iii) R (-4, 0)

(iv) S (0, 5)

Solution:

(i) P (5, 0)

Its ordinate or y-axis is 0. It lies on x-axis

(ii) Q (0 – 2)

Its abscissa or x-axis is 0. It lies on y-axis

(iii) R (-4, 0)

Its ordinate is 0 It lies on x-axis

(iv) S (0, 5)

Its abscissa is 0. It lies on y-axis

Question 2.

Let ABCD be a square of side 2a. Find the coordinates of the vertices of this square when

(i) A coincides with the origin and AB and AD are along OX and OY respectively.

(ii) The centre of the square is at the-origin and coordinate axes are parallel to the sides AB and AD respectively.

Solution:

ABCD is a square whose side is 2a

(i) A coincides with origin (0, 0)

AB and AD are along OX and OY respectively

Co-ordinates of A are (0, 0), of B are (2a, 0) of C are (2a, 2a) and of D are (0, 2a)

(ii) The centre of the square is at the origin (0, 0) and co-ordinates axes are parallel to the sides AB and AD respectively. Then the co-ordinates of A are (a, a) of B are (-a, a), of C are (-a, -a) and of D are (a, -a) as shown in the figure given below :

Question 3.

The base PQ of two equilateral triangles PQR and PQR’ with side 2a lies along y- axis such.that the mid-point of PQ is at the origin. Find the coordinates of the vertices R and R’ of the triangles.

Solution:

∆PQR and PQR’ are equilateral triangles with side 2a each and base PQ and mid of point of PQ is 0 (0, 0) and PQ lies along y-axis

We have provided complete details of RD Sharma Class 10 Solutions Chapter 14 Exercise 14.1. If you have any queries related to **CBSE** Class 10, feel free to ask us in the comment section below.

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