### Discussion :: Hydraulics - Section 1 (Q.No.17)

Kanishk said: (Sep 10, 2013) | |

The expression is given as: Tau = del(p)/del(x) * r/2. where r = distance from the central axis. So the answer should be B. |

Ujwal said: (Oct 21, 2013) | |

Shear stress is maximum at the pipe faces and will be minimum at the center. Velocity will be max at the center and minimum at the face of pipe. |

Magnus Hwosafe said: (Nov 25, 2013) | |

The answer is correct; the velocity is maximum @ the centre hence the shear stress being proportional to the velocity gradient is also maximum. |

Prashant Tomar said: (Nov 20, 2015) | |

Shear stress is minimum in center and maximum at face. |

Ejaz Ahmad said: (Nov 30, 2015) | |

In circular pipe Shear stress is minimum at center and maximum at face inside the pipe because it varies with are i.e radius keeping dp/dx is constant but in case of velocity i.e velocity is maximum at center and minimum at face inside the pipe. Hence answer should be B. |

R.Verman said: (Mar 5, 2016) | |

Answer should be B. |

Parth Bhai said: (Jun 10, 2016) | |

Yes, the answer should be option B. |

Aman said: (Aug 11, 2016) | |

Shear is maximum at wall surface and velocity is maximum at center of pipe. |

Shailendra Kumar said: (Oct 10, 2016) | |

Answer should be D because shear stress is 0 at centre and maximum at surface not inside the surface. |

Sarath Kumar said: (Dec 10, 2016) | |

Answer 'A' because shear stress is maxed at faces n min at center as viscous flow is nothing but laminar flow. |

Baloch said: (Jan 8, 2017) | |

Stress increases linearly with distance from the centre, i.e min at centre and max at the boundary of the pipe. |

Pavankalyan said: (Mar 1, 2017) | |

As it is a viscous liquid it offers some resistance. So, shear stress will be min. At centre and max. At surface of the pipe. So, the answer should be B. If it is non-viscous fluid then answer is correct. |

Sk Imtiaj Alam said: (Mar 14, 2017) | |

Actually, shear stress is max at inside the surface of pipe and min at the centre but distribution of shear stress is linear. So answer is (C). |

Sachinreddy said: (Apr 9, 2017) | |

Answer B is right because shear stress varies linearly from the centre of the pipe to the boundary. It Means zero shear stress at centre & Maximum at the boundary. |

Jagmohan said: (Apr 17, 2017) | |

Shear stress is minimum at the centre. |

Sarang Mote said: (Apr 24, 2017) | |

I think the correct answer is B. |

Udk Soni said: (May 19, 2017) | |

It is min at centre and max at the boundary. |

Athira said: (Jun 6, 2017) | |

Shear stress distribution is linear in a pipe with max at its inner face and zero at the centre. |

Sandeep Maurya said: (Oct 20, 2017) | |

In a pipe flow friction developed, Which cause velocity not constant throughout the section, so that shear stress never constant through the section. Shear stress proportional to the distance from center of the pipe. As radius 0 shear stress 0, and are maximum, shear stress will be maximum. |

R H said: (Nov 11, 2017) | |

Answer will be (D) none of these. As shear stress distribution is minimum at centre and maximum at pipe wall. Don't get confused. |

Vishnu Sharma said: (Nov 16, 2017) | |

Shear stress is maximum at outer face of pipe and zero at the center of pipe of axis. |

Dilwar Hossain said: (Nov 28, 2017) | |

Shear stress is minimum at the center and maximum at the face of wall inside the pipe. |

Venkatesh said: (Dec 9, 2017) | |

B is correct. I also agree. |

Raj said: (Jan 19, 2018) | |

Yes, the distribution diagram is K shaped. Hence, maximum at the inside faces and zero at centre. Option B is correct. |

Suraj said: (Apr 2, 2018) | |

Shear stress across a section varies with r. Hence dp/dx across a section is constant. Hence shear across a section is linear. Hence shear stress is maxed at inside surface of the pipe. |

Jithin said: (Apr 8, 2018) | |

The correct answer is B. |

Anomi said: (Apr 15, 2018) | |

It is Zero at centre of pipe |

Rohit Singh Baghel said: (Jun 17, 2018) | |

The Answer is correct because of the behaviour of shear stress that is one at Maximum at face and minimum at centre in constant throughout all the sections. |

Sudhir said: (Jul 5, 2018) | |

Answer should be D. |

Dharmendra said: (Aug 9, 2018) | |

Answer is B, because shear stress is min at centre and Max at inside of the surface. |

Basavaraj said: (Aug 24, 2018) | |

For shear Max at the boundary min at center where as for velocity it is parabolic section. |

Asad said: (Oct 25, 2018) | |

The Correct Answer is B. Because shear stress is maximum at distance r=D/2 from the centre of the pipe. |

Ajayveer said: (Oct 28, 2018) | |

I think Option B should be correct. |

Hussain Azam said: (Dec 25, 2018) | |

The Correct option is B. Because velocity is maximum at the centre whereas the shear stress is maximum at the inner surface of pipe. |

Abahy Dubey said: (Apr 11, 2019) | |

Option B is the correct answer. |

Pradeep said: (Aug 26, 2019) | |

1. Velocity distribution is parabolic. That is maximum at the centre. 2. The shear stress distribution is zero at the centre and gradually increased though it the inner surface. Here, "B" is the correct answer. |

Tanmoy Karmakar said: (Aug 27, 2020) | |

Shear stress distribution is linear at center is zero and maximum at wall surface. |

Jafar said: (Sep 18, 2020) | |

Here, τ = -dp/dx(r/2). |

Nadeem Qadir said: (Jan 20, 2021) | |

Shear stress is more at the surface and minimum at center. Answer should be B. |

Pkota said: (Apr 8, 2021) | |

In the case of inviscous flow i.e. ideal flow shear stress distribution is of rectangular shape so answer c is correct. In case of real flow steady and laminar then option B will be correct. |

Karam Bharmoria said: (Jul 19, 2021) | |

B is the correct answer. |

Mjm Gcek said: (Jul 26, 2021) | |

B is the correct answer. |

Baloch said: (Sep 12, 2021) | |

I think the given answer is correct because it is being asked regarding Shear stress distribution in VISCOUS FLUID. So, for VISCOUS FLUID shear stress distribution will be the same throughout the section. |

Baloch said: (Sep 12, 2021) | |

I think the given answer is correct because it is being asked regarding Shear stress distribution in VISCOUS FLUID. So, for VISCOUS FLUID shear stress distribution will be the same throughout the section. |

Mesbah Ullah said: (Oct 9, 2021) | |

The option B is correct. As per my knowledge, shear stress is linearly increased from the centre (r=0) and maximum at boundary where (r max). |

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