**RS Aggarwal Solutions Class 8 Maths Chapter 7 Factorisation: **Ace your Class 8 Maths exam with the RS Aggarwal Solutions Class 8 Maths**.** Subject matter experts have designed the solutions of RS Aggarwal Solutions Class 8 Maths Chapter 7 Factorisation for your better understanding. The solutions are as per the current CBSE Syllabus.

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## Download RS Aggarwal Solutions Class 8 Maths Chapter 7 Factorisation PDF

RS Aggarwal Solutions Class 8 Maths Chapter 7 Factorisation

## RS Aggarwal Solutions Class 8 Maths Chapter 7 Factorisation – Summary

In the beginning, you will get to know about the actors of natural numbers and of algebraic expressions. Then you will know about what factorisation is, as a written expression as a product of its factors. For example, we would factorise the number 20 by writing it as (4 x 5), or (2 x 10), or (2 x 2 x 5) when we are factorising it.

There are various methods of factorisation using algebric expressions, mentioned below:

- Common factors: Break down the algebric expression using the factors which the constants and variables have in common. For example, the expression 4a
^{2}b + 8ab^{2}will be broken down into its common factors and written as: 2 x 2 x a x a x b + 2 x 2 x 2 a x b x b. - Regrouping: When algebraic expressions have the same variable in it so that it can be factorised more easily, it is called regrouping. For example, the expression 6xy – 4y + 6 – 9x does not have any common factors other 6xy and -4y, and the number 3, thus, these two will be grouped and the other two will be grouped together as two different parts, then put together to factorise. 2y(3x – 2)is the first group and -3(3x – 2) is the second group. Putting these two ‘groups’ together, we get (2y – 3) and (3x – 2) as the factors of the expression.
- Identities: You can use the three basic identities, mentioned below:

- (a + b)2 = a
^{2}+ 2ab + b^{2} - (a – b)2 = a
^{2}– 2ab + b^{2} - (a + b)(a – b) = a
^{2}+ b^{2}

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