**RS Aggarwal Class 8 Maths Chapter 12 Ex 12.1 Solutions**: This exercise covers concepts related to variation & direct proportion. The top Mathematics experts have prepared this exercise in an easy language to ensure that the students are thorough with their basic concepts by practicing the solutions on regular basis. The exercise solutions are solved by our Mathematics expert team to assist students to easily understand the fundamentals.

These solutions enable the students by offering them the elaborated answers for each question as per the latest CBSE syllabus. These solutions also assist the students to have a skillful studying pattern with which they can secure excellent marks in the Maths exam. The students can build a study plan for the final exam depending on their stronger & weaker areas & then can improve their performance by solving RS Aggarwal Class 8 Maths Chapter 12 Ex 12.1 Solutions regularly.

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**Download ****RS Aggarwal Class 8 Maths Chapter 12 Ex 12.1 Solutions**

** RS Aggarwal Class 8 Maths Chapter 12 Ex 12.1 Solutions**

**Important Definition for ****RS Aggarwal Class 8 Maths Chapter 12 Ex 12.1 Solutions**

**Direct and inverse proportion**

It is used to show how the amount & quantities are related to each other. The symbol used to express the proportionality is’∝’.

For instance: Suppose x is proportional to y, then it is represented as ‘x∝y’ & if a is inversely proportional to b, then it is denoted as ‘x∝1/y’.

These relations are conducted by some proportionality rules. In these cases, the value of ‘x’ converts in terms of ‘y’, or if the value of ‘y’ changes, the value of ‘x’ also gets converted. The change in both values is identified with a constant of proportionality.

**Direct Proportion**

Two quantities a & b are known to be in direct proportion if they increase or decrease together. The ratio of their corresponding values remains constant i.e a/ b = k

Where k is a positive number, then the quantities a & b are known to vary directly.

In such a case if the values b_{1}, b_{2} of b corresponding to the values a_{1}, a_{2} of a respectively then it becomes a_{1}//b_{1} = a_{2} /b_{2}

**Inverse Proportion**

Two quantities a & b are known to be in inverse proportion if an increase in quantity a, there will be a decrease in the quantity b, & vice-versa. The product of their corresponding values should remain constant i.e if ab = k, then a & b are said to vary inversely. In this case, if b_{1}, b_{2} are the values of b corresponding to the values a_{1}, a_{2} of a respectively then a_{1} b_{1} = a_{2} b_{2} or a_{1}/a_{2} = b_{2} /b_{1}

The statement ‘a is inversely proportional to b is written as a ∝ 1/b

**Set up an Equation with the below steps**

(i) Write down the proportional symbol.

(ii) Convert it as an equation with the help of constant of proportionality.

(iii) Find the constant of proportionality from the given information.

(iv) Substitute in an equation, after finding the constant of proportionality.

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