# RD Sharma Solutions Class 9 Maths Chapter 7- Introduction to Euclid’s Geometry (Updated for 2021-22) RD Sharma Solutions Class 9 Maths Chapter 7 Introduction to Euclid’s Geometry: RD Sharma CBSE Class 9 Maths solution to Euclid’s Geometry has been prepared by our mathematics teachers to help you solve exercise questions effortlessly with ease. To know more about the RD Sharma Solutions Class 9 Maths Chapter 7, read the whole blog.

## Download RD Sharma Solutions Class 9 Maths Chapter 7 – Introduction to Euclid’s Geometry PDF

RD Sharma Solutions Class 9 Maths Chapter 7

## Exercise-wise: RD Sharma Solutions Class 9 Maths Chapter 1

 RD Sharma Solutions Class 9 Chapter 7 Exercise 7.1

## Access answers of RD Sharma Solutions Class 9 Maths Chapter 7

### RD Sharma Solutions Class 9 Chapter 7 Introduction to Euclid’s Geometry Ex 7.1

Question 1.
Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:
(i) -2x + 3y = 12
(ii) x-y2 -5 = 0
(iii) 2x + 3y = 9.35
(iv) 3x = -7y
(v) 2x + 3 = 0
(vi) y – 5 = 0
(vii) 4 = 3x
(viii) y = x2
Solution:
(i) -2x + 3y = 12
⇒  -2x + 3y – 12 = 0
Here a -2, b = 3, c = – 12
(ii) x – y2 -5 = 0
Here a = 1, b =12 ,c = -5
(iii) 2x + 3y = 9.35
⇒  2x + 3y – 9.35 = 0
Here a = 2, b = 3, c = – 9.35
(iv) 3x = -7y
⇒  3x + 7y + 0 = 0
Here a = 3, b = 7,c = 0
(v) 2x + 3 = 0
⇒ 2x + 0y + 3 = 0
Here a = 2, b = 0, c = 3
(vi) y-5 = 0 ⇒ ox+y-5 = 0
Here a = 0, b = 1, c = -5
(vii) 4 = 3x
⇒ 3x – 4 = 0
⇒ 3x + 0y – 4 = 0
Here a = 3, b = 0, c = -4
(Viii) y= x2
⇒  x2 – y+ 0 = 0
⇒  x-2y + 0 = 0
Here a = 1, y = -2, c = 0

Question 2.
Write each of the following as an equation in two variables.
(i) 2x = -3
(ii) y = 3
(iii) 5x = 72
(iv) y =32x
Solution:
(i) 2x = -3⇒  2x + 3 = 0
⇒ 2x + 0y + 3 = 0
(ii) y= 3 ⇒  y-3=0
⇒  0x+ y-3 = 0
(iii) 5x =72 ⇒ 10x = 7
⇒  10x + 0y – 7 = 0
(iv) y=32x⇒2y = 3x
⇒ 3x – 2y + 0 = 0

Question 3.
The cost of ball pen is ₹5 less than half of the cost of fountain pen. Write this statement as a linear equation in two variables.
Solution:
Let cost of a fountain pen = ₹x
and cost of ball pen = ₹y
∴ According to the condition,
y = x2 -5
⇒  2y = x – 10
⇒  x – 2y – 10 = 0

### Introduction to Euclid’s Geometry RD Sharma Class 9 Solutions  2 (i)
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2 (ii)
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PQ,QR,PR   ## Summary: Class 9 Maths RD Sharma Chapter 7

### Euclid’s concepts are based on two categories that include:

• Axioms
• Postulates

Euclid used and applied Postulates to elaborate assumptions specific to geometry. Euclid used and applied the axioms as the hypothesis in all the concepts of maths. Most of them were related to geometry. Euclid concluded that some statements were already proven and termed those theories and statements as propositions or theorems.

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