RD Sharma Class 10 Solutions Chapter 13 Probability Exercise 13.2 (Updated for 2024)

RD Sharma Class 10 Solutions Chapter 13 Exercise 13.2

RD Sharma Class 10 Solutions Chapter 13 Exercise 13.2: The concept of geometrical probability is tested with various interesting questions in this exercise. The RD Sharma Class 10 Solutions is an excellent resource for students studying for their qualifying exams. For your convenience, we’ve included the RD Sharma Solutions for Class 10 Maths Chapter 13 Probability Exercise 13.2 PDF.

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RD Sharma Class 10 Solutions Chapter 13 Exercise 13.2

Access answers to RD Sharma Solutions Class 10 Maths Chapter 13 Exercise 13.2- Important Question with Answers

1. Suppose you drop a tie at random on the rectangular region shown in fig. below. What is the probability that it will land inside the circle with a diameter 1 m?

Solution:

R D Sharma Solutions For Class 10 Maths Chapter 13 Probability ex 13.2 - 1

Area of a circle with radius 0.5 m A circle = (0.5)2 = 0.25 πm2

Area of rectangle = 3 x 2 = 6m2

R D Sharma Solutions For Class 10 Maths Chapter 13 Probability ex 13.2 - 2

The probability that the tie will land inside the circle with a diameter 1m

R D Sharma Solutions For Class 10 Maths Chapter 13 Probability ex 13.2 - 3

Therefore, the probability that the tie will land inside the circle = π/24

2. In the accompanying diagram, a fair spinner is placed at the centre O of the circle. Diameter AOB and radius OC divide the circle into three regions labelled X, Y and Z.? If ∠BOC = 45°. What is the probability that the spinner will land in the region X?

Solution:

R D Sharma Solutions For Class 10 Maths Chapter 13 Probability ex 13.2 - 4

Given,

∠BOC = 45°

∠AOC = 180 – 45 = 135° [Linear Pair]

Area of circle = πr2

Area of region x = θ/360 × πr2

= 135/360 × πr2

= 3/8 × πr2

The probability that the spinner will land in the region

R D Sharma Solutions For Class 10 Maths Chapter 13 Probability ex 13.2 - 5

x = 3/8

Therefore, the probability that the spinner will land in Region X is 3/8.

3. A target is shown in fig. below consists of three concentric circles of radii, 3, 7 and 9 cm respectively. A dart is thrown and lands on the target. What is the probability that the dart will land on the shaded region?

Solution:

R D Sharma Solutions For Class 10 Maths Chapter 13 Probability ex 13.2 - 6

We have,

1st circle – with radius 3

2nd circle – with radius 7

3rd circle – with radius 9

So, their areas would be

Area of 1st circle = π(3)2 = 9π

Area of 2nd circle = π(7)2 = 49π

Area of 3rd circle = π(9)2 = 81π

Area of shaded region = Area of 2nd circle – Area of 1st circle

= 49π − 9π

= 40π

The probability that it will land in the shaded region

R D Sharma Solutions For Class 10 Maths Chapter 13 Probability ex 13.2 - 7

Therefore, the probability that the dart will land in the shaded region is 40/81.

We have provided complete details of RD Sharma Class 10 Solutions Chapter 13 Exercise 13.2. If you have any queries related to CBSE Class 10, feel free to ask us in the comment section below.

FAQs on RD Sharma Class 10 Solutions Chapter 13 Exercise 13.2

Is the RD Sharma Class 10 Maths Solutions Chapter 13 Exercise 13.2 available on the Kopykitab website?

Yes, the PDFs of RD Sharma Class 10 Solutions Chapter 13 Exercise 13.2 are available. These solutions are created in a unique method by Kopykitab’s expert faculty.

What are the benefits of using the RD Sharma Solutions for Chapter 13 Exercise 13.2 of Class 10 Maths?

The following are some of the benefits of using the RD Sharma Solutions for Class 10 Maths Chapter 13 Exercise 13.2:
1. RD Sharma Solutions follows the CBSE syllabus and guidelines.
2. The fundamental concepts are well-explained in a straightforward and easy-to-understand manner.
3. The most dependable reference source for students preparing for exams.
4. Students can use the solutions PDF to help them with their revisions.

Where can I get RD Sharma Solutions Class 10 Maths Chapter 13 Exercise 13.2 Free PDF?

You can get RD Sharma Class 10 Solutions Chapter 13 Exercise 13.2 Free PDF from the above article.

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