RD Sharma Class 10 Solutions Chapter 11 Constructions Exercise 11.3 (Updated for 2021-22)

RD Sharma Class 10 Solutions Chapter 11 Exercise 11.3

RD Sharma Class 10 Solutions Chapter 11 Exercise 11.3: The construction of tangents to a circle is the key topic covered in this exercise. Students can learn the proper procedures for dealing with difficult problems by approaching RD Sharma Class 10 Solutions. The RD Sharma Solutions for Class 10 Maths Chapter 11 Constructions Exercise 11.3 PDF is given for students below to help them understand how to answer the problems in this exercise.

Download RD Sharma Class 10 Solutions Chapter 11 Exercise 11.3 Free PDF

 


RD Sharma Class 10 Solutions Chapter 11 Exercise 11.3

Access answers to RD Sharma Solutions Class 10 Maths Chapter 11 Exercise 11.3- Important Question with Answers

Question 1.
Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the pair of tangents to the circle and measure their lengths.
Solution:
Steps of construction :
(i) Draw a circle with an O centre and 6 cm radius.
(ii) Take a point P, 10 cm away from the centre O.
(iii) Join PO and bisect it at M.
(iv) With centre M and diameter PO, draw a circle intersecting the given circle at T and S.
(v) Join PT and PS.
Then PT and PS are the required tangents.
Constructions Class 10 RD Sharma

Question 2.
Draw a circle of radius 3 cm. Take two points P and Q on one of its extended diameters each at a distance of 7 cm from its centre. Draw tangents to the circle from these two points P and Q.
Solution:
Steps of construction :
(i) Draw a circle with centre O and radius 3 cm.
(ii) Draw a diameter and produce it to both sides.
(iii) Take two points P and Q on this diameter with a distance of 7 cm each from the centre O.
(iv) Bisect PO at M and QO at N
(v) With centres M and N, draw a circle on PO and QO as diameter which intersects the given circle at S, T, and S’, T’ respectively.
(vi) Join PS, PT, QS’ and QT’.
Then PS, PT, QS’ and QT’ are the required tangents to the given circle.
RD Sharma Class 10 Solutions Constructions

Question 3.
Draw a line segment AB of length 8 cm. Taking A as the centre, draw a circle of radius 4 cm, and taking B as centre, draw another circle of radius 3 cm. Construct tangents to each circle from the centre of the other circle. [CBSE 2013]
Solution:
Steps of construction :
(i) Draw a line segment AB = 8 cm.
(ii) With centre A and radius 4 cm and with centre B and radius 3 cm, circles are drawn.
(iii) Bisect AB at M.
(iv) With centre M and diameter AB, draw a circle that intersects the two circles at S’, T’ and S, T respectively.
(v) Join AS, AT, BS’and BT’.
Then AS, AT, BS’ and BT’ are the required tangent.
RD Sharma Class 10 Solutions Constructions Exercise 11.3

Question 4.
Draw two tangents to a circle of radius 3.5 cm from a point P at a distance of 6.2 cm from its centre.
Solution:
Steps of construction :
(i) Draw a circle with centre O and radius 3.5 cm
(ii) Take a point P which is 6.2 cm from O.
(iii) Bisect PO at M and draw a circle with centre M and diameter OP which intersects the given circle at T and S respectively.
(iv) Join PT and PS.
PT and PS are the required tangents to circle.
RD Sharma Class 10 Solutions Chapter 11 Constructions

Question 5.
Draw a pair of tangents to a circle of radius 4.5 cm, which are inclined to each other at an angle of 45°. [CBSE 2013]
Solution:
Steps of construction :
The angle at the centre 180° – 45° = 135°
(i) Draw a circle with centre O and radius 4.5 cm.
RD Sharma Class 10 Pdf Chapter 11 Constructions
(ii) At O, draw an angle ∠TOS = 135°
(iii) At T and S draw perpendicular which meet each other at P.
PT and PS are the tangents that inclined each other 45°.

Question 6.
Draw a right triangle ABC in which AB = 6 cm, BC = 8 cm and ∠B = 90°. Draw BD perpendicular from B on AC and draw a circle passing through the points B, C and D. Construct tangents from A to this circle.
Solution:
Steps of Construction :
Draw a line segment BC = 8 cm
From B draw an angle of 90°
Draw an arc BA˘ = 6cm cutting the angle at A.
Join AC.
ΔABC is the required A.
Draw ⊥ bisector of BC cutting BC at M.
Take M as centre and BM as radius, draw a circle.
Take A as centre and AB as radius draw an arc cutting the circle at E. Join AE.
AB and AE are the required tangents.
Justification :
∠ABC = 90° (Given)
Since OB is a radius of the circle.
∴ AB is a tangent to the circle.
Also, AE is a tangent to the circle.
RD Sharma Solutions Class 10 Chapter 11 Constructions

Question 7.
Draw two concentric circles of radii 3 cm and 5 cm. Construct a tangent to the smaller circle from a point on the larger circle. Also, measure its length. [CBSE 2016]
Solution:
Given, two concentric circles of radii 3 cm and 5 cm with centre O. We have to draw pair of tangents from point P on the outer circle to the other.
Learncbse.In Class 10 Chapter 11 Constructions
Steps of construction :
(i) Draw two concentric circles with centre O and radii 3 cm and 5 cm.
(ii) Taking any point P on the outer circle. Join OP.
(iii) Bisect OP, let M’ be the mid-point of OP.
Taking M’ as centre and OM’ as radius draw a circle dotted which cuts the inner circle as M and P’.
(iv) Join PM and PP’. Thus, PM and PP’ are the required tangents.


(v) On measuring PM and PP’, we find that PM = PP’ = 4 cm.
Actual calculation:
In right angle ΔOMP, ∠PMO = 90°
∴ PM2 = OP2 – OM2
[by Pythagoras theorem i.e. (hypotenuse)2 = (base)2 + (perpendicular)2]
⇒ PM2 = (5)2 – (3)2 = 25 – 9 = 16
⇒ PM = 4 cm
Hence, the length of both tangents is 4 cm.

We have provided complete details of RD Sharma Class 10 Solutions Chapter 11 Exercise 11.3. If you have any queries related to CBSE Class 10, feel free to ask us in the comment section below.

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Yes, RD Sharma Class 10 Maths Solutions Chapter 11 Exercise 11.3 of Class 10 Maths is an essential chapter. These answers are centered on understanding several Math shortcuts and strategies for quick and easy calculations.

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