In the case of S.H.M., at the time of maximum kineticenergy :
In the case of S.H.M.
P.E. + K.E. = constant
P.E. = constant-K.E.
(P.E.)min = constant - (K.E.)max
A particle of mass m is executing S.H.M. of time periodT, and amplitude a0. The force on particle at the meanposition is :
F = - mw2 x
At mean position, x = 0
Two particles A and B execute simple harmonic motionof periods T and 5T/4. They start from mean position.The phase difference between them when the particle Acompletes an oscillation will be :
y1 = a1 sin w1t
y2 = a2 sin w2t
The ratio of time periods of oscillations of situationsshown in figures (i) and (ii) is:
For a simple pendulum, the graph between T2 and L is:
A hollow metal sphere is filled with water through asmall hole in it. It is hanging by a long thread and ismade to oscillate. Water slowly flows out of the hole atthe bottom. How will the period of oscillation beaffected ?
Two particles executing S.H.M. have time periods in ratioof 1 : 4. Both are given small displacements in the samedirection at the same instant. They will again be in phaseat the mean position after the second particle hascompleted n oscillations. The value of n is :