{"id":73914,"date":"2023-03-22T01:25:00","date_gmt":"2023-03-21T19:55:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=73914"},"modified":"2023-03-22T13:49:24","modified_gmt":"2023-03-22T08:19:24","slug":"rd-sharma-chapter-15-class-9-maths-exercise-15-2-solutions","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-9-maths-exercise-15-2-solutions\/","title":{"rendered":"RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions"},"content":{"rendered":"\n<p>RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions is based on the topics like- Rectangular region, Polygon region, Area Axioms, Triangular region, etc., which is concerned with the Area of Parallelograms and Triangles. Students will learn about \u2018how to calculate Areas of Parallelograms and Triangles through the questions mentioned in the attached PDF.<\/p>\n<p>The RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions PDF is prepared by our subject experts, and provided a variety of questions based on the rectangular region, polygon region, etc., with detailed explanations and examples. Go down to the article and learn about the topics and subtopics concerned under this exercise of Chapter 15.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-15-areas-of-parallelograms-and-triangles\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Learn about RD Sharma Class 9 Chapter 15 (Areas Of\u00a0And Triangles)<\/strong><\/a><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69d2ac6a13407\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69d2ac6a13407\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-9-maths-exercise-15-2-solutions\/#download-rd-sharma-chapter-15-class-9-maths-exercise-152-solutions-pdf\" title=\"Download RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions PDF\">Download RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-9-maths-exercise-15-2-solutions\/#important-definitions-rd-sharma-chapter-15-class-9-maths-exercise-152-solutions\" title=\"Important Definitions RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions\">Important Definitions RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-9-maths-exercise-15-2-solutions\/#examples-of-rd-sharma-chapter-15-class-9-maths-exercise-152-solutions\" title=\"Examples of RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions\">Examples of RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-9-maths-exercise-15-2-solutions\/#frequently-asked-questions-faqs-of-rd-sharma-chapter-15-class-9-maths-exercise-152-solutions\" title=\"Frequently Asked Questions (FAQs) of RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions\">Frequently Asked Questions (FAQs) of RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-9-maths-exercise-15-2-solutions\/#what-is-the-area-of-a-parallelogram-and-triangle\" title=\"What is the area of a parallelogram and triangle?\">What is the area of a parallelogram and triangle?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-9-maths-exercise-15-2-solutions\/#what-is-the-relationship-between-a-parallelogram-and-a-triangle\" title=\"What is the relationship between a parallelogram and a triangle?\">What is the relationship between a parallelogram and a triangle?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-15-class-9-maths-exercise-152-solutions-pdf\"><\/span>Download RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Solutions-for-Class-9-Maths-Chapter-15-Area-of-Parallelogram-and-Triangles-Exercise-15.2.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Solutions-for-Class-9-Maths-Chapter-15-Area-of-Parallelogram-and-Triangles-Exercise-15.2.pdf\">Solutions for Class 9 Maths Chapter 15 Area of Parallelogram and Triangles Exercise 15.2<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definitions-rd-sharma-chapter-15-class-9-maths-exercise-152-solutions\"><\/span>Important Definitions RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>The topics and subtopics of the Area of Parallelograms and Triangles are mentioned below-<\/p>\n<ol>\n<li>Polygon Regions<\/li>\n<li>Triangular region<\/li>\n<li>Rectangular region<\/li>\n<li>Polygon region<\/li>\n<li>Area Axiom\n<ol>\n<li>Area Axiom<\/li>\n<li>Congruent area axiom<\/li>\n<li>Area monotone axiom<\/li>\n<li>Area addition axiom<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<h3><span class=\"ez-toc-section\" id=\"examples-of-rd-sharma-chapter-15-class-9-maths-exercise-152-solutions\"><\/span><strong>Examples of RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Ques 1- If PQRS is a parallelogram, then prove that-<\/strong><\/p>\n<p><strong>ar(\u0394 PQS) = ar(\u0394 QRS) = ar(\u0394 PQR)=ar(\u0394 PRS) = 1\/2 ar(parallelogram PQRS)<\/strong><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p>PQRS is a parallelogram.<\/p>\n<p>When we join the diagonal of the parallelogram, it divides it into two quadrilaterals.<\/p>\n<p>Step 1: Let PR is diagonal, then, Area (\u0394PQR) = Area (\u0394PRS) = 1\/2(Area of parallelogram PQRS)<\/p>\n<p>Step 2: Let QS be another diagonal<\/p>\n<p>Area (\u0394PQS) = Area (\u0394QRS) = 1\/2( Area of parallelogram PQRS)<\/p>\n<p>Now,<\/p>\n<p>From Steps 1 and step 2, we have<\/p>\n<p>Area (\u0394PQR) = Area (\u0394PQS) = Area (\u0394PQS) = Area (\u0394QRS) = 1\/2(Area of parallelogram PQRS)<\/p>\n<p>Hence Proved.<\/p>\n<p><strong>Ques 2- Let PQRS be a parallelogram of area 124 cm2. If T and U are the mid-points of sides PQ and RS, respectively, then find the area of parallelogram PTUS.<\/strong><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p>PQRS be a parallelogram.<\/p>\n<p>Area of parallelogram = 124 cm2 (Given)<\/p>\n<p>Consider point A and join PA, which is perpendicular to SR.<\/p>\n<p>Now, Area of parallelogram TQRU = UR x PA and<\/p>\n<p>Area of parallelogram PUTS = SU x PA<\/p>\n<p>Since F is the mid-point of SR, so SU = UR<\/p>\n<p>From the above results, we have<\/p>\n<p>Area of parallelogram PTUS = Area of parallelogram TQRU = 1\/2 (Area of parallelogram PQRS)<\/p>\n<p>= 124\/2<\/p>\n<p>= 62<\/p>\n<p>The area of parallelogram PTUS is 62 cm2 (Hence Proved).<\/p>\n<p><a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Know about CBSE Board<\/strong><\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"frequently-asked-questions-faqs-of-rd-sharma-chapter-15-class-9-maths-exercise-152-solutions\"><\/span>Frequently Asked Questions (FAQs) of RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>\u00a0<\/p>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1679466518184\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-is-the-area-of-a-parallelogram-and-triangle\"><\/span>What is the area of a parallelogram and triangle?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>The area of a triangle is \u00bd x base x height. Practice questions in this theorem from areas of parallelograms and triangles If a triangle and parallelogram are on the corresponding base and within the same parallels, then the area of the triangle is equivalent to half the area of a parallelogram.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1679466537286\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-is-the-relationship-between-a-parallelogram-and-a-triangle\"><\/span>What is the relationship between a parallelogram and a triangle?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Each triangle brings up specifically one-half of a parallelogram. From this, the area of a triangle is one-half the area of a parallelogram, or an area of a parallelogram is two times (twice) the area of a triangle.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions is based on the topics like- Rectangular region, Polygon region, Area Axioms, Triangular region, etc., which is concerned with the Area of Parallelograms and Triangles. Students will learn about \u2018how to calculate Areas of Parallelograms and Triangles through the questions mentioned in the attached PDF. &#8230; <a title=\"RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-9-maths-exercise-15-2-solutions\/\" aria-label=\"More on RD Sharma Chapter 15 Class 9 Maths Exercise 15.2 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":241,"featured_media":73915,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,2917,73719,73411,73410],"tags":[3081,3086,3085],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73914"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/241"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=73914"}],"version-history":[{"count":3,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73914\/revisions"}],"predecessor-version":[{"id":335732,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73914\/revisions\/335732"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/73915"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=73914"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=73914"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=73914"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}