{"id":73899,"date":"2021-02-08T13:22:43","date_gmt":"2021-02-08T07:52:43","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=73899"},"modified":"2021-02-08T13:22:48","modified_gmt":"2021-02-08T07:52:48","slug":"rd-sharma-chapter-14-class-9-maths-exercise-14-4-solutions","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-14-class-9-maths-exercise-14-4-solutions\/","title":{"rendered":"RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions"},"content":{"rendered":"\n<p>\u00a0RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions is based on the topics like- Useful Facts about Triangles and Theorems Result of Triangles.<\/p>\n<p>Some important results-<\/p>\n<ul>\n<li>The line segment connecting the mid-points of any two sides of a triangle is parallel to the third and equivalent to half of it.<\/li>\n<li>The line formed through the mid-point of one side of a triangle, parallel to the other side, crosses the third side at its mid-point.<\/li>\n<\/ul>\n<p>We have given the RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions PDF for more understanding about the exercise. In this PDF, various types of questions are there with complete stepwise explanations and examples. Go down to the article and know about the facts about the triangle and the result of the theorem with explanations and examples.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-14-quadrilaterals\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Learn about RD Sharma Class 9 Chapter 14- Quadrilaterals<\/strong><\/a><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69dc9a0717b6e\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69dc9a0717b6e\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-14-class-9-maths-exercise-14-4-solutions\/#download-rd-sharma-chapter-14-class-9-maths-exercise-144-solutions-pdf\" title=\"Download RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions PDF\">Download RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-14-class-9-maths-exercise-14-4-solutions\/#important-definitions-rd-sharma-chapter-14-class-9-maths-exercise-144-solutions\" title=\"Important Definitions RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions\">Important Definitions RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-14-class-9-maths-exercise-14-4-solutions\/#examples-of-rd-sharma-chapter-14-class-9-maths-exercise-144-solutions\" title=\"Examples of RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions\">Examples of RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-14-class-9-maths-exercise-14-4-solutions\/#frequently-asked-questions-faqs-of-rd-sharma-chapter-14-class-9-maths-exercise-144-solutions\" title=\"Frequently Asked Questions (FAQs) of RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions\">Frequently Asked Questions (FAQs) of RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions<\/a><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-14-class-9-maths-exercise-144-solutions-pdf\"><\/span>Download RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Solutions-for-Class-9-Maths-Chapter-14-Quadrilaterals-Exercise-14.4.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Solutions-for-Class-9-Maths-Chapter-14-Quadrilaterals-Exercise-14.4.pdf\">Solutions for Class 9 Maths Chapter 14 Quadrilaterals Exercise 14.4<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definitions-rd-sharma-chapter-14-class-9-maths-exercise-144-solutions\"><\/span>Important Definitions RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Here are some significant results of the theorems of triangles-<\/p>\n<ol>\n<li>The line segment connecting the mid-points of any two sides of a triangle is parallel to the third and equivalent to half of it.<\/li>\n<li>The line formed through the mid-point of one side of a triangle, parallel to the other side, crosses the third side at its mid-point.<\/li>\n<\/ol>\n<h3><span class=\"ez-toc-section\" id=\"examples-of-rd-sharma-chapter-14-class-9-maths-exercise-144-solutions\"><\/span><strong>Examples of RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Ques 1- In a \u0394LMN, O, P, and Q are, respectively, the midpoints of MN, NL, and LM. If the lengths of sides LM, MN, and NL are 7 cm, 8 cm, and 9 cm, respectively, find the perimeter of \u0394OPQ.<\/p>\n<p>Solution-<\/p>\n<p>Given: LM = 7 cm, MN = 8 cm, LN = 9 cm<\/p>\n<p>In \u2206LMN,<\/p>\n<p>In a \u0394LMN, O, P, and Q are, respectively, the midpoints of MN, NL, and LM.<\/p>\n<p>According to Midpoint Theorem: OP= 1\/2 LM<\/p>\n<p>Now, Perimeter of \u2206OPQ = OP + PQ + OQ<\/p>\n<p>= 1\/2 (LM + MN + NL)<\/p>\n<p>= 1\/2 (7 + 8 + 9)<\/p>\n<p>= 12<\/p>\n<p>Ques 2- In a \u0394LMN, \u2220L = 50\u00b0, \u2220M = 60\u00b0 and \u2220N = 70\u00b0. Obtain the measures of the angles of the triangle formed by joining the mid-points of the sides of this triangle.<\/p>\n<p><img class=\"alignnone wp-image-73902 size-full\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/14.4-1.png\" alt=\"RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions\" width=\"448\" height=\"346\" \/><\/p>\n<p>Solution-<\/p>\n<p>\u00a0In \u0394LMN,<\/p>\n<p>Triangle LMNO and P are midpoints of LM and MN.<\/p>\n<p>By Midpoint theorem,<\/p>\n<p>NO \u2225 LN, OP = (1\/2) LM<\/p>\n<p>Q is the midpoint of LN<\/p>\n<p>Then, OP = (1\/2) LN = NQ<\/p>\n<p>In a Quadrilateral OPNQ<\/p>\n<p>OP \u2225 LN, OP = NQ<\/p>\n<p>Hence OPNQ is a parallelogram.<\/p>\n<p>Therefore, \u2220N = \u2220O = 70\u00b0 [Opposite sides of a parallelogram]<\/p>\n<p>Similarly<\/p>\n<p>MPQO is a parallelogram, \u2220M = \u2220Q = 60\u00b0<\/p>\n<p>LOPQ is a parallelogram, \u2220L = \u2220P = 50\u00b0<\/p>\n<p>Therefore, Angles of \u0394OPQ are<\/p>\n<p>\u2220O = 70\u00b0, \u2220P = 50\u00b0, \u2220Q = 60\u00b0<\/p>\n<h2><span class=\"ez-toc-section\" id=\"frequently-asked-questions-faqs-of-rd-sharma-chapter-14-class-9-maths-exercise-144-solutions\"><\/span>Frequently Asked Questions (FAQs) of RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Ques 1- How many triangles make a quadrilateral?<\/p>\n<p>Ans- Two triangles make a quadrilateral. As the total of the interior angles of any triangle is 180\u00b0 (180 degrees) and there are two (2) triangles in a quadrilateral, the whole of the angles for each quadrilateral is 360\u00b0 (360 degrees).<\/p>\n<p>Ques 2- What makes a shape a quadrilateral?<\/p>\n<p>Ans- A quadrilateral is a polygon that has specifically four sides\/ edges. (This also signifies that a quadrilateral has specifically four vertices and four angles.)<\/p>\n<p><a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Know about CBSE Board<\/strong><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>\u00a0RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions is based on the topics like- Useful Facts about Triangles and Theorems Result of Triangles. Some important results- The line segment connecting the mid-points of any two sides of a triangle is parallel to the third and equivalent to half of it. The line formed &#8230; <a title=\"RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-14-class-9-maths-exercise-14-4-solutions\/\" aria-label=\"More on RD Sharma Chapter 14 Class 9 Maths Exercise 14.4 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":241,"featured_media":73901,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,2917,73719,73411,73410],"tags":[3081,3086,3085],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73899"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/241"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=73899"}],"version-history":[{"count":2,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73899\/revisions"}],"predecessor-version":[{"id":73946,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73899\/revisions\/73946"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/73901"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=73899"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=73899"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=73899"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}