{"id":73721,"date":"2021-02-08T13:17:43","date_gmt":"2021-02-08T07:47:43","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=73721"},"modified":"2021-02-08T13:17:43","modified_gmt":"2021-02-08T07:47:43","slug":"rd-sharma-chapter-13-class-9-maths-exercise-13-2-solutions","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-13-class-9-maths-exercise-13-2-solutions\/","title":{"rendered":"RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions"},"content":{"rendered":"\n<p>RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions is based on finding the solution of a linear equation. In this exercise, we will explain to students about solving the questions of linear equations efficiently. Let ax+ by + c = 0 where a, b, c are the real numbers, a and b are not equal to zero (a and b \u2260 0), and x, y are the variables, then every pair of values of x and y, which completes the equation is known as a solution of it. Learn about the properties of a linear equation in detail in this article.<\/p>\n<p>Moreover, we have attached the RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions PDF, which helps students practice for the exam by solving various problems. Start practicing with the problems mentioned in the PDF, which is prepared by our subject experts by RD Sharma, CBSE Text Book, and Previous Year\u2019s Question Paper.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-13-linear-equations-in-two-variables\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Learn about RD Sharma Chapter 13 (Linear Equations In Two Variables) Class 9<\/strong><\/a><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69d2ac69d2d08\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69d2ac69d2d08\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-13-class-9-maths-exercise-13-2-solutions\/#download-rd-sharma-chapter-13-class-9-maths-exercise-132-solutions-pdf\" title=\"Download RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions PDF\">Download RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-13-class-9-maths-exercise-13-2-solutions\/#important-definitions-rd-sharma-chapter-13-class-9-maths-exercise-132-solutions\" title=\"Important Definitions RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions\">Important Definitions RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-13-class-9-maths-exercise-13-2-solutions\/#a-solution-of-linear-equations-in-two-variables\" title=\"A solution of Linear Equations in Two Variables\">A solution of Linear Equations in Two Variables<\/a><ul class='ez-toc-list-level-4'><li class='ez-toc-heading-level-4'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-13-class-9-maths-exercise-13-2-solutions\/#example-of-a-solution-of-linear-equations-in-two-variables\" title=\"Example of A Solution of Linear Equations in Two Variables\">Example of A Solution of Linear Equations in Two Variables<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-13-class-9-maths-exercise-13-2-solutions\/#unique-solution\" title=\"Unique Solution\">Unique Solution<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-13-class-9-maths-exercise-13-2-solutions\/#no-solution\" title=\"No Solution\">No Solution<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-13-class-9-maths-exercise-13-2-solutions\/#examples-of-rd-sharma-chapter-13-class-9-maths-exercise-132-solutions\" title=\"Examples of RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions\">Examples of RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-13-class-9-maths-exercise-132-solutions-pdf\"><\/span>Download RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Solutions-for-Class-9-Maths-Chapter-13-Linear-Equations-in-Two-Variables-Exercise-13.2.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Solutions-for-Class-9-Maths-Chapter-13-Linear-Equations-in-Two-Variables-Exercise-13.2.pdf\">Solutions for Class 9 Maths Chapter 13 Linear Equations in Two Variables Exercise 13.2<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definitions-rd-sharma-chapter-13-class-9-maths-exercise-132-solutions\"><\/span>Important Definitions RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>In the following points, we have given the complete information about finding the solution of a linear equation.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"a-solution-of-linear-equations-in-two-variables\"><\/span><strong>A solution of Linear Equations in Two Variables<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>A solution of a linear equation in two variables, ax + by = c, is a particular spot in the graph. When x-coordinate is multiplied by \u2018a\u2019 and y-coordinate is multiplied by \u2018b.\u2019 The total of these two conditions will be equal to \u2018c.\u2019<\/p>\n<p>Fundamentally, for a linear equation in two variables, there are infinitely various solutions.<\/p>\n<h4><span class=\"ez-toc-section\" id=\"example-of-a-solution-of-linear-equations-in-two-variables\"><\/span><strong>Example of A Solution of Linear Equations in Two Variables<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h4>\n<p>5p + 3q = 30<\/p>\n<p>= The above equation has two variables namely p and q.<\/p>\n<p>= Graphically, this equation can be described by replacing the variables to zero.<\/p>\n<p>= The value of p when q = 0 is<\/p>\n<p>= 5p + 3(0) = 30<\/p>\n<p>= p = 6<\/p>\n<p>= and the value of q when p = 0 is,<\/p>\n<p>= 5 (0) + 3q = 30<\/p>\n<p>= q = 10<\/p>\n<h3><span class=\"ez-toc-section\" id=\"unique-solution\"><\/span><strong>Unique Solution<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>For the given linear equations in two (2) variables, the solution would be unique for both the equations, only if they cross at a single point.\u00a0<\/p>\n<p>The circumstance to get the unique solution for the provided linear equations is the hill of the line determined by the two equations, respectively, should not be equal.<\/p>\n<p>Suppose n1 and n2 are two slopes of equations of two lines in two variables. Therefore, if the equations have a unique solution, then-<\/p>\n<p>n1 \u2260 n2<\/p>\n<h3><span class=\"ez-toc-section\" id=\"no-solution\"><\/span><strong>No Solution<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>If the two linear equations have equivalent slope values, then the equations will have no solutions.<\/p>\n<p>n1 = n2<\/p>\n<p>This is because the lines are parallel to one another and do not meet.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"examples-of-rd-sharma-chapter-13-class-9-maths-exercise-132-solutions\"><\/span><strong>Examples of RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Ques- If p = 1 and q = 6 is a solution of the equation 8p \u2013 aq + a2 = 0, find the values of a.<\/strong><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p>Given, ( 1 , 6 ) is the solution of an equation 8p \u2013 aq + a2 = 0<\/p>\n<p>= Substituting p = 1 and q = 6 in 8p \u2013 aq + a2 = 0, we get<\/p>\n<p>= 8 x 1 \u2013 a x 6 + a2 = 0<\/p>\n<p>= a2 \u2013 6a + 8 = 0 (a quadratic equation)<\/p>\n<p>= By using quadratic factorization<\/p>\n<p>= a2 \u2013 4a \u2013 2a + 8 = 0<\/p>\n<p>= a (a \u2013 4) \u2013 2 (a \u2013 4) = 0<\/p>\n<p>= (a \u2013 2) (a \u2013 4)= 0<\/p>\n<p>= a = 2 and 4<\/p>\n<p>= Values of &#8216;a&#8217; are 2 and 4.<\/p>\n<p><strong>Ques- Find the value of \u03bb, if a = \u2013\u03bb and b = 5\/2 is a solution of the equation a + 4b \u2013 7 = 0<\/strong><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p>Given, (-\u03bb, 5\/2) is the solution of equation 3a + 4b= k<\/p>\n<p>= Substituting a = \u2013 \u03bb and b = 5\/2 in a + 4b \u2013 7 = 0, we get<\/p>\n<p>= \u2013 \u03bb + 4 (5\/2) \u2013 7 =0<\/p>\n<p>= \u2013 \u03bb + 10 \u2013 7 = 0<\/p>\n<p>= \u03bb = 3<\/p>\n<p><a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Know about CBSE Board<\/strong><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions is based on finding the solution of a linear equation. In this exercise, we will explain to students about solving the questions of linear equations efficiently. Let ax+ by + c = 0 where a, b, c are the real numbers, a and b are &#8230; <a title=\"RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-13-class-9-maths-exercise-13-2-solutions\/\" aria-label=\"More on RD Sharma Chapter 13 Class 9 Maths Exercise 13.2 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":241,"featured_media":73738,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,2917,73719,73411,73410],"tags":[3081,3086,3085],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73721"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/241"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=73721"}],"version-history":[{"count":3,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73721\/revisions"}],"predecessor-version":[{"id":73939,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73721\/revisions\/73939"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/73738"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=73721"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=73721"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=73721"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}