{"id":73335,"date":"2021-02-05T22:25:46","date_gmt":"2021-02-05T16:55:46","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=73335"},"modified":"2021-02-05T22:25:50","modified_gmt":"2021-02-05T16:55:50","slug":"rd-sharma-chapter-5-class-9-maths-exercise-5-2-solutions","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-5-class-9-maths-exercise-5-2-solutions\/","title":{"rendered":"RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions"},"content":{"rendered":"\n<p>In this Chapter of Factorization of Algebraic Expression, students will learn about the Factorization of algebraic identities expressible as the sum or difference of two cubes. These identities will be explained step-by-step in the following PDF attached to this article. RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions are prepared by the professional by keeping in mind the shortcuts and easy methods, which helps learners to understand the simplification easily.<\/p>\n<p>The problems mentioned in the RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions PDF are the combination of the questions given in the RD Sharma and CBSE. Students should by-heart the formulas based on the Factorization of Algebraic Expressions the sum and differences of two cubes while going through the solving problems.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-5-factorization-of-algebraic-expressions\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Learn about RD Sharma Chapter 5 (Factorization of Algebraic Expressions) Class 9<\/strong><\/a><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69ee518a4dd31\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69ee518a4dd31\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-5-class-9-maths-exercise-5-2-solutions\/#download-rd-sharma-chapter-5-class-9-maths-exercise-52-solutions-pdf\" title=\"Download RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions PDF\">Download RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-5-class-9-maths-exercise-5-2-solutions\/#important-definitions-rd-sharma-chapter-5-class-9-maths-exercise-52-solutions\" title=\"Important Definitions RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions\">Important Definitions RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-5-class-9-maths-exercise-5-2-solutions\/#frequently-asked-questions-faqs-of-rd-sharma-chapter-5-class-9-maths-exercise-52-solutions\" title=\"Frequently Asked Questions (FAQs) of RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions\">Frequently Asked Questions (FAQs) of RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions<\/a><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-5-class-9-maths-exercise-52-solutions-pdf\"><\/span>Download RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Class-9-Maths-Chapter-5-Factorization-of-Algebraic-Expressions-Exercise-5.2.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Class-9-Maths-Chapter-5-Factorization-of-Algebraic-Expressions-Exercise-5.2.pdf\">Class 9 Maths Chapter 5 Factorization of Algebraic Expressions Exercise 5.2<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definitions-rd-sharma-chapter-5-class-9-maths-exercise-52-solutions\"><\/span>Important Definitions RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To memorize the patterns involved in the formula of Sum and Difference of two cubes is given in the below points-<\/p>\n<ol>\n<li>The polynomial in the form x3+y3 is known as the sum of two cubes because two cubic terms getting added together.<\/li>\n<li>The polynomial in the form x3-y3 is known as the difference of two cubes because two cubic terms are signifying deduction.<\/li>\n<\/ol>\n<p>So, here are the formulas that summarize about the sum and difference of two cubes-<\/p>\n<ul>\n<li>a3 + b3 = (a + b) (a2 + b2 \u2013 ab)<\/li>\n<li>a3 \u2013 b3 = (a \u2013 b) (a2 + b2 + ab)<\/li>\n<\/ul>\n<p>Follow the steps while doing factorization of algebraic identities-<\/p>\n<ol>\n<li>&#8220;Factor Out&#8221; any of the common terms.<\/li>\n<li>Check if it fits any of the identities, plus any more may know.<\/li>\n<li>Keep going till can&#8217;t factor the identities anymore.<\/li>\n<\/ol>\n<p>We have provided some examples below in which the factorization of algebraic expressions is solved in expanded form-<\/p>\n<p><strong>Ques- 8<\/strong><strong><em>x<\/em><\/strong><strong>3<\/strong><strong><em>y<\/em><\/strong><strong>3<\/strong><strong> + 27<\/strong><strong><em>a<\/em><\/strong><strong>3<\/strong><\/p>\n<p><strong>Solution- <\/strong>8x3y3+27a3 =(2xy)3+(3a)3<\/p>\n<p>Algebraic Identity- a3 + b3 = (a + b) (a2 + b2 \u2013 ab)<\/p>\n<p>= 8x3y3+27a3 =(2xy+3a) {(2xy)2-2xy3a+(3a)2}<\/p>\n<p>= (2xy+3a) (4x2y2-6ax+9a2)<\/p>\n<p>Therefore, the required factorization of 8x3y3+27a3 is (2xy+3a) (4x2y2-6ax+9a2)<\/p>\n<p><strong>Ques- 64a<\/strong><strong>3<\/strong><strong> \u2212 b<\/strong><strong>3<\/strong><\/p>\n<p><strong>Solution- <\/strong>64a3 \u2212 b3 = (4a)3\u2212 b3<\/p>\n<p>Algebraic Identity- a3 \u2013 b3 = (a \u2013 b) (a2 + ab + b2)<\/p>\n<p>64a3 \u2212 b3 = (4a\u2212b) {(4a)2 + 4a\u00d7b + b2}<\/p>\n<p>=(4a\u2212b) (16a2 +4ab+b2)<\/p>\n<p>Therefore, the required factorization of 64a3 \u2212 b3 is (4a\u2212b) (16a2 +4ab+b2)<\/p>\n<h2><span class=\"ez-toc-section\" id=\"frequently-asked-questions-faqs-of-rd-sharma-chapter-5-class-9-maths-exercise-52-solutions\"><\/span>Frequently Asked Questions (FAQs) of RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Ques 1- How do you factor the sum or difference of two cubes?<\/p>\n<p>Ans- The sum or difference of two cubes can be factorized into an output of binomial times a trinomial.<\/p>\n<p>Ques 2- Which expression is the difference between two cubes?<\/p>\n<p>Ans- The difference of two cubes is equivalent to the difference of their cube roots times a trinomial, which comprises the squares of the cube roots and the reverse of the outcome of the cube roots. A number&#8217;s opposite is that likewise number among a distinctive sign in front.<\/p>\n<p><a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Know about CBSE Board<\/strong><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>In this Chapter of Factorization of Algebraic Expression, students will learn about the Factorization of algebraic identities expressible as the sum or difference of two cubes. These identities will be explained step-by-step in the following PDF attached to this article. RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions are prepared by the professional &#8230; <a title=\"RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-5-class-9-maths-exercise-5-2-solutions\/\" aria-label=\"More on RD Sharma Chapter 5 Class 9 Maths Exercise 5.2 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":241,"featured_media":73337,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,2917,73719,73411,73410],"tags":[3081,3086,3085],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73335"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/241"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=73335"}],"version-history":[{"count":3,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73335\/revisions"}],"predecessor-version":[{"id":73794,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73335\/revisions\/73794"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/73337"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=73335"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=73335"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=73335"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}