{"id":73072,"date":"2021-10-25T05:45:00","date_gmt":"2021-10-25T00:15:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=73072"},"modified":"2021-10-25T19:09:40","modified_gmt":"2021-10-25T13:39:40","slug":"rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/","title":{"rendered":"RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 (Updated For 2021-22)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-143824\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/10\/Chapter-6-Ex-6.3.jpg\" alt=\"RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/10\/Chapter-6-Ex-6.3.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/10\/Chapter-6-Ex-6.3-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3:\u00a0<\/strong>Want to prepare for your Class 7 Maths exam without any hassle? Try starting your exam prep with <a href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-class-7-maths-solutions\/\" target=\"_blank\" rel=\"noopener\">RS Aggarwal Solutions Class 7 Maths<\/a>. It is easy to understand the solutions of RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 because of the accuarte and well-explained solutions designed by the subject matter experts.<\/p>\n<p>Download the Free PDF of <a href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-algebraic-expressions\/\" target=\"_blank\" rel=\"noopener\">RS Aggarwal Solutions Class 7 Maths Chapter 6<\/a> Ex 6.3 using the download link given in the blog. To know more, read the whole blog.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69d08094c393f\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69d08094c393f\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#download-rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63-pdf\" title=\"Download RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 PDF\">Download RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63-%e2%80%93-overview\" title=\"RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 &#8211; Overview\">RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 &#8211; Overview<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#multiplying-monomials\" title=\"Multiplying Monomials\">Multiplying Monomials<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#multiplying-a-monomial-by-a-binomial\" title=\"Multiplying a Monomial by a Binomial\">Multiplying a Monomial by a Binomial<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#multiplying-two-binomials\" title=\"Multiplying Two Binomials\">Multiplying Two Binomials<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#using-foil-method-first-out-inner-last\" title=\"Using FOIL Method (First, Out, Inner, Last)\">Using FOIL Method (First, Out, Inner, Last)<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#faqs-on-rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63\" title=\"FAQs on RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3\u00a0\">FAQs on RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3\u00a0<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#from-where-can-i-find-the-download-link-for-the-rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63-pdf\" title=\"From where can I find the download link for the RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 PDF?\">From where can I find the download link for the RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 PDF?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#how-much-does-it-cost-to-download-the-rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63-pdf\" title=\"How much does it cost to download the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3\u00a0PDF?\">How much does it cost to download the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3\u00a0PDF?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#can-i-access-the-rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63-pdf-offline\" title=\"Can I access the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 PDF Offline?\">Can I access the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 PDF Offline?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#how-to-multiply-a-monomial-with-a-binomial\" title=\"How to multiply a monomial with a binomial?\">How to multiply a monomial with a binomial?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/#how-to-multiply-a-binomial\" title=\"How to multiply a binomial?\">How to multiply a binomial?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63-pdf\"><\/span>Download RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/10\/Algebraic-Expressions-Ex-6-C.pdf\" target=\"_blank\" rel=\"noopener\">RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/10\/Algebraic-Expressions-Ex-6-C.pdf\", \"#example1\");<\/script><\/p>\n<h2><span class=\"ez-toc-section\" id=\"rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63-%e2%80%93-overview\"><\/span>RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 &#8211; Overview<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>In this exercise, you will solve the problems related to the multiplication operation between the binomial and the monomial.\u00a0<\/p>\n<p>It can be done via associative property or distributive property. In contrast to this, when we multiply the binomial with another binomial, it also requires the use of the same rules. All of this can be done using the shortcut method of the FOIL i.e., ( First, Out, Inner, Last).<\/p>\n<h3><span class=\"ez-toc-section\" id=\"multiplying-monomials\"><\/span>Multiplying Monomials<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div dir=\"auto\">A Monomial can be multiplied with another monomial correctly utilizing the properties of the exponents and the properties of the rational numbers.\u00a0<\/div>\n<div dir=\"auto\">\u00a0<\/div>\n<div dir=\"auto\">Let\u2019s say we have to multiply the two monomials i.e., 2x and 5x. It can be multiplied with others using the commutative &amp; associative multiplication properties. It can be done like:<\/div>\n<div dir=\"auto\">\u00a0<\/div>\n<div dir=\"auto\">\u00a02x \u00d7 5x = ( 2 \u00d7 5 ) \u00d7 ( x \u00d7 x )<\/div>\n<div dir=\"auto\">\u00a02x \u00d7 5x = ( 10 ) \u00d7 (x\u00b2)<\/div>\n<div dir=\"auto\">\u00a02x \u00d7 5x = 10x\u00b2<\/div>\n<div dir=\"auto\">\u00a0<\/div>\n<h3><span class=\"ez-toc-section\" id=\"multiplying-a-monomial-by-a-binomial\"><\/span>Multiplying a Monomial by a Binomial<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Multiplying a monomial with a binomial is done using the distributive property rule. Let us take the binomial like 3x + 5 and multiply it further the monomial 2x.\u00a0<\/p>\n<div dir=\"auto\">(3x + 5) \u00d7 2x = 3x (2x) + 5 (2x)<\/div>\n<div dir=\"auto\">(3x + 5) \u00d7 2x = 6x\u00b2 + 10x<\/div>\n<div dir=\"auto\">\u00a0<\/div>\n<h3><span class=\"ez-toc-section\" id=\"multiplying-two-binomials\"><\/span>Multiplying Two Binomials<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>While multiplying two binomials, we use the distributive property two times.\u00a0<\/p>\n<div dir=\"auto\">Eg: ( x + 2 ) and ( x + 5 ), here, it can be solved via using the distributive property as mentioned below.\u00a0<\/div>\n<div dir=\"auto\">( x + 2 ) \u00d7 ( x + 5 ) = x ( x + 5 ) + 2 ( x + 5 )\u00a0<\/div>\n<div dir=\"auto\">( x + 2 ) \u00d7 ( x + 5 ) = x\u00b2 + 5x + 2x + 10<\/div>\n<div dir=\"auto\">( x + 2 ) \u00d7 ( x + 5 ) = x\u00b2 + 7x + 10<\/div>\n<div dir=\"auto\">\u00a0<\/div>\n<h3 dir=\"auto\"><span class=\"ez-toc-section\" id=\"using-foil-method-first-out-inner-last\"><\/span>Using FOIL Method (First, Out, Inner, Last)<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>This is the shortcut method that can easily replace the multiplication operation done between monomials and binomials via distribution property.<\/p>\n<ul>\n<li>Initially multiply the first number contained in each of the binomials, the outside number contained in each of the binomials, the inside number contained in each of the binomials, and the last number contained in each of the binomial\u201d \u2013 this is how we perform the calculation via the FOIL method.<\/li>\n<li>Accumulate all the like numbers, this is to be done by performing the addition operation between the outside terms. This way the result that will see is exactly going to be the same as the distributive property method.<\/li>\n<\/ul>\n<div dir=\"auto\">Here, calculating the ( 3x\u00b2 \u2013 4) ( x \u2013 3 ) by using the FOIL method:<\/div>\n<div dir=\"auto\">\u00a0<\/div>\n<div dir=\"auto\">The first number ( 3x\u00b2 ) ( x ) or 3x\u00b3, the outside terms are ( 3x\u00b2 ) ( -3 ) or -9x\u00b2, the inside terms ( -4 )( x ) or -4x, and the last numbers are ( -4 ) ( -3 ) which is 12.<\/div>\n<div dir=\"auto\">\u00a0<\/div>\n<div dir=\"auto\">Therefore, the expression,\u00a0<\/div>\n<div dir=\"auto\">(3x\u00b2 \u2013 4) (x \u2013 3 ) will be equivalent to the 3x\u00b3 \u2013 9x\u00b2 \u2013 4x + 12<\/div>\n<p>This is the complete blog on RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3. To know more about the <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 7 Maths exam, ask in the comments.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63\"><\/span>FAQs on RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3\u00a0<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1635165660285\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"from-where-can-i-find-the-download-link-for-the-rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63-pdf\"><\/span>From where can I find the download link for the RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can find the download link in the above blog.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1635165684276\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-much-does-it-cost-to-download-the-rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63-pdf\"><\/span>How much does it cost to download the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3\u00a0PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download it for free.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1635165714594\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-access-the-rs-aggarwal-solutions-class-7-maths-chapter-6-ex-63-pdf-offline\"><\/span>Can I access the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 PDF Offline?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Once you have downloaded the PDF online, you can access it offline whenever you want.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1635165745721\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-to-multiply-a-monomial-with-a-binomial\"><\/span>How to multiply a monomial with a binomial?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Multiplying a monomial with a binomial is done using the distributive property rule. Let us take the binomial like 3x + 5 and multiply it further the monomial 2x.\u00a0<br \/>(3x + 5) \u00d7 2x = 3x (2x) + 5 (2x)<br \/>(3x + 5) \u00d7 2x = 6x\u00b2 + 10x<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1635165809450\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-to-multiply-a-binomial\"><\/span>How to multiply a binomial?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>While multiplying two binomials, we use the distributive property two times.\u00a0<br \/>Eg: ( x + 2 ) and ( x + 5 ), here, it can be solved via using the distributive property as mentioned below.\u00a0<br \/>( x + 2 ) \u00d7 ( x + 5 ) = x ( x + 5 ) + 2 ( x + 5 )\u00a0<br \/>( x + 2 ) \u00d7 ( x + 5 ) = x\u00b2 + 5x + 2x + 10<br \/>( x + 2 ) \u00d7 ( x + 5 ) = x\u00b2 + 7x + 10<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3:\u00a0Want to prepare for your Class 7 Maths exam without any hassle? Try starting your exam prep with RS Aggarwal Solutions Class 7 Maths. It is easy to understand the solutions of RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 because of the accuarte &#8230; <a title=\"RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 (Updated For 2021-22)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-6-exercise-6-3\/\" aria-label=\"More on RS Aggarwal Solutions Class 7 Maths Chapter 6 Ex 6.3 (Updated For 2021-22)\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":143824,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73412,73410],"tags":[73320,77308,77518],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73072"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=73072"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73072\/revisions"}],"predecessor-version":[{"id":143825,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/73072\/revisions\/143825"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/143824"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=73072"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=73072"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=73072"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}