{"id":72719,"date":"2021-02-05T00:29:16","date_gmt":"2021-02-04T18:59:16","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=72719"},"modified":"2021-08-25T17:24:35","modified_gmt":"2021-08-25T11:54:35","slug":"rd-sharma-chapter-10-class-9-maths-exercise-10-1-solutions-2","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-9-maths-exercise-10-1-solutions-2\/","title":{"rendered":"RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions"},"content":{"rendered":"\n<p>This chapter of Class 9 will help students to learn about congruent triangles. As we know, a triangle is a three-sided polygon holding three angles that add up to 180 degrees. But, when it comes to the congruence of triangles, two triangles are congruent if they overlay on each other or if the sides and angles should have the same lengths and measurements. In the RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions is based on the topics like- Congruence of Line segments, Congruence of Line Angles, Congruence of Triangles, Congruence Relation, Congruence Criteria, etc.<\/p>\n<p>The PDF attached below is prepared by our experts in which questions are collected from teh previous year\u2019s question papers, CBSE Text Book, and RD Sharma of Class 9. These questions will help to understand the topics of this exercise, and the stepwise easy explanation will help learners to score well in the exam.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-10-congruent-triangles\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Learn about RD Sharma Class 9 Chapter 10- Congruent Triangles<\/strong><\/a><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69ed40b3630e5\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69ed40b3630e5\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-9-maths-exercise-10-1-solutions-2\/#download-rd-sharma-chapter-10-class-9-maths-exercise-101-solutions-pdf\" title=\"Download RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions PDF\">Download RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-9-maths-exercise-10-1-solutions-2\/#important-definitions-rd-sharma-chapter-10-class-9-maths-exercise-101-solutions\" title=\"Important Definitions RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions\">Important Definitions RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-9-maths-exercise-10-1-solutions-2\/#congruence-of-line-segments\" title=\"Congruence of Line segments\">Congruence of Line segments<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-9-maths-exercise-10-1-solutions-2\/#congruence-of-angles\" title=\"Congruence of Angles\">Congruence of Angles<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-9-maths-exercise-10-1-solutions-2\/#congruence-criteria-of-triangles\" title=\"Congruence Criteria of Triangles\">Congruence Criteria of Triangles<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-9-maths-exercise-10-1-solutions-2\/#examples-of-rd-sharma-chapter-10-class-9-maths-exercise-101-solutions\" title=\"Examples of RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions\">Examples of RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-10-class-9-maths-exercise-101-solutions-pdf\"><\/span>Download RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Solutions-for-Class-9-Maths-Chapter-10-Congruent-Triangles-Exercise-10.1.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Solutions-for-Class-9-Maths-Chapter-10-Congruent-Triangles-Exercise-10.1.pdf\">Solutions for Class 9 Maths Chapter 10 Congruent Triangles Exercise 10.1<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definitions-rd-sharma-chapter-10-class-9-maths-exercise-101-solutions\"><\/span>Important Definitions RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Here is the list of the topics and subtopics of the Congruent Triangles-<\/p>\n<ul>\n<li>Congruence of Line segments<\/li>\n<li>Congruence of Angles<\/li>\n<li>Congruence of Triangles<\/li>\n<li>Congruence Relation<\/li>\n<li>Congruence Criteria\n<ul>\n<li>SAS (Side-Angle-Side)<\/li>\n<li>SSS (Side-Side-Side)<\/li>\n<li>ASA (Angle-Side-Angle)<\/li>\n<li>RHS (Right angle- Hypotenuse-Side)<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"congruence-of-line-segments\"><\/span><strong>Congruence of Line segments<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Line segments are congruent if they possess the same length. Though, they must not be parallel. Line Segments can be at any angle or adjustment on the plane.<\/p>\n<p>It is possible to form (draw) a congruent line segment to a provided segment with a compass (protractor) and straightedge.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"congruence-of-angles\"><\/span><strong>Congruence of Angles<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>These are the angles (with the same radians or degrees) with the same measures.\u00a0<\/p>\n<ul>\n<li>Congruence Angles do not have to point in the equivalent direction.<\/li>\n<li>Congruence Angles do not have to be on equal-sized lines.<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"congruence-criteria-of-triangles\"><\/span><strong>Congruence Criteria of Triangles<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The following are the different criteria of Congruency of Triangles-<\/p>\n<ul>\n<li>SAS (Side-Angle-Side)- If any two sides and an angle comprised between the sides of one triangle are similar to the corresponding two sides and an angle within the sides of the second triangle, then the two triangles are assumed to be congruent by Side-Angle-Side (SAS) rule.<\/li>\n<li>SSS (Side-Side-Side)- If all the three sides of one triangle are similar to the corresponding three sides of the second triangle, the two triangles are assumed to be congruent with the Side-Side-Side (SSS) rule.<\/li>\n<li>ASA (Angle-Side-Angle)- If any two angles and the sides involved between an angle of one triangle are similar to the corresponding two angles and the side involved between angles of the second triangle, then the two triangles are assumed to be congruent by the Angle-Side-Angle (ASA) rule.<\/li>\n<li>RHS (Right angle- Hypotenuse-Side)- If the hypotenuse and the side of a right-angled triangle are similar to the hypotenuse and a side of the second right-angled triangle, then the two right triangles are assumed to be congruent by the Right angle- Hypotenuse-Side (RHS) rule.<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"examples-of-rd-sharma-chapter-10-class-9-maths-exercise-101-solutions\"><\/span><strong>Examples of RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Ques:<\/strong> In the below figure, the sides BA and CA have been provided such that BA = AD and CA = AE. Prove the segment DE \u2225 BC.<\/p>\n<p><img class=\"alignnone size-full wp-image-72720\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/fig-11.png\" alt=\"RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions\" width=\"750\" height=\"494\" \/><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p><strong>Sides BA and CA have been provided such that BA = AD and CA = AE.<\/strong><\/p>\n<p><strong>Prove- DE \u2225 BC<\/strong><\/p>\n<p>= Consider \u25b3BAC and \u25b3DAE,<\/p>\n<p>= BA = AD and CA= AE (Given)<\/p>\n<p>= \u2220BAC = \u2220DAE (vertically opposite angles)<\/p>\n<p>= By SAS congruence criterion, we have<\/p>\n<p>= \u25b3 BAC \u2243 \u25b3 DAE<\/p>\n<p>= We know, corresponding positions of congruent triangles are similar<\/p>\n<p>= So, BC = DE and \u2220DEA = \u2220BCA, \u2220EDA = \u2220CBA<\/p>\n<p>= Now, DE and BC are two lines intersected by a transversal DB s.t.<\/p>\n<p>= \u2220DEA= \u2220BCA (alternate angles are similar)<\/p>\n<p>= Therefore, DE \u2225 BC (Hence Proved).<\/p>\n<p><a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Know about CBSE Board<\/strong><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>This chapter of Class 9 will help students to learn about congruent triangles. As we know, a triangle is a three-sided polygon holding three angles that add up to 180 degrees. But, when it comes to the congruence of triangles, two triangles are congruent if they overlay on each other or if the sides and &#8230; <a title=\"RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-9-maths-exercise-10-1-solutions-2\/\" aria-label=\"More on RD Sharma Chapter 10 Class 9 Maths Exercise 10.1 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":241,"featured_media":72721,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,2917,73719,73411],"tags":[3081,3086,3085],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72719"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/241"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=72719"}],"version-history":[{"count":3,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72719\/revisions"}],"predecessor-version":[{"id":73603,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72719\/revisions\/73603"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/72721"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=72719"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=72719"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=72719"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}