{"id":72648,"date":"2021-02-08T13:32:02","date_gmt":"2021-02-08T08:02:02","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=72648"},"modified":"2021-02-08T13:32:07","modified_gmt":"2021-02-08T08:02:07","slug":"rd-sharma-chapter-19-class-9-maths-exercise-19-1-solutions","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-19-class-9-maths-exercise-19-1-solutions\/","title":{"rendered":"RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions"},"content":{"rendered":"\n<p>RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions have been provided over here. These exercises are primarily covered around the problems related to calculating the surface area of the cylinder. Upon regular practice of the problems revolving around the calculation of the surface area of a circular cylinder can be significant in terms of having a greater understanding of its topics. Specifically, the solved questions here can be useful for more significant preparations on it.<\/p>\n<p>The exercises here cover the topics around calculating the surface area of a right circular cylinder and calculating the surface area of hollow cylinders. The solutions are prepared by our subject experts to assure a better understanding of the exercise, which helps to score well in the exam. However, those having better fundamentals about solving problems around cylinders of both hollow and right cylinders can find it easier while dealing with RD Sharma problems.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-19-surface-area-and-volume-of-a-right-circular-cylinder\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Learn about RD Sharma Class 9 Chapter 19 (Surface Area And Volume Of Right Circular Cylinder)<\/strong><\/a><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e8eff3bf982\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e8eff3bf982\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-19-class-9-maths-exercise-19-1-solutions\/#download-rd-sharma-chapter-19-class-9-maths-exercise-191-solutions-pdf\" title=\"Download RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions PDF\">Download RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-19-class-9-maths-exercise-19-1-solutions\/#important-definitions-rd-sharma-chapter-19-class-9-maths-exercise-191-solutions\" title=\"Important Definitions RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions\">Important Definitions RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-19-class-9-maths-exercise-19-1-solutions\/#surface-area-of-a-right-circular-cylinder\" title=\"Surface Area of a Right Circular Cylinder\">Surface Area of a Right Circular Cylinder<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-19-class-9-maths-exercise-19-1-solutions\/#surface-area-of-a-hollow-cylinder\" title=\"Surface Area of a Hollow Cylinder\">Surface Area of a Hollow Cylinder<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-19-class-9-maths-exercise-19-1-solutions\/#examples-of-rd-sharma-chapter-19-class-9-maths-exercise-191-solutions\" title=\"Examples of RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions\">Examples of RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-19-class-9-maths-exercise-191-solutions-pdf\"><\/span>Download RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Solutions-for-Class-9-Maths-Chapter-19-Surface-Area-and-Volume-of-A-Right-Circular-Cylinder-Exercise-19.1.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/02\/Solutions-for-Class-9-Maths-Chapter-19-Surface-Area-and-Volume-of-A-Right-Circular-Cylinder-Exercise-19.1.pdf\">Solutions for Class 9 Maths Chapter 19 Surface Area and Volume of A Right Circular Cylinder Exercise 19.1<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definitions-rd-sharma-chapter-19-class-9-maths-exercise-191-solutions\"><\/span>Important Definitions RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"surface-area-of-a-right-circular-cylinder\"><\/span>Surface Area of a Right Circular Cylinder<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The Right Circular Cylinder\u2019s surface area can be calculated using formula A = 2 \u03c0rh+2\u03c0r2 where \u2018r\u2019 is the radius and h is the height.\u00a0<\/p>\n<h3><span class=\"ez-toc-section\" id=\"surface-area-of-a-hollow-cylinder\"><\/span>Surface Area of a Hollow Cylinder<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The surface area of a hollow cylinder can be calculated through the formula 2\u03c0 (r1 + r2) (r2 &#8211; r1 +h), in which r1 is the inner Radius, r2 is the Outer Radius, and \u2018h\u2019 is the height.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"examples-of-rd-sharma-chapter-19-class-9-maths-exercise-191-solutions\"><\/span>Examples of RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Ques- Curved surface section of a right circular cylinder is 4.4 m2. Suppose the radius of the bottom of the cylinder is 0.7 m. Find its height.<\/strong><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p>= Radius of the bottom of the cylinder = r = 0.7 m (Given)<\/p>\n<p>= Curved surface section of cylinder = C.S.A = 4.4m2 (Given)<\/p>\n<p>= Let \u2018k\u2019 be the height of the cylinder.<\/p>\n<p>= We know, the curved surface section of a cylinder = 2\u03c0rk<\/p>\n<p>= Therefore,<\/p>\n<p>= 2\u03c0rk = 4.4<\/p>\n<p>= 2 x 3.14 (22\/7) x 0.7 x k = 4.4<\/p>\n<p>= [using \u03c0=3.14 ]<\/p>\n<p>= or k = 1<\/p>\n<p>= Hence, the height of a cylinder is 1m.<\/p>\n<p><strong>Ques- In a hot water heating system, there is a cylindrical tube of the length of 28 m and a diameter of 5 cm. Find the entire radiating surface in the system.<\/strong><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p>= Height of cylinder (k) = Length of cylindrical tube = 28 m or 2800 cm (Given)<\/p>\n<p>[1 m = 100 cm]<\/p>\n<p>= Diameter of circular end of tube = 5 cm (given)<\/p>\n<p>= Let \u2018s\u2019 be the radius of circular end, then s = diameter\/2 = 5\/2 cm<\/p>\n<p>= We know, Curved surface area of the cylindrical pipe = 2\u03c0sk<\/p>\n<p>= 2 x 3.14 (22\/7) x 5\/2 x 2800<\/p>\n<p>= [using \u03c0 = 3.14 9 (22\/7)]<\/p>\n<p>= 44000<\/p>\n<p>= Therefore, the space of the radiating surface is 44000 cm2.<\/p>\n<p><strong>Ques- The cylindrical pillar is 50 cm in diameter and 3.5 m in height. Find the cost of painting the rounded surface of the pillar at the rate of Rs 12.50 per m2.<\/strong><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p>= Height of the cylindrical pillar (h) = 3.5 m<\/p>\n<p>= Radius of circular end of the pillar (r) = 50\/2 cm = 25 cm = 0.25 m<\/p>\n<p>= [As radius = half of a diameter] and [1 m = 100 cm]<\/p>\n<p>= The rounded surface space of the cylindrical pillar = 2\u03c0rh<\/p>\n<p>= 2 x 3.14 (22\/7) x 0.25 x 3.5<\/p>\n<p>= 5.5<\/p>\n<p>= So, the curved surface area of the cylindrical pillar is 5.5 m.<\/p>\n<p><strong>Find the cost-<\/strong><\/p>\n<p>= Cost of the whitewashing 1m2 is Rs 12.50 (Given)<\/p>\n<p>= Cost of thewhitewashing 5.5 m2 area = Rs. 12.50 x 5.5 = Rs. 68.75<\/p>\n<p>= Therefore the cost of whitewashing the pillar is Rs 68.75.<\/p>\n<p><a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Know about CBSE Board<\/strong><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions have been provided over here. These exercises are primarily covered around the problems related to calculating the surface area of the cylinder. Upon regular practice of the problems revolving around the calculation of the surface area of a circular cylinder can be significant in terms &#8230; <a title=\"RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-19-class-9-maths-exercise-19-1-solutions\/\" aria-label=\"More on RD Sharma Chapter 19 Class 9 Maths Exercise 19.1 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":241,"featured_media":72649,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,2917,73719,73411,73410],"tags":[3081,3086,3085],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72648"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/241"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=72648"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72648\/revisions"}],"predecessor-version":[{"id":73969,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72648\/revisions\/73969"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/72649"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=72648"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=72648"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=72648"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}