{"id":72571,"date":"2021-02-08T13:31:55","date_gmt":"2021-02-08T08:01:55","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=72571"},"modified":"2021-02-08T13:32:01","modified_gmt":"2021-02-08T08:02:01","slug":"rd-sharma-chapter-20-class-9-maths-exercise-20-1-solutions","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-20-class-9-maths-exercise-20-1-solutions\/","title":{"rendered":"RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions"},"content":{"rendered":"\n<p>RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions can be significant for addressing questions around right circular cones. To be specific, it can be significant for solving questions around surface area and volume of right circular cones. As the questions of the problems have been provided by the experts, students can stay assured of its accuracy. These exercises can be absolutely relevant from an examination point of view.<\/p>\n<p>The solutions provided here are thoroughly analyzed as per the questions. Hence, they can be significant for understanding the concepts of surface area and volume of right circular cones and the exercises based on the same. RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions focuses on two specific topics called the Right Circular Cone Introduction and The Surface Area of Right Circular Cone. Those having strong fundamentals about the concepts of right circular cones at the CBSE level can find it easier to attain.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-20-surface-area-and-volume-of-a-right-circular-cone\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Learn about Class 9 Chapter 20 (Surface Area And Volume Of Right Circular Cone)<\/strong><\/a><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e8eff50f078\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e8eff50f078\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-20-class-9-maths-exercise-20-1-solutions\/#download-rd-sharma-chapter-20-class-9-maths-exercise-201-solutions-pdf\" title=\"Download RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions PDF\">Download RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-20-class-9-maths-exercise-20-1-solutions\/#important-definitions-rd-sharma-chapter-20-class-9-maths-exercise-201-solutions\" title=\"Important Definitions RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions\">Important Definitions RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-20-class-9-maths-exercise-20-1-solutions\/#right-circular-cone-introduction\" title=\"Right Circular Cone Introduction\">Right Circular Cone Introduction<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-20-class-9-maths-exercise-20-1-solutions\/#surface-area-of-a-right-circular-cone\" title=\"Surface Area of a Right Circular Cone\">Surface Area of a Right Circular Cone<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-20-class-9-maths-exercise-20-1-solutions\/#examples-of-rd-sharma-chapter-20-class-9-maths-exercise-201-solutions\" title=\"Examples of RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions\">Examples of RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-20-class-9-maths-exercise-20-1-solutions\/#frequently-asked-questions-of-rd-sharma-chapter-20-class-9-maths-exercise-201-solutions\" title=\"Frequently Asked Questions of RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions\">Frequently Asked Questions of RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions<\/a><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-20-class-9-maths-exercise-201-solutions-pdf\"><\/span>Download RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/Solutions-for-Class-9-Maths-Chapter-20-Surface-Area-and-Volume-of-A-Right-Circular-Cone-Exercise-20.1.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/Solutions-for-Class-9-Maths-Chapter-20-Surface-Area-and-Volume-of-A-Right-Circular-Cone-Exercise-20.1.pdf\">Solutions for Class 9 Maths Chapter 20 Surface Area and Volume of A Right Circular Cone Exercise 20.1<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definitions-rd-sharma-chapter-20-class-9-maths-exercise-201-solutions\"><\/span>Important Definitions RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"right-circular-cone-introduction\"><\/span>Right Circular Cone Introduction<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The right circular cone is primarily a cone having its base as a circle. Its axis remains perpendicular to the base. It is also termed the cone of revolution.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"surface-area-of-a-right-circular-cone\"><\/span>Surface Area of a Right Circular Cone<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The surface area of the Right Circular Cone can be calculated through the below formula.<\/p>\n<p>A= \u03c0r(r+ \u221ah2+r2)<\/p>\n<p>Here \u2018r\u2019 is the radius of the base circle, and \u2018h\u2019 is the height of the cone.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"examples-of-rd-sharma-chapter-20-class-9-maths-exercise-201-solutions\"><\/span>Examples of RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Ques- Find the rounded surface space of a cone if its slant height is 60cm and the radius of its base is 21cm.<\/strong><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p>Slant height of cone (a) = 60 cm<\/p>\n<p>The radius of the base of the cone (b) = 21 cm<\/p>\n<p>Now,<\/p>\n<p>Rounded surface space of the right circular cone = \u03c0ba = 22\/7 x 21 x 60 = 3960 cm2<\/p>\n<p>Hence the rounded surface space of the right circular cone is 3960 cm2<\/p>\n<p><strong>Ques- The radius of a cone is 5cm, and the vertical height is 12cm. Find the area of the rounded surface.<\/strong><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p>Radius of cone (c) = 5 cm<\/p>\n<p>Height of cone (b) = 12 cm<\/p>\n<p>Find Slant Height of cone (a):<\/p>\n<p>We know, a2 = b2 + c2<\/p>\n<p>a2 = 52 +122<\/p>\n<p>a2 = 25 + 144 = 169<\/p>\n<p>Or a = 13 cm<\/p>\n<p>Now,<\/p>\n<p>C.S.A = \u03c0cb =3.14 x 5 x 13 = 204.28<\/p>\n<p>Hence, the rounded surface space of the cone is 204.28 cm2<\/p>\n<p><strong>Ques- Find the entire surface space of a right circular cone with a radius of 6 cm and a height of 8 cm.<\/strong><\/p>\n<p><strong>Solution-<\/strong><\/p>\n<p>Radius of cone (b) = 6 cm<\/p>\n<p>Height of cone (a) = 8 cm<\/p>\n<p>The total Surface area of a cone (T.S.A)=?<\/p>\n<p>Find slant height of cone:<\/p>\n<p>We know, c2 = b2 + a2<\/p>\n<p>=62+82<\/p>\n<p>= 36 + 64<\/p>\n<p>= 100<\/p>\n<p>or c = 10 cm<\/p>\n<p>Now,<\/p>\n<p>The entire Surface space of the cone (T.S.A) = Rounded surface space of a cone\u00a0<\/p>\n<p>+ Area of the circular base<\/p>\n<p>= \u03c0bc + \u03c0b2<\/p>\n<p>= (22\/7 x 6 x 10) + (22\/7 x 6 x 6)<\/p>\n<p>= 1320\/7 + 792\/7<\/p>\n<p>= 301.71<\/p>\n<p>Hence, the area of the base is 301.71cm2.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"frequently-asked-questions-of-rd-sharma-chapter-20-class-9-maths-exercise-201-solutions\"><\/span>Frequently Asked Questions of RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>Ques 1- Can it be useful for class 9 examination preparation?<\/strong><\/p>\n<p><strong>Ans-<\/strong>\u00a0Yes, a student can expect absolutely similar questions in the examinations.<\/p>\n<p><strong>Ques 2- Are the questions only based on the surface area?<\/strong><\/p>\n<p><strong>Ans-<\/strong> Simultaneously, revolving around surface area calculation of right circular cone, it also covers the questions around the volume of right circular cones. One can find the whole range of questions here.<\/p>\n<p><a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Know about CBSE Board<\/strong><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions can be significant for addressing questions around right circular cones. To be specific, it can be significant for solving questions around surface area and volume of right circular cones. As the questions of the problems have been provided by the experts, students can stay assured &#8230; <a title=\"RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-20-class-9-maths-exercise-20-1-solutions\/\" aria-label=\"More on RD Sharma Chapter 20 Class 9 Maths Exercise 20.1 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":241,"featured_media":72573,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,2917,73719,73411,73410],"tags":[3081,3086,3085],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72571"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/241"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=72571"}],"version-history":[{"count":3,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72571\/revisions"}],"predecessor-version":[{"id":73967,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72571\/revisions\/73967"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/72573"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=72571"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=72571"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=72571"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}