{"id":72555,"date":"2021-02-08T13:32:04","date_gmt":"2021-02-08T08:02:04","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=72555"},"modified":"2021-02-08T13:32:10","modified_gmt":"2021-02-08T08:02:10","slug":"rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions\/","title":{"rendered":"RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions"},"content":{"rendered":"\n<p>RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions can be comprehensive for a greater exercise on surface area and exercises related to Cuboid volume. This exercise is considered the most effective method. This is because of the strategic and stepwise approach to solving the questions.\u00a0<\/p>\n<p>It can also help the students obtain a broader understanding of different topics around the surface area and problems related to the Cuboid and answer questions on Cubes. To be specific about this exercise, it is more focused on the cuboid volume calculations and exercises around cubes.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-18-surface-area-and-volume-of-a-cuboid-and-cube\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Learn about Class 9 Chapter 18 (Surface Area And Volume Of A Cuboid And Cube)<\/strong><\/a><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e903a9aac38\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e903a9aac38\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions\/#download-rd-sharma-chapter-18-class-9-maths-exercise-182-solutions-pdf\" title=\"Download RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions PDF\">Download RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions\/#what-are-the-topics-covered-under-rd-sharma-chapter-18-class-9-maths-exercise-182-solutions\" title=\"What are the Topics Covered Under RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions?\u00a0\">What are the Topics Covered Under RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions?\u00a0<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions\/#important-definitions-rd-sharma-chapter-18-class-9-maths-exercise-182-solutions\" title=\"Important Definitions RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions\">Important Definitions RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions\/#surface-area-of-a-cuboid\" title=\"Surface Area of a Cuboid\">Surface Area of a Cuboid<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions\/#surface-area-of-a-cube\" title=\"Surface Area of a Cube\">Surface Area of a Cube<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions\/#lateral-surface-area-of-a-cuboid\" title=\"Lateral Surface Area of a Cuboid\">Lateral Surface Area of a Cuboid<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions\/#lateral-surface-area-of-a-cube\" title=\"Lateral Surface Area of a Cube\">Lateral Surface Area of a Cube<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions\/#examples-of-rd-sharma-chapter-18-class-9-maths-exercise-182-solutions\" title=\"Examples of RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions\">Examples of RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-18-class-9-maths-exercise-182-solutions-pdf\"><\/span>Download RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/Solutions-for-Class-9-Maths-Chapter-18-Surface-Area-and-Volume-of-Cuboid-and-Cube-Exercise-18.2.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/Solutions-for-Class-9-Maths-Chapter-18-Surface-Area-and-Volume-of-Cuboid-and-Cube-Exercise-18.2.pdf\">Solutions for Class 9 Maths Chapter 18 Surface Area and Volume of Cuboid and Cube Exercise 18.2<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"what-are-the-topics-covered-under-rd-sharma-chapter-18-class-9-maths-exercise-182-solutions\"><\/span>What are the Topics Covered Under RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions?\u00a0<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Students are primarily taught about the following topics as part of Class 9 Maths Chapter 18 Cube Exercise 18.2.<\/p>\n<ul>\n<li>It provides exercises around the surface area of a Cuboid<\/li>\n<li>It covers the topic around the calculation of the surface area of a cube<\/li>\n<li>It covers the topics around calculations of lateral surface Area of a Cuboid<\/li>\n<li>It covers the topics around the Lateral Surface Area of a Cub<\/li>\n<\/ul>\n<p><strong>Surface Area of a Cuboid<\/strong><\/p>\n<p>Cuboid comes with six rectangular faces, the surface area of which is calculated upon adding the areas of all six faces. It can be calculated using the formula SA= 2lw+2lh+2hw, where l means length, w means width, and h means the prism\u2019s height.\u00a0<\/p>\n<p><strong>Surface Area of a Cube<\/strong><\/p>\n<p>The surface area is calculated through formula A=6a2, where A is the area, and \u2018a\u2019 is the length of the edge.\u00a0<\/p>\n<p><strong>Lateral Surface Area of a Cuboid<\/strong><\/p>\n<p>The lateral surface area of Cuboid has calculated through the formula Lateral Surface area = 2 height (length + breadth)<\/p>\n<p><strong>Lateral Surface Area of a Cube<\/strong><\/p>\n<p>The lateral surface area is calculated through formula 4a2, where \u2018a\u2019 is the length of each side.\u00a0<\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definitions-rd-sharma-chapter-18-class-9-maths-exercise-182-solutions\"><\/span>Important Definitions RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"surface-area-of-a-cuboid\"><\/span><strong>Surface Area of a Cuboid<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Cuboid comes with six rectangular faces, the surface area of which is calculated upon adding the areas of all six faces. It can be calculated using the formula SA= 2lw+2lh+2hw, where l means length, w means width, and h means the prism\u2019s height.\u00a0<\/p>\n<h3><span class=\"ez-toc-section\" id=\"surface-area-of-a-cube\"><\/span><strong>Surface Area of a Cube<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The surface area is calculated through formula A = 6a2, where A is the area, and \u2018a\u2019 is the length of the edge.\u00a0<\/p>\n<h3><span class=\"ez-toc-section\" id=\"lateral-surface-area-of-a-cuboid\"><\/span><strong>Lateral Surface Area of a Cuboid<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The lateral surface area of Cuboid has calculated through the formula Lateral Surface area = 2 height (length + breadth)<\/p>\n<h3><span class=\"ez-toc-section\" id=\"lateral-surface-area-of-a-cube\"><\/span><strong>Lateral Surface Area of a Cube<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The lateral surface area is calculated through formula 4a2, where \u2018a\u2019 is the length of each side.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"examples-of-rd-sharma-chapter-18-class-9-maths-exercise-182-solutions\"><\/span><strong>Examples of RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Ques: A cuboidal water tank measures 5 meters long, 6 meters wide, and 4.5 meters deep. How many liters (l) of water can it hold?<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Dimensions of the cuboidal tank-<\/p>\n<p>= Length = l = 5m<\/p>\n<p>= Breadth = b = 6m<\/p>\n<p>= Height = h = 4.5m<\/p>\n<p>= Volume of the cuboidal water tank = l x b x h<\/p>\n<p>By equating the values, we get-<\/p>\n<p>= Volume, V = 5\u00d7 6\u00d7 4.5<\/p>\n<p>= 135<\/p>\n<p>Therefore, Volume of the cuboidal water tank is 135 m3<\/p>\n<p>Converting into liters:<\/p>\n<p>= As 1 m3 = 1000 liters<\/p>\n<p>= So, 135m3 = (135 \u00d7 1000) liters<\/p>\n<p>= 135000 liters<\/p>\n<p>Hence, the tank can accommodate 1,35,000 liters of water.<\/p>\n<p><strong>Ques: A cuboidal vessel is 10 meters long and 8 meters wide. How high must it be created to hold 380 cubic meters of a liquid?<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Dimensions of the cuboidal vessel:<\/p>\n<p>Length = l = 10 m<\/p>\n<p>Breadth = b = 8 m<\/p>\n<p>vessel volume = 380 m3\u00a0<\/p>\n<p>Let \u2018h\u2019 be the height of cuboidal vessel.<\/p>\n<p>Volume of cuboidal vessel = lbh<\/p>\n<p>lbh = 380 m3<\/p>\n<p>or 10\u00d7 8\u00d7 h = 380<\/p>\n<p>or h = (380)\/ (10\u00d78)<\/p>\n<p>or h = 4.75<\/p>\n<p>Hence, height of the vessel should be 4.75 m.<\/p>\n<p><strong>Ques: Find the cost of digging a cuboidal hole 8 meters long, 6 meters broad, and 3 meters deep at the rate of Rs 30 per m3.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Dimensions of the cuboidal hole-<\/p>\n<p>= Length = l = 8 m<\/p>\n<p>= Breadth = b = 6 m<\/p>\n<p>= Height or depth = h = 3 m<\/p>\n<p>= Volume of the Cuboidal pit = l x b x h<\/p>\n<p>= 8\u00d7 6\u00d7 3<\/p>\n<p>= 144m3<\/p>\n<p>Volume of the Cuboidal hole is 144 m3<\/p>\n<p>Now, finding the cost-<\/p>\n<p>= Cost of digging 1 m3 hole = Rs. 30 (from question)<\/p>\n<p>= Cost of digging 144 m3 holeit = 144 x 30 = Rs. 4320<\/p>\n<p><a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Know about CBSE Board<\/strong><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions can be comprehensive for a greater exercise on surface area and exercises related to Cuboid volume. This exercise is considered the most effective method. This is because of the strategic and stepwise approach to solving the questions.\u00a0 It can also help the students obtain a &#8230; <a title=\"RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-18-class-9-maths-exercise-18-2-solutions\/\" aria-label=\"More on RD Sharma Chapter 18 Class 9 Maths Exercise 18.2 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":241,"featured_media":72556,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,2917,73719,73411,73410],"tags":[3081,3086,3085],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72555"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/241"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=72555"}],"version-history":[{"count":3,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72555\/revisions"}],"predecessor-version":[{"id":73970,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72555\/revisions\/73970"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/72556"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=72555"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=72555"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=72555"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}