{"id":72051,"date":"2021-02-08T14:35:11","date_gmt":"2021-02-08T09:05:11","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=72051"},"modified":"2021-02-08T14:35:14","modified_gmt":"2021-02-08T09:05:14","slug":"rd-sharma-chapter-9-class-9-maths-exercise-9-2-solutions","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-9-class-9-maths-exercise-9-2-solutions\/","title":{"rendered":"RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions"},"content":{"rendered":"\n<p>In this exercise of Triangles and their angles, students will learn about the Exterior Angles of a Triangle. RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions is based on the fundamental theories of exterior angles of a triangle, which says that, if a side of a triangle is given, the exterior angle so set is equal to the total of the two interior opposite angles. Go down to the article to know more about the triangle\u2019s exterior angles. This section is one of the easiest exercises to score well in the examination.<\/p>\n<p>Students are suggested to practice with the RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions PDF attached to this article that helps to score well in the exam. The PDF is prepared by our experts with complete informative solutions. The PDF is available for free to do practice to score well in the exam.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-9-triangle-and-its-angles\/\" target=\"_blank\" rel=\"noopener noreferrer\">Learn more about Triangles and its Angles of Chapter 9 Class 9<\/a><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69d2ac44ee6d8\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69d2ac44ee6d8\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-9-class-9-maths-exercise-9-2-solutions\/#download-rd-sharma-chapter-9-class-9-maths-exercise-92-solutions-pdf\" title=\"Download RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions PDF\">Download RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-9-class-9-maths-exercise-9-2-solutions\/#important-definitions-rd-sharma-chapter-9-class-9-maths-exercise-92-solutions\" title=\"Important Definitions RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions\">Important Definitions RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-9-class-9-maths-exercise-9-2-solutions\/#triangle-exterior-angle-theorem\" title=\"Triangle Exterior angle Theorem\">Triangle Exterior angle Theorem<\/a><ul class='ez-toc-list-level-4'><li class='ez-toc-heading-level-4'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-9-class-9-maths-exercise-9-2-solutions\/#properties-of-exterior-angles\" title=\"Properties of exterior angles\">Properties of exterior angles<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-9-class-9-maths-exercise-9-2-solutions\/#get-the-unknown-exterior-angle-of-a-triangle\" title=\"Get the Unknown Exterior Angle of a Triangle\">Get the Unknown Exterior Angle of a Triangle<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-9-class-9-maths-exercise-9-2-solutions\/#frequently-asked-questions-faqs-of-rd-sharma-chapter-9-class-9-maths-exercise-92-solutions\" title=\"Frequently Asked Questions (FAQs) of RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions\">Frequently Asked Questions (FAQs) of RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions<\/a><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-9-class-9-maths-exercise-92-solutions-pdf\"><\/span>Download RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/Solutions-for-Class-9-Maths-Chapter-9-Triangle-and-its-Angles-Exercise-9.2.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/Solutions-for-Class-9-Maths-Chapter-9-Triangle-and-its-Angles-Exercise-9.2.pdf\">Solutions for Class 9 Maths Chapter 9 Triangle and its Angles Exercise 9.2<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definitions-rd-sharma-chapter-9-class-9-maths-exercise-92-solutions\"><\/span>Important Definitions RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>A triangle is a three-sided structure with three interior angles. Also, there are other angles outside the triangle, which are known as exterior angles.<\/p>\n<p>Here we will learn about the following points-<\/p>\n<ol>\n<li>The Theorem of Triangle exterior angle<\/li>\n<li>Find the unknown exterior angle of a triangle<\/li>\n<\/ol>\n<h3><span class=\"ez-toc-section\" id=\"triangle-exterior-angle-theorem\"><\/span>Triangle Exterior angle Theorem<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The theorem of the exterior angle declares that the sum of each exterior angle of a triangle is equal to the total of the non-adjacent and opposite interior angles.<\/p>\n<p><img class=\"alignnone size-full wp-image-72053 aligncenter\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/fig-4.png\" alt=\"RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions\" width=\"505\" height=\"220\" \/><\/p>\n<p><strong>Note: The two non-adjacent interior angles opposite to the exterior angle are sometimes introduced as a remote interior angle.<\/strong><\/p>\n<p>For example, in the above triangle ABC-<\/p>\n<p>= d = b + a<\/p>\n<p>= e = a + c<\/p>\n<p>= f = b + c<\/p>\n<h4><span class=\"ez-toc-section\" id=\"properties-of-exterior-angles\"><\/span><strong>Properties of exterior angles<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h4>\n<p>An exterior angle of a triangle is equivalent to the total of the two opposite interior angles.<\/p>\n<p>The total of the exterior angle and interior angle is equivalent to 180 degrees.<\/p>\n<p>= c + d = 180\u00b0 (180 degrees)<\/p>\n<p>= a + f = 180\u00b0 (180 degrees)<\/p>\n<p>= b + e = 180\u00b0 (180 degrees)<\/p>\n<p>All exterior angles of the triangle add up to 360\u00b0 (360 degrees).<\/p>\n<p>Proof:<\/p>\n<p>= d + e + f = b + a + a + c + b + c<\/p>\n<p>= d +e + f = 2a + 2b + 2c<\/p>\n<p>= 2 (a + b + c)<\/p>\n<p>According to the triangle angle sum theorem.<\/p>\n<p>a + b + c = 180\u00b0 (180 degrees)<\/p>\n<p>Therefore, = d +e + f = 2(180\u00b0)<\/p>\n<p>= 360\u00b0, Hence Proved<\/p>\n<h3><span class=\"ez-toc-section\" id=\"get-the-unknown-exterior-angle-of-a-triangle\"><\/span><strong>Get the Unknown Exterior Angle of a Triangle<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The rules to find the triangle&#8217;s unknown exterior angles are the same as the rules of interior angles of a triangle. Because wherever there is an exterior angle, it exists with an interior angle, and both of them add up to 180\u00b0 (180 degrees).<\/p>\n<p>For Example-<\/p>\n<p>The two interior angles 25\u00b0 and (a + 15) \u00b0 are non-adjacent to an exterior angle (3a \u2013 10) \u00b0, find the value of a.<\/p>\n<p>Solution-<\/p>\n<p>Apply the theorem of Triangle exterior angle-<\/p>\n<p>= (3a \u2212 10) = (25) + (a + 15)<\/p>\n<p>= (3a \u2212 10) = (25) + (a +15)<\/p>\n<p>= 3a \u221210 = a + 40<\/p>\n<p>= 3a \u2013 10 = a + 40<\/p>\n<p>= 3a = a + 50<\/p>\n<p>= 3a = a + 50<\/p>\n<p>= 2a = 50<\/p>\n<p>= a = 25<\/p>\n<p>Hence, a = 25\u00b0<\/p>\n<p>Replace the value of x into the three equations.<\/p>\n<p>= (3a \u2212 10) = 3(25\u00b0) \u2013 10\u00b0<\/p>\n<p>= (75\u00b0 \u2013 10\u00b0) = 65\u00b0<\/p>\n<p>= (a+15) = (25\u00b0 + 15\u00b0) = 40\u00b0<\/p>\n<p>So, the angles are 25\u00b0, 40\u00b0, and 65\u00b0.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"frequently-asked-questions-faqs-of-rd-sharma-chapter-9-class-9-maths-exercise-92-solutions\"><\/span>Frequently Asked Questions (FAQs) of RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>Ques 1- What is the sum of the exterior angles of a triangle?<\/strong><\/p>\n<p><strong>Ans-<\/strong> An exterior angle of the triangle is equivalent to the two opposite interior angles. The total of the exterior angle and interior angle is equivalent to 180 degrees.<\/p>\n<p><strong>Ques 2- Are the exterior angles of a triangle equal to 360?<\/strong><\/p>\n<p><strong>Ans-<\/strong> The exterior angles of a triangle make a linear pair with the interior angles by increasing the triangle&#8217;s sides. The sum of the exterior angles of the triangle and any polygon is 360 degrees.<\/p>\n<p><a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener noreferrer\"><strong>Know about CBSE Board<\/strong><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>In this exercise of Triangles and their angles, students will learn about the Exterior Angles of a Triangle. RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions is based on the fundamental theories of exterior angles of a triangle, which says that, if a side of a triangle is given, the exterior angle so &#8230; <a title=\"RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-9-class-9-maths-exercise-9-2-solutions\/\" aria-label=\"More on RD Sharma Chapter 9 Class 9 Maths Exercise 9.2 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":241,"featured_media":74011,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,2917,73719,73411,73410],"tags":[3081,3086,3085],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72051"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/241"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=72051"}],"version-history":[{"count":3,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72051\/revisions"}],"predecessor-version":[{"id":74012,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/72051\/revisions\/74012"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/74011"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=72051"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=72051"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=72051"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}