{"id":71712,"date":"2023-06-10T18:08:00","date_gmt":"2023-06-10T12:38:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=71712"},"modified":"2023-12-18T10:34:05","modified_gmt":"2023-12-18T05:04:05","slug":"rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/","title":{"rendered":"RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 (Updated For 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-144645\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/10\/Chapter-13-Ex-13.1.jpg\" alt=\"RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/10\/Chapter-13-Ex-13.1.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/10\/Chapter-13-Ex-13.1-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1:\u00a0<\/strong>You can rely totally on the <a href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-class-7-maths-solutions\/\" target=\"_blank\" rel=\"noopener\">RS Aggarwal Solutions Class 7 Maths<\/a>, be it your class tests or assignments. It is because the solutions of RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 are very helpful in clearing your doubts. The solutions are designed by subject matter experts and are very credible.<\/p>\n<p>Download the Free PDF of <a href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-lines-and-angles\/\" target=\"_blank\" rel=\"noopener\">RS Aggarwal Solutions Class 7 Maths Chapter 13<\/a> Ex 13.1 by using the download link in the blog. To know more, read the whole blog.\u00a0<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69d808a382696\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" 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PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#access-the-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131\" title=\"Access The RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1\">Access The RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131-%e2%80%93-overview\" title=\"RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 &#8211; Overview\">RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 &#8211; Overview<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#basic-concepts\" title=\"Basic Concepts\u00a0\">Basic Concepts\u00a0<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#important-topics\" title=\"Important Topics\">Important Topics<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#definitions\" title=\"Definitions\">Definitions<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#types-of-angles\" title=\"Types OF Angles\">Types OF Angles<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#related-angles\" title=\"Related Angles\">Related Angles<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#pairs-of-lines\" title=\"Pairs Of Lines\">Pairs Of Lines<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#faqs-on-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131\" title=\"FAQs on RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1\u00a0\">FAQs on RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1\u00a0<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#define-an-intersecting-line\" title=\"Define an intersecting line.\">Define an intersecting line.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#what-is-a-line-segment\" title=\"What is a line segment?\">What is a line segment?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#define-angles-made-by-a-transversal\" title=\"Define Angles made by a transversal.\">Define Angles made by a transversal.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#from-where-can-i-find-the-download-link-for-the-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131-pdf\" title=\"From where can I find the download link for the RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 PDF?\">From where can I find the download link for the RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 PDF?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#how-much-does-it-cost-to-download-the-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131-pdf\" title=\"How much does it cost to download the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter\u00a013 Ex 13.1\u00a0PDF?\">How much does it cost to download the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter\u00a013 Ex 13.1\u00a0PDF?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/#can-i-access-the-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131-pdf-offline\" title=\"Can I access the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1\u00a0PDF Offline?\">Can I access the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1\u00a0PDF Offline?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131-pdf\"><\/span>Download RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/Lines-and-Angles-RS-Aggarwal-Class-7-Maths-Solutions-1.pdf\" target=\"_blank\" rel=\"noopener\">RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/Lines-and-Angles-RS-Aggarwal-Class-7-Maths-Solutions-1.pdf\", \"#example1\");<\/script><\/p>\n<h2><span class=\"ez-toc-section\" id=\"access-the-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131\"><\/span>Access The RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>Question 1.<\/strong><br \/><strong>Solution:<\/strong><br \/>(i) The given angle = 35\u00b0<br \/>Let x be its complementary, then<br \/>x + 35\u00b0 = 90\u00b0<br \/>\u21d2 x = 90\u00b0 \u2013 35\u00b0 = 55\u00b0<br \/>Complement angle = 55\u00b0<br \/>(ii) The given angle = 47\u00b0<br \/>Let x be its complement, then<br \/>x + 47\u00b0 = 90 \u21d2 x = 90\u00b0 \u2013 47\u00b0 = 43\u00b0<br \/>Complement angle = 43\u00b0<br \/>(iii) The given angles = 60\u00b0<br \/>Let x be its complement angle<br \/>x + 60\u00b0 = 90\u00b0 \u21d2 x = 90\u00b0 \u2013 60\u00b0 = 30\u00b0<br \/>Complement angle = 30\u00b0<br \/>(iv) The given angle = 73\u00b0<br \/>Let x be its complement angle<br \/>x + 73\u00b0 = 90\u00b0<br \/>\u21d2 x = 90\u00b0 \u2013 73\u00b0 = 17\u00b0<br \/>Complement angle = 17\u00b0<\/p>\n<p><strong>Question 2.<\/strong><br \/><strong>Solution:<\/strong><br \/>(i) Given angle = 80\u00b0<br \/>Let x be its supplement angle, then<br \/>x + 80\u00b0 = 180\u00b0<br \/>\u21d2 x = 180\u00b0 \u2013 80\u00b0 = 100\u00b0<br \/>Supplement angle = 100\u00b0<br \/>(ii) Given angle = 54\u00b0<br \/>Let x be its supplement angle, then<br \/>x + 54\u00b0 = 180\u00b0<br \/>\u21d2 x = 180\u00b0 \u2013 54\u00b0 = 126\u00b0<br \/>Supplement angle = 126\u00b0<br \/>(iii) Given angle = 105\u00b0<br \/>let x be its supplement angle, then<br \/>x + 105\u00b0 = 180\u00b0<br \/>\u21d2 x = 180\u00b0 \u2013 105\u00b0 = 75\u00b0<br \/>Supplement angle = 75\u00b0<br \/>(iv) Given angle = 123\u00b0<br \/>Let x be its supplement angle, then<br \/>x + 123\u00b0 = 180\u00b0<br \/>\u21d2 x = 180\u00b0 \u2013 123\u00b0 = 57\u00b0<br \/>\u21d2 Supplement angle = 57\u00b0<\/p>\n<p><strong>Question 3.<\/strong><br \/><strong>Solution:<\/strong><br \/>Let smaller angle =x<br \/>Then larger angle = x + 36\u00b0<br \/>But x + x + 36\u00b0 = 180\u00b0 (Angles are supplementary)<br \/>2x = 180\u00b0 \u2013 36\u00b0= 144\u00b0<br \/>x = 72\u00b0<br \/>Smaller angle = 72\u00b0<br \/>and larger angle = 72\u00b0 + 36\u00b0 = 108\u00b0<\/p>\n<aside class=\"scaip scaip-2    \">\n<aside id=\"block-3\" class=\"widget_block clearfix\"><ins class=\"adsbygoogle\" data-ad-client=\"ca-pub-8012231244430966\" data-ad-slot=\"4142978075\" data-ad-format=\"auto\" data-full-width-responsive=\"true\" data-adsbygoogle-status=\"done\" data-ad-status=\"unfilled\">\n<div id=\"aswift_2_host\" tabindex=\"0\" title=\"Advertisement\" aria-label=\"Advertisement\">\u00a0<\/div>\n<\/ins><\/aside>\n<\/aside>\n<p><strong>Question 4.<\/strong><br \/><strong>Solution:<\/strong><br \/>Let angle be = x<br \/>Then other supplement angle = 180\u00b0- x<br \/>x = 180\u00b0 \u2013 x<br \/>\u21d2 x + x = 180\u00b0<br \/>\u21d2 2x = 180\u00b0<br \/>\u21d2 x = 90\u00b0<br \/>Hence angles are 90\u00b0, and 90\u00b0<\/p>\n<p><strong>Question 5.<\/strong><br \/><strong>Solution:<\/strong><br \/>Sum of two supplementary angles is 180\u00b0<br \/>If one is acute, then second will be obtuse or both angles will be equal<br \/>Hence both angles can not be acute or obtuse<br \/>Both can be right angles only<\/p>\n<p><strong>Question 6.<\/strong><br \/><strong>Solution:<\/strong><br \/>In the given figure,<br \/>AOB is a straight line and the ray OC stands on it.<br \/>\u2220AOC = 64\u00b0 and \u2220BOC = x\u00b0<\/p>\n<aside class=\"scaip scaip-3    \">\n<aside id=\"block-4\" class=\"widget_block clearfix\"><ins class=\"adsbygoogle\" data-ad-client=\"ca-pub-8012231244430966\" data-ad-slot=\"4142978075\" data-ad-format=\"auto\" data-full-width-responsive=\"true\" data-adsbygoogle-status=\"done\" data-ad-status=\"unfilled\">\n<div id=\"aswift_3_host\" tabindex=\"0\" title=\"Advertisement\" aria-label=\"Advertisement\">\u00a0<\/div>\n<\/ins><\/aside>\n<\/aside>\n<figure class=\"wp-block-image size-full\"><img class=\"wp-image-552091 jetpack-lazy-image entered lazyloaded jetpack-lazy-image--handled\" style=\"box-sizing: border-box; user-select: text !important; height: auto; max-width: 100%; border-style: none; position: relative; opacity: 1; transition: opacity 400ms ease 0ms; vertical-align: bottom; display: block;\" src=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-1.png?resize=236%2C150&amp;is-pending-load=1#038;ssl=1\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question 6\" width=\"236\" height=\"150\" data-attachment-id=\"552091\" data-permalink=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-13-lines-and-angles\/rs-aggarwal-class-7-solutions-chapter-13-lines-and-angles-ex-13-1\/\" data-orig-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-1.png?fit=236%2C150&amp;ssl=1\" data-orig-size=\"236,150\" data-comments-opened=\"0\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-1\" data-image-description=\"&lt;p&gt;RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-1&lt;\/p&gt;\n\" data-image-caption=\"&lt;p&gt;RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-1&lt;\/p&gt;\n\" data-medium-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-1.png?fit=236%2C150&amp;ssl=1\" data-large-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-1.png?fit=236%2C150&amp;ssl=1\" data-recalc-dims=\"1\" data-ll-status=\"loaded\" data-lazy-loaded=\"1\" \/><\/figure>\n<p><br \/>\u2220AOC + \u2220BOC = 180\u00b0 (Linear pair)<br \/>\u21d2 64\u00b0 + x = 180\u00b0<br \/>\u21d2 x = 180\u00b0 \u2013 64\u00b0 = 116\u00b0<br \/>Hence x = 116\u00b0<\/p>\n<p><strong>Question 7.<\/strong><br \/><strong>Solution:<\/strong><br \/>AOB is a straight line and ray OC stands on it \u2220AOC = (2x \u2013 10)\u00b0, \u2220BOC = (3x + 20)\u00b0<\/p>\n<figure class=\"wp-block-image size-full\"><img class=\"wp-image-552092 jetpack-lazy-image entered lazyloaded jetpack-lazy-image--handled\" style=\"box-sizing: border-box; user-select: text !important; height: auto; max-width: 100%; border-style: none; position: relative; opacity: 1; transition: opacity 400ms ease 0ms; vertical-align: bottom; display: block;\" src=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-2.png?resize=243%2C153&amp;is-pending-load=1#038;ssl=1\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question7\" width=\"243\" height=\"153\" data-attachment-id=\"552092\" data-permalink=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-13-lines-and-angles\/rs-aggarwal-class-7-solutions-chapter-13-lines-and-angles-ex-13-2\/\" data-orig-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-2.png?fit=243%2C153&amp;ssl=1\" data-orig-size=\"243,153\" data-comments-opened=\"0\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-2\" data-image-description=\"&lt;p&gt;RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-2&lt;\/p&gt;\n\" data-image-caption=\"&lt;p&gt;RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-2&lt;\/p&gt;\n\" data-medium-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-2.png?fit=243%2C153&amp;ssl=1\" data-large-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-2.png?fit=243%2C153&amp;ssl=1\" data-recalc-dims=\"1\" data-ll-status=\"loaded\" data-lazy-loaded=\"1\" \/><\/figure>\n<p><br \/>\u2220AOC + \u2220BOC = 180\u00b0 (Linear pair)<br \/>\u21d2 2x \u2013 10\u00b0 + 3x + 20\u00b0 = 180\u00b0<br \/>\u21d2 5x + 10\u00b0 = 180\u00b0<br \/>\u21d2 5x = 170\u00b0<br \/>\u21d2 x = 34\u00b0<br \/>\u2220AOC = (2x \u2013 10)\u00b0 = 2 x 34\u00b0 \u2013 10 = 68\u00b0 \u2013 10\u00b0 = 58\u00b0<br \/>\u2220BOC = (3x + 20)\u00b0 = 3 x 34\u00b0 + 20\u00b0 \u2013 102\u00b0 + 20\u00b0 = 122\u00b0<\/p>\n<aside class=\"scaip scaip-4    \">\n<aside id=\"block-5\" class=\"widget_block clearfix\"><ins class=\"adsbygoogle\" data-ad-client=\"ca-pub-8012231244430966\" data-ad-slot=\"4142978075\" data-ad-format=\"auto\" data-full-width-responsive=\"true\" data-adsbygoogle-status=\"done\" data-ad-status=\"unfilled\">\n<div id=\"aswift_4_host\" tabindex=\"0\" title=\"Advertisement\" aria-label=\"Advertisement\">\u00a0<\/div>\n<\/ins><\/aside>\n<\/aside>\n<p><strong>Question 8.<\/strong><br \/><strong>Solution:<\/strong><br \/>AOB is a straight line and rays OC and OD stands on it \u2220AOC = 65\u00b0, \u2220BOD = 70\u00b0 and \u2220COD = x<\/p>\n<figure class=\"wp-block-image size-full\"><img class=\"wp-image-552093 jetpack-lazy-image entered lazyloaded jetpack-lazy-image--handled\" style=\"box-sizing: border-box; user-select: text !important; height: auto; max-width: 100%; border-style: none; position: relative; opacity: 1; transition: opacity 400ms ease 0ms; vertical-align: bottom; display: block;\" src=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-3.png?resize=245%2C141&amp;is-pending-load=1#038;ssl=1\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question 8\" width=\"245\" height=\"141\" data-attachment-id=\"552093\" data-permalink=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-13-lines-and-angles\/rs-aggarwal-class-7-solutions-chapter-13-lines-and-angles-ex-13-3\/\" data-orig-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-3.png?fit=245%2C141&amp;ssl=1\" data-orig-size=\"245,141\" data-comments-opened=\"0\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-3\" data-image-description=\"&lt;p&gt;RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-3&lt;\/p&gt;\n\" data-image-caption=\"&lt;p&gt;RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-3&lt;\/p&gt;\n\" data-medium-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-3.png?fit=245%2C141&amp;ssl=1\" data-large-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-3.png?fit=245%2C141&amp;ssl=1\" data-recalc-dims=\"1\" data-ll-status=\"loaded\" data-lazy-loaded=\"1\" \/><\/figure>\n<p>But \u2220AOC + \u2220COD + \u2220BOD = 180\u00b0 (Angles on one side of the straight line)<br \/>\u21d2 65\u00b0 + x + 70\u00b0 = 180\u00b0<br \/>\u21d2 135\u00b0 + x = 180\u00b0<br \/>\u21d2 x = 180\u00b0 \u2013 135\u00b0<br \/>\u21d2 x = 45\u00b0<br \/>Hence x = 45\u00b0<\/p>\n<p><strong>Question 9.<\/strong><br \/><strong>Solution:<\/strong><br \/>Two straight lines AB and CD intersect each other at O.<\/p>\n<aside class=\"scaip scaip-5    \">\n<aside id=\"block-6\" class=\"widget_block clearfix\"><ins class=\"adsbygoogle\" data-ad-client=\"ca-pub-8012231244430966\" data-ad-slot=\"4142978075\" data-ad-format=\"auto\" data-full-width-responsive=\"true\" data-adsbygoogle-status=\"done\" data-ad-status=\"unfilled\">\n<div id=\"aswift_5_host\" tabindex=\"0\" title=\"Advertisement\" aria-label=\"Advertisement\">\u00a0<\/div>\n<\/ins><\/aside>\n<\/aside>\n<figure class=\"wp-block-image size-full\"><img class=\"wp-image-552094 jetpack-lazy-image entered lazyloaded jetpack-lazy-image--handled\" style=\"box-sizing: border-box; user-select: text !important; height: auto; max-width: 100%; border-style: none; position: relative; opacity: 1; transition: opacity 400ms ease 0ms; vertical-align: bottom; display: block;\" src=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-4.png?resize=243%2C121&amp;is-pending-load=1#038;ssl=1\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question 9\" width=\"243\" height=\"121\" data-attachment-id=\"552094\" data-permalink=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-13-lines-and-angles\/rs-aggarwal-class-7-solutions-chapter-13-lines-and-angles-ex-13-4\/\" data-orig-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-4.png?fit=243%2C121&amp;ssl=1\" data-orig-size=\"243,121\" data-comments-opened=\"0\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-4\" data-image-description=\"&lt;p&gt;RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-4&lt;\/p&gt;\n\" data-image-caption=\"&lt;p&gt;RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-4&lt;\/p&gt;\n\" data-medium-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-4.png?fit=243%2C121&amp;ssl=1\" data-large-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-4.png?fit=243%2C121&amp;ssl=1\" data-recalc-dims=\"1\" data-ll-status=\"loaded\" data-lazy-loaded=\"1\" \/><\/figure>\n<p><br \/>\u2220AOC = 42\u00b0<br \/>AB and CD intersect each other at O.<br \/>\u2220AOC = \u2220BOD (Vertically opposite angles)<br \/>and \u2220AOD = \u2220BOC<br \/>But \u2220AOC = 42\u00b0<br \/>\u2220BOD = 42\u00b0<br \/>AOB is a straight line and OC stands on it<br \/>\u2220AOC + \u2220BOC = 180\u00b0<br \/>\u21d2 42\u00b0 = \u2220BOC = 180\u00b0<br \/>\u21d2 \u2220BOC = 180\u00b0 \u2013 42\u00b0 = 138\u00b0<br \/>But \u2220AOD = \u2220BOC (vertically opposite angles)<br \/>\u2220AOD = 138\u00b0<br \/>Hence \u2220AOD = 138\u00b0, \u2220BOD = 42\u00b0 and \u2220COB =138\u00b0<\/p>\n<p><strong>Question 10.<\/strong><br \/><strong>Solution:<\/strong><br \/>Two straight lines PQ and RS intersect at O.<br \/>\u2220POS = 114\u00b0<br \/>Straight lines<\/p>\n<p>PQ and RS intersect each other at O<br \/>\u2220POS = \u2220QOR (Vertically opposite angles)<br \/>But \u2220POS = 114\u00b0<br \/>\u2220QOR = 114\u00b0 or \u2220ROQ = 114\u00b0<br \/>But \u2220POS + \u2220POR = 180\u00b0 (Linear pair)<br \/>\u21d2 114\u00b0 + \u2220POR = 180\u00b0<br \/>\u21d2 \u2220POR = 180\u00b0 \u2013 114\u00b0 = 66\u00b0<br \/>But \u2220QOS = \u2220POR (vertically opposite angles)<br \/>\u2220QOS = 66\u00b0<br \/>Hence \u2220POR = 66\u00b0, \u2220ROQ =114\u00b0 and \u2220QOS = 66\u00b0<\/p>\n<aside class=\"scaip scaip-6    \">\n<aside id=\"block-7\" class=\"widget_block clearfix\"><ins class=\"adsbygoogle\" data-ad-client=\"ca-pub-8012231244430966\" data-ad-slot=\"4142978075\" data-ad-format=\"auto\" data-full-width-responsive=\"true\" data-adsbygoogle-status=\"done\" data-ad-status=\"unfilled\">\n<div id=\"aswift_6_host\" tabindex=\"0\" title=\"Advertisement\" aria-label=\"Advertisement\">\u00a0<\/div>\n<\/ins><\/aside>\n<\/aside>\n<p><strong>Question 11.<\/strong><br \/><strong>Solution:<\/strong><br \/>In the given figure, rays OA, OB, OC and OD meet at O and ZAOB \u2013 56\u00b0,<br \/>\u2220BOC = 100\u00b0, \u2220COD = x and \u2220DOA = 74\u00b0<\/p>\n<figure class=\"wp-block-image size-full\"><img class=\"wp-image-552096 jetpack-lazy-image entered lazyloaded jetpack-lazy-image--handled\" style=\"box-sizing: border-box; user-select: text !important; height: auto; max-width: 100%; border-style: none; position: relative; opacity: 1; transition: opacity 400ms ease 0ms; vertical-align: bottom; display: block;\" src=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6.png?resize=231%2C231&amp;is-pending-load=1#038;ssl=1\" sizes=\"(max-width: 231px) 100vw, 231px\" srcset=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6.png?w=231&amp;ssl=1 231w, https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6.png?resize=150%2C150&amp;ssl=1 150w, https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6.png?resize=200%2C200&amp;ssl=1 200w\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question 11\" width=\"231\" height=\"231\" data-attachment-id=\"552096\" data-permalink=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-13-lines-and-angles\/rs-aggarwal-class-7-solutions-chapter-13-lines-and-angles-ex-13-6\/\" data-orig-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6.png?fit=231%2C231&amp;ssl=1\" data-orig-size=\"231,231\" data-comments-opened=\"0\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6\" data-image-description=\"&lt;p&gt;RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6&lt;\/p&gt;\n\" data-image-caption=\"&lt;p&gt;RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6&lt;\/p&gt;\n\" data-medium-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6.png?fit=231%2C231&amp;ssl=1\" data-large-file=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6.png?fit=231%2C231&amp;ssl=1\" data-recalc-dims=\"1\" data-ll-status=\"loaded\" data-lazy-loaded=\"1\" \/><\/figure>\n<p><br \/>But \u2220AOB + \u2220BOC + \u2220COD + \u2220DOA = 360\u00b0 (Angles at a point)<br \/>56\u00b0 + 100\u00b0 + x\u00b0 + 74\u00b0 = 360\u00b0<br \/>\u21d2 230\u00b0 + x\u00b0 = 360\u00b0<br \/>\u21d2 x\u00b0 = 360\u00b0 \u2013 230\u00b0 = 130\u00b0<br \/>\u21d2 x = 130\u00b0<\/p>\n<h2><span class=\"ez-toc-section\" id=\"rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131-%e2%80%93-overview\"><\/span>RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 &#8211; Overview<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"basic-concepts\"><\/span>Basic Concepts\u00a0<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Here are the basic concepts of this exercise:<\/p>\n<ul>\n<li>Adjacent and Vertical Angles<\/li>\n<li>Complementary Angles<\/li>\n<li>Supplementary Angles<\/li>\n<li>Alternate Angles<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"important-topics\"><\/span>Important Topics<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Here are the important topics you must cover<\/p>\n<ul>\n<li>Introduction<\/li>\n<li>Related Angles<\/li>\n<li>Complementary angles<\/li>\n<li>Supplementary angles<\/li>\n<li>Adjacent angles<\/li>\n<li>Linear pair<\/li>\n<li>Vertically opposite angles<\/li>\n<li>Pairs of Lines<\/li>\n<li>Intersecting lines<\/li>\n<li>Transversal<\/li>\n<li>Angles made by the transversal<\/li>\n<li>Transversal of Parallel Lines<\/li>\n<li>Checking for Parallel Lines<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"definitions\"><\/span>Definitions<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ol>\n<li>Line: A figure that can be extended as much as you want in opposite directions without any obligations to having the endpoints is called a line.\u00a0<\/li>\n<li>Ray: The completely straight line that starts from a fixed point moving only in one direction is called a ray.<\/li>\n<li>Line Segment: It can be defined as the line made using the two definite starting and ending points. It doesn\u2019t have any thickness &amp; is only a one-dimensional figure.<\/li>\n<li>Angle: An angle is formed when the two line segments are joined at a single point. It is a combination of at least two line segments meeting at a common point, called as the vertex of the angle. The sides\/arms of the formed angle are those two line segments only.<\/li>\n<\/ol>\n<h3><span class=\"ez-toc-section\" id=\"types-of-angles\"><\/span>Types OF Angles<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>There are 6 types of angles, mentioned below:<\/p>\n<ol>\n<li>Acute Angle: It can be defined as angles less than 90 degrees.<\/li>\n<li>Obtuse Angle: An angle that can be defined as an angle more than 90 degrees.<\/li>\n<li>Right Angle: An angle that can be defined as an angle formed exactly at 90 degrees.<\/li>\n<li>Straight Angle: An angle that can be defined as an angle formed exactly at 180 degrees.<\/li>\n<li>Reflex Angle: Angle: An angle that can be defined as an angle of mof or 180 degrees but less than 270 degrees.<\/li>\n<li>Full Angle: An angle that can be defined as an angle formed exactly at 360 degrees.<\/li>\n<\/ol>\n<h3><span class=\"ez-toc-section\" id=\"related-angles\"><\/span>Related Angles<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Apart from the other six angles, here are some related angles you should know about.<\/p>\n<ol>\n<li>Complementary Angle: When the sum of two angles measures is equivalent to 90\u00b0, then we call it the Complementary Angle.<\/li>\n<li>Supplementary Angle: When the sum of two angles measures is equivalent to 180\u00b0, then we call it the Supplementary Angle.<\/li>\n<li>Adjacent Angle: These angles are the ones having a common vertex plus a common arm. Additionally, they do not possess any common interior points.<\/li>\n<li>Linear pair: It can be defined as a pair of adjacent angles, and its non-common sides are the opposite rays.<\/li>\n<li>Vertically Opposite Angles: The vertically opposite angles formed whenever the two lines intersect with each other are always equal.<\/li>\n<\/ol>\n<h3><span class=\"ez-toc-section\" id=\"pairs-of-lines\"><\/span>Pairs Of Lines<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ol>\n<li>Intersecting lines: The Intersection between two or more lines happens only if they have a common point. The common point symbolized as O is what we call their point of intersection.<\/li>\n<li>Transversal: It can be defined as the Intersection between two or more lines at different points.<\/li>\n<li>Angles made by the transversal: When the transversal cuts the lines, then multiple different angles are formed. They are:<\/li>\n<\/ol>\n<ul>\n<li>Interior angles<\/li>\n<li>Exterior angles<\/li>\n<li>Pairs of Alternate interior angles<\/li>\n<li>Pairs of Alternate exterior angles<\/li>\n<li>Pairs of Corresponding angles<\/li>\n<li>Pairs of interior angles (-Similar side of the transversal-)<\/li>\n<\/ul>\n<p>4. Transversal of Parallel Lines: These lines do not meet anywhere. Also, the\u00a0 Transversal of Parallel Lines gives birth to some interesting results.<\/p>\n<p>This is the complete blog on RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1. To know more about the <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 7 Maths exam, ask in the comments.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131\"><\/span>FAQs on RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1\u00a0<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1635254017231\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"define-an-intersecting-line\"><\/span>Define an intersecting line.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>The Intersection between two or more lines happens only if they have a common point. The common point symbolized as O is what we call their point of intersection.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1635254029231\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-is-a-line-segment\"><\/span>What is a line segment?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>It can be defined as the line made using the two definite starting and ending points. It doesn\u2019t have any thickness &amp; is only a one-dimensional figure.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1635254051415\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"define-angles-made-by-a-transversal\"><\/span>Define Angles made by a transversal.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>When the transversal cuts the lines, then multiple different angles are formed. They are:<br \/>Interior angles<br \/>Exterior angles<br \/>Pairs of Alternate interior angles<br \/>Pairs of Alternate exterior angles<br \/>Pairs of Corresponding angles<br \/>Pairs of interior angles (-Similar side of the transversal-)<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1635254105274\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"from-where-can-i-find-the-download-link-for-the-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131-pdf\"><\/span>From where can I find the download link for the RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can find the download link in the above blog.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1635254114502\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-much-does-it-cost-to-download-the-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131-pdf\"><\/span>How much does it cost to download the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter\u00a013 Ex 13.1\u00a0PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download it for free.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1635254126431\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-access-the-rs-aggarwal-solutions-class-7-maths-chapter-13-ex-131-pdf-offline\"><\/span>Can I access the\u00a0RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1\u00a0PDF Offline?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Once you have downloaded the PDF online, you can access it offline whenever you want.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1:\u00a0You can rely totally on the RS Aggarwal Solutions Class 7 Maths, be it your class tests or assignments. It is because the solutions of RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 are very helpful in clearing your doubts. The solutions are designed &#8230; <a title=\"RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 (Updated For 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-7-maths-chapter-13-exercise-13-1\/\" aria-label=\"More on RS Aggarwal Solutions Class 7 Maths Chapter 13 Ex 13.1 (Updated For 2024)\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":144645,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73412,73410],"tags":[73320,77308,77549],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/71712"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=71712"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/71712\/revisions"}],"predecessor-version":[{"id":523834,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/71712\/revisions\/523834"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/144645"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=71712"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=71712"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=71712"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}