{"id":68125,"date":"2021-08-30T11:25:00","date_gmt":"2021-08-30T05:55:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=68125"},"modified":"2021-08-30T14:38:31","modified_gmt":"2021-08-30T09:08:31","slug":"rd-sharma-solutions-class-11-maths-chapter-32-exercise-32-2","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-32-exercise-32-2\/","title":{"rendered":"RD Sharma Class 11 Solutions Chapter 32 Statistics Exercise 32.2 (Updated for 2021-22)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-121395\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Class-11-Solutions-Chapter-32-Exercise-32.2.jpg\" alt=\"RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Class-11-Solutions-Chapter-32-Exercise-32.2.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Class-11-Solutions-Chapter-32-Exercise-32.2-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2:\u00a0<\/strong>In this exercise, we&#8217;ll look at the mean deviation of a discrete frequency distribution and how to compute it using an algorithm. Students who are experiencing difficulty solving arithmetic questions can use the solutions prepared by experts, who have presented the solutions in the most straightforward manner possible for any pupil to understand. Students who are unable to resolve their doubts during class can refer the <a href=\"https:\/\/www.kopykitab.com\/blog\/cbse-class-11-maths-rd-sharma-solutions\/\"><strong>RD Sharma Class 11 Maths Solutions<\/strong><\/a>. Students can easily obtain the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-32-statistics\/\"><strong>RD Sharma Solutions Class 11 Maths Chapter 32<\/strong><\/a> Exercise 32.2 pdf by clicking on the links below.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69da6a8a24557\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" 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href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-32-exercise-32-2\/#download-rd-sharma-class-11-solutions-chapter-32-statistics-exercise-322-free-pdf\" title=\"Download RD Sharma Class 11 Solutions Chapter 32 Statistics Exercise 32.2 Free PDF\">Download RD Sharma Class 11 Solutions Chapter 32 Statistics Exercise 32.2 Free PDF<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-32-exercise-32-2\/#access-answers-to-rd-sharma-solutions-class-11-maths-chapter-32-exercise-322-important-question-with-answers\" title=\"Access answers to RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2- Important Question with Answers\">Access answers to RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2- Important Question with Answers<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a 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href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-32-exercise-32-2\/#is-rd-sharma-class-11-solutions-chapter-32-exercise-322-for-free\" title=\"Is RD Sharma Class 11 Solutions Chapter 32 Exercise 32.2 for free?\">Is RD Sharma Class 11 Solutions Chapter 32 Exercise 32.2 for free?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-32-exercise-32-2\/#where-can-i-download-rd-sharma-class-11-solutions-chapter-32-exercise-322-free-pdf\" title=\"Where can I download RD Sharma Class 11 Solutions Chapter 32 Exercise 32.2 free PDF?\">Where can I download RD Sharma Class 11 Solutions Chapter 32 Exercise 32.2 free PDF?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-class-11-solutions-chapter-32-statistics-exercise-322-free-pdf\"><\/span>Download RD Sharma Class 11 Solutions Chapter 32 Statistics Exercise 32.2 Free PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Solutions-Class-11-Maths-Chapter-32-Ex-32.2-1.pdf\">RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 800px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Solutions-Class-11-Maths-Chapter-32-Ex-32.2-1.pdf\", \"#example1\");<\/script><\/p>\n<h3><span class=\"ez-toc-section\" id=\"access-answers-to-rd-sharma-solutions-class-11-maths-chapter-32-exercise-322-important-question-with-answers\"><\/span>Access answers to RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2- Important Question with Answers<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>1. Calculate the mean deviation from the median of the following frequency distribution:<br \/><\/strong><\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td>\n<p><strong>Heights in inches<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>58<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>59<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>60<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>61<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>62<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>63<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>64<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>65<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>66<\/strong><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p><strong>No. of students<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>15<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>20<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>32<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>35<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>35<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>22<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>20<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>10<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>8<\/strong><\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p><strong>Solution:<\/strong><\/p>\n<p>To find the mean deviation from the median, firstly let us calculate the median.<\/p>\n<p>We know, Median is the Middle term,<\/p>\n<p>So, Median = 61<\/p>\n<p>Let x<sub>i<\/sub>\u00a0=Heights in inches<\/p>\n<p>And, f<sub>i<\/sub>\u00a0= Number of students<\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td>\n<p>x<sub>i<\/sub><\/p>\n<\/td>\n<td>\n<p>f<sub>i<\/sub><\/p>\n<\/td>\n<td>\n<p>Cumulative Frequency<\/p>\n<\/td>\n<td>\n<p>|d<sub>i<\/sub>| = |x<sub>i<\/sub>\u00a0\u2013 M|<\/p>\n<p>= |x<sub>i<\/sub>\u00a0\u2013 61|<\/p>\n<\/td>\n<td>\n<p>f<sub>i<\/sub>\u00a0|d<sub>i<\/sub>|<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>58<\/p>\n<\/td>\n<td>\n<p>15<\/p>\n<\/td>\n<td>\n<p>15<\/p>\n<\/td>\n<td>\n<p>3<\/p>\n<\/td>\n<td>\n<p>45<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>59<\/p>\n<\/td>\n<td>\n<p>20<\/p>\n<\/td>\n<td>\n<p>35<\/p>\n<\/td>\n<td>\n<p>2<\/p>\n<\/td>\n<td>\n<p>40<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>60<\/p>\n<\/td>\n<td>\n<p>32<\/p>\n<\/td>\n<td>\n<p>67<\/p>\n<\/td>\n<td>\n<p>1<\/p>\n<\/td>\n<td>\n<p>32<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>61<\/p>\n<\/td>\n<td>\n<p>35<\/p>\n<\/td>\n<td>\n<p>102<\/p>\n<\/td>\n<td>\n<p>0<\/p>\n<\/td>\n<td>\n<p>0<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>62<\/p>\n<\/td>\n<td>\n<p>35<\/p>\n<\/td>\n<td>\n<p>137<\/p>\n<\/td>\n<td>\n<p>1<\/p>\n<\/td>\n<td>\n<p>35<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>63<\/p>\n<\/td>\n<td>\n<p>22<\/p>\n<\/td>\n<td>\n<p>159<\/p>\n<\/td>\n<td>\n<p>2<\/p>\n<\/td>\n<td>\n<p>44<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>64<\/p>\n<\/td>\n<td>\n<p>20<\/p>\n<\/td>\n<td>\n<p>179<\/p>\n<\/td>\n<td>\n<p>3<\/p>\n<\/td>\n<td>\n<p>60<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>65<\/p>\n<\/td>\n<td>\n<p>10<\/p>\n<\/td>\n<td>\n<p>189<\/p>\n<\/td>\n<td>\n<p>4<\/p>\n<\/td>\n<td>\n<p>40<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>66<\/p>\n<\/td>\n<td>\n<p>8<\/p>\n<\/td>\n<td>\n<p>197<\/p>\n<\/td>\n<td>\n<p>5<\/p>\n<\/td>\n<td>\n<p>40<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>N = 197<\/p>\n<\/td>\n<td>\n<p>Total = 336<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>N=197<\/p>\n<p>\\(MD = \\frac{1}{n}\\sum_{i=1}^{n}|d_{i}|\\)<\/p>\n<p>= 1\/197 \u00d7 336<\/p>\n<p>= 1.70<\/p>\n<p>\u2234 The mean deviation is 1.70.<\/p>\n<p><strong>2.<\/strong>\u00a0<strong>The number of telephone calls received at an exchange in 245 successive on2-minute intervals is shown in the following frequency distribution:<br \/><\/strong><\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td>\n<p><strong>Number of calls<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>0<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>1<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>2<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>3<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>4<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>5<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>6<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>7<\/strong><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p><strong>Frequency<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>14<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>21<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>25<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>43<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>51<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>40<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>39<\/strong><\/p>\n<\/td>\n<td>\n<p><strong>12<\/strong><\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p><strong>Compute the mean deviation about the median.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>To find the mean deviation from the median, firstly let us calculate the median.<\/p>\n<p>We know, Median is the even term,\u00a03+5\/2 = 4<\/p>\n<p>So, Median = 8<\/p>\n<p>Let x<sub>i<\/sub>\u00a0=Number of calls<\/p>\n<p>And, f<sub>i<\/sub>\u00a0= Frequency<\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td>\n<p>x<sub>i<\/sub><\/p>\n<\/td>\n<td>\n<p>f<sub>i<\/sub><\/p>\n<\/td>\n<td>\n<p>Cumulative Frequency<\/p>\n<\/td>\n<td>\n<p>|d<sub>i<\/sub>| = |x<sub>i<\/sub>\u00a0\u2013 M|<\/p>\n<p>= |x<sub>i<\/sub>\u00a0\u2013 61|<\/p>\n<\/td>\n<td>\n<p>f<sub>i<\/sub>\u00a0|d<sub>i<\/sub>|<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>0<\/p>\n<\/td>\n<td>\n<p>14<\/p>\n<\/td>\n<td>\n<p>14<\/p>\n<\/td>\n<td>\n<p>4<\/p>\n<\/td>\n<td>\n<p>56<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>1<\/p>\n<\/td>\n<td>\n<p>21<\/p>\n<\/td>\n<td>\n<p>35<\/p>\n<\/td>\n<td>\n<p>3<\/p>\n<\/td>\n<td>\n<p>63<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>2<\/p>\n<\/td>\n<td>\n<p>25<\/p>\n<\/td>\n<td>\n<p>60<\/p>\n<\/td>\n<td>\n<p>2<\/p>\n<\/td>\n<td>\n<p>50<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>3<\/p>\n<\/td>\n<td>\n<p>43<\/p>\n<\/td>\n<td>\n<p>103<\/p>\n<\/td>\n<td>\n<p>1<\/p>\n<\/td>\n<td>\n<p>43<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>4<\/p>\n<\/td>\n<td>\n<p>51<\/p>\n<\/td>\n<td>\n<p>154<\/p>\n<\/td>\n<td>\n<p>0<\/p>\n<\/td>\n<td>\n<p>0<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>5<\/p>\n<\/td>\n<td>\n<p>40<\/p>\n<\/td>\n<td>\n<p>194<\/p>\n<\/td>\n<td>\n<p>1<\/p>\n<\/td>\n<td>\n<p>40<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>6<\/p>\n<\/td>\n<td>\n<p>39<\/p>\n<\/td>\n<td>\n<p>233<\/p>\n<\/td>\n<td>\n<p>2<\/p>\n<\/td>\n<td>\n<p>78<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>7<\/p>\n<\/td>\n<td>\n<p>12<\/p>\n<\/td>\n<td>\n<p>245<\/p>\n<\/td>\n<td>\n<p>3<\/p>\n<\/td>\n<td>\n<p>36<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>Total = 366<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p>Total = 245<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>N = 245<\/p>\n<p>\\(MD = \\frac{1}{n}\\sum_{i=1}^{n}|d_{i}|\\)<\/p>\n<p>= 1\/245 \u00d7 336<\/p>\n<p>= 1.49<\/p>\n<p>\u2234 The mean deviation is 1.49.<\/p>\n<p><strong>Statistics Ex 32.2 Q3<\/strong><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7552\/16128614476_fb1905b6b7_o.png\" alt=\"RD-Sharma-class-11 Solutions-Chapter-32-Statistics-Ex-32.2-Q-3\" width=\"485\" height=\"306\" \/><br \/><strong>Statistics Ex 32.2 Q4(i)<\/strong><br \/><img src=\"https:\/\/farm9.staticflickr.com\/8679\/16152497131_daafd8d47f_o.png\" alt=\"RD-Sharma-class-11 Solutions-Chapter-32-Statistics-Ex-32.2-Q-4\" width=\"437\" height=\"298\" \/><\/p>\n<p><strong>Statistics Ex 32.2 Q4(ii)<\/strong><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7529\/15534666243_e4fc439e76_o.png\" alt=\"RD-Sharma-class-11 Solutions-Chapter-32-Statistics-Ex-32.2-Q-4 i\" width=\"475\" height=\"155\" \/><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7470\/16152497361_ca7a4acef1_o.png\" alt=\"RD-Sharma-class-11 Solutions-Chapter-32-Statistics-Ex-32.2-Q-4 ii\" width=\"331\" height=\"119\" \/><\/p>\n<p><strong>Statistics Ex 32.2 Q4(iii)<\/strong><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7571\/15967092000_8d766ca8cb_o.png\" alt=\"RD-Sharma-class-11 Solutions-Chapter-32-Statistics-Ex-32.2-Q-4 iii\" width=\"473\" height=\"167\" \/><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7513\/15968644867_440a658bfa_o.png\" alt=\"RD-Sharma-class-11 Solutions-Chapter-32-Statistics-Ex-32.2-Q-4 iv\" width=\"285\" height=\"118\" \/><\/p>\n<p><strong>Statistics Ex 32.2 Q4(iv)<\/strong><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7494\/16153647542_5775438b3c_o.png\" alt=\"RD-Sharma-class-11 Solutions-Chapter-32-Statistics-Ex-32.2-Q-4 v\" width=\"468\" height=\"221\" \/><br \/><strong>Statistics Ex 32.2 Q5<\/strong><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7461\/16128614066_44cd4db8b3_o.png\" alt=\"RD-Sharma-class-11 Solutions-Chapter-32-Statistics-Ex-32.2-Q-5\" width=\"468\" height=\"260\" \/><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7546\/15966957228_4f9fb25bf6_o.png\" alt=\"RD-Sharma-class-11 Solutions-Chapter-32-Statistics-Ex-32.2-Q-5 i\" width=\"620\" height=\"469\" \/><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7479\/15532067794_a448315b20_o.png\" alt=\"RD-Sharma-class-11 Solutions-Chapter-32-Statistics-Ex-32.2-Q-5 ii\" width=\"445\" height=\"257\" \/><\/p>\n<p>We have provided complete details of RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2. If you have any queries related to <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\"><strong>CBSE<\/strong><\/a> Class 11, feel free to ask us in the comment section below.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-solutions-class-11-maths-chapter-32-exercise-322\"><\/span>FAQs on RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1630311178883\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-many-questions-are-there-in-rd-sharma-class-11-solutions-chapter-32-statistics-exercise-322\"><\/span>How many questions are there in RD Sharma Class 11 Solutions Chapter 32 Statistics Exercise 32.2?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>There are a total of 5 questions in RD Sharma Class 11 Solutions Chapter 32 Exercise 32.2.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630311369578\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-rd-sharma-class-11-solutions-chapter-32-exercise-322-for-free\"><\/span>Is RD Sharma Class 11 Solutions Chapter 32 Exercise 32.2 for free?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, You can get RD Sharma Class 11 Solutions Chapter 32 Exercise 32.2 for free.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630311445834\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"where-can-i-download-rd-sharma-class-11-solutions-chapter-32-exercise-322-free-pdf\"><\/span>Where can I download RD Sharma Class 11 Solutions Chapter 32 Exercise 32.2 free PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download RD Sharma Class 11 Solutions Chapter 32 Exercise 32.2 free PDF from the above article.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Solutions Class 11 Maths Chapter 32 Exercise 32.2:\u00a0In this exercise, we&#8217;ll look at the mean deviation of a discrete frequency distribution and how to compute it using an algorithm. Students who are experiencing difficulty solving arithmetic questions can use the solutions prepared by experts, who have presented the solutions in the most straightforward &#8230; <a title=\"RD Sharma Class 11 Solutions Chapter 32 Statistics Exercise 32.2 (Updated for 2021-22)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-32-exercise-32-2\/\" aria-label=\"More on RD Sharma Class 11 Solutions Chapter 32 Statistics Exercise 32.2 (Updated for 2021-22)\">Read more<\/a><\/p>\n","protected":false},"author":238,"featured_media":121395,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411,2985,73410],"tags":[3428,73334,73564,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/68125"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/238"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=68125"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/68125\/revisions"}],"predecessor-version":[{"id":121449,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/68125\/revisions\/121449"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/121395"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=68125"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=68125"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=68125"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}