{"id":67972,"date":"2023-09-13T12:39:00","date_gmt":"2023-09-13T07:09:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=67972"},"modified":"2023-11-15T10:04:41","modified_gmt":"2023-11-15T04:34:41","slug":"rd-sharma-solutions-class-11-maths-chapter-16-exercise-16-1","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-16-exercise-16-1\/","title":{"rendered":"RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-121894\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/08\/RD-Sharma-Class-11-Solutions-Chapter-16-Exercise-16.1.jpg\" alt=\"RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/08\/RD-Sharma-Class-11-Solutions-Chapter-16-Exercise-16.1.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/08\/RD-Sharma-Class-11-Solutions-Chapter-16-Exercise-16.1-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1<\/strong>: In this exercise, we will introduce the term and notation for a factorial. Our solution module uses several tips and shortcut diagrams to explain all exercise problems in the most understandable language. Subject matter experts have simplified difficult problems into simple steps, which students can easily solve with accuracy. <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-16-permutations\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 11 Mathematics Chapter 16 Solutions<\/a> for the chapter Permutations will help students gain solid knowledge and mastery of the subject. Students can easily download the PDF from the link provided below.\u00a0<\/p>\n<ul>\n<li><a href=\"https:\/\/www.kopykitab.com\/blog\/cbse-class-11-maths-rd-sharma-solutions\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 11 Maths<\/a>\u00a0<\/li>\n<\/ul>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69d5058b43d75\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69d5058b43d75\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-16-exercise-16-1\/#download-rd-sharma-solutions-class-11-maths-chapter-16-exercise-161-pdf\" title=\"Download RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF:\">Download RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-16-exercise-16-1\/#access-rd-sharma-solutions-class-11-maths-chapter-16\" title=\"Access RD Sharma Solutions Class 11 Maths Chapter 16\">Access RD Sharma Solutions Class 11 Maths Chapter 16<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-16-exercise-16-1\/#faq-rd-sharma-solutions-class-11-maths-chapter-16-exercise-161\" title=\"FAQ: RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1\">FAQ: RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-16-exercise-16-1\/#can-i-open-rd-sharma-solutions-class-11-maths-chapter-16-exercise-161-pdf-on-my-smartphone\" title=\"Can I open RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF on my smartphone?\">Can I open RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF on my smartphone?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-16-exercise-16-1\/#what-are-the-benefits-of-studying-from-rd-sharma-solutions-class-12\" title=\"What are the benefits of studying from RD Sharma Solutions Class 12?\">What are the benefits of studying from RD Sharma Solutions Class 12?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-16-exercise-16-1\/#can-i-download-rd-sharma-solutions-class-11-maths-chapter-16-exercise-161-pdf-free\" title=\"Can I download RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF free?\">Can I download RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF free?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-16-exercise-16-1\/#is-rd-sharma-enough-for-class-12-maths\" title=\"Is RD Sharma enough for Class 12 Maths? \">Is RD Sharma enough for Class 12 Maths? <\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-solutions-class-11-maths-chapter-16-exercise-161-pdf\"><\/span>Download RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF:<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/08\/RD-Sharma-Solutions-Class-11-Maths-Chapter-16-Ex-16.1.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/08\/RD-Sharma-Solutions-Class-11-Maths-Chapter-16-Ex-16.1.pdf\" target=\"_blank\" rel=\"noopener\">Download Class 11 RD Sharma Solutions Maths Chapter 16 Exercise 16.1<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"access-rd-sharma-solutions-class-11-maths-chapter-16\"><\/span>Access RD Sharma Solutions Class 11 Maths Chapter 16<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>1. Compute:<\/strong><\/p>\n<p><strong>(i) 30!\/28!<\/strong><\/p>\n<p><strong>(ii) (11! \u2013 10!)\/9!<\/strong><\/p>\n<p><strong>(iii) L.C.M. (6!, 7!, 8!)<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>(i)\u00a0<\/strong>30!\/28!<\/p>\n<p>Let us evaluate,<\/p>\n<p>30!\/28! = (30 \u00d7 29 \u00d7 28!)\/28!<\/p>\n<p>= 30 \u00d7 29<\/p>\n<p>= 870<\/p>\n<p><strong>(ii)\u00a0<\/strong>(11! \u2013 10!)\/9!<\/p>\n<p>Let us evaluate,<\/p>\n<p>We know,<\/p>\n<p>11! = 11 \u00d7 10 \u00d7 9 \u00d7 \u2026. \u00d7 1<\/p>\n<p>10! = 10 \u00d7 9 \u00d7 8 \u00d7 \u2026 \u00d7 1<\/p>\n<p>9! = 9 \u00d7 8 \u00d7 7 \u00d7 \u2026 \u00d7 1<\/p>\n<p>By using these values we get,<\/p>\n<p>(11! \u2013 10!)\/9! = (11 \u00d7 10 \u00d7 9! \u2013 10 \u00d7 9!)\/ 9!<\/p>\n<p>= 9! (110 \u2013 10)\/9!<\/p>\n<p>= 110 \u2013 10<\/p>\n<p>= 100<\/p>\n<p><strong>(iii)\u00a0<\/strong>L.C.M. (6!, 7!, 8!)<\/p>\n<p>Let us find the LCM of (6!, 7!, 8!)<\/p>\n<p>We know,<\/p>\n<p>8! = 8 \u00d7 7 \u00d7 6!<\/p>\n<p>7! = 7 \u00d7 6!<\/p>\n<p>6! = 6!<\/p>\n<p>So,<\/p>\n<p>L.C.M. (6!, 7!, 8!) = LCM [8 \u00d7 7 \u00d7 6!, 7 \u00d7 6!, 6!]<\/p>\n<p>= 8 \u00d7 7 \u00d7 6!<\/p>\n<p>= 8!<\/p>\n<p><strong>2. Prove that: 1\/9! + 1\/10! + 1\/11! = 122\/11!<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given:<\/p>\n<p>1\/9! + 1\/10! + 1\/11! = 122\/11!<\/p>\n<p>Let us consider LHS: 1\/9! + 1\/10! + 1\/11!<\/p>\n<p>1\/9! + 1\/10! + 1\/11! = 1\/9! + 1\/(10\u00d79!) + 1\/(11\u00d710\u00d79!)<\/p>\n<p>= (110 + 11 + 1)\/(11 \u00d7 10 \u00d7 9!)<\/p>\n<p>= 122\/11!<\/p>\n<p>= RHS<\/p>\n<p>Hence proved.<\/p>\n<p><strong>3. Find x in each of the following:<\/strong><\/p>\n<p><strong>(i) 1\/4! + 1\/5! = x\/6!<\/strong><\/p>\n<p><strong>(ii) x\/10! = 1\/8! + 1\/9!<\/strong><\/p>\n<p><strong>(iii) 1\/6! + 1\/7! = x\/8!<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>(i)\u00a0<\/strong>1\/4! + 1\/5! = x\/6!<\/p>\n<p>We know that<\/p>\n<p>5! = 5 \u00d7 4 \u00d7 3 \u00d7 2 \u00d7 1<\/p>\n<p>6! = 6 \u00d7 5 \u00d7 4 \u00d7 3 \u00d7 2 \u00d7 1<\/p>\n<p>So by using these values,<\/p>\n<p>1\/4! + 1\/5! = x\/6!<\/p>\n<p>1\/4! + 1\/(5\u00d74!) = x\/6!<\/p>\n<p>(5 + 1) \/ (5\u00d74!) = x\/6!<\/p>\n<p>6\/5! = x\/(6\u00d75!)<\/p>\n<p>x = (6 \u00d7 6 \u00d7 5!)\/5!<\/p>\n<p>= 36<\/p>\n<p>\u2234 The value of x is 36.<\/p>\n<p><strong>(ii)\u00a0<\/strong>x\/10! = 1\/8! + 1\/9!<\/p>\n<p>We know that<\/p>\n<p>10! = 10 \u00d7 9!<\/p>\n<p>9! = 9 \u00d7 8!<\/p>\n<p>So by using these values,<\/p>\n<p>x\/10! = 1\/8! + 1\/9!<\/p>\n<p>x\/10! = 1\/8! + 1\/(9\u00d78!)<\/p>\n<p>x\/10! = (9 + 1) \/ (9\u00d78!)<\/p>\n<p>x\/10! = 10\/9!<\/p>\n<p>x\/(10\u00d79!) = 10\/9!<\/p>\n<p>x = (10 \u00d7 10 \u00d7 9!)\/9!<\/p>\n<p>= 10 \u00d7 10<\/p>\n<p>= 100<\/p>\n<p>\u2234 The value of x is 100.<\/p>\n<p><strong>(iii)<\/strong>\u00a01\/6! + 1\/7! = x\/8!<\/p>\n<p>We know that<\/p>\n<p>8! = 8 \u00d7 7 \u00d7\u00a06!<\/p>\n<p>7! =\u00a07 \u00d7\u00a06!<\/p>\n<p>So by using these values,<\/p>\n<p>1\/6! + 1\/7! = x\/8!<\/p>\n<p>1\/6! + 1\/(7\u00d76!) = x\/8!<\/p>\n<p>(1 + 7)\/(7\u00d76!) = x\/8!<\/p>\n<p>8\/7! = x\/8!<\/p>\n<p>8\/7! = x\/(8\u00d77!)<\/p>\n<p>x = (8 \u00d7 8 \u00d7 7!)\/7!<\/p>\n<p>= 8 \u00d7 8<\/p>\n<p>= 64<\/p>\n<p>\u2234 The value of x is 64.<\/p>\n<p><strong>4. Convert the following products into factorials:<br \/>(i) 5\u00a0\u22c5\u00a06\u00a0\u22c5\u00a07\u00a0\u22c5\u00a08\u00a0\u22c5\u00a09\u00a0\u22c5\u00a010<\/strong><\/p>\n<p><strong>(ii) 3\u00a0\u22c5\u00a06\u00a0\u22c5\u00a09\u00a0\u22c5\u00a012\u00a0\u22c5\u00a015\u00a0\u22c5\u00a018<\/strong><\/p>\n<p><strong>(iii) (n + 1) (n + 2) (n + 3) \u2026(2n)<br \/>(iv) 1\u00a0\u22c5\u00a03\u00a0\u22c5\u00a05\u00a0\u22c5\u00a07\u00a0\u22c5\u00a09 \u2026 (2n \u2013 1)<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>(i)\u00a0<\/strong>5\u00a0\u22c5\u00a06\u00a0\u22c5\u00a07\u00a0\u22c5\u00a08\u00a0\u22c5\u00a09\u00a0\u22c5\u00a010<\/p>\n<p>Let us evaluate<\/p>\n<p>We can write it as:<\/p>\n<p>5\u00a0\u22c5\u00a06\u00a0\u22c5\u00a07\u00a0\u22c5\u00a08\u00a0\u22c5\u00a09\u00a0\u22c5\u00a010 = (1\u00d72\u00d73\u00d74\u00d75\u00d76\u00d77\u00d78\u00d79\u00d710)\/(1\u00d72\u00d73\u00d74)<\/p>\n<p>= 10!\/4!<\/p>\n<p><strong>(ii)\u00a0<\/strong>3\u00a0\u22c5\u00a06\u00a0\u22c5\u00a09\u00a0\u22c5\u00a012\u00a0\u22c5\u00a015\u00a0\u22c5\u00a018<\/p>\n<p>Let us evaluate<\/p>\n<p>3\u00a0\u22c5\u00a06\u00a0\u22c5\u00a09\u00a0\u22c5\u00a012\u00a0\u22c5\u00a015\u00a0\u22c5\u00a018 = (3\u00d71) \u00d7 (3\u00d72) \u00d7 (3\u00d73) \u00d7 (3\u00d74) \u00d7 (3\u00d75) \u00d7 (3\u00d76)<\/p>\n<p>= 3<sup>6<\/sup>\u00a0(1\u00d72\u00d73\u00d74\u00d75\u00d76)<\/p>\n<p>= 3<sup>6<\/sup>\u00a0(6!)<\/p>\n<p><strong>(iii)\u00a0<\/strong>(n + 1) (n + 2) (n + 3) \u2026 (2n)<\/p>\n<p>Let us evaluate<\/p>\n<p>(n + 1) (n + 2) (n + 3) \u2026 (2n) = [(1) (2) (3) .. (n) \u2026 (n + 1) (n + 2) (n + 3) \u2026 (2n)] \/ (1) (2) (3) .. (n)<\/p>\n<p>= (2n)!\/n!<\/p>\n<p><strong>(iv)\u00a0<\/strong>1\u00a0\u22c5\u00a03\u00a0\u22c5\u00a05\u00a0\u22c5\u00a07\u00a0\u22c5\u00a09 \u2026 (2n \u2013 1)<\/p>\n<p>Let us evaluate<\/p>\n<p>1\u00a0\u22c5\u00a03\u00a0\u22c5\u00a05\u00a0\u22c5\u00a07\u00a0\u22c5\u00a09 \u2026 (2n \u2013 1) = [(1) (3) (5) \u2026 (2n-1)] [(2) (4) (6) \u2026 (2n)] \/ [(2) (4) (6) \u2026 (2n)]<\/p>\n<p>= [(1) (2) (3) (4) \u2026 (2n-1) (2n)] \/ 2<sup>n<\/sup>\u00a0[(1) (2) (3) \u2026 (n)]<\/p>\n<p>= (2n)! \/ 2<sup>n<\/sup>\u00a0n!<\/p>\n<p><strong>5. Which of the following is true:<\/strong><\/p>\n<p><strong>(i) (2 + 3)! = 2! + 3!<\/strong><\/p>\n<p><strong>(ii) (2 \u00d7 3)! = 2! \u00d7 3!<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>(i)\u00a0<\/strong>(2 + 3)! = 2! + 3!<\/p>\n<p>Let us consider LHS: (2 + 3)!<\/p>\n<p>(2 + 3)! = 5!<\/p>\n<p>Now RHS,<\/p>\n<p>2! + 3! = (2\u00d71) + (3\u00d72\u00d71)<\/p>\n<p>= 2 + 6<\/p>\n<p>= 8<\/p>\n<p>LHS \u2260\u00a0RHS<\/p>\n<p>\u2234 The given expression is false.<\/p>\n<p><strong>(ii)\u00a0<\/strong>(2 \u00d7 3)! = 2! \u00d7 3!<\/p>\n<p>Let us consider LHS: (2 \u00d7 3)!<\/p>\n<p>(2 \u00d7 3)! = 6!<\/p>\n<p>= 6 \u00d7 5 \u00d7 4 \u00d7 3 \u00d7 2 \u00d7 1<\/p>\n<p>= 720<\/p>\n<p>Now RHS,<\/p>\n<p>2! \u00d7 3! = (2\u00d71) \u00d7 (3\u00d72\u00d71)<\/p>\n<p>= 12<\/p>\n<p>LHS \u2260\u00a0RHS<\/p>\n<p>\u2234 The given expression is false.<\/p>\n<p><strong>6. Prove that: n! (n + 2) = n! + (n + 1)!<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given:<\/p>\n<p>n! (n + 2) = n! + (n + 1)!<\/p>\n<p>Let us consider RHS = n! + (n + 1)!<\/p>\n<p>n! + (n + 1)! = n! + (n + 1) (n + 1 \u2013 1)!<\/p>\n<p>= n! + (n + 1)n!<\/p>\n<p>= n!(1 + n + 1)<\/p>\n<p>= n! (n + 2)<\/p>\n<p>= L.H.S<\/p>\n<p>L.H.S = R.H.S<\/p>\n<p>Hence, Proved.<\/p>\n<p>We have included all the information regarding <a href=\"https:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener\">CBSE <\/a>RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1. If you have any queries feel free to ask in the comment section.\u00a0<\/p>\n<h3><span class=\"ez-toc-section\" id=\"faq-rd-sharma-solutions-class-11-maths-chapter-16-exercise-161\"><\/span>FAQ: RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1<span class=\"ez-toc-section-end\"><\/span><\/h3>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1630392603045\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-open-rd-sharma-solutions-class-11-maths-chapter-16-exercise-161-pdf-on-my-smartphone\"><\/span>Can I open RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF on my smartphone?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, you can open RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF on any device.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630392642998\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-are-the-benefits-of-studying-from-rd-sharma-solutions-class-12\"><\/span>What are the benefits of studying from RD Sharma Solutions Class 12?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>By practicing these solutions, students can earn higher academic grades. Our experts solve these solutions with utmost accuracy to help students in their studies.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630392646622\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-download-rd-sharma-solutions-class-11-maths-chapter-16-exercise-161-pdf-free\"><\/span>Can I download RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF free?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, you can download RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 PDF free.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630392647879\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-rd-sharma-enough-for-class-12-maths\"><\/span>Is RD Sharma enough for Class 12 Maths? <span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>RD Sharma is a good book that gives you thousands of questions to practice. <\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1: In this exercise, we will introduce the term and notation for a factorial. Our solution module uses several tips and shortcut diagrams to explain all exercise problems in the most understandable language. Subject matter experts have simplified difficult problems into simple steps, which students can &#8230; <a title=\"RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-16-exercise-16-1\/\" aria-label=\"More on RD Sharma Solutions Class 11 Maths Chapter 16 Exercise 16.1 (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":244,"featured_media":121894,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2917,73397,73717,73411,2985,73410],"tags":[3428,73334,73564],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/67972"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/244"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=67972"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/67972\/revisions"}],"predecessor-version":[{"id":507251,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/67972\/revisions\/507251"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/121894"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=67972"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=67972"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=67972"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}