{"id":67928,"date":"2023-09-07T23:55:00","date_gmt":"2023-09-07T18:25:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=67928"},"modified":"2023-11-03T10:06:05","modified_gmt":"2023-11-03T04:36:05","slug":"rd-sharma-solutions-class-11-maths-chapter-8-exercise-8-1","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-8-exercise-8-1\/","title":{"rendered":"RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1 (Updated For 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-122229\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Class-11-Solutions-Chapter-8-Exercise-8.1.jpg\" alt=\"RD Sharma Class 11 Solutions Chapter 8 Exercise 8.1\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Class-11-Solutions-Chapter-8-Exercise-8.1.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Class-11-Solutions-Chapter-8-Exercise-8.1-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p>RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1: As per the current CBSE Syllabus <a href=\"https:\/\/www.kopykitab.com\/blog\/cbse-class-11-maths-rd-sharma-solutions\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 11 Maths<\/a> are originally designed.\u00a0 It is advised to prepare for your Class 11 Maths exams with the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-8-transformation-formulae\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 11 Maths Chapter 8<\/a> Exercise 8.1. Subject matter experts have designed easy-to-understand solutions just for your benefit.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e767483dda4\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: 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Maths Chapter 8 Exercise 8.1 PDF:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-8-exercise-8-1\/#access-answers-of-rd-sharma-solutions-class-11-maths-chapter-8-exercise-81\" title=\"Access answers of RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1\">Access answers of RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-8-exercise-8-1\/#faqs-on-rd-sharma-solutions-class-11-maths-chapter-8-exercise-81\" title=\"FAQs on RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1\">FAQs on RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-8-exercise-8-1\/#how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-solutions-for-class-11-maths-chapter-8-exercise-81\" title=\"How much does it cost to download the PDF of RD Sharma Solutions for Class 11 Maths Chapter 8 Exercise 8.1?\">How much does it cost to download the PDF of RD Sharma Solutions for Class 11 Maths Chapter 8 Exercise 8.1?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-8-exercise-8-1\/#how-many-questions-are-there-in-rd-sharma-solutions-for-class-11-maths-chapter-8-exercise-81\" title=\"How many questions are there in RD Sharma Solutions for Class 11 Maths Chapter 8 Exercise 8.1?\">How many questions are there in RD Sharma Solutions for Class 11 Maths Chapter 8 Exercise 8.1?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-8-exercise-8-1\/#from-where-can-i-download-the-pdf-of-rd-sharma-solutions-for-class-11-maths-chapter-8-exercise-81\" title=\"From where can I download the PDF of RD Sharma Solutions for Class 11 Maths Chapter 8 Exercise 8.1?\">From where can I download the PDF of RD Sharma Solutions for Class 11 Maths Chapter 8 Exercise 8.1?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-solutions-class-11-maths-chapter-8-exercise-81-pdf\"><\/span>Download RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1 PDF:<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p style=\"text-align: justify;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/rd-8.1.pdf\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 11 Solutions Chapter 8 Exercise 8.1<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/rd-8.1.pdf\",\"#example1\");<\/script><\/p>\n<h2><span class=\"ez-toc-section\" id=\"access-answers-of-rd-sharma-solutions-class-11-maths-chapter-8-exercise-81\"><\/span>Access answers of RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<article id=\"post-52866\" class=\"post-52866 page type-page status-publish hentry\">\n<p><strong>1. Express each of the following as the sum or difference of sines and cosines:<br \/>(i) 2 sin 3x cos x<br \/>(ii) 2 cos 3x sin 2x<br \/>(iii) 2 sin 4x sin 3x<br \/>(iv) 2 cos 7x cos 3x<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>(i)<\/strong>\u00a02 sin 3x cos x<\/p>\n<p>By using the formula,<\/p>\n<p>2 sin A cos B = sin (A + B) + sin (A \u2013 B)<\/p>\n<p>2 sin 3x cos x = sin (3x + x) + sin (3x \u2013 x)<\/p>\n<p>= sin (4x) + sin (2x)<\/p>\n<p>= sin 4x + sin 2x<\/p>\n<p><br \/><strong>(ii)<\/strong>\u00a02 cos 3x sin 2x<\/p>\n<p>By using the formula,<\/p>\n<p>2 cos A sin B = sin (A + B) \u2013 sin (A \u2013 B)<\/p>\n<p>2 cos 3x sin 2x = sin (3x + 2x) \u2013 sin (3x \u2013 2x)<\/p>\n<p>= sin (5x) \u2013 sin (x)<\/p>\n<p>= sin 5x \u2013 sin x<\/p>\n<p><br \/><strong>(iii)<\/strong>\u00a02 sin 4x sin 3x<\/p>\n<p>By using the formula,<\/p>\n<p>2 sin A sin B = cos (A \u2013 B) \u2013 cos (A + B)<\/p>\n<p>2 sin 4x sin 3x = cos (4x \u2013 3x) \u2013 cos (4x + 3x)<\/p>\n<p>= cos (x) \u2013 cos (7x)<\/p>\n<p>= cos x \u2013 cos 7x<\/p>\n<p><br \/><strong>(iv)<\/strong>\u00a02 cos 7x cos 3x<\/p>\n<p>By using the formula,<\/p>\n<p>2 cos A cos B = cos (A + B) + cos (A \u2013 B)<\/p>\n<p>2 sin 3x cos x = cos (7x + 3x) + cos (7x \u2013 3x)<\/p>\n<p>= cos (10x) + cos (4x)<\/p>\n<p>= cos 10x + cos 4x<\/p>\n<p><strong>2.<\/strong>\u00a0<strong>Prove that:<br \/>(i) 2 sin 5\u03c0\/12 sin \u03c0\/12 = 1\/2<\/strong><\/p>\n<p><strong>(ii) 2 cos 5\u03c0\/12 cos \u03c0\/12 = 1\/2<\/strong><\/p>\n<p><strong>(iii) 2 sin 5\u03c0\/12 cos \u03c0\/12 = (\u221a3 + 2)\/2<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>(i)\u00a0<\/strong>2 sin 5\u03c0\/12 sin \u03c0\/12 = 1\/2<\/p>\n<p>By using the formula,<\/p>\n<p>2 sin A sin B = cos (A \u2013 B) \u2013 cos (A + B)<\/p>\n<p>2 sin 5\u03c0\/12 sin \u03c0\/12 = cos (5\u03c0\/12 \u2013 \u03c0\/12) \u2013 cos (5\u03c0\/12 + \u03c0\/12)<\/p>\n<p>= cos (4\u03c0\/12) \u2013 cos (6\u03c0\/12)<\/p>\n<p>= cos (\u03c0\/3) \u2013 cos (\u03c0\/2)<\/p>\n<p>= cos (180<sup>o<\/sup>\/3) \u2013 cos (180<sup>o<\/sup>\/2)<\/p>\n<p>= cos 60\u00b0 \u2013 cos 90\u00b0<\/p>\n<p>= 1\/2 \u2013 0<\/p>\n<p>= 1\/2<\/p>\n<p>Hence Proved.<\/p>\n<p><strong>(ii)\u00a0<\/strong>2 cos 5\u03c0\/12 cos \u03c0\/12 = 1\/2<\/p>\n<p>By using the formula,<\/p>\n<p>2 cos A cos B = cos (A + B) + cos (A \u2013 B)<\/p>\n<p>2 cos 5\u03c0\/12 cos \u03c0\/12 = cos (5\u03c0\/12 + \u03c0\/12) + cos (5\u03c0\/12 \u2013 \u03c0\/12)<\/p>\n<p>= cos (6\u03c0\/12) + cos (4\u03c0\/12)<\/p>\n<p>= cos (\u03c0\/2) + cos (\u03c0\/3)<\/p>\n<p>= cos (180<sup>o<\/sup>\/2) + cos (180<sup>o<\/sup>\/3)<\/p>\n<p>= cos 90\u00b0 + cos 60\u00b0<\/p>\n<p>= 0 + 1\/2<\/p>\n<p>= 1\/2<\/p>\n<p>Hence Proved.<\/p>\n<p><strong>(iii)\u00a0<\/strong>2 sin 5\u03c0\/12 cos \u03c0\/12 = (\u221a3 + 2)\/2<\/p>\n<p>By using the formula,<\/p>\n<p>2 sin A cos B = sin (A + B) + sin (A \u2013 B)<\/p>\n<p>2 sin 5\u03c0\/12 cos \u03c0\/12 = sin (5\u03c0\/12 + \u03c0\/12) + sin (5\u03c0\/12 \u2013 \u03c0\/12)<\/p>\n<p>= sin (6\u03c0\/12) + sin (4\u03c0\/12)<\/p>\n<p>= sin (\u03c0\/2) + sin (\u03c0\/3)<\/p>\n<p>= sin (180<sup>o<\/sup>\/2) + sin (180<sup>o<\/sup>\/3)<\/p>\n<p>= sin 90\u00b0 + sin 60\u00b0<\/p>\n<p>= 1 + \u221a3<\/p>\n<p>= (2 + \u221a3)\/2<\/p>\n<p>= (\u221a3 + 2)\/2<\/p>\n<p>Hence Proved.<\/p>\n<p><strong>3. show that:<\/strong><\/p>\n<p><strong>(i) sin 50<sup>o<\/sup>\u00a0cos 85<sup>o<\/sup>\u00a0= (1 \u2013 \u221a2sin 35<sup>o<\/sup>)\/2\u221a2<\/strong><\/p>\n<p><strong>(ii) sin 25<sup>o<\/sup>\u00a0cos 115<sup>o<\/sup>\u00a0= 1\/2 {sin 140<sup>o<\/sup>\u00a0\u2013 1}<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>(i)\u00a0<\/strong>sin 50<sup>o<\/sup>\u00a0cos 85<sup>o<\/sup>\u00a0= (1 \u2013 \u221a2sin 35<sup>o<\/sup>)\/2\u221a2<\/p>\n<p>By using the formula,<\/p>\n<p>2 sin A cos B = sin (A + B) + sin (A \u2013 B)<\/p>\n<p>sin A cos B = [sin (A + B) + sin (A \u2013 B)] \/ 2<\/p>\n<p>sin 50<sup>o<\/sup>\u00a0cos 85<sup>o<\/sup>\u00a0= [sin(50<sup>o<\/sup>\u00a0+ 85<sup>o<\/sup>) + sin (50<sup>o<\/sup>\u00a0\u2013 85<sup>o<\/sup>)] \/ 2<\/p>\n<p>= [sin (135<sup>o<\/sup>) + sin (-35<sup>o<\/sup>)] \/ 2<\/p>\n<p>= [sin (135<sup>o<\/sup>) \u2013 sin (35<sup>o<\/sup>)] \/ 2 (since, sin (-x) = -sin x)<\/p>\n<p>= [sin (180<sup>o<\/sup>\u00a0\u2013 45<sup>o<\/sup>) \u2013 sin 35<sup>o<\/sup>] \/ 2<\/p>\n<p>= [sin 45<sup>o<\/sup>\u00a0\u2013 sin 35<sup>o<\/sup>] \/ 2<\/p>\n<p>= [(1\/\u221a2) \u2013 sin 35<sup>o<\/sup>] \/ 2<\/p>\n<p>= [(1 \u2013 sin 35<sup>o<\/sup>)\/<strong>\u221a<\/strong>2] \/ 2<\/p>\n<p>= (1 \u2013 sin 35<sup>o<\/sup>) \/ 2<strong>\u221a<\/strong>2<\/p>\n<p>Hence proved.<\/p>\n<p><strong>(ii)\u00a0<\/strong>sin 25<sup>o<\/sup>\u00a0cos 115<sup>o<\/sup>\u00a0= 1\/2 {sin 140<sup>o<\/sup>\u00a0\u2013 1}<\/p>\n<p>By using the formula,<\/p>\n<p>2 sin A cos B = sin (A + B) + sin (A \u2013 B)<\/p>\n<p>sin A cos B = [sin (A + B) + sin (A \u2013 B)] \/ 2<\/p>\n<p>sin 20<sup>o<\/sup>\u00a0cos 115<sup>o<\/sup>\u00a0= [sin(25<sup>o<\/sup>\u00a0+ 115<sup>o<\/sup>) + sin (25<sup>o<\/sup>\u00a0\u2013 115<sup>o<\/sup>)] \/ 2<\/p>\n<p>= [sin (140<sup>o<\/sup>) + sin (-90<sup>o<\/sup>)] \/ 2<\/p>\n<p>= [sin (140<sup>o<\/sup>) \u2013 sin (90<sup>o<\/sup>)] \/ 2 (since, sin (-x) = -sin x)<\/p>\n<p>= 1\/2 {sin 140<sup>o<\/sup>\u00a0\u2013 1}<\/p>\n<p>Hence proved.<\/p>\n<p><strong>4. Prove that:<\/strong><\/p>\n<p><strong>4 cos x cos (\u03c0\/3 + x) cos (\u03c0\/3 \u2013 x) = cos 3x<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Let us consider LHS:<\/p>\n<p>4 cos x cos (\u03c0\/3 + x) cos (\u03c0\/3 \u2013 x) = 2 cos x (2 cos (\u03c0\/3 + x) cos (\u03c0\/3 \u2013 x))<\/p>\n<p>By using the formula,<\/p>\n<p>2 cos A cos B = cos (A + B) + cos (A \u2013 B)<\/p>\n<p>2 cos x (2 cos (\u03c0\/3+x) cos (\u03c0\/3 \u2013 x)) = 2 cos x (cos (\u03c0\/3+x + \u03c0\/3-x) + cos (\u03c0\/3+x \u2013 \u03c0\/3+ x))<br \/><br \/>= 2 cos x (cos (2\u03c0\/3) + cos (2x))<\/p>\n<p>= 2 cos x {cos 120\u00b0 + cos 2x}<\/p>\n<p>= 2 cos x {cos (180\u00b0 \u2013 60\u00b0) + cos 2x}<\/p>\n<p>= 2 cos x (cos 2x \u2013 cos 60\u00b0) (since, {cos (180\u00b0 \u2013 A) = \u2013 cos A})<\/p>\n<p>= 2 cos 2x cos x \u2013 2 cos x cos 60\u00b0<\/p>\n<p>= (cos (x + 2x) + cos (2x \u2013 x)) \u2013 (2cos x)\/2<\/p>\n<p>= cos 3x + cos x \u2013 cos x<\/p>\n<p>= cos 3x<\/p>\n<p>= RHS<\/p>\n<p>Hence Proved.<\/p>\n<\/article>\n<p>To Know more about the <a href=\"https:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a>\u00a0Class 11 Maths exam, ask in the comments.\u00a0<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-solutions-class-11-maths-chapter-8-exercise-81\"><\/span>FAQs on RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1630433834877\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-solutions-for-class-11-maths-chapter-8-exercise-81\"><\/span>How much does it cost to download the PDF of RD Sharma Solutions for Class 11 Maths Chapter 8 Exercise 8.1?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download it for free.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630434738621\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-many-questions-are-there-in-rd-sharma-solutions-for-class-11-maths-chapter-8-exercise-81\"><\/span>How many questions are there in RD Sharma Solutions for Class 11 Maths Chapter 8 Exercise 8.1?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>There are 8 questions in\u00a0RD Sharma Solutions for Class 11 Maths Chapter 8 Exercise 8.1.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630434765084\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"from-where-can-i-download-the-pdf-of-rd-sharma-solutions-for-class-11-maths-chapter-8-exercise-81\"><\/span>From where can I download the PDF of RD Sharma Solutions for Class 11 Maths Chapter 8 Exercise 8.1?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can find the download link from the above blog.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1: As per the current CBSE Syllabus RD Sharma Solutions Class 11 Maths are originally designed.\u00a0 It is advised to prepare for your Class 11 Maths exams with the RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1. Subject matter experts have designed easy-to-understand solutions &#8230; <a title=\"RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1 (Updated For 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-8-exercise-8-1\/\" aria-label=\"More on RD Sharma Solutions Class 11 Maths Chapter 8 Exercise 8.1 (Updated For 2024)\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":122229,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2917,73397,73717,73411,2985,73410],"tags":[3428,73334,73564],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/67928"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=67928"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/67928\/revisions"}],"predecessor-version":[{"id":501532,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/67928\/revisions\/501532"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/122229"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=67928"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=67928"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=67928"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}