{"id":67281,"date":"2023-04-05T06:42:00","date_gmt":"2023-04-05T01:12:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=67281"},"modified":"2023-12-26T11:45:27","modified_gmt":"2023-12-26T06:15:27","slug":"rs-aggarwal-chapter-11-class-9-maths-exercise-11-1-solutions","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-chapter-11-class-9-maths-exercise-11-1-solutions\/","title":{"rendered":"RS Aggarwal Chapter 11 Class 9 Maths Exercises 11.1 (ex 11a) Solutions"},"content":{"rendered":"\n<p>RS Aggarwal Chapter 11 Class 9 Maths Exercise 11.1 Solutions: You have studied many properties of a triangle in Chapters 6 and 7 and you know that on joining three non-collinear points in pairs, the figure so obtained is a triangle. Now, let us mark four points and see what we obtain by joining them in pairs in some order. Although most of the objects we see around are of the shape of a special quadrilateral called a rectangle, we shall study more about quadrilaterals and especially parallelograms because a rectangle is also a parallelogram and all properties of a parallelogram are true for a rectangle as well. Know more on the Chapter <a href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-solutions-class-9-maths-chapter-10-quadrilaterals\/\">here<\/a>.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69d16c8f11742\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69d16c8f11742\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-chapter-11-class-9-maths-exercise-11-1-solutions\/#download-rs-aggarwal-chapter-11-class-9-maths-exercise-111-solutions\" title=\"Download RS Aggarwal Chapter 11 Class 9 Maths Exercise 11.1 Solutions\">Download RS Aggarwal Chapter 11 Class 9 Maths Exercise 11.1 Solutions<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-chapter-11-class-9-maths-exercise-11-1-solutions\/#important-definition-for-rs-aggarwal-chapter-11-class-9-maths-ex-11a-solutions\" title=\"Important Definition for RS Aggarwal Chapter 11 Class 9\u00a0Maths Ex 11a\u00a0Solutions\">Important Definition for RS Aggarwal Chapter 11 Class 9\u00a0Maths Ex 11a\u00a0Solutions<\/a><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rs-aggarwal-chapter-11-class-9-maths-exercise-111-solutions\"><\/span>Download RS Aggarwal Chapter 11 Class 9 Maths Exercise 11.1 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/EXERCISE-10A.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/EXERCISE-10A.pdf\">EXERCISE 10A<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definition-for-rs-aggarwal-chapter-11-class-9-maths-ex-11a-solutions\"><\/span>Important Definition for RS Aggarwal Chapter 11 Class 9\u00a0Maths Ex 11a\u00a0Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>A parallelogram is a type of quadrilateral that contains parallel opposite sides.<\/p>\n<ol>\n<li>Area of parallelogram = Base \u00d7 Height<\/li>\n<li>Area of Triangle =\u00a0(1\/2)\u00d7 Base \u00d7 Height<\/li>\n<\/ol>\n<p>Know more at the <a href=\"https:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener\">official website<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>RS Aggarwal Chapter 11 Class 9 Maths Exercise 11.1 Solutions: You have studied many properties of a triangle in Chapters 6 and 7 and you know that on joining three non-collinear points in pairs, the figure so obtained is a triangle. Now, let us mark four points and see what we obtain by joining them &#8230; <a title=\"RS Aggarwal Chapter 11 Class 9 Maths Exercises 11.1 (ex 11a) Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rs-aggarwal-chapter-11-class-9-maths-exercise-11-1-solutions\/\" aria-label=\"More on RS Aggarwal Chapter 11 Class 9 Maths Exercises 11.1 (ex 11a) Solutions\">Read more<\/a><\/p>\n","protected":false},"author":236,"featured_media":67388,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[1,73395,73412,2985,73410],"tags":[3081,3086,4711],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/67281"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/236"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=67281"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/67281\/revisions"}],"predecessor-version":[{"id":526644,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/67281\/revisions\/526644"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/67388"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=67281"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=67281"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=67281"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}