{"id":66782,"date":"2023-09-13T13:04:00","date_gmt":"2023-09-13T07:34:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=66782"},"modified":"2023-09-14T20:26:45","modified_gmt":"2023-09-14T14:56:45","slug":"rd-sharma-chapter-15-class-10-maths-exercise-15-5-solutions","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-10-maths-exercise-15-5-solutions\/","title":{"rendered":"RD Sharma Chapter 15 Class 10 Maths Exercise 15.5 Solutions"},"content":{"rendered":"\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-maths-solutions-chapter-14-statistics\/\">RD Sharma Chapter 15<\/a> Class 10 Maths Exercise 15.5 Solutions is a comprehensive collection of answers to questions based on statistical concepts. This chapter first introduces you to statistical terms such as grouped and ungrouped data, frequency and class intervals. Our solutions for RD Sharma Class 10 Maths Solutions for Chapter 15 help you dig deeper into the concepts of mean, median, and mode to provide the best solution to the problems related to them.<\/p>\n<p>RD Sharma Chapter 15 Class 10 Maths Exercise 15.5 Solutions: Here you will get a total of 9 questions, all of which require you to calculate the mode for a given data set. Additionally, some questions also ask you to find the mean and median of a given data set.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69d5683819be8\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69d5683819be8\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-10-maths-exercise-15-5-solutions\/#download-rd-sharma-chapter-15-class-10-maths-exercise-155-solutions\" title=\"Download RD Sharma Chapter 15 Class 10 Maths Exercise 15.5 Solutions\">Download RD Sharma Chapter 15 Class 10 Maths Exercise 15.5 Solutions<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-10-maths-exercise-15-5-solutions\/#important-definition-for-rd-sharma-chapter-15-class-10-maths-exercise-155-solutions\" title=\"Important Definition for RD Sharma&nbsp;Chapter 15 Class 10 Maths Exercise 15.5 Solutions\">Important Definition for RD Sharma&nbsp;Chapter 15 Class 10 Maths Exercise 15.5 Solutions<\/a><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-15-class-10-maths-exercise-155-solutions\"><\/span>Download RD Sharma Chapter 15 Class 10 Maths Exercise 15.5 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">&nbsp;<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2020\/12\/RD-SHARMA-Solutions-Class-10-Maths-Chapter-7-Ex-7.5.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2020\/12\/RD-SHARMA-Solutions-Class-10-Maths-Chapter-7-Ex-7.5.pdf\">RD SHARMA Solutions Class 10 Maths Chapter 7 Ex 7.5<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definition-for-rd-sharma-chapter-15-class-10-maths-exercise-155-solutions\"><\/span>Important Definition for RD Sharma&nbsp;Chapter 15 Class 10 Maths Exercise 15.5 Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li><b><\/b><strong><b>Mean of Grouped Data<\/b><\/strong><\/li>\n<\/ul>\n<p>Here you learn the method of calculating the mean for grouped data with and without class interval, using the direct method, assumed mean method, and step-deviation method which are represented below.<\/p>\n<ul>\n<li>the direct method, mean = \u2211fixi \/ \u2211fi<\/li>\n<li>(ii) the assumed mean method, mean = a + (\u2211fi<em><i>d<\/i><\/em>i&nbsp;\/ \u2211fi)<\/li>\n<li>(iii) the step deviation method, mean = a + [(\u2211fi<em><i>u<\/i><\/em>i&nbsp;\/ \u2211fi)&nbsp;\u00d7&nbsp;<em><i>h<\/i><\/em>]<\/li>\n<\/ul>\n<p>All these are based on the assumption that the frequency of a class is centred at its mid-point, called its class mark.<\/p>\n<ul>\n<li><b><\/b><strong><b>Mode of Grouped Data<\/b><\/strong><\/li>\n<\/ul>\n<p>Here you learn the methods of calculating the median from a set of grouped data with and without class intervals, cumulative frequency, types of cumulative frequency distribution, and the most interesting, graphical representation of median.<\/p>\n<p>The mode for grouped data can be determined by using the formula \u2013<\/p>\n<p>Mode =&nbsp;<em><i>l<\/i><\/em>&nbsp;+ [(<em><i>f<\/i><\/em><em><i>1<\/i><\/em>&nbsp;\u2013<em><i>f<\/i><\/em><em><i>0<\/i><\/em>) \/ 2<em><i>f<\/i><\/em><em><i>1<\/i><\/em>&nbsp;\u2013&nbsp;<em><i>f<\/i><\/em><em><i>0<\/i><\/em>&nbsp;\u2013<em><i>f<\/i><\/em><em><i>2<\/i><\/em><em><i>) \u00d7&nbsp;h]<\/i><\/em><\/p>\n<p>The cumulative frequency of a class is the frequency obtained by adding the frequencies of all the classes preceding the given class.<\/p>\n<ul>\n<li><b><\/b><strong><b>Median of Grouped Data<\/b><\/strong><\/li>\n<\/ul>\n<p>Here you learn the ways of calculating mode from a set of grouped and ungrouped data, finding mode without class intervals, representing mode graphically, and calculating central tendency.<\/p>\n<p>The median for grouped data is formed by using the formula \u2013&nbsp;Median =&nbsp;<em><i>l<\/i><\/em>&nbsp;+ [(<em><i>n<\/i><\/em>\/2 \u2013&nbsp;<em><i>cf<\/i><\/em>) \/&nbsp;<em><i>f<\/i><\/em>] \u00d7&nbsp;h<\/p>\n<p>Know more at the <a href=\"https:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener\">official website<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>RD Sharma Chapter 15 Class 10 Maths Exercise 15.5 Solutions is a comprehensive collection of answers to questions based on statistical concepts. This chapter first introduces you to statistical terms such as grouped and ungrouped data, frequency and class intervals. Our solutions for RD Sharma Class 10 Maths Solutions for Chapter 15 help you dig &#8230; <a title=\"RD Sharma Chapter 15 Class 10 Maths Exercise 15.5 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-15-class-10-maths-exercise-15-5-solutions\/\" aria-label=\"More on RD Sharma Chapter 15 Class 10 Maths Exercise 15.5 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":236,"featured_media":66910,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,2917,73396,73718,73411,73410],"tags":[3243,9206,73520],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/66782"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/236"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=66782"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/66782\/revisions"}],"predecessor-version":[{"id":70384,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/66782\/revisions\/70384"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/66910"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=66782"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=66782"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=66782"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}