{"id":66751,"date":"2023-09-07T12:55:00","date_gmt":"2023-09-07T07:25:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=66751"},"modified":"2023-11-03T14:25:13","modified_gmt":"2023-11-03T08:55:13","slug":"rd-sharma-chapter-10-class-10-maths-exercise-10-1-solution","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-10-maths-exercise-10-1-solution\/","title":{"rendered":"RD Sharma Chapter 10 Class 10 Maths Exercise 10.1 Solutions"},"content":{"rendered":"\n<p>RD Sharma Chapter 10 Class 10 Maths Exercise 10.1 Solution- Trigonometric Ratios were designed to help you prepare well for the CBSE Class 10 board exam. These solutions cover all aspects of trigonometric ratios based on the relationship between the sides and angles of a triangle. Trigonometry is used to measure the height and length of objects and the greater distance that would be difficult to measure with common instruments. This chapter mentions that the ratio of the acute angles of a right triangle to its sides is known as the trigonometric ratio of the angles.<\/p>\n<p>RD Sharma Chapter 10 Class 10 Maths Exercise 10.1 Solution: There are 36 questions in this exercise. Question 1 asks to determine the value of trigonometric ratio for a triangle when another ratio is given. Questions 2 and 6 ask to determine the value of a trigonometric ratio when measurements of the sides of a triangle are given. Question 3 asks to prove the equality of trigonometric ratios for triangles. Question 3 through 5 and 7 through 36 ask you to find the values \u200b\u200bof trigonometric ratios using the equation drawn with the corresponding trigonometric terms.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e9069e8bc6b\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e9069e8bc6b\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-10-maths-exercise-10-1-solution\/#download-rd-sharma-chapter-10-class-10-maths-exercise-101-solution\" title=\"Download RD Sharma Chapter 10 Class 10 Maths Exercise 10.1 Solution\">Download RD Sharma Chapter 10 Class 10 Maths Exercise 10.1 Solution<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-10-maths-exercise-10-1-solution\/#important-definition-for-rd-sharma-chapter-10-class-10-maths-exercise-101-solutions\" title=\"Important Definition for RD Sharma\u00a0Chapter 10 Class 10 Maths Exercise 10.1\u00a0Solutions\">Important Definition for RD Sharma\u00a0Chapter 10 Class 10 Maths Exercise 10.1\u00a0Solutions<\/a><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-chapter-10-class-10-maths-exercise-101-solution\"><\/span>Download RD Sharma Chapter 10 Class 10 Maths Exercise 10.1 Solution<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2020\/12\/RD-SHARMA-Solutions-Class-10-Maths-Chapter-5-Ex-5.1.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2020\/12\/RD-SHARMA-Solutions-Class-10-Maths-Chapter-5-Ex-5.1.pdf\">RD SHARMA Solutions Class 10 Maths Chapter 5 Ex 5.1<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-definition-for-rd-sharma-chapter-10-class-10-maths-exercise-101-solutions\"><\/span>Important Definition for RD Sharma\u00a0Chapter 10 Class 10 Maths Exercise 10.1\u00a0Solutions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li><b><\/b><strong><b>Trigonometric Ratios<\/b><\/strong><\/li>\n<\/ul>\n<p>This chapter teaches you that the Trigonometric Ratios of an acute angle in a right-angle triangle mention the relationship among the angle and the length of its sides. Imagine a triangle ABC right angled at B, the ratios are defined with respect to either of the acute angle \u2018A\u2019 or \u2018C\u2019. The angle may be called as \u2018\u03b8\u2019.<\/p>\n<p>The 6 Trigonometric Ratios with respect to the sides of a chosen angle A are given as \u2013<\/p>\n<p>sin A = side opposite to angle A\/ hypotenuse\u00a0<\/p>\n<p>cos A = side next to to angle\/ hypotenuse<\/p>\n<p>tan A = side opposite to angle A\/side adjacent to angle A.<\/p>\n<p>cosec A = 1\/sin A; sec A = 1 \/ cos A; tan A = 1\/ cot A; tan A = sin A\/ cos A\u00a0<\/p>\n<p>Knowing one of the Trigonometric Ratios of an acute angle, we come to know about the remaining Trigonometric Ratios of the angle also. There is no change in values related to Trigonometric Ratios of an angle when we change the measurements of the sides of the triangle, in case the angle remains the same.\u00a0<\/p>\n<ul>\n<li><b><\/b><strong><b>Trigonometric Ratios of Some Specific Angles\u00a0<\/b><\/strong><\/li>\n<\/ul>\n<p>Here you learn to\u00a0derive the particular numerical values for Trigonometric Ratios for 0\u00b0, 30\u00b0, 45\u00b0, 60\u00b0 and 90\u00b0. You also come to know that sin A increases from 0 to 1 whereas cos A decreases from 1 to 0 when angling A increases from 0\u00b0 to 90\u00b0.\u00a0<\/p>\n<ul>\n<li><b><\/b><strong><b>Trigonometric Ratios of Complementary Angles\u00a0<\/b><\/strong><\/li>\n<\/ul>\n<p>In this section of the Chapter, you will learn that we call any two angles of complementary angles when their sum is equal to 90\u00b0. In a right-angled triangle the other two angles except for the right angle, have the sum of 90\u00b0 and hence they are complementary to each other. So in general, sin (90\u00b0 \u2013 A) = cos A, cos (90\u00b0 \u2013 A) = sin A; tan (90\u00b0 \u2013 A) = cot A, cot (90\u00b0 \u2013 A) = tan A; sec (90\u00b0 \u2013 A) = cosec A, cosec (90\u00b0 \u2013 A) = sec A; for all the values of angle A lying between.<\/p>\n<p>Know more at the <a href=\"https:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener\">official website<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>RD Sharma Chapter 10 Class 10 Maths Exercise 10.1 Solution- Trigonometric Ratios were designed to help you prepare well for the CBSE Class 10 board exam. These solutions cover all aspects of trigonometric ratios based on the relationship between the sides and angles of a triangle. Trigonometry is used to measure the height and length &#8230; <a title=\"RD Sharma Chapter 10 Class 10 Maths Exercise 10.1 Solutions\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-10-class-10-maths-exercise-10-1-solution\/\" aria-label=\"More on RD Sharma Chapter 10 Class 10 Maths Exercise 10.1 Solutions\">Read more<\/a><\/p>\n","protected":false},"author":236,"featured_media":66884,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,73396,73411,73410],"tags":[3243,9206,73520],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/66751"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/236"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=66751"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/66751\/revisions"}],"predecessor-version":[{"id":501988,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/66751\/revisions\/501988"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/66884"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=66751"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=66751"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=66751"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}