{"id":66107,"date":"2023-09-12T15:32:00","date_gmt":"2023-09-12T10:02:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=66107"},"modified":"2023-11-10T10:14:28","modified_gmt":"2023-11-10T04:44:28","slug":"rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/","title":{"rendered":"RD Sharma Class 11 Solutions Chapter 2 Relations Exercise 2.1 (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone wp-image-123776 size-full\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Class-11-Solutions-Chapter-2-Exercise-2.1.jpg\" alt=\"RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Class-11-Solutions-Chapter-2-Exercise-2.1.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/01\/RD-Sharma-Class-11-Solutions-Chapter-2-Exercise-2.1-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1:<\/strong> Is here to help you with preparing the Relation chapter with ease. To make it a much better exam session, here are exercises <a href=\"https:\/\/www.kopykitab.com\/blog\/cbse-class-11-maths-rd-sharma-solutions\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 11 Maths<\/a> Chapter 2 Exercise 2.1. Here students will get a better look at the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-relations\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 11 Maths Chapter 2<\/a> Exercise 2.1 which concentrates on sums on ordered pairs along with cartesian products of the set.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e718fe5171d\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e718fe5171d\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#download-rd-sharma-solutions-class-11-maths-chapter-2-exercise-21-pdf\" title=\"Download RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1 PDF\">Download RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1 PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#access-rd-sharma-solutions-class-11-maths-chapter-2-exercise-21\" title=\"Access RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1\">Access RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#1-i-if-a3-1-b-%e2%80%93-23-53-13-find-the-values-of-a-and-b\" title=\"(1) (i) If (a\/3 + 1, b \u2013 2\/3) = (5\/3, 1\/3), find the values of a and b.\">(1) (i) If (a\/3 + 1, b \u2013 2\/3) = (5\/3, 1\/3), find the values of a and b.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#ii-if-x-1-1-3y-y-%e2%80%93-1-find-the-values-of-x-and-y\" title=\"(ii) If (x + 1, 1) = (3y, y \u2013 1), find the values of x and y.\">(ii) If (x + 1, 1) = (3y, y \u2013 1), find the values of x and y.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#ii-if-x-1-1-3y-y-%e2%80%93-1-find-the-values-of-x-and-y-2\" title=\"(ii)\u00a0If (x + 1, 1) = (3y, y \u2013 1), find the values of x and y.\">(ii)\u00a0If (x + 1, 1) = (3y, y \u2013 1), find the values of x and y.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#2-if-the-ordered-pairs-x-%e2%80%93-1-and-5-y-belong-to-the-set-a-b-b-2a-%e2%80%93-3-find-the-values-of-x-and-y\" title=\"2. If the ordered pairs (x, \u2013 1) and (5, y) belong to the set {(a, b): b = 2a \u2013 3}, find the values of x and y.\">2. If the ordered pairs (x, \u2013 1) and (5, y) belong to the set {(a, b): b = 2a \u2013 3}, find the values of x and y.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#3-if-a-%e2%88%88-1-2-3-4-5-and-b-%e2%88%88-0-3-6-write-the-set-of-all-ordered-pairs-a-b-such-that-a-b-5\" title=\"3. If a\u00a0\u2208\u00a0{- 1, 2, 3, 4, 5} and b\u00a0\u2208\u00a0{0, 3, 6}, write the set of all ordered pairs (a, b) such that a + b = 5.\">3. If a\u00a0\u2208\u00a0{- 1, 2, 3, 4, 5} and b\u00a0\u2208\u00a0{0, 3, 6}, write the set of all ordered pairs (a, b) such that a + b = 5.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#4-if-a-%e2%88%88-2-4-6-9-and-b-%e2%88%88-4-6-18-27-then-form-the-set-of-all-ordered-pairs-a-b-such-that-a-divides-b-and-a\" title=\"4. If a\u00a0\u2208\u00a0{2, 4, 6, 9} and b\u00a0\u2208 {4, 6, 18, 27}, then form the set of all ordered pairs (a, b) such that a divides b and a&lt;b.\">4. If a\u00a0\u2208\u00a0{2, 4, 6, 9} and b\u00a0\u2208 {4, 6, 18, 27}, then form the set of all ordered pairs (a, b) such that a divides b and a&lt;b.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#5-if-a-1-2-and-b-1-3-find-a-x-b-and-b-x-a\" title=\"5. If A = {1, 2} and B = {1, 3}, find A x B and B x A.\">5. If A = {1, 2} and B = {1, 3}, find A x B and B x A.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#6-let-a-1-2-3-and-b-3-4-find-a-x-b-and-show-it-graphically\" title=\"6. Let A = {1, 2, 3} and B = {3, 4}. Find A x B and show it graphically\">6. Let A = {1, 2, 3} and B = {3, 4}. Find A x B and show it graphically<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#7-if-a-1-2-3-and-b-2-4-what-are-a-x-b-b-x-a-a-x-a-b-x-b-and-a-x-b-%e2%88%a9-b-x-a\" title=\"7. If A = {1, 2, 3} and B = {2, 4}, what are A x B, B x A, A x A, B x B, and (A x B)\u00a0\u2229\u00a0(B x A)?\">7. If A = {1, 2, 3} and B = {2, 4}, what are A x B, B x A, A x A, B x B, and (A x B)\u00a0\u2229\u00a0(B x A)?<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#faqs-on-rd-sharma-solutions-class-11-maths-chapter-2-exercise-21\" title=\"FAQs on RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1\">FAQs on RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#is-it-even-beneficial-to-study-solutions-of-rd-sharma-class-11-chapter-2-pdf-for-exercise-21\" title=\"Is it even beneficial to study solutions of RD Sharma Class 11 Chapter 2 PDF for Exercise 2.1?\">Is it even beneficial to study solutions of RD Sharma Class 11 Chapter 2 PDF for Exercise 2.1?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#can-i-access-the-rd-sharma-solutions-class-11-maths-chapter-2-exercise-21-pdf-offline\" title=\"Can I access the RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1 PDF offline?\">Can I access the RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1 PDF offline?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/#how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-solutions-class-11-maths-chapter-2-exercise-21\" title=\"How much does it cost to download the PDF of RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1?\">How much does it cost to download the PDF of RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-solutions-class-11-maths-chapter-2-exercise-21-pdf\"><\/span>Download RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1 PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/2.1.pdf\" target=\"_blank\" rel=\"noopener\"> Chapter 2 Exercise 2.1 RD Sharma Class 11 PDF Solutions<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 800px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/2.1.pdf\", \"#example1\");<\/script><\/p>\n<h2><span class=\"ez-toc-section\" id=\"access-rd-sharma-solutions-class-11-maths-chapter-2-exercise-21\"><\/span>Access RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"1-i-if-a3-1-b-%e2%80%93-23-53-13-find-the-values-of-a-and-b\"><\/span>(1) (i) If (a\/3 + 1, b \u2013 2\/3) = (5\/3, 1\/3), find the values of a and b.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<h3><span class=\"ez-toc-section\" id=\"ii-if-x-1-1-3y-y-%e2%80%93-1-find-the-values-of-x-and-y\"><\/span>(ii) If (x + 1, 1) = (3y, y \u2013 1), find the values of x and y.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Solution:<\/p>\n<p>Given:\u00a0<\/p>\n<p>(a\/3 + 1, b \u2013 2\/3) = (5\/3, 1\/3)<\/p>\n<p>By the definition of equality of ordered pairs,<\/p>\n<p>Let us solve for a and b<\/p>\n<p>a\/3 + 1 = 5\/3 and b \u2013 2\/3 = 1\/3<\/p>\n<p>a\/3 = 5\/3 \u2013 1 and b = 1\/3 + 2\/3<\/p>\n<p>a\/3 = (5-3)\/3 and b = (1+2)\/3<\/p>\n<p>a\/3 = 2\/3 and b = 3\/3<\/p>\n<p>a = 2(3)\/3 and b = 1<\/p>\n<p>a = 2 and b = 1<\/p>\n<p>\u2234 Values of a and b are, a = 2 and b = 1<\/p>\n<h3><span class=\"ez-toc-section\" id=\"ii-if-x-1-1-3y-y-%e2%80%93-1-find-the-values-of-x-and-y-2\"><\/span>(ii)\u00a0If (x + 1, 1) = (3y, y \u2013 1), find the values of x and y.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Given:<\/p>\n<p>(x + 1, 1) = (3y, y \u2013 1)<\/p>\n<p>By the definition of equality of ordered pairs,<\/p>\n<p>Let us solve for x and y<\/p>\n<p>x + 1 = 3y and\u00a01 = y \u2013 1<\/p>\n<p>x = 3y \u2013 1 and\u00a0y = 1 + 1<\/p>\n<p>x = 3y \u2013 1 and y = 2<\/p>\n<p>Since, y = 2 we can substitute in<\/p>\n<p>x = 3y \u2013 1<\/p>\n<p>= 3(2) \u2013 1<\/p>\n<p>= 6 \u2013 1<\/p>\n<p>= 5<br \/><br \/>\u2234 Values of x and y are, x = 5 and y = 2<\/p>\n<h3><span class=\"ez-toc-section\" id=\"2-if-the-ordered-pairs-x-%e2%80%93-1-and-5-y-belong-to-the-set-a-b-b-2a-%e2%80%93-3-find-the-values-of-x-and-y\"><\/span>2. If the ordered pairs (x, \u2013 1) and (5, y) belong to the set {(a, b): b = 2a \u2013 3}, find the values of x and y.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Solution:<\/p>\n<p>Given:<\/p>\n<p>The ordered pairs (x, \u2013 1) and (5, y) belong to the set {(a, b): b = 2a \u2013 3}<\/p>\n<p>Solving for first-order pair<\/p>\n<p>(x, \u2013 1) = {(a, b): b = 2a \u2013 3}<\/p>\n<p>x = a and -1 = b<\/p>\n<p>By taking b = 2a \u2013 3<\/p>\n<p>If b = \u2013 1 then 2a = \u2013 1 + 3<\/p>\n<p>= 2<\/p>\n<p>a = 2\/2<\/p>\n<p>= 1<\/p>\n<p>So, a = 1<\/p>\n<p>Since x = a, x = 1<\/p>\n<p>Similarly, solving for second-order pair<\/p>\n<p>(5, y) = {(a, b): b = 2a \u2013 3}<\/p>\n<p>5 = a and y = b<\/p>\n<p>By taking b = 2a \u2013 3<\/p>\n<p>If a = 5 then b = 2\u00d75 \u2013 3<\/p>\n<p>= 10 \u2013 3<\/p>\n<p>= 7<\/p>\n<p>So, b = 7<\/p>\n<p>Since y = b, y = 7<\/p>\n<p>\u2234 Values of x and y are, x = 1 and y = 7<\/p>\n<h3><span class=\"ez-toc-section\" id=\"3-if-a-%e2%88%88-1-2-3-4-5-and-b-%e2%88%88-0-3-6-write-the-set-of-all-ordered-pairs-a-b-such-that-a-b-5\"><\/span>3. If a\u00a0\u2208\u00a0{- 1, 2, 3, 4, 5} and b\u00a0\u2208\u00a0{0, 3, 6}, write the set of all ordered pairs (a, b) such that a + b = 5.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Solution:<\/p>\n<p>Given: a\u00a0\u2208\u00a0{- 1, 2, 3, 4, 5} and b\u00a0\u2208\u00a0{0, 3, 6},<\/p>\n<p>To find: the ordered pair (a, b) such that a + b = 5<\/p>\n<p>Then the ordered pair (a, b) such that a + b = 5 are as follows<\/p>\n<p>(a, b) \u2208\u00a0{(- 1, 6), (2, 3), (5, 0)}<\/p>\n<h3><span class=\"ez-toc-section\" id=\"4-if-a-%e2%88%88-2-4-6-9-and-b-%e2%88%88-4-6-18-27-then-form-the-set-of-all-ordered-pairs-a-b-such-that-a-divides-b-and-a\"><\/span>4. If a\u00a0\u2208\u00a0{2, 4, 6, 9} and b\u00a0\u2208 {4, 6, 18, 27}, then form the set of all ordered pairs (a, b) such that a divides b and a&lt;b.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Solution:<\/p>\n<p>Given:<\/p>\n<p>a\u00a0\u2208\u00a0{2, 4, 6, 9} and b\u00a0\u2208{4, 6, 18, 27}<\/p>\n<p>Here,<\/p>\n<p>2 divides 4, 6, 18 and is also less than all of them<\/p>\n<p>4 divides 4 and is also less than none of them<\/p>\n<p>6 divides 6, 18 and is less than 18 only<\/p>\n<p>9 divides 18, 27 and is less than all of them<\/p>\n<p>\u2234 Ordered pairs (a, b) are (2, 4), (2, 6), (2, 18), (6, 18), (9, 18) and (9, 27)<\/p>\n<h3><span class=\"ez-toc-section\" id=\"5-if-a-1-2-and-b-1-3-find-a-x-b-and-b-x-a\"><\/span>5. If A = {1, 2} and B = {1, 3}, find A x B and B x A.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Solution:<\/p>\n<p>Given:<\/p>\n<p>A = {1, 2} and B = {1, 3}<\/p>\n<p>A \u00d7 B = {1, 2} \u00d7 {1, 3}<\/p>\n<p>= {(1, 1), (1, 3), (2, 1), (2, 3)}<\/p>\n<p>B \u00d7 A = {1, 3} \u00d7 {1, 2}<\/p>\n<p>= {(1, 1), (1, 2), (3, 1), (3, 2)}<\/p>\n<h3><span class=\"ez-toc-section\" id=\"6-let-a-1-2-3-and-b-3-4-find-a-x-b-and-show-it-graphically\"><\/span>6. Let A = {1, 2, 3} and B = {3, 4}. Find A x B and show it graphically<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Solution:<\/p>\n<p>Given:<\/p>\n<p>A = {1, 2, 3} and B = {3, 4}<\/p>\n<p>A x B = {1, 2, 3} \u00d7 {3, 4}<\/p>\n<p>= {(1, 3), (1, 4), (2, 3), (2, 4), (3, 3), (3, 4)}<\/p>\n<p><br \/>Steps to follow to represent A \u00d7 B graphically,<\/p>\n<p>Step 1: One horizontal and one vertical axis should be drawn<\/p>\n<p>Step 2: Element of set A should be represented in a horizontal axis and on vertical axis elements of set B should be represented<\/p>\n<p>Step 3: Draw dotted lines perpendicular to horizontal and vertical axes through the elements of set A and B<\/p>\n<p>Step 4: Point of intersection of these perpendicular represents A \u00d7 B<\/p>\n<p><img title=\"RD Sharma Solutions for Class 11 Maths Chapter 2 \u2013 Relations image- 1\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2020\/01\/rd-sharma-solutions-for-class-11-maths-chapter-2.png\" alt=\"RD Sharma Solutions for Class 11 Maths Chapter 2 \u2013 Relations image- 1\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"7-if-a-1-2-3-and-b-2-4-what-are-a-x-b-b-x-a-a-x-a-b-x-b-and-a-x-b-%e2%88%a9-b-x-a\"><\/span>7. If A = {1, 2, 3} and B = {2, 4}, what are A x B, B x A, A x A, B x B, and (A x B)\u00a0\u2229\u00a0(B x A)?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Solution:<\/p>\n<p>Given:<\/p>\n<p>A = {1, 2, 3} and B = {2, 4}<\/p>\n<p>Now let us find: A \u00d7 B, B \u00d7 A, A \u00d7 A, (A \u00d7 B)\u00a0\u2229\u00a0(B\u00a0\u00d7\u00a0A)<\/p>\n<p>A \u00d7 B = {1, 2, 3} \u00d7 {2, 4}<\/p>\n<p>= {(1, 2), (1, 4), (2, 2), (2, 4), (3, 2), (3, 4)}<\/p>\n<p><br \/>B \u00d7 A = {2, 4} \u00d7 {1, 2, 3}<\/p>\n<p>= {(2, 1), (2, 2), (2, 3), (4, 1), (4, 2), (4, 3)}<\/p>\n<p><br \/>A \u00d7 A = {1, 2, 3} \u00d7 {1, 2, 3}<\/p>\n<p>= {(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3)}<\/p>\n<p><br \/>B \u00d7 B = {2, 4} \u00d7 {2, 4}<\/p>\n<p>= {(2, 2), (2, 4), (4, 2), (4, 4)}<\/p>\n<p>The intersection of two sets represents common elements of both the sets<\/p>\n<p>So,<\/p>\n<p>(A \u00d7 B)\u00a0\u2229\u00a0(B\u00a0\u00d7\u00a0A) = {(2, 2)}<\/p>\n<p>Well, everything from EX 2.1 <a href=\"https:\/\/rdsharmasolution.com\/\" target=\"_blank\" rel=\"noopener\">RD Sharma<\/a> Solutions <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 11 Maths Chapter 2 is chalked down here. Take advantage of the situation and start with a fresh mind for a thorough look at the exercise-wise solutions. Hope you find our study material effective for your maths exam.\u00a0<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-solutions-class-11-maths-chapter-2-exercise-21\"><\/span>FAQs on RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1630428328840\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-it-even-beneficial-to-study-solutions-of-rd-sharma-class-11-chapter-2-pdf-for-exercise-21\"><\/span><strong>Is it even beneficial to study solutions of RD Sharma Class 11 Chapter 2 PDF for Exercise 2.1?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, your preparation will be strengthened with this amazing help book. All your questions will be answered by this book.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630428345194\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-access-the-rd-sharma-solutions-class-11-maths-chapter-2-exercise-21-pdf-offline\"><\/span><strong>Can I access the RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1 PDF offline?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Once you have downloaded the PDF online, you can access it offline as well.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630428359447\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-solutions-class-11-maths-chapter-2-exercise-21\"><\/span><strong>How much does it cost to download the PDF of RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download it for free<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1: Is here to help you with preparing the Relation chapter with ease. To make it a much better exam session, here are exercises RD Sharma Solutions Class 11 Maths Chapter 2 Exercise 2.1. Here students will get a better look at the RD Sharma Solutions &#8230; <a title=\"RD Sharma Class 11 Solutions Chapter 2 Relations Exercise 2.1 (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-11-maths-chapter-2-exercise-2-1\/\" aria-label=\"More on RD Sharma Class 11 Solutions Chapter 2 Relations Exercise 2.1 (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":249,"featured_media":123776,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411],"tags":[3217,3428,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/66107"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/249"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=66107"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/66107\/revisions"}],"predecessor-version":[{"id":505670,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/66107\/revisions\/505670"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/123776"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=66107"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=66107"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=66107"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}