{"id":64029,"date":"2023-04-05T01:00:00","date_gmt":"2023-04-04T19:30:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=64029"},"modified":"2023-12-01T10:31:06","modified_gmt":"2023-12-01T05:01:06","slug":"rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/","title":{"rendered":"RD Sharma Solutions Class 9 Maths Chapter 24 &#8211; Measure of Central Tendency (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-124736\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Solutions-Class-9-Maths-Chapter-24-Measures-Of-Central-Tendency.png\" alt=\"RD Sharma Solutions Class 9 Maths Chapter 24\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Solutions-Class-9-Maths-Chapter-24-Measures-Of-Central-Tendency.png 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Solutions-Class-9-Maths-Chapter-24-Measures-Of-Central-Tendency-768x432.png 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Solutions Class 9 Maths Chapter 24 &#8211;<\/strong> RD Sharma Solutions Class 9 Maths Chapter 24 has a very high weightage in your maths exams and the student needs to understand the concepts of this unit in detail. <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Maths<\/a> Chapter 24 focuses on the calculation of mean, median, and mode of the data by using both traditional and formula methods. To know more, read the whole blog.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e84edae3236\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e84edae3236\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#download-rd-sharma-solutions-class-9-maths-chapter-24-pdf\" title=\"Download RD Sharma Solutions Class 9 Maths Chapter 24 PDF\">Download RD Sharma Solutions Class 9 Maths Chapter 24 PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#exercise-wise-rd-sharma-solutions-class-9-maths-chapter-24-pdf\" title=\"Exercise-wise RD Sharma Solutions Class 9 Maths Chapter 24 PDF\">Exercise-wise RD Sharma Solutions Class 9 Maths Chapter 24 PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#acces-answers-of-rd-sharma-solutions-class-9-maths-chapter-24\" title=\"Acces answers of RD Sharma Solutions Class 9 Maths Chapter 24\">Acces answers of RD Sharma Solutions Class 9 Maths Chapter 24<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#exercise-241-page-no-249\" title=\"Exercise 24.1 Page No: 24.9\">Exercise 24.1 Page No: 24.9<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#exercise-242-page-no-2414\" title=\"Exercise 24.2 Page No: 24.14\">Exercise 24.2 Page No: 24.14<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#exercise-243-page-no-2418\" title=\"Exercise 24.3 Page No: 24.18\">Exercise 24.3 Page No: 24.18<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#exercise-244-page-no-2420\" title=\"Exercise 24.4 Page No: 24.20\">Exercise 24.4 Page No: 24.20<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#exercise-vsaqs-page-no-2421\" title=\"Exercise VSAQs Page No: 24.21\">Exercise VSAQs Page No: 24.21<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#detailed-exercise-wise-explanation-with-listing-of-important-topics-in-the-exercise\" title=\"Detailed Exercise-wise Explanation with Listing of Important Topics in the Exercise\">Detailed Exercise-wise Explanation with Listing of Important Topics in the Exercise<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#rd-sharma-solutions-class-9-maths-chapter-24-ex-241\" title=\"RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.1\">RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#rd-sharma-solutions-class-9-maths-chapter-24-ex-242\" title=\"RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.2\">RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#rd-sharma-solutions-class-9-maths-chapter-24-ex-243\" title=\"RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.3\">RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.3<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#rd-sharma-solutions-class-9-maths-chapter-24-ex-244\" title=\"RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.4\">RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#important-topics-from-rd-sharma-solutions-class-9-maths-chapter-24\" title=\"Important Topics From RD Sharma Solutions Class 9 Maths Chapter 24\">Important Topics From RD Sharma Solutions Class 9 Maths Chapter 24<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#rd-sharma-solutions-for-class-9-maths-chapter-24\" title=\"RD Sharma Solutions for Class 9 Maths Chapter 24\">RD Sharma Solutions for Class 9 Maths Chapter 24<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-solutions-for-class-9-maths-chapter-24\" title=\"How much does it cost to download the PDF of RD Sharma Solutions for Class 9 Maths Chapter 24?\">How much does it cost to download the PDF of RD Sharma Solutions for Class 9 Maths Chapter 24?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-17\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#from-where-can-i-download-the-pdf-of-rd-sharma-solutions-class-9-maths-chapter-24\" title=\"From where can I download the PDF of RD Sharma Solutions Class 9 Maths Chapter 24?\">From where can I download the PDF of RD Sharma Solutions Class 9 Maths Chapter 24?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-18\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/#can-i-access-the-rd-sharma-solutions-for-class-9-maths-chapter-24-pdf-offline\" title=\"Can I access the RD Sharma Solutions for Class 9 Maths Chapter 24\u00a0PDF offline?\">Can I access the RD Sharma Solutions for Class 9 Maths Chapter 24\u00a0PDF offline?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-solutions-class-9-maths-chapter-24-pdf\"><\/span><strong>Download RD Sharma Solutions Class 9 Maths Chapter 24 PDF<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/24-1.pdf\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 24<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">&nbsp;<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/24-1.pdf\", \"#example1\");<\/script><\/p>\n<h2><span class=\"ez-toc-section\" id=\"exercise-wise-rd-sharma-solutions-class-9-maths-chapter-24-pdf\"><\/span><strong>Exercise-wise RD Sharma Solutions Class 9 Maths Chapter 24 PDF<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 100%;\">\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-24-class-9-maths-exercise-24-1-solutions\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 9 Maths Chapter 24 Exercise 24.1<\/a><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-24-class-9-maths-exercise-24-2-solutions\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 9 Maths Chapter 24 Exercise 24.2<\/a><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-24-class-9-maths-exercise-24-3-solutions\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 9 Maths Chapter 24 Exercise 24.3<\/a><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-24-class-9-maths-exercise-24-4-solutions\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 9 Maths Chapter 24 Exercise 24.4<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2><span class=\"ez-toc-section\" id=\"acces-answers-of-rd-sharma-solutions-class-9-maths-chapter-24\"><\/span><strong>Acces answers of RD Sharma Solutions Class 9 Maths Chapter 24<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"exercise-241-page-no-249\"><\/span>Exercise 24.1 Page No: 24.9<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Question 1: If the heights of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm respectively. Find the mean height.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>The heights of 5 persons are 140 cm , 150 cm , 152 cm , 158 cm and 161 cm (Given)<\/p>\n<p>Mean height = (Sum of heights) \/ (Total number of persons)<\/p>\n<p>Sum of heights = 140 + 150 + 152 + 158 + 161 = 761<\/p>\n<p>Total number of persons = 5<\/p>\n<p>So, Mean height = 761\/5 =152.2<\/p>\n<p><strong>Question 2: Find the mean of 994 , 996 , 998 , 1002 , 1000.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Sum of numbers = 994+996+998+1000+100 = 4990<\/p>\n<p>Total counts = 5<\/p>\n<p>Therefore, Mean = (Sum of numbers)\/(Total Counts)<\/p>\n<p>= 4990\/5<\/p>\n<p>= 998<\/p>\n<p>Mean = 998<\/p>\n<p><strong>Question 3: Find the mean of first five natural numbers.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>First five natural numbers are 1 , 2 , 3 , 4 , 5.<\/p>\n<p>Sum of all the numbers = 1+2+3+4+5 = 15<\/p>\n<p>Total Numbers = 5<\/p>\n<p>Therefore, Mean = (Sum of numbers)\/(Total Numbers)<\/p>\n<p>= 15\/5<\/p>\n<p>= 3<\/p>\n<p>Mean = 3<\/p>\n<p><strong>Question 4: Find the mean of all factors of 10.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Factors of 10 are 1, 2, 5, 10.<\/p>\n<p>Sum of all the factors = 1+2+5+10 = 18<\/p>\n<p>Total Numbers = 4<\/p>\n<p>Therefore, Mean = (Sum of factors)\/(Total Numbers)<\/p>\n<p>= 18\/4<\/p>\n<p>= 4.5<\/p>\n<p>Mean = 4.5<\/p>\n<p><strong>Question 5: Find the mean of first 10 even natural numbers.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>First 10 even natural numbers = 2 , 4 , 6 , 8 , 10 , 12 , 14 , 16 , 18 , 20<\/p>\n<p>Sum of numbers = 2+4+6+8+10+12+14+16+18+20 = 110<\/p>\n<p>Total Numbers = 10<\/p>\n<p>Now,<\/p>\n<p>Mean = (Sum of numbers) \/ (Total Numbers)<\/p>\n<p>= 110\/10<\/p>\n<p>Mean = 11<\/p>\n<p><strong>Question 6: Find the mean of x , x + 2 , x + 4 , x + 6 , x + 8.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given numbers are x , x + 2 , x + 4 , x + 6 , x + 8.<\/p>\n<p>Sum of numbers = x+(x+2) + (x+4) + (x+6) + (x+8) = 5x+20<\/p>\n<p>Total Numbers = 5<\/p>\n<p>Now,<\/p>\n<p>Mean = (Sum of numbers) \/ (Total Numbers)<\/p>\n<p>= (5x+20)\/5<\/p>\n<p>= 5(x + 4)\/5<\/p>\n<p>= x + 4<\/p>\n<p>Mean = x + 4<\/p>\n<p><strong>Question 7: Find the mean of first five multiples of 3.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>First five multiples of 3 are 3 , 6 , 9 , 12 , 15.<\/p>\n<p>Sum of numbers = 3+6+9+12+15 = 45<\/p>\n<p>Total Numbers = 5<\/p>\n<p>Now,<\/p>\n<p>Mean = (Sum of numbers) \/ (Total Numbers)<\/p>\n<p>= 45\/5<\/p>\n<p>=9<\/p>\n<p>Mean = 9<\/p>\n<p><strong>Question 8: Following are the weights (in kg) of 10 new born babies in a hospital on a particular day: 3.4 , 3 .6 , 4.2 , 4.5 , 3.9 , 4.1 , 3.8 , 4.5 , 4.4 , 3.6. Find the mean.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>The weights of 10 new born babies (in kg): 3.4 , 3 .6 , 4.2 , 4.5 , 3.9 , 4.1 , 3.8 , 4.5 , 4.4 , 3.6<\/p>\n<p>Sum of weights = 3.4+3.6+4.2+4.5+3.9+4.1+3.8+4.5+4.4+3.6 = 40<\/p>\n<p>Total number of babies = 10<\/p>\n<p>No, Mean = (Sum of weights) \/ (Total number of babies)<\/p>\n<p>= 40\/10<\/p>\n<p>= 4<\/p>\n<p>Mean weight = 4 kg<\/p>\n<p><strong>Question 9: The percentage marks obtained by students of a class in mathematics are :<br>64 , 36 , 47 , 23 , 0 , 19 , 81 , 93 , 72 , 35 , 3 , 1. Find their mean.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>The percentage marks obtained by students: 64 , 36 , 47 , 23 , 0 , 19 , 81 , 93 , 72 , 35 , 3 , 1<\/p>\n<p>Sum of marks = 64+36+47+23+0+19+81+93+72+35+3+1 = 474<\/p>\n<p>Total students = 12<\/p>\n<p>Now, Mean marks = (Sum of marks ) \/ (Total students )<\/p>\n<p>=474\/12<\/p>\n<p>= 39.5<\/p>\n<p>Mean Marks = 39.5<\/p>\n<p><strong>Question 10: The numbers of children in 10 families of a locality are:<\/strong><\/p>\n<p><strong>2 , 4 , 3 , 4 , 2 , 3 , 5 , 1 , 1 , 5. Find the number of children per family.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>The numbers of children in 10 families: 2 , 4 , 3 , 4 , 2 , 3 , 5 , 1 , 1 , 5<\/p>\n<p>Total number of children = 2+4+3+4+2+3+5+1+1+5 = 30<\/p>\n<p>Total Families = 10<\/p>\n<p>Number of children per family = Mean = (Total number of children) \/ (Total Families) = 30\/10<\/p>\n<p>= 3<\/p>\n<p>Therefore, Number of children per family is 3.<\/p>\n<hr>\n<h3><span class=\"ez-toc-section\" id=\"exercise-242-page-no-2414\"><\/span>Exercise 24.2 Page No: 24.14<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Question 1: Calculate the mean for the following distribution:<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 1\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 1\"><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 1 soln\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-1.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 1 soln\"><\/p>\n<p>Formula to calculate mean:<\/p>\n<p><img title=\"Mean formula\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/mean-formula.png\" alt=\"Mean formula\"><\/p>\n<p>= 281\/40<\/p>\n<p>= 7.025<\/p>\n<p>\u21d2 Mean for the given distribution is 7.025.<\/p>\n<p><strong>Question 2: Find the mean of the following data:<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 2\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-2.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 2\"><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 2 soln\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-3.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 2 soln\"><\/strong><\/p>\n<p>Formula to calculate mean:<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 2 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-4.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 2 solution\"><\/p>\n<p>= 2650\/106<\/p>\n<p>= 25<\/p>\n<p>\u21d2 Mean for the given data is 25.<\/p>\n<p><strong>Question 3: The mean of the following data is 20.6 .Find the value of p.<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 3\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-5.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 3\"><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 3 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-6.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 3 solution\"><\/p>\n<p>Formula to calculate mean:<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 3 soln\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-7.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 3 soln\"><\/p>\n<p>= (25p + 530)\/50<\/p>\n<p>Mean = 20.6 (Given)<\/p>\n<p>So,<\/p>\n<p>20.6 = (25p + 530)\/50<\/p>\n<p>25p + 530 = 1030<\/p>\n<p>25p = 1030 \u2212 530 = 500<\/p>\n<p>or p = 20<\/p>\n<p>\u21d2 The value of p is 20.<\/p>\n<p><strong>Question 4: If the mean of the following data is 15, find p.<\/strong><\/p>\n<p><strong><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 4\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-8.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 4\"><\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 4 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-9.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 4 solution\"><\/strong><\/p>\n<p>Formula to calculate mean:<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 4 soln\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-10.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 4 soln\"><\/p>\n<p>= (10p + 445)\/(p + 27)<\/p>\n<p>Mean = 15 (Given)<\/p>\n<p>So, (10p + 445)\/(p + 27) = 15<\/p>\n<p>10p + 445 = 15(p + 27)<\/p>\n<p>10p \u2013 15p = 405 \u2013 445 = -40<\/p>\n<p>-5p = -40<\/p>\n<p>or p = 8<\/p>\n<p>\u21d2 The value of p is 8.<\/p>\n<p><strong>Question 5: Find the value of p for the following distribution whose mean is 16.6.<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 5\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-11.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 5\"><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 5 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-12.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 5 solution\"><\/p>\n<p>Formula to calculate mean:<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 5 soln\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-13.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 5 soln\"><\/p>\n<p>= (24p + 1228)\/100<\/p>\n<p>Mean = 16.6 (given)<\/p>\n<p>So, (24p + 1228)\/100 = 16.6<\/p>\n<p>24p + 1228 = 1660<\/p>\n<p>24p = 1660 \u2013 1228 = 432<\/p>\n<p>p = 432\/24 = 18<\/p>\n<p>\u21d2 The value of p is 18.<\/p>\n<p><strong>Question 6: Find the missing value of p for the following distribution whose mean is 12.58.<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 6\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-14.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 6\"><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 6 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-15.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 6 solution\"><\/p>\n<p>Formula to calculate mean:<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 6 soln\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-16.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 6 soln\"><\/p>\n<p>= (7p + 524)\/50<\/p>\n<p>Mean = 12.58 (given)<\/p>\n<p>So, (7p + 524)\/50 = 12.58<\/p>\n<p>7p + 524 = 12.58 x 50<\/p>\n<p>7p + 524 = 629<\/p>\n<p>7p = 629 \u2013 524 = 105<\/p>\n<p>p = 105\/7 = 15<\/p>\n<p>\u21d2 The value of p is 15.<\/p>\n<p><strong>Question 7: Find the missing frequency (p) for the following distribution whose mean is 7.68.<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 7\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-17.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 7\"><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 7 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-18.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 7 solution\"><\/p>\n<p>Formula to calculate mean:<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.2 question 7 soln\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-2-questio-19.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.2 question 7 soln\"><\/p>\n<p>= (9p + 303)\/(p+41)<\/p>\n<p>Mean = 7.68 (given)<\/p>\n<p>So, (9p + 303)\/(p+41) = 7.68<\/p>\n<p>9p + 303 = 7.68 (p + 41)<\/p>\n<p>9p + 303 = 7.68p + 314.88<\/p>\n<p>9p \u2212 7.68p = 314.88 \u2212 303<\/p>\n<p>1.32p = 11.88<\/p>\n<p>or p = (11.881)\/(1.32) = 9<\/p>\n<p>\u21d2 The value of p is 9.<\/p>\n<hr>\n<h3><span class=\"ez-toc-section\" id=\"exercise-243-page-no-2418\"><\/span>Exercise 24.3 Page No: 24.18<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Question 1:&nbsp;<\/strong><strong>Find the median of the following data:<\/strong><\/p>\n<p><strong>83 , 37 , 70 , 29 , 45 , 63 , 41 , 70 , 34 , 54<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Arranging given numbers in ascending order:<\/p>\n<p>29 , 34 , 37 , 41 , 45 , 54 , 63 , 70 , 70 , 83<\/p>\n<p>Here, Total number of terms = n = 10 (even)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.3 question 1\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-3-questio.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.3 question 1\"><\/p>\n<p><strong>Question 2: Find the median of the following data:<\/strong><\/p>\n<p><strong>133 , 73 , 89 , 108 , 94 , 104 , 94 , 85 , 100 , 120<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Arranging given numbers in ascending order:<\/p>\n<p>73 , 85 , 89 ,94 , 94 , 100 , 104 , 108 , 120 , 133<\/p>\n<p>Here, total number of terms = n = 10 (even)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.3 question 2\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-3-questio-1.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.3 question 2\"><\/p>\n<p><strong>Question 3: Find the median of the following data:<\/strong><\/p>\n<p><strong>31 , 38 , 27 , 28 , 36 , 25 , 35 , 40<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Arranging given numbers in ascending order<\/p>\n<p>25 , 27 , 28 , 31 , 35 , 36 , 38 , 40<\/p>\n<p>Here, total number of terms = n = 8 (even)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.3 question 3\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-3-questio-2.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.3 question 3\"><\/p>\n<p><strong>Question 4: Find the median of the following data:<\/strong><\/p>\n<p>15 , 6 , 16 , 8 , 22 , 21 , 9 , 18 , 25<\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Arranging given numbers in ascending order<\/p>\n<p>6 , 8 , 9 , 15 , 16 , 18, 21 , 22 , 25<\/p>\n<p>Here, total number of terms = n = 9 (odd)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.3 question 4\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-3-questio-3.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.3 question 4\"><\/p>\n<p><strong>Question 5: Find the median of the following data:<\/strong><\/p>\n<p><strong>41 , 43 , 127 , 99 , 71 , 92 , 71 , 58 , 57<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Arranging given numbers in ascending order<\/p>\n<p>41 , 43 , 57 , 58 , 71 , 71 , 92 , 99 , 127<\/p>\n<p>Here, total number of terms = n = 9 (odd)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.3 question 5\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-3-questio-4.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.3 question 5\"><\/p>\n<p><strong>Question 6: Find the median of the following data:<\/strong><\/p>\n<p><strong>25 , 34 , 31 , 23 , 22 , 26 , 35 , 29 , 20 , 32<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Arranging given numbers in ascending order<\/p>\n<p>20 , 22 , 23 , 25 , 26 , 29 , 31 , 32 , 34 , 35<\/p>\n<p>Here, total number of terms = n = 10 (even)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.3 question 6\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-3-questio-5.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.3 question 6\"><\/p>\n<p><strong>Question 7: Find the median of the following data:<\/strong><\/p>\n<p><strong>12 , 17 , 3 , 14 , 5 , 8 , 7 , 15<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Arranging given numbers in ascending order<\/p>\n<p>3 , 5 , 7 , 8 , 12 , 14 , 15 , 17<\/p>\n<p>Here, total number of terms = n = 8(even)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.3 question 7\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-3-questio-6.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.3 question 7\"><\/p>\n<p><strong>Question 8: Find the median of the following data:<\/strong><\/p>\n<p><strong>92 , 35 , 67 , 85 , 72 , 81 , 56 , 51 , 42 , 69<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Arranging given numbers in ascending order<\/p>\n<p>35 , 42 , 51 , 56 , 67 , 69 , 72 , 81 , 85 , 92<\/p>\n<p>Here, total number of terms = n = 10(even)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.3 question 8\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-3-questio-7.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.3 question 8\"><\/p>\n<hr>\n<h3><span class=\"ez-toc-section\" id=\"exercise-244-page-no-2420\"><\/span>Exercise 24.4 Page No: 24.20<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Question 1: Find out the mode of the following marks obtained by 15 students in a class:<\/strong><\/p>\n<p><strong>Marks : 4 , 6 , 5 , 7 , 9 , 8 , 10 , 4 , 7 , 6 , 5 , 9 , 8 , 7 , 7.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Mode is the value which occurs most frequently in a set of observations.<\/p>\n<p>Frequency of given set of observations are:<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.4 question 1\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-4-questio.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.4 question 1\"><\/p>\n<p>Here, we can see that 7 occurred most frequently.<\/p>\n<p>So, Mode = 7<\/p>\n<p><strong>Question 2: Find out the mode from the following data :<\/strong><\/p>\n<p><strong>125 , 175 , 225 , 125 , 225 , 175 , 325 , 125 , 375 , 225 , 125<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Find the frequency of given set of observations:<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.4 question 2 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-4-questio-1.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.4 question 2 solution\"><\/p>\n<p>125 occurred for 4 times than any other values.<\/p>\n<p>So, Mode = 125<\/p>\n<p><strong>Question 3: Find the mode for the following series:<\/strong><\/p>\n<p><strong>7.5 , 7.3 , 7.2 , 7.2 , 7.4 , 7.7 , 7.7 , 7.5 , 7.3 , 7.2 , 7.6 , 7.2<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Find the frequency:<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 24 ex 24.4 question 3\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-24-ex-24-4-questio-2.png\" alt=\"RD sharma class 9 maths chapter 24 ex 24.4 question 3 solution\"><\/p>\n<p>Maximum frequency 4 corresponds to the value 7.2.<\/p>\n<p>So, mode = 7.2<\/p>\n<hr>\n<h3><span class=\"ez-toc-section\" id=\"exercise-vsaqs-page-no-2421\"><\/span>Exercise VSAQs Page No: 24.21<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Question 1: If the ratio of mean and median of a certain data is 2:3, then find the ratio of its mode and mean.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Empirical formula: Mode = 3 median \u2013 2 mean<\/p>\n<p>Since, ratio of mean and median of a certain data is 2:3, then mean = 2x and median = 3x<\/p>\n<p>Mode = 3(3x) \u2013 2(2x)<\/p>\n<p>= 9x \u2013 4x<\/p>\n<p>= 5x<\/p>\n<p>Therefore,<\/p>\n<p>Mode: Mean = 5x:2x or 5: 2<\/p>\n<p><strong>Question 2: If the ratio of mode and median of a certain data is 6 : 5, then find the ratio of its mean and median.<\/strong><\/p>\n<p><strong>Solution:<\/strong>&nbsp;We know, Empirical formula: Mode = 3 Median \u2013 2 Mean<\/p>\n<p>Since, ratio of mode and median of a certain data is 6:5.<\/p>\n<p>\u21d2 Mode\/Median = 6\/5<\/p>\n<p>or Mode = (6 Median)\/5<\/p>\n<p>Now,<\/p>\n<p>(6 Median)\/5 = 3 Median \u2013 2 Mean<\/p>\n<p>(6 Median)\/5 \u2013 3 Median = \u2013 2 Mean<\/p>\n<p>or 9\/10 (Median) = Mean<\/p>\n<p>or Mean\/ Median = 9\/10 or 9:10.<\/p>\n<p><strong>Question 3: If the mean of x+2, 2x+3, 3x+4, 4x+5 is x+2, find x.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given: Mean of x+2, 2x+3, 3x+4, 4x+5 is x+2<\/p>\n<p>We know, Mean = (Sum of all the observations) \/ (Total number of observations)<\/p>\n<p>Sum of all the observations = x+2 + 2x+3 + 3x+4 + 4x+5 = 10x + 14<\/p>\n<p>Total number of observations = 4<\/p>\n<p>\u21d2 Mean = (10x + 14)\/4<\/p>\n<p>or (x + 2) = (10x + 14)\/4 (using given)<\/p>\n<p>4x + 8 = 10x + 14<\/p>\n<p>x = -1<\/p>\n<p><strong>Question 4: The arithmetic mean and mode of a data are 24 and 12 respectively, then find the median of the data.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given: The arithmetic mean and mode of a data are 24 and 12 respectively<\/p>\n<p>We know, Empirical formula: Mode = 3 Median \u2013 2 Mean<\/p>\n<p>or 3 Median = Mode + 2 Mean<\/p>\n<p>Using given values, we get<\/p>\n<p>3 Median = 12 + 2(24) = 60<\/p>\n<p>or Median = 20<\/p>\n<p><strong>Question 5: If the difference of mode and median of a data is 24, then find the difference of median and mean.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given: difference of mode and median of a data is 24.<\/p>\n<p>That is, Mode \u2013 Median = 24<\/p>\n<p>or Mode = 24 + Median \u2026(1)<\/p>\n<p>We know, Empirical formula: Mode = 3 Median \u2013 2 Mean<\/p>\n<p>24 + Median = 3 Median \u2013 2 Mean<\/p>\n<p>(Using (1))<\/p>\n<p>24 = 2 Median \u2013 2 Mean<\/p>\n<p>or 12 = Median \u2013 Mean<\/p>\n<p>Therefore, the difference of median and mean is 12.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"detailed-exercise-wise-explanation-with-listing-of-important-topics-in-the-exercise\"><\/span><strong>Detailed Exercise-wise Explanation with Listing of Important Topics in the Exercise<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Before understanding the detailed explanation for the exercise, we should understand some basic terms-<\/p>\n<ol>\n<li>Mean- It is the method of calculating the average of all the numbers present in the data.<\/li>\n<li>Median- The middle number of an ascended or descended series is called a median.<\/li>\n<li>Mode- The number that repeats the most times in a series is called the mode of the series.<\/li>\n<\/ol>\n<h3><span class=\"ez-toc-section\" id=\"rd-sharma-solutions-class-9-maths-chapter-24-ex-241\"><\/span>RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.1<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>This exercise contains 10 questions that talk about calculating the mean by using the average method. It is not a very complex exercise but the student should know the concept well to avoid any mistakes in their maths examination.<\/p>\n<p>RD Sharma solution PDF contains answers in a very detailed manner so that a student can understand the concept very well. It is a high-quality study material, which includes a step-wise method for answering questions and the student can incorporate the same pattern in their maths examination.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"rd-sharma-solutions-class-9-maths-chapter-24-ex-242\"><\/span>RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.2<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>There are a total of 7 questions in this exercise which also focuses on calculating mean but by using a formula. The data given is in a tabular form that contains frequency and to handle such types of questions you need to use a mean formula. The formula is a little complex but the student can easily learn through regular practice.<\/p>\n<p>RD Sharma Solutions Class 9 Maths Chapter 24 PDF will provide a stepwise answer so that you can easily understand the concept very well. These types of questions contain high weightage in the maths exams so every student needs to be extra careful while solving this exercise.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"rd-sharma-solutions-class-9-maths-chapter-24-ex-243\"><\/span>RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.3<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The following exercise contains 8 questions which are based on the calculation of Median. The students have to calculate the median by using the formula method and there are two formulas one is- if the total number in the series is even then the other one will be used if they are odd.<\/p>\n<p>RD Sharma solutions class 9-chapter 24 24.2 will help you in solving all the questions accurately. Our pdf is made following the latest CBSE pattern so that you easily use the methods and steps we use in your maths exams or while doing homework.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"rd-sharma-solutions-class-9-maths-chapter-24-ex-244\"><\/span>RD Sharma Solutions Class 9 Maths Chapter 24 Ex 24.4<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>&nbsp;There are a total of 3 questions in this exercise that are dedicated to calculating the mode of the series. It is an easy exercise and can be solved by a student who has thoroughly learned all the concepts of mode.<\/p>\n<p>The pdf solution of RD Sharma class 9 chapter 23 will give an insight on how to solve these types of questions and we also mention tips and tricks so that you can solve the questions more efficiently.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"important-topics-from-rd-sharma-solutions-class-9-maths-chapter-24\"><\/span>Important Topics From RD Sharma Solutions Class 9 Maths Chapter 24<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Before solving the questions of this unit, you need to know all the important topics that will help you score high grades in your maths exam.<\/p>\n<p>Here, is the list of all the topics that you should study before solving this chapter-<\/p>\n<ul>\n<li>Calculation of mean and its formulas<\/li>\n<li>Calculation of mode and its formulas<\/li>\n<li>Calculation of mode and its formulas<\/li>\n<\/ul>\n<p>his is the complete blog on RD Sharma Solutions Class 9 Maths Chapter 24. To know more about the <a href=\"https:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 9 Maths exams, ask in the comments.&nbsp;<\/p>\n<h2><span class=\"ez-toc-section\" id=\"rd-sharma-solutions-for-class-9-maths-chapter-24\"><\/span>RD Sharma Solutions for Class 9 Maths Chapter 24<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1630915702253\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-solutions-for-class-9-maths-chapter-24\"><\/span>How much does it cost to download the PDF of RD Sharma Solutions for Class 9 Maths Chapter 24?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download it for free.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630915748192\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"from-where-can-i-download-the-pdf-of-rd-sharma-solutions-class-9-maths-chapter-24\"><\/span>From where can I download the PDF of RD Sharma Solutions Class 9 Maths Chapter 24?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can find the download link from the above blog.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630915768872\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-access-the-rd-sharma-solutions-for-class-9-maths-chapter-24-pdf-offline\"><\/span>Can I access the RD Sharma Solutions for Class 9 Maths Chapter 24\u00a0PDF offline?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Once you have downloaded the PDF online, you can access it offline as well.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Solutions Class 9 Maths Chapter 24 &#8211; RD Sharma Solutions Class 9 Maths Chapter 24 has a very high weightage in your maths exams and the student needs to understand the concepts of this unit in detail. RD Sharma Class 9 Maths Chapter 24 focuses on the calculation of mean, median, and mode &#8230; <a title=\"RD Sharma Solutions Class 9 Maths Chapter 24 &#8211; Measure of Central Tendency (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-24-measure-of-central-tendency\/\" aria-label=\"More on RD Sharma Solutions Class 9 Maths Chapter 24 &#8211; Measure of Central Tendency (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":124736,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411,2985,73410],"tags":[3081,3086,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/64029"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=64029"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/64029\/revisions"}],"predecessor-version":[{"id":515121,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/64029\/revisions\/515121"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/124736"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=64029"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=64029"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=64029"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}