{"id":63713,"date":"2023-09-09T13:15:00","date_gmt":"2023-09-09T07:45:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=63713"},"modified":"2023-12-12T11:29:50","modified_gmt":"2023-12-12T05:59:50","slug":"rd-sharma-solution-class-9-maths-chapter-25-probability","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solution-class-9-maths-chapter-25-probability\/","title":{"rendered":"RD Sharma Solution Class 9 Maths Chapter 25 &#8211; Probability (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-124762\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Solutions-Class-9-Maths-Chapter-25-Probability.png\" alt=\"RD Sharma Solution Class 9 Maths Chapter 25\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Solutions-Class-9-Maths-Chapter-25-Probability.png 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Solutions-Class-9-Maths-Chapter-25-Probability-768x432.png 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><span style=\"font-weight: 400;\"><strong>RD Sharma Solution Class 9 Maths Chapter 25 &#8211; Probability:<\/strong> RD Sharma Solution Class 9 Maths Chapter 25 is one of the student\u2019s favorite chapters as it does not require those heavy calculations and you can easily understand its concept with proper guidance. But, it doesn&#8217;t make the chapter less important, this unit will ask the most scoring questions in your mathematics exams. To know more about the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solution Class 9 Maths<\/a> Chapter 25, read the whole blog.<\/span><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e77753eb6b2\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e77753eb6b2\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solution-class-9-maths-chapter-25-probability\/#download-rd-sharma-solutions-class-9-maths-chapter-25-pdf\" title=\"Download RD Sharma Solutions Class 9 Maths Chapter 25 PDF\">Download RD Sharma Solutions Class 9 Maths Chapter 25 PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solution-class-9-maths-chapter-25-probability\/#exercise-wise-rd-sharma-solutions-class-9-maths-chapter-25-%e2%80%93-probability\" title=\"Exercise-wise RD Sharma solutions class 9 Maths Chapter 25 &#8211; Probability\">Exercise-wise RD Sharma solutions class 9 Maths Chapter 25 &#8211; Probability<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solution-class-9-maths-chapter-25-probability\/#access-answers-of-rd-sharma-solutions-class-9-maths-chapter-25\" title=\"Access answers of RD Sharma Solutions Class 9 Maths Chapter 25\">Access answers of RD Sharma Solutions Class 9 Maths Chapter 25<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solution-class-9-maths-chapter-25-probability\/#important-topics-%e2%80%93-rd-sharma-solution-class-9-maths-chapter-25\" title=\"Important Topics &#8211; RD Sharma Solution Class 9 Maths Chapter 25\">Important Topics &#8211; RD Sharma Solution Class 9 Maths Chapter 25<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solution-class-9-maths-chapter-25-probability\/#faqs-on-rd-sharma-solution-class-9-maths-chapter-25-probability\" title=\"FAQs on RD Sharma Solution Class 9 Maths Chapter 25 Probability\">FAQs on RD Sharma Solution Class 9 Maths Chapter 25 Probability<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solution-class-9-maths-chapter-25-probability\/#can-i-access-the-rd-sharma-solutions-for-class-9-maths-chapter-25-pdf-offline\" title=\"Can I access the RD Sharma Solutions for Class 9 Maths Chapter 25\u00a0PDF offline?\">Can I access the RD Sharma Solutions for Class 9 Maths Chapter 25\u00a0PDF offline?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solution-class-9-maths-chapter-25-probability\/#how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-solutions-for-class-9-maths-chapter-25\" title=\"How much does it cost to download the PDF of RD Sharma Solutions for Class 9 Maths Chapter 25?\">How much does it cost to download the PDF of RD Sharma Solutions for Class 9 Maths Chapter 25?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solution-class-9-maths-chapter-25-probability\/#from-where-can-i-download-the-pdf-of-rd-sharma-solutions-class-9-maths-chapter-25\" title=\"From where can I download the PDF of RD Sharma Solutions Class 9 Maths Chapter 25?\">From where can I download the PDF of RD Sharma Solutions Class 9 Maths Chapter 25?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-solutions-class-9-maths-chapter-25-pdf\"><\/span><strong>Download RD Sharma Solutions Class 9 Maths Chapter 25 PDF<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p style=\"text-align: justify;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/25-1.pdf\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 25<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">&nbsp;<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/25-1.pdf\", \"#example1\");<\/script><\/p>\n<h2><span class=\"ez-toc-section\" id=\"exercise-wise-rd-sharma-solutions-class-9-maths-chapter-25-%e2%80%93-probability\"><\/span><strong>Exercise-wise RD Sharma solutions class 9 Maths Chapter 25 &#8211; Probability<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 100%;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-chapter-25-class-9-maths-exercise-25-1-solutions\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 9 Maths Chapter 25 Exercise 25.1<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2><span class=\"ez-toc-section\" id=\"access-answers-of-rd-sharma-solutions-class-9-maths-chapter-25\"><\/span><strong>Access answers of RD Sharma Solutions Class 9 Maths Chapter 25<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><b><u>Exercise 25.1 Page No: 25.13<\/u><\/b><\/p>\n<p><strong>Question 1: A coin is tossed 1000 times in the following sequence:<\/strong><\/p>\n<p><strong>Head: 455, Tail: 545<\/strong><\/p>\n<p><strong>Compute the probability of each event.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>The coin is tossed 1000 times, which means, the number of trials is 1000.<\/p>\n<p>Let us consider, the event of getting head and the event of getting tail to be E and F respectively.<\/p>\n<p>Number of favorable outcomes = Number of trials in which the E happens = 455<\/p>\n<p>So, Probability of E = (Number of favorable outcomes) \/ (Total number of trials)<\/p>\n<p>P(E) = 455\/1000 = 0.455<\/p>\n<p>Similarly,<\/p>\n<p>Number of favorable outcomes = Number of trials in which the F happens = 545<\/p>\n<p>Probability of the event getting a tail, P(F) = 545\/1000 = 0.545<\/p>\n<p><strong>Question 2: Two coins are tossed simultaneously 500 times with the following frequencies of different outcomes:<\/strong><\/p>\n<p><strong>Two heads: 95 times<\/strong><\/p>\n<p><strong>One tail: 290 times<\/strong><\/p>\n<p><strong>No head: 115 times<\/strong><\/p>\n<p><strong>Find the probability of occurrence of each of these events.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>We know that, Probability of any event = (Number of favorable outcomes) \/ (Total number of trials)<\/p>\n<p>Total number of trials = 95 + 290 + 115 = 500<\/p>\n<p>Now,<\/p>\n<p>P(Getting two heads) = 95\/500 = 0.19<\/p>\n<p>P(Getting one tail) = 290\/500 = 0.58<\/p>\n<p>P(Getting no head) = 115\/500 = 0.23<\/p>\n<p><strong>Question 3: Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes:<\/strong><\/p>\n<table class=\"table table-bordered\">\n<tbody>\n<tr>\n<td><strong>Outcome<\/strong><\/td>\n<td><strong>No head<\/strong><\/td>\n<td><strong>One head<\/strong><\/td>\n<td><strong>Two heads<\/strong><\/td>\n<td><strong>Three heads<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>Frequency<\/strong><\/td>\n<td><strong>14<\/strong><\/td>\n<td><strong>38<\/strong><\/td>\n<td><strong>36<\/strong><\/td>\n<td><strong>12<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><strong>If the three coins are simultaneously tossed again, compute the probability of:<\/strong><\/p>\n<p><strong>(i) 2 heads coming up<\/strong><\/p>\n<p><strong>(ii) 3 heads coming up<\/strong><\/p>\n<p><strong>(iii) At least one head coming up<\/strong><\/p>\n<p><strong>(iv) Getting more heads than tails<\/strong><\/p>\n<p><strong>(v) Getting more tails than heads<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>We know, Probability of an event = (Number of Favorable outcomes) \/ (Total Number of outcomes)<\/p>\n<p>In this case, the total number of outcomes = 100.<\/p>\n<p><strong>(i)<\/strong>&nbsp;Probability of 2 Heads coming up = 36\/100 = 0.36<\/p>\n<p><strong>(ii)<\/strong>&nbsp;Probability of 3 Heads coming up = 12\/100 = 0.12<\/p>\n<p><strong>(iii)<\/strong>&nbsp;Probability of at least one head coming up = (38+36+12) \/ 100 = 86\/100 = 0.86<\/p>\n<p><strong>(iv)<\/strong>&nbsp;Probability of getting more Heads than Tails = (36+12)\/100 = 48\/100 = 0.48<\/p>\n<p><strong>(v)<\/strong>&nbsp;Probability of getting more tails than heads = (14+38) \/ 100 = 52\/100 = 0.52<\/p>\n<p><strong>Question 4: 1500 families with 2 children were selected randomly, and the following data were recorded:<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 25 ex 25.1 Question 4\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-25-ex-25-1-questio.png\" alt=\"RD sharma class 9 maths chapter 25 ex 25.1 Question 4\"><\/p>\n<p><strong>If a family is chosen at random, compute the probability that it has:<\/strong><\/p>\n<p><strong>(i) No girl (ii) 1 girl (iii) 2 girls (iv) At most one girl (v) More girls than boys<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>We know, Probability of an event = (Number of Favorable outcomes) \/ (Total Number of outcomes)<\/p>\n<p>In this case, the total number of outcomes = 211 + 814 + 475 = 1500.<\/p>\n<p>(Here, total numbers of outcomes = total number of families)<\/p>\n<p><strong>(i)<\/strong>&nbsp;Probability of having no girl = 211\/1500 = 0.1406<\/p>\n<p><strong>(ii)<\/strong>&nbsp;Probability of having 1 girl = 814\/1500 = 0.5426<\/p>\n<p><strong>(iii)<\/strong>&nbsp;Probability of having 2 girls = 475\/1500 = 0.3166<\/p>\n<p><strong>(iv)<\/strong>&nbsp;Probability of having at the most one girl = (211+814) \/1500 = 1025\/1500 = 0.6833<\/p>\n<p><strong>(v)<\/strong>&nbsp;Probability of having more girls than boys = 475\/1500 = 0.31<\/p>\n<p><strong>Question 5: In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. Find the probability that on a ball played:<\/strong><\/p>\n<p><strong>(i) He hits a boundary (ii) He does not hit a boundary.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Total number of balls played by a player = 30<\/p>\n<p>Number of times he hits a boundary = 6<\/p>\n<p>Number of times he does not hit a boundary = 30 \u2013 6 = 24<\/p>\n<p>We know, Probability of an event = (Number of Favorable outcomes) \/ (Total Number of outcomes)<\/p>\n<p>Now,<\/p>\n<p><strong>(i)<\/strong>&nbsp;Probability (he hits boundary) = (Number of times he hit a boundary) \/ (Total number of balls he played)<\/p>\n<p>= 6\/30 = 1\/5<\/p>\n<p><strong>(ii)<\/strong>&nbsp;Probability that the batsman does not hit a boundary = 24\/30 = 4\/5<\/p>\n<p><strong>Question 6: The percentage of marks obtained by a student in monthly unit tests is given below:<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 25 ex 25.1 Question 6\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-25-ex-25-1-questio-1.png\" alt=\"RD sharma class 9 maths chapter 25 ex 25.1 Question 6\"><\/p>\n<p><strong>Find the probability that the student gets<\/strong><\/p>\n<p><strong>(i) More than 70% of marks<\/strong><\/p>\n<p><strong>(ii) Less than 70% of marks<\/strong><\/p>\n<p><strong>(iii) A distinction<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Total number of unit tests taken = 5<\/p>\n<p>We know, Probability of an event = (Number of Favorable outcomes) \/ (Total Number of outcomes)<\/p>\n<p><strong>(i)<\/strong>&nbsp;Number of times student got more than 70% = 3<\/p>\n<p>Probability (Getting more than 70%) = 3\/5 = 0.6<\/p>\n<p><strong>(ii)<\/strong>&nbsp;Number of times student got less than 70% = 2<\/p>\n<p>Probability (Getting less than 70%) = 2\/5 = 0.4<\/p>\n<p><strong>(iii)<\/strong>&nbsp;Number of times student got a distinction = 1<\/p>\n<p>[Marks more than 75%]<\/p>\n<p>Probability (Getting a distinction) = 1\/5 = 0.2<\/p>\n<p><strong>Question 7: To know the opinion of the students about Mathematics, a survey of 200 students was conducted. The data was recorded in the following table:<\/strong><\/p>\n<p><img title=\"RD sharma class 9 maths chapter 25 ex 25.1 Question 7\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-25-ex-25-1-questio-2.png\" alt=\"RD sharma class 9 maths chapter 25 ex 25.1 Question 7\"><\/p>\n<p><strong>Find the probability that students are chosen at random:<\/strong><\/p>\n<p><strong>(i) Likes Mathematics (ii) Does not like it.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Total number of students = 200<\/p>\n<p>Students like mathematics = 135<\/p>\n<p>Students dislike Mathematics = 65<\/p>\n<p>We know, Probability of an event = (Number of Favorable outcomes) \/ (Total Number of outcomes)<\/p>\n<p>(i) Probability (Student likes mathematics) = 135\/200 = 0.675<\/p>\n<p>(ii) Probability (Student does not like mathematics) = 65\/200 = 0.325<\/p>\n<h2><span class=\"ez-toc-section\" id=\"important-topics-%e2%80%93-rd-sharma-solution-class-9-maths-chapter-25\"><\/span><strong>Important Topics &#8211; RD Sharma Solution Class 9 Maths Chapter 25<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><span style=\"font-weight: 400;\">Here is the list of topics that you should go through before starting a chapter.<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Understanding the concept of Probability<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Calculating probability in coins<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Calculating probability in different daily situations<\/span><\/li>\n<\/ul>\n<p>This is the complete blog on RD Sharma Solutions Class 9 Maths Chapter 25. To know more about the <a href=\"https:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 9 Maths, ask in the comments.&nbsp;<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-solution-class-9-maths-chapter-25-probability\"><\/span><strong>FAQs on RD Sharma Solution Class 9 Maths Chapter 25 Probability<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1630919406917\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-access-the-rd-sharma-solutions-for-class-9-maths-chapter-25-pdf-offline\"><\/span>Can I access the RD Sharma Solutions for Class 9 Maths Chapter 25\u00a0PDF offline?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Once you have downloaded the PDF online, you can access it offline as well.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630919450773\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-solutions-for-class-9-maths-chapter-25\"><\/span>How much does it cost to download the PDF of RD Sharma Solutions for Class 9 Maths Chapter 25?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download it for free.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630919475331\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"from-where-can-i-download-the-pdf-of-rd-sharma-solutions-class-9-maths-chapter-25\"><\/span>From where can I download the PDF of RD Sharma Solutions Class 9 Maths Chapter 25?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can find the download link from the above blog.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Solution Class 9 Maths Chapter 25 &#8211; Probability: RD Sharma Solution Class 9 Maths Chapter 25 is one of the student\u2019s favorite chapters as it does not require those heavy calculations and you can easily understand its concept with proper guidance. But, it doesn&#8217;t make the chapter less important, this unit will ask &#8230; <a title=\"RD Sharma Solution Class 9 Maths Chapter 25 &#8211; Probability (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solution-class-9-maths-chapter-25-probability\/\" aria-label=\"More on RD Sharma Solution Class 9 Maths Chapter 25 &#8211; Probability (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":124762,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2985,73411,73410],"tags":[3081,3086,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/63713"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=63713"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/63713\/revisions"}],"predecessor-version":[{"id":520871,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/63713\/revisions\/520871"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/124762"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=63713"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=63713"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=63713"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}