{"id":55750,"date":"2021-07-29T17:55:00","date_gmt":"2021-07-29T12:25:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=55750"},"modified":"2023-05-22T17:00:51","modified_gmt":"2023-05-22T11:30:51","slug":"ncert-solutions-for-class-11-chemistry-chapter-13","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/","title":{"rendered":"Class 11 Chemistry NCERT Solutions 2023 for Chapter 13\u00a0Hydrocarbons"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-109997\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2020\/09\/NCERT-Solutions-For-Class-11-Chemistry-Chapter-13-Hydrocarbons-1.jpg\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2020\/09\/NCERT-Solutions-For-Class-11-Chemistry-Chapter-13-Hydrocarbons-1.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2020\/09\/NCERT-Solutions-For-Class-11-Chemistry-Chapter-13-Hydrocarbons-1-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons<\/strong>: NCERT solutions help students understand complex concepts in a better way. NCERT Solutions for Class 11 Chemistry Chapter 13 is Hydrocarbons. And NCERT solutions include all the topics in the chapter with in-depth explanations for the same. So, going through the solutions will help you to know how to formulate answers in a better way.<\/p>\n<ul>\n<li><a href=\"https:\/\/www.kopykitab.com\/blog\/cbse-class-11-chemistry-ncert-solutions\/\" target=\"_blank\" rel=\"noopener noreferrer\">NCERT Solutions For 11th Chemistry All Chapters<\/a><\/li>\n<\/ul>\n<p>It also helps revise the entire chapter so that you are thorough with all the concepts. NCERT Solutions not only help you to prepare for NCERT Solutions for Class 11 Chemistry Chapter 13 final exams but also the board exams of Class 12, as well as other competitive exams such as NEET and IIT-JEE.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69ee8e9b5615d\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69ee8e9b5615d\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons\" title=\"NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons\">NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#what-will-you-learn-in-ncert-class-11-chemistry-chapter-13-hydrocarbons\" title=\"What will you learn in NCERT Class 11 Chemistry Chapter 13\u00a0Hydrocarbons?\">What will you learn in NCERT Class 11 Chemistry Chapter 13\u00a0Hydrocarbons?<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#acyclic-and-heterocyclic-hydrocarbons\" title=\"Acyclic and Heterocyclic Hydrocarbons\">Acyclic and Heterocyclic Hydrocarbons<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#alkanes\" title=\"Alkanes\">Alkanes<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#nomenclature-of-alkanes\" title=\"Nomenclature of Alkanes\">Nomenclature of Alkanes<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#alkynes\" title=\"Alkynes\">Alkynes<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#nomenclature-of-alkynes\" title=\"Nomenclature of Alkynes\">Nomenclature of Alkynes<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#isomerism\" title=\"Isomerism\">Isomerism<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#aromaticity\" title=\"Aromaticity\">Aromaticity<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#physical-and-chemical-properties-of-benzene\" title=\"Physical and Chemical Properties of Benzene\">Physical and Chemical Properties of Benzene<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#benefits-of-studying-from-ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons\" title=\"Benefits of Studying from NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons\">Benefits of Studying from NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#1-exemplar-problems\" title=\"1. Exemplar Problems\">1. Exemplar Problems<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#2-tips-and-tricks\" title=\"2. Tips and Tricks\">2. Tips and Tricks<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#3-worksheets\" title=\"3. Worksheets\">3. Worksheets<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#4-numerical-problems\" title=\"4. Numerical Problems\">4. Numerical Problems<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#access-ncert-solutions-for-class-11-chemistry-chapter-13\" title=\"Access NCERT Solutions For Class 11 Chemistry Chapter 13\">Access NCERT Solutions For Class 11 Chemistry Chapter 13<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-17\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-1-how-do-you-account-for-the-formation-of-ethane-during-the-chlorination-of-methane\" title=\"Question 1. How do you account for the formation of ethane during the chlorination of methane?\">Question 1. How do you account for the formation of ethane during the chlorination of methane?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-18\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-2-write-the-iupac-names-of-the-following-compounds\" title=\"Question 2. Write the IUPAC names of the following compounds: \">Question 2. Write the IUPAC names of the following compounds: <\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-19\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-3-for-the-following-compounds-write-structural-formulas-and-iupac-names-for-all-possible-isomers-having-the-number-of-double-or-triple-bonds-as-indicated-a-c4h8-one-double-bond-b-c5h8-one-triple-bond\" title=\"Question 3. For the following compounds, write structural formulas and IUPAC names for all possible isomers having the number of double or triple bonds as indicated: (a) C4H8\u00a0(one double bond) (b) C5H8\u00a0(one triple bond)\">Question 3. For the following compounds, write structural formulas and IUPAC names for all possible isomers having the number of double or triple bonds as indicated: (a) C4H8\u00a0(one double bond) (b) C5H8\u00a0(one triple bond)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-20\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-4-write-iupac-names-of-the-products-obtained-by-the-ozonolytic-of-the-following-compounds-i-pent-2-ene-ii-3-4-dimethylhept-3-ene-iii-2-ethylbut-l-ene-iv-1-phenylbut-l-ene\" title=\"Question 4. Write IUPAC names of the products obtained by the ozonolytic of the following compounds: (i) Pent-2-ene (ii) 3, 4-Dimethylhept-3-ene (iii) 2-Ethylbut-l-ene (iv) 1-Phenylbut-l-ene.\">Question 4. Write IUPAC names of the products obtained by the ozonolytic of the following compounds: (i) Pent-2-ene (ii) 3, 4-Dimethylhept-3-ene (iii) 2-Ethylbut-l-ene (iv) 1-Phenylbut-l-ene.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-21\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-5-an-alkene-%e2%80%98a%e2%80%99-on-ozonolysis-gives-a-mixture-of-ethanol-and-pentane-3-one-write-the-structure-and-iupac-name-of-%e2%80%98a%e2%80%99\" title=\"Question 5. An alkene \u2018A\u2019 on ozonolysis gives a mixture of ethanol and pentane-3-one. Write the structure and IUPAC name of \u2018A\u2019.\">Question 5. An alkene \u2018A\u2019 on ozonolysis gives a mixture of ethanol and pentane-3-one. Write the structure and IUPAC name of \u2018A\u2019.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-22\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-6-an-alkene-%e2%80%98a%e2%80%99-contains-three-c%e2%80%94c-eight-c%e2%80%94h-a-bonds-and-one-c%e2%80%94c-n-bond-%e2%80%98a%e2%80%99-on-ozonolysis-gives-two-moles-of-an-aldehyde-of-molar-mass-44-u-write-the-iupac-name-of-%e2%80%99a%e2%80%99\" title=\"Question 6. An alkene \u2018A\u2019 contains three C\u2014C, eight C\u2014H, a-bonds, and one C\u2014C n-bond. \u2018A\u2019 on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write the IUPAC name of \u2019A\u2019.\">Question 6. An alkene \u2018A\u2019 contains three C\u2014C, eight C\u2014H, a-bonds, and one C\u2014C n-bond. \u2018A\u2019 on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write the IUPAC name of \u2019A\u2019.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-23\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-7-propanal-and-pentane-3-ene-are-the-ozonolysis-products-of-an-alkene-what-is-the-structural-formula-of-the-alkene\" title=\"Question 7. Propanal and pentane-3-ene are the ozonolysis products of an alkene. What is the structural formula of the alkene?\">Question 7. Propanal and pentane-3-ene are the ozonolysis products of an alkene. What is the structural formula of the alkene?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-24\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-8-write-chemical-equations-for-the-combustion-reaction-of-the-following-hydrocarbons-i-butane-ii-pentene-iii-hexyne-iv-toluene\" title=\"Question 8. Write chemical equations for the combustion reaction of the following hydrocarbons,\u00a0(i) Butane (ii) Pentene (iii) Hexyne (iv) Toluene\">Question 8. Write chemical equations for the combustion reaction of the following hydrocarbons,\u00a0(i) Butane (ii) Pentene (iii) Hexyne (iv) Toluene<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-25\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-9-draw-the-cis-and-trans-structures-for-hex-2-one-which-isomer-will-have-higher-bp-and-why\" title=\"Question 9. Draw the cis- and trans-structures for hex-2-one. Which isomer will have higher b.p. and why?\">Question 9. Draw the cis- and trans-structures for hex-2-one. Which isomer will have higher b.p. and why?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-26\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-10-why-is-benzene-extra-ordinarily-stable-though-it-contains-three-double-bonds\" title=\"Question 10. Why is benzene extra-ordinarily stable though it contains three double bonds?\">Question 10. Why is benzene extra-ordinarily stable though it contains three double bonds?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-27\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-11-what-are-the-necessary-conditions-for-any-system-to-be-aromatic\" title=\"Question 11. What are the necessary conditions for any system to be aromatic?\">Question 11. What are the necessary conditions for any system to be aromatic?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-28\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-12-explain-why-the-following-systems-are-not-aromatic\" title=\"Question 12. Explain why the following systems are not aromatic. \">Question 12. Explain why the following systems are not aromatic. <\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-29\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-13-how-will-you-convert-benzene-into-ip-nitrobromobenzene-ii-m-nitrochlorobenzene-iii-p-nitrotoluene-iv-acetophenone\" title=\"Question 13. How will you convert benzene into\u00a0(i)p-nitrobromobenzene (ii) m-nitrochlorobenzene (iii) p-nitrotoluene (iv) acetophenone?\">Question 13. How will you convert benzene into\u00a0(i)p-nitrobromobenzene (ii) m-nitrochlorobenzene (iii) p-nitrotoluene (iv) acetophenone?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-30\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-14-in-the-alkane-ch3ch2%e2%80%94cch32%e2%80%94ch2%e2%80%94chch32-identify-1%c2%b0-2%c2%b0-3%c2%b0-carbon-atoms-and-give-the-number-of-h-atoms-bonded-to-each-one-of-these\" title=\"Question 14. In the alkane, CH3CH2\u2014C(CH3)2\u2014CH2\u2014CH(CH3)2, identify 1\u00b0, 2\u00b0, 3\u00b0 carbon atoms and give the number of H-atoms bonded to each one of these.\">Question 14. In the alkane, CH3CH2\u2014C(CH3)2\u2014CH2\u2014CH(CH3)2, identify 1\u00b0, 2\u00b0, 3\u00b0 carbon atoms and give the number of H-atoms bonded to each one of these.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-31\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-15-what-effect-does-the-branching-of-an-alkane-chain-have-on-its-boiling-point\" title=\"Question 15. What effect does the branching of an alkane chain have on its boiling point?\">Question 15. What effect does the branching of an alkane chain have on its boiling point?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-32\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-16-addition-of-hbr-to-propene-yields-2-bromopropane-while-in-the-presence-of-benzoyl-peroxide-the-same-reaction-yields-1-bromopropane-explain-and-give-the-mechanism\" title=\"Question 16. Addition of HBr to propene yields 2-bromopropane, while in the presence of benzoyl peroxide, the same reaction yields 1-bromopropane. Explain and give the mechanism.\">Question 16. Addition of HBr to propene yields 2-bromopropane, while in the presence of benzoyl peroxide, the same reaction yields 1-bromopropane. Explain and give the mechanism.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-33\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-17-write-down-the-products-ozonolysis-of-2-dimethylbenzene-o-xylene-how-does-the-result-support-the-kekune-structure-of-benzene\" title=\"Question 17. Write down the products ozonolysis of, 2-dimethylbenzene (o-xylene). How does the result support the Kekune structure of benzene?\">Question 17. Write down the products ozonolysis of, 2-dimethylbenzene (o-xylene). How does the result support the Kekune structure of benzene?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-34\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-18-arrange-benzene-n-hexane-and-ethyne-in-decreasing-order-of-acidic-behavior-also-give-a-reason-for-this-behavior\" title=\"Question 18. Arrange benzene, n-hexane, and ethyne in decreasing order of acidic behavior. Also, give a reason for this behavior.\">Question 18. Arrange benzene, n-hexane, and ethyne in decreasing order of acidic behavior. Also, give a reason for this behavior.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-35\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-19-why-does-benzene-undergo-electrophilic-substitution-reactions-easily-and-nucleophilic-substitutions-with-difficulty\" title=\"Question 19. Why does benzene undergo electrophilic substitution reactions easily and nucleophilic substitutions with difficulty?\">Question 19. Why does benzene undergo electrophilic substitution reactions easily and nucleophilic substitutions with difficulty?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-36\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-20-how-will-you-convert-the-following-compounds-into-benzene-i-ethyne-ii-ethene-iii-hexane\" title=\"Question 20. How will you convert the following compounds into benzene? (i) Ethyne (ii) Ethene (iii) Hexane.\">Question 20. How will you convert the following compounds into benzene? (i) Ethyne (ii) Ethene (iii) Hexane.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-37\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-21-write-structures-of-all-the-alkenes-which-on-hydrogeneration-give-2-methylbutane\" title=\"Question 21. Write structures of all the alkenes which on hydrogeneration give 2-methylbutane.\">Question 21. Write structures of all the alkenes which on hydrogeneration give 2-methylbutane.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-38\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-22-arrange-the-following-set-of-compounds-in-order-of-their-decreasing-relative-reactivity-with-an-electrophile-e-a-chlorobenzene-2-4-dinitrochlorobenzene-p-nitrochlorobenzene-b-toluene%e2%80%94h3c%e2%80%94c6h4%e2%80%94no2-p%e2%80%94o2n%e2%80%94c6h4%e2%80%94no2\" title=\"Question 22. Arrange the following set of compounds in order of their decreasing relative reactivity with an electrophile, E+. (a) Chlorobenzene, 2, 4-dinitrochlorobenzene, p-nitrochlorobenzene (b) Toluene\u2014H3C\u2014C6H4\u2014NO2, p\u2014O2N\u2014C6H4\u2014NO2.\">Question 22. Arrange the following set of compounds in order of their decreasing relative reactivity with an electrophile, E+. (a) Chlorobenzene, 2, 4-dinitrochlorobenzene, p-nitrochlorobenzene (b) Toluene\u2014H3C\u2014C6H4\u2014NO2, p\u2014O2N\u2014C6H4\u2014NO2.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-39\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-23-out-of-benzene-m-dinitrobenzene-and-toluene-which-will-undergo-nitration-most-easily-and-why\" title=\"Question 23. Out of benzene, m-dinitrobenzene, and toluene which will undergo nitration most easily and why?\">Question 23. Out of benzene, m-dinitrobenzene, and toluene which will undergo nitration most easily and why?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-40\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-24-suggest-the-name-of-another-lewis-acid-instead-of-anhydrous-aluminium-chloride-which-can-be-used-during-ethylation-of-benzene\" title=\"Question 24. Suggest the name of another Lewis acid instead of anhydrous aluminium chloride which can be used during ethylation of benzene.\">Question 24. Suggest the name of another Lewis acid instead of anhydrous aluminium chloride which can be used during ethylation of benzene.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-41\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-25-why-is-the-wurtz-reaction-not-preferred-for-the-preparation-of-alkanes-containing-an-odd-number-of-carbon-atoms-illustrate-your-answer-by-taking-one-example\" title=\"Question 25. Why is the Wurtz reaction not preferred for the preparation of alkanes containing an odd number of carbon atoms? Illustrate your answer by taking one example.\">Question 25. Why is the Wurtz reaction not preferred for the preparation of alkanes containing an odd number of carbon atoms? Illustrate your answer by taking one example.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-42\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#more-questions-solved\" title=\"MORE QUESTIONS SOLVED\">MORE QUESTIONS SOLVED<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-43\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#ncert-solutions-for-class-11-chemistry-chapter-13-very-short-answer-type-questions\" title=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Very Short Answer Type Questions\">NCERT Solutions for Class 11 Chemistry Chapter 13 Very Short Answer Type Questions<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-44\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-1-%3e\" title=\"Question\u00a01. &gt;\">Question\u00a01. &gt;<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-45\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-2-what-are-conformations\" title=\"Question 2. What are conformations?\">Question 2. What are conformations?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-46\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-3-what-is-decarboxylation-give-an-example\" title=\"Question 3. What is decarboxylation? Give an example.\">Question 3. What is decarboxylation? Give an example.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-47\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-4-what-do-you-mean-by-pyrolysis\" title=\"Question 4. What do you mean by pyrolysis?\">Question 4. What do you mean by pyrolysis?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-48\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-5-what-happens-when-ethanol-is-heated-with-a-cone-h2so4\" title=\"Question 5. What happens when ethanol is heated with a cone? H2SO4?\">Question 5. What happens when ethanol is heated with a cone? H2SO4?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-49\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-6-convert-ethylene-to-ethane\" title=\"Question 6. Convert ethylene to ethane.\">Question 6. Convert ethylene to ethane.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-50\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-7-what-is-lindlar%e2%80%99s-catalyst-give-its-use\" title=\"Question 7. What is Lindlar\u2019s catalyst? Give its use.\">Question 7. What is Lindlar\u2019s catalyst? Give its use.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-51\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-8-what-happens-when-benzene-is-treated-with-an-excess-of-cl2-in-the-presence-of-sunlight-give-chemical-reaction\" title=\"Question 8. What happens when benzene is treated with an excess of Cl2 in the presence of sunlight? Give chemical reaction.\">Question 8. What happens when benzene is treated with an excess of Cl2 in the presence of sunlight? Give chemical reaction.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-52\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-9-why-are-alkanes-called-paraffin\" title=\"Question 9. Why are alkanes called paraffin?\">Question 9. Why are alkanes called paraffin?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-53\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-10-arrange-the-three-isomers-of-pentane-in-increasing-order-of-their-boiling-points\" title=\"Question 10. Arrange the three isomers of pentane in increasing order of their boiling points.\">Question 10. Arrange the three isomers of pentane in increasing order of their boiling points.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-54\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-11-arrange-the-following-hcl-hbr-hi-hf-in-order-of-decreasing-reactivity-towards-alkenes\" title=\"Question 11. Arrange the following: HCl, HBr, HI, HF in order of decreasing reactivity towards alkenes.\">Question 11. Arrange the following: HCl, HBr, HI, HF in order of decreasing reactivity towards alkenes.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-55\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-12-although-benzene-is-highly-unsaturated-it-does-not-undergo-addition-reactions-why\" title=\"Question 12. Although benzene is highly unsaturated it does not undergo addition reactions. Why?\">Question 12. Although benzene is highly unsaturated it does not undergo addition reactions. Why?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-56\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-13-why-are-alkenes-called-olefins\" title=\"Question 13. Why are Alkenes called olefins?\">Question 13. Why are Alkenes called olefins?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-57\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-14-which-is-more-acidic-ethene-or-ethyne-and-why\" title=\"Question 14. Which is more acidic: ethene or ethyne and why?\">Question 14. Which is more acidic: ethene or ethyne and why?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-58\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-15-what-is-huckel%e2%80%99s-rule\" title=\"Question 15. What is Huckel&#8217;s rule?\">Question 15. What is Huckel&#8217;s rule?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-59\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-16-how-will-you-distinguish-between-propene-and-propane\" title=\"Question 16. How will you distinguish between propene and propane?\">Question 16. How will you distinguish between propene and propane?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-60\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-17-how-will-you-distinguish-between-acetylene-and-ethylene\" title=\"Question 17. How will you distinguish between acetylene and ethylene?\">Question 17. How will you distinguish between acetylene and ethylene?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-61\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-18-what-happens-when-benzene-is-treated-with-acetyl-chloride-in-the-presence-of-alcl3\" title=\"Question 18. What happens when benzene is treated with acetyl chloride in the presence of AlCl3?\">Question 18. What happens when benzene is treated with acetyl chloride in the presence of AlCl3?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-62\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-19-which-type-of-isomerism-is-exhibited-by-but-l-one-and-but-2-one\" title=\"Question 19. Which type of isomerism is exhibited by but-l-one and but-2-one?\">Question 19. Which type of isomerism is exhibited by but-l-one and but-2-one?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-63\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-20-what-is-electrophile-in-sulphonation\" title=\"Question 20. What is electrophile in sulphonation?\">Question 20. What is electrophile in sulphonation?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-64\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-21-what-is-the-hybridization-of-central-carbon-in-12-propadiene-ch2cch2\" title=\"Question 21. What is the hybridization of central carbon in 1,2-propadiene (CH2=C=CH2)?\">Question 21. What is the hybridization of central carbon in 1,2-propadiene (CH2=C=CH2)?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-65\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#question-22-what-are-arenes\" title=\"Question 22. What are Arenes?\">Question 22. What are Arenes?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-66\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#faq-ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons-structure-of-atom\" title=\"FAQ: NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons Structure Of Atom\">FAQ: NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons Structure Of Atom<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-67\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#can-i-download-ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons-structure-of-atom-pdf-for-free\" title=\"Can I download NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons Structure Of Atom PDF for free? \">Can I download NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons Structure Of Atom PDF for free? <\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-68\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#what-are-aromatic-hydrocarbons\" title=\"What are aromatic hydrocarbons? \">What are aromatic hydrocarbons? <\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-69\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#what-are-the-benefits-of-studying-from-ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons\" title=\"What are the Benefits of Studying from NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons? \">What are the Benefits of Studying from NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons? <\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-70\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/#what-will-i-learn-in-ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons\" title=\"What will I learn in NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons?\">What will I learn in NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons\"><\/span><strong>NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Experts having immense knowledge in Chemistry develop NCERT Solutions for Class 11 Chemistry Chapter 13 with the sole intent of offering rich educational content for students of Class 11.<\/p>\n<p>The chapter, Hydrocarbons, consists of six main topics. Each of these six topics further consists of sub-topics related to a concept.<\/p>\n<p>NCERT solutions are available for download in PDF format. So, you can download and start studying from them right away. Also, for all those students who are not well-versed in English, you can download the Hindi versions of NCERT solutions.<\/p>\n<p>The solutions also have been solved as well as practice questions at the end of the chapter. So, you can prepare for the exams by working on them. And in case you are not able to figure out the answer to any of the questions, you can always refer to the solutions. The solutions also give you hints, tips, and other tricks that help you to write your answers in a faster and more effective way.<\/p>\n<p>You can download\u00a0CBSE NCERT Solutions for Class 11 Chemistry\u00a0Chapter 13\u00a0Hydrocarbons\u00a0from below.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2020\/09\/chapter_13_hydrocarbons.pdf\">Download NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons<\/a><\/p>\n<p>\u00a0<\/p>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\">.pdfobject-container { height: 500px;}<br \/>.pdfobject { border: 1px solid #666; }<\/p>\n<p style=\"text-align: justify;\"><br \/>PDFObject.embed(&#8220;https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2020\/09\/chapter_13_hydrocarbons.pdf&#8221;, &#8220;#example1&#8221;);<\/p>\n<h2><span class=\"ez-toc-section\" id=\"what-will-you-learn-in-ncert-class-11-chemistry-chapter-13-hydrocarbons\"><\/span>What will you learn in NCERT Class 11 Chemistry Chapter 13\u00a0Hydrocarbons?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>The reaction of Carbon and Hydrogen forms hydrocarbons. If a hydrocarbon has single bonds, then it is saturated. And if it has multiple bonds, it is unsaturated.<\/p>\n<p>Also, those hydrocarbons formed by Benzene and its derivatives are known as aromatic hydrocarbons.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"acyclic-and-heterocyclic-hydrocarbons\"><\/span><strong>Acyclic and Heterocyclic Hydrocarbons<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Sometimes, hydrocarbons consist of only carbon compounds. And such compounds are known as acyclic hydrocarbon compounds. Similarly, hydrocarbon compounds having a carbon atom along with other elements are known as heterocyclic hydrocarbon compounds.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"alkanes\"><\/span><strong>Alkanes<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Alkanes are the simplest forms of hydrocarbons. In these types of compounds, the carbon atoms have single covalent bonds that are fully saturated by Hydrogen atoms. So, they are also known as saturated hydrocarbons.<\/p>\n<p>Alkanes have strong bonds and are, therefore, chemically inert. And because of this, they also are known as \u2018paraffin,\u2019 meaning that they have a lesser affinity towards chemical reactions.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"nomenclature-of-alkanes\"><\/span><strong>Nomenclature of Alkanes<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The IUPAC has guidelines for writing the structure of Hydrocarbons. As such, you can use the following steps to write the structural formula for different hydrocarbon compounds.<\/p>\n<ol>\n<li>Find the longest chain that is present in the hydrocarbon compound.<\/li>\n<li>Number the chain from left to right.<\/li>\n<li>Find the alkyl group.<\/li>\n<li>Write the IUPAC name.<\/li>\n<\/ol>\n<p>When writing the formula, separate each number by a comma. Also, isolate the numbers from the names. You don\u2019t have to write the prefixes if you are using their alphabet substitutes.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"alkynes\"><\/span><strong>Alkynes<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Alkynes are those hydrocarbons with three bonds in the molecules. Acetylenes are the most important compounds in this class of hydrocarbons.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"nomenclature-of-alkynes\"><\/span><strong>Nomenclature of Alkynes<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>You can give names to alkynes using the parent alkanes and add the suffix \u2018-yne\u2019 to them. You must then assign numbers to the carbon chain along with the triple bonds, starting from the end that is nearest to that bond.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"isomerism\"><\/span><strong>Isomerism<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>There are two types of isomerism when it comes to organic compounds. The first type is structural isomerism, and the second type is geometrical isomerism. Most hydrocarbons don\u2019t show any signs of structural isomerism. However, some compounds that have double bonds tend to show geometrical isomerism.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"aromaticity\"><\/span><strong>Aromaticity<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Hydrocarbons exhibit aromaticity if they satisfy any of the following conditions.<\/p>\n<ol>\n<li>The hydrocarbons must be cyclic and planar.<\/li>\n<li>Each atom in the hydrocarbon must have a parallel p orbital so that they can overlap continuously.<\/li>\n<\/ol>\n<h3><span class=\"ez-toc-section\" id=\"physical-and-chemical-properties-of-benzene\"><\/span><strong>Physical and Chemical Properties of Benzene<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Benzene is a colorless liquid and is insoluble in water. However, it is soluble in substances like alcohol, chloroform, and ether.<\/p>\n<p>It is also a suitable solvent for various other organic and inorganic substances like fat, resins, and Sulphur. Additionally, Benzene also undergoes Electrophilic Substitution and Addition Reactions.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"benefits-of-studying-from-ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons\"><\/span><strong>Benefits of Studying from NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Studying Chemistry from NCERT solutions come with a ton of benefits, especially for a concept like hydrocarbons. For instance, the solutions have practice questions at the end of each chapter.<\/p>\n<p>So, students can work on them and come out on top in not only the class 11 exams but also in the class 12 board exams and various other competitive examinations. Likewise, there are other advantages to studying NCERT solutions.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"1-exemplar-problems\"><\/span><strong>1. <\/strong><strong>Exemplar Problems<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The solutions come with exemplar problems that offer a means for the students to understand the subject from a unique perspective.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"2-tips-and-tricks\"><\/span><strong>2. <\/strong><strong>Tips and Tricks<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The solutions offer tips and tricks on the way the students should be writing answers in the exams. These tips and tricks should help them score well for each question as well as in the subject.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"3-worksheets\"><\/span><strong>3. <\/strong><strong>Worksheets<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>The solutions also have worksheets and many questions for the students to answer. By working on them, you can rest assured that you will score well in the exams.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"4-numerical-problems\"><\/span><strong>4. <\/strong><strong>Numerical Problems<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>In addition to worksheets and exercise questions, NCERT solutions for Chemistry also have numerical problems that are likely to appear in the exams. Their question paper can consist of various levels of numerical problems, and NCERT solutions list all of them.<\/p>\n<p>It is best if you studied prominent topics such as Hydrocarbons by referring to NCERT solutions. They not only give you in-depth insights about the chapter but also help you to prepare for the exams by offering questions and problems at the end of each chapter.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"access-ncert-solutions-for-class-11-chemistry-chapter-13\"><\/span>Access NCERT Solutions For Class 11 Chemistry Chapter 13<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"question-1-how-do-you-account-for-the-formation-of-ethane-during-the-chlorination-of-methane\"><\/span><strong>Question 1. How do you account for the formation of ethane during the chlorination of methane?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong> Chlorination of methane is a free radical reaction that occurs by the following mechanism:<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q1\" width=\"760\" height=\"336\" \/><br \/>From the above mechanism, it is evident that during the propagation step, CH<sub>3<\/sub>\u00a0free radicals are produced which may undergo three reactions, i.e., (i) \u2014 (iii). In the chain termination step, the two CH<sub>3<\/sub> free radicals combine together to form an ethane (CH<sub>3<\/sub>\u2014CH<sub>3<\/sub>) molecule.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-2-write-the-iupac-names-of-the-following-compounds\"><\/span><strong>Question 2. Write the IUPAC names of the following compounds:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q2.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q2\" width=\"594\" height=\"87\" \/><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<h3><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q2.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q2.1\" width=\"531\" height=\"193\" \/><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q2.2.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q2.2\" width=\"708\" height=\"486\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-3-for-the-following-compounds-write-structural-formulas-and-iupac-names-for-all-possible-isomers-having-the-number-of-double-or-triple-bonds-as-indicated-a-c4h8-one-double-bond-b-c5h8-one-triple-bond\"><\/span><strong>Question 3. For the following compounds, write structural formulas and IUPAC names for all possible isomers having the number of double or triple bonds as indicated:<\/strong><br \/><strong>(a) C<sub>4<\/sub>H<sub>8<\/sub>\u00a0(one double bond) (b) C<sub>5<\/sub>H<sub>8<\/sub>\u00a0(one triple bond)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0(a) Isomers of C<sub>4<\/sub>H<sub>8<\/sub>\u00a0having one double bond are:<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q3.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q3\" width=\"641\" height=\"209\" \/><\/p>\n<p><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q3.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q3.1\" width=\"673\" height=\"92\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-4-write-iupac-names-of-the-products-obtained-by-the-ozonolytic-of-the-following-compounds-i-pent-2-ene-ii-3-4-dimethylhept-3-ene-iii-2-ethylbut-l-ene-iv-1-phenylbut-l-ene\"><\/span><b>Question 4. Write IUPAC names of the products obtained by the ozonolytic of the following compounds:<\/b><br \/><strong>(i) Pent-2-ene (ii) 3, 4-Dimethylhept-3-ene (iii) 2-Ethylbut-l-ene (iv) 1-Phenylbut-l-ene.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q4.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q4\" width=\"795\" height=\"447\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-5-an-alkene-%e2%80%98a%e2%80%99-on-ozonolysis-gives-a-mixture-of-ethanol-and-pentane-3-one-write-the-structure-and-iupac-name-of-%e2%80%98a%e2%80%99\"><\/span><strong>Question 5. An alkene \u2018A\u2019 on ozonolysis gives a mixture of ethanol and pentane-3-one. Write the structure and IUPAC name of \u2018A\u2019.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0<strong>Step 1<\/strong>. Write the structure of the products side by side with their oxygen atoms pointing toward each other.<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q5.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q5\" width=\"297\" height=\"78\" \/><\/p>\n<p><strong>Step 2.<\/strong>\u00a0Remove the oxygen atoms and join the two ends by a double bond, the structure of the alkene \u2018A\u2019 is<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q5.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q5.1\" width=\"284\" height=\"91\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-6-an-alkene-%e2%80%98a%e2%80%99-contains-three-c%e2%80%94c-eight-c%e2%80%94h-a-bonds-and-one-c%e2%80%94c-n-bond-%e2%80%98a%e2%80%99-on-ozonolysis-gives-two-moles-of-an-aldehyde-of-molar-mass-44-u-write-the-iupac-name-of-%e2%80%99a%e2%80%99\"><\/span><strong>Question 6. An alkene \u2018A\u2019 contains three C\u2014C, eight C\u2014H, a-bonds, and one C\u2014C n-bond. \u2018A\u2019 on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write the IUPAC name of \u2019A\u2019.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong> (i) An aldehyde with a molar mass of 44 u is ethanal, CH<sub>3<\/sub>CH=0<\/p>\n<p>(ii) Write two moles of ethanal side by side with their oxygen atoms pointing towards each other.<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q6.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q6\" width=\"253\" height=\"52\" \/><\/p>\n<p>(iii) Remove the oxygen atoms and join them by a double bond, the structure of alkene \u2018A\u2019 is<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q6.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q6.1\" width=\"465\" height=\"96\" \/><br \/>As required, but-2-ene has three C\u2014C, eight C\u2014H a-bonds, and one C\u2014C \u03c0-bond.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-7-propanal-and-pentane-3-ene-are-the-ozonolysis-products-of-an-alkene-what-is-the-structural-formula-of-the-alkene\"><\/span><strong>Question 7. Propanal and pentane-3-ene are the ozonolysis products of an alkene. What is the structural formula of the alkene?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong> (i) Write the structures of propanal and pentane-3-ene with their oxygen atoms facing each other, we have,<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q7.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q7\" width=\"356\" height=\"95\" \/><\/p>\n<p>(ii) Remove oxygen atoms and join the two fragments by a double bond, the structure of the alkene is<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q7.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q7.1\" width=\"264\" height=\"116\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-8-write-chemical-equations-for-the-combustion-reaction-of-the-following-hydrocarbons-i-butane-ii-pentene-iii-hexyne-iv-toluene\"><\/span><strong>Question 8. Write chemical equations for the combustion reaction of the following hydrocarbons,\u00a0<\/strong><strong>(i) Butane (ii) Pentene (iii) Hexyne (iv) Toluene<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q8.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q8\" width=\"568\" height=\"247\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-9-draw-the-cis-and-trans-structures-for-hex-2-one-which-isomer-will-have-higher-bp-and-why\"><\/span>Question 9. Draw the cis- and trans-structures for hex-2-one. Which isomer will have higher b.p. and why?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0The structures of cis- and trans-isomer of hex-2-ene are:<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q9.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q9\" width=\"612\" height=\"111\" \/><br \/>The boiling point of a molecule depends upon dipole-dipole interactions. Since cis-isomer has a higher dipole moment, therefore, it has a higher boiling point.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-10-why-is-benzene-extra-ordinarily-stable-though-it-contains-three-double-bonds\"><\/span><strong>Question 10. Why is benzene extra-ordinarily stable though it contains three double bonds?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q10.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q10\" width=\"588\" height=\"204\" \/><br \/>The six electrons of the p-orbitals cover all six carbon atoms and are said to be delocalized. As a result of delocalization, there formed a stronger n-bond and a more stable molecule.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-11-what-are-the-necessary-conditions-for-any-system-to-be-aromatic\"><\/span><strong>Question 11. What are the necessary conditions for any system to be aromatic?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0The necessary conditions for a molecule to be aromatic are:<\/p>\n<ul>\n<li>It should have a single cyclic cloud of delocalized n-electrons above and below the plane of the molecule.<\/li>\n<li>It should be planar. This is because complete delocalization of n-electrons is possible only if the ring is planar to allow a cyclic overlap of p-orbitals.<\/li>\n<li>It should contain Huckel&#8217;s number of electrons, i.e., (4n + 2) n-electrons where n = 0, 1, 2, 3, etc.<br \/>A molecule that does not satisfy any one or more of the above conditions is said to be non-aromatic.<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"question-12-explain-why-the-following-systems-are-not-aromatic\"><\/span><strong>Question 12. Explain why the following systems are not aromatic.<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q12.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q12\" width=\"474\" height=\"53\" \/><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q12.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q12.1\" width=\"139\" height=\"50\" \/><br \/>Due to the presence of a sp3-hybridized carbon, the system is not<br \/>planar. It does contain six n-electrons but the system is not fully conjugated since all the six n-electrons do not form a single cyclic electron cloud that surrounds all the atoms of the ring. Therefore, it is not an aromatic compound.<\/p>\n<p>(ii)<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q12.2.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q12.2\" width=\"83\" height=\"72\" \/><br \/>Due to the presence of a sp3 -carbon, the system is not planar. Further, it contains only four n-electrons, therefore, the system is not aromatic because it does not contain a planar cyclic cloud having (4n + 2) n-electrons.<\/p>\n<p>(iii)<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q12.3.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q12.3\" width=\"276\" height=\"91\" \/><br \/>Cyclo-octatetraene is not planar but is tub-shaped. It is, therefore, a non-planar system having 8 n-electrons.<br \/>Therefore, the molecule is not aromatic since it does not contain a planar cyclic cloud having (4n + 2) n-electrons.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-13-how-will-you-convert-benzene-into-ip-nitrobromobenzene-ii-m-nitrochlorobenzene-iii-p-nitrotoluene-iv-acetophenone\"><\/span><strong>Question 13. How will you convert benzene into\u00a0<\/strong><strong>(i)p-nitrobromobenzene (ii) m-nitrochlorobenzene (iii) p-nitrotoluene (iv) acetophenone?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0(i) The two substituents in the benzene ring are present at p-positions. Therefore, the sequence of reactions should be such that first an o, p-directing group, i.e., Br atom should be introduced in the benzene ring and this should be followed by nitration. Thus,<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q13.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q13\" width=\"673\" height=\"217\" \/><\/p>\n<p>(ii) Here since the two substituents are at p-position w.r.t. each other, therefore, the first substituent in the benzene ring should be a o, p-directing group (i.e., CH<sub>3<\/sub>) and then the other group (i.e., NO<sub>2<\/sub>) should be introduced. Therefore, the sequence of reactions is:<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q13.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q13.1\" width=\"634\" height=\"94\" \/><\/p>\n<p>(iii)Here since the two substituents are at m-position w.r.t. each other, therefore, the first substituent in the benzene ring should be a m-directing group (i.e., NO<sub>2<\/sub>), and then the other group (i.e., Cl) should be introduced.<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q13.2.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q13.2\" width=\"748\" height=\"201\" \/><\/p>\n<p>(iv)Acetophenone can be prepared by F.C. acylation using either acetyl chloride or acetic anhydride.<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q13.3.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q13.3\" width=\"693\" height=\"252\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-14-in-the-alkane-ch3ch2%e2%80%94cch32%e2%80%94ch2%e2%80%94chch32-identify-1%c2%b0-2%c2%b0-3%c2%b0-carbon-atoms-and-give-the-number-of-h-atoms-bonded-to-each-one-of-these\"><\/span><strong>Question 14. In the alkane, CH<sub>3<\/sub>CH<sub>2<\/sub>\u2014C(CH<sub>3<\/sub>)<sub>2<\/sub>\u2014CH<sub>2<\/sub>\u2014CH(CH<sub>3<\/sub>)<sub>2<\/sub>, identify 1\u00b0, 2\u00b0, 3\u00b0 carbon atoms and give the number of H-atoms bonded to each one of these.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0The expanded formula of the given compound is<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q14.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q14\" width=\"300\" height=\"129\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-15-what-effect-does-the-branching-of-an-alkane-chain-have-on-its-boiling-point\"><\/span><strong>Question 15. What effect does the branching of an alkane chain have on its boiling point?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong> The branching of the carbon atom chain decreases the boiling point of alkane.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-16-addition-of-hbr-to-propene-yields-2-bromopropane-while-in-the-presence-of-benzoyl-peroxide-the-same-reaction-yields-1-bromopropane-explain-and-give-the-mechanism\"><\/span><strong>Question 16. Addition of HBr to propene yields 2-bromopropane, while in the presence of benzoyl peroxide, the same reaction yields 1-bromopropane. Explain and give the mechanism.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong> The addition of HBr to propene is an ionic electrophilic addition reaction in which the electrophile, i.e., H<sup>+<\/sup>\u00a0first adds to give a more stable 2\u00b0 carbocation. In the 2nd step, the carbocation is rapidly attacked by the nucleophile Br~ ion to give 2-bromopropane.<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q16.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q16\" width=\"559\" height=\"271\" \/><\/p>\n<p>In the presence of benzoyl peroxide, the reaction is still electrophilic but the electrophile here is a Br free radical which is obtained by the action of benzoyl peroxide on HBr<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q16.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q16.1\" width=\"699\" height=\"136\" \/><\/p>\n<p>In the first step, Br radical adds to propene in such a way so as to generate the more stable 2\u00b0 free radical. In the second step, the free radical thus obtained rapidly abstracts a hydrogen atom from HBr to give 1-bromopropane.<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q16.2.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q16.2\" width=\"512\" height=\"155\" \/><\/p>\n<p>From the above discussion, it is evident that although both reactions are electrophilic addition reactions it is due to different orders of addition of H and Br atoms which gives different products.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-17-write-down-the-products-ozonolysis-of-2-dimethylbenzene-o-xylene-how-does-the-result-support-the-kekune-structure-of-benzene\"><\/span><b>Question 17. Write down the products ozonolysis of, 2-dimethylbenzene (o-xylene). How does the result support the Kekune structure of benzene?<\/b><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong> o-Xylene may be regarded as a resonance hybrid of the following two Kekune structures. Ozonolysis of each one of these gives two products as shown below:<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q17.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q17\" width=\"616\" height=\"388\" \/><br \/>Thus, in all, three products are formed. Since all three products cannot be obtained from any one of the two Kekule structures, this\u2019 shows that o-xylene is a resonance hybrid of the two Kekule structures (I and II).<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-18-arrange-benzene-n-hexane-and-ethyne-in-decreasing-order-of-acidic-behavior-also-give-a-reason-for-this-behavior\"><\/span><strong>Question 18. Arrange benzene, n-hexane, and ethyne in decreasing order of acidic behavior. Also, give a reason for this behavior.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0The hybridization state of carbon in these three compounds is:<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q18.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q18\" width=\"701\" height=\"135\" \/><\/p>\n<p>Since s-electrons are closer to the nucleus, therefore, as the s-character of the orbital making the C\u2014H bond increases, the electrons of the C\u2014H bond lie closer and closer to the carbon atom.<\/p>\n<p>In other words, the partial +ve charge on the H-atom and hence the acidic character increases as the s-character of the orbital increases. Thus, the acidic character decreases in the order: Ethyne &gt; Benzene &gt; Hexane.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-19-why-does-benzene-undergo-electrophilic-substitution-reactions-easily-and-nucleophilic-substitutions-with-difficulty\"><\/span><strong>Question 19. Why does benzene undergo electrophilic substitution reactions easily and nucleophilic substitutions with difficulty?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Due to the presence of an electron cloud containing 6 n-electrons above and below the plane of the ring, benzene is a rich source of electrons.<\/p>\n<p>Consequently, it attracts the electrophiles (electron-deficient) reagents towards it and repels nucleophiles (electron-rich) reagents. As a result, benzene undergoes electrophilic substitution reactions easily and nucleophilic substitutions with difficulty.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-20-how-will-you-convert-the-following-compounds-into-benzene-i-ethyne-ii-ethene-iii-hexane\"><\/span><strong>Question 20. How will you convert the following compounds into benzene?<\/strong><br \/><strong>(i) Ethyne (ii) Ethene (iii) Hexane.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q20.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q20\" width=\"682\" height=\"475\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-21-write-structures-of-all-the-alkenes-which-on-hydrogeneration-give-2-methylbutane\"><\/span><strong>Question 21. Write structures of all the alkenes which on hydrogeneration give 2-methylbutane.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q21.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q21\" width=\"721\" height=\"223\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-22-arrange-the-following-set-of-compounds-in-order-of-their-decreasing-relative-reactivity-with-an-electrophile-e-a-chlorobenzene-2-4-dinitrochlorobenzene-p-nitrochlorobenzene-b-toluene%e2%80%94h3c%e2%80%94c6h4%e2%80%94no2-p%e2%80%94o2n%e2%80%94c6h4%e2%80%94no2\"><\/span><strong>Question 22. Arrange the following set of compounds in order of their decreasing relative reactivity with an electrophile, E<sup>+<\/sup>.<\/strong><br \/><strong>(a) Chlorobenzene, 2, 4-dinitrochlorobenzene, p-nitrochlorobenzene<\/strong><br \/><b>(b) Toluene\u2014H<\/b><sub style=\"font-weight: bold;\">3<\/sub><b>C\u2014C<\/b><sub style=\"font-weight: bold;\">6<\/sub><b>H<\/b><sub style=\"font-weight: bold;\">4<\/sub><b>\u2014NO<\/b><sub style=\"font-weight: bold;\">2<\/sub><b>, p\u2014O<\/b><sub style=\"font-weight: bold;\">2<\/sub><b>N\u2014C<\/b><sub style=\"font-weight: bold;\">6<\/sub><b>H<\/b><sub style=\"font-weight: bold;\">4<\/sub><b>\u2014NO<\/b><sub style=\"font-weight: bold;\">2<\/sub><b>.<\/b><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong> (a) The typical reactions of benzene are electrophilic substitution reactions. The higher the electron density in the benzene ring, the more reactive the compound is toward these reactions. Since N02 is a more powerful electron-withdrawing group than Cl, therefore, more the number of nitro groups, the less reactive the compound. Thus, the overall reactivity decreases in the order:<br \/>Chlorobenzene &gt; p-nitrochlorobenzene &gt; 2, 4-dinitrochlorobenzene<\/p>\n<p>(b) Here, the CH3 group is electron donating but the N02 group is electron-withdrawing. Therefore, the maximum electron density will be in toluene, followed by p-nitrotoluene followed by p-dinitrobenzene. Thus, the overall reactivity decreases in the order:<br \/>Toluene &gt;p\u2014H<sub>3<\/sub>C\u2014C<sub>6<\/sub>H<sub>4<\/sub>\u2014NO<sub>2<\/sub>, p\u2014O<sub>2<\/sub>N\u2014C<sub>6<\/sub>H<sub>4<\/sub>\u2014NO<sub>2<\/sub>.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-23-out-of-benzene-m-dinitrobenzene-and-toluene-which-will-undergo-nitration-most-easily-and-why\"><\/span><strong>Question 23. Out of benzene, m-dinitrobenzene, and toluene which will undergo nitration most easily and why?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0CH<sub>3<\/sub>\u00a0group is electron-donating while\u2014NO<sub>2\u00a0<\/sub>group is electron-withdrawing. Therefore, the maximum electron density will be in toluene, followed by benzene, and at least in m-dinitrobenzene. Therefore, the ease of nitration decreases in the order: toluene &gt; benzene &gt; m-dinitrobenzene.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-24-suggest-the-name-of-another-lewis-acid-instead-of-anhydrous-aluminium-chloride-which-can-be-used-during-ethylation-of-benzene\"><\/span><strong>Question 24. Suggest the name of another Lewis acid instead of anhydrous aluminium chloride which can be used during ethylation of benzene.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Anhydrous Ferric Chloride (FeCl<sub>3<\/sub>) is another Lewis acid that can be used.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-25-why-is-the-wurtz-reaction-not-preferred-for-the-preparation-of-alkanes-containing-an-odd-number-of-carbon-atoms-illustrate-your-answer-by-taking-one-example\"><\/span><strong>Question 25. Why is the Wurtz reaction not preferred for the preparation of alkanes containing an odd number of carbon atoms? Illustrate your answer by taking one example.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong> For the preparation of alkanes containing an odd number of carbon atoms, a mixture of two alkyl halides has to be used. Since two alkyl halides can react in three different ways, therefore, a mixture of three alkanes instead of the desired alkane would be formed.<\/p>\n<p>For example, the Wurtz reaction between \u20181-bromopropane and 1-bromobutane gives a mixture of three alkanes i.e., hexane, heptane, and octane as shown below:<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-Q25.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons Q25\" width=\"714\" height=\"287\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"more-questions-solved\"><\/span>MORE QUESTIONS SOLVED<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<h3><span class=\"ez-toc-section\" id=\"ncert-solutions-for-class-11-chemistry-chapter-13-very-short-answer-type-questions\"><\/span>NCERT Solutions for Class 11 Chemistry Chapter 13 Very Short Answer Type Questions<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<h3><span class=\"ez-toc-section\" id=\"question-1-%3e\"><\/span><strong>Question\u00a0<\/strong><strong>1.<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-VSAQ-Q1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons VSAQ Q1\" width=\"456\" height=\"92\" \/>&gt;<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-VSAQ-Q1.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons VSAQ Q1.1\" width=\"456\" height=\"92\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-2-what-are-conformations\"><\/span><strong>Question 2. What are conformations?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong> Conformations are spatial arrangements that are obtained by rotation around sigma bonds.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-3-what-is-decarboxylation-give-an-example\"><\/span><strong>Question 3. What is decarboxylation? Give an example.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong> The process by which carbon dioxide is removed from sodium acetate (or any sodium salt of acid) with the help of soda lime is called decarboxylation.<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-VSAQ-Q3.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons VSAQ Q3\" width=\"374\" height=\"44\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-4-what-do-you-mean-by-pyrolysis\"><\/span><strong>Question 4. What do you mean by pyrolysis?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0The decomposition of a compound by heat is called pyrolysis. This process when applied to alkanes is known as cracking.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-5-what-happens-when-ethanol-is-heated-with-a-cone-h2so4\"><\/span><strong>Question 5. What happens when ethanol is heated with a cone? H<sub>2<\/sub>SO<sub>4<\/sub>?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-VSAQ-Q5.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons VSAQ Q5\" width=\"488\" height=\"71\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-6-convert-ethylene-to-ethane\"><\/span><strong>Question 6. Convert ethylene to ethane.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-VSAQ-Q6.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons VSAQ Q6\" width=\"333\" height=\"62\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-7-what-is-lindlar%e2%80%99s-catalyst-give-its-use\"><\/span><strong>Question 7. What is Lindlar\u2019s catalyst? Give its use.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Pd\/BaSO<sub>4<\/sub>\u00a0is known as Lindlar\u2019s catalyst. It is used in the conversion of alkynes to alkenes with the help of H<sub>2<\/sub>.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-8-what-happens-when-benzene-is-treated-with-an-excess-of-cl2-in-the-presence-of-sunlight-give-chemical-reaction\"><\/span><strong>Question 8. What happens when benzene is treated with an excess of Cl<sub>2<\/sub> in the presence of sunlight? Give chemical reaction.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-13-Hydrocarbons-VSAQ-Q8.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons VSAQ Q8\" width=\"487\" height=\"194\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-9-why-are-alkanes-called-paraffin\"><\/span><strong>Question 9. Why are alkanes called paraffin?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>Paraffin means little affinity. Alkanes due to strong C\u2014C and C\u2014H bonds are relatively chemically inert.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-10-arrange-the-three-isomers-of-pentane-in-increasing-order-of-their-boiling-points\"><\/span><strong>Question 10. Arrange the three isomers of pentane in increasing order of their boiling points.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>2, 2-Dimethylpropane &lt; 2-methyl butane &lt; pentane.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-11-arrange-the-following-hcl-hbr-hi-hf-in-order-of-decreasing-reactivity-towards-alkenes\"><\/span><strong>Question 11. Arrange the following: HCl, HBr, HI, HF in order of decreasing reactivity towards alkenes.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>HI &gt; HBr &gt; HCl &gt; HF<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-12-although-benzene-is-highly-unsaturated-it-does-not-undergo-addition-reactions-why\"><\/span><strong>Question 12. Although benzene is highly unsaturated it does not undergo addition reactions. Why?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>It is due to the delocalization of \u03c0 -electrons in benzene it is highly stable.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-13-why-are-alkenes-called-olefins\"><\/span><strong>Question 13. Why are Alkenes called olefins?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Alkenes are commonly known as olefins because the lower members form oily products on treatment with chlorine or bromine.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-14-which-is-more-acidic-ethene-or-ethyne-and-why\"><\/span><strong>Question 14. Which is more acidic: ethene or ethyne and why?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong> Ethyne is more acidic than ethene because it has \u2018sp\u2019 hybridized \u2018C\u2019 which is more electronegative.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-15-what-is-huckel%e2%80%99s-rule\"><\/span><strong>Question 15. What is Huckel&#8217;s rule?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>Huckel rule states that a compound is said to be aromatic if it has (4n + 2) n electrons<br \/>delocalized where n = an integer 0,1, 2, 3,<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-16-how-will-you-distinguish-between-propene-and-propane\"><\/span><strong>Question 16. How will you distinguish between propene and propane?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>Pass them through a dilute cold KMnO4 solution\u00a0(purple) or Br<sub>2<\/sub>\u00a0in CCl<sub>4<\/sub> solution (red). Propene will decolorize both the solutions but propane does not react.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-17-how-will-you-distinguish-between-acetylene-and-ethylene\"><\/span><strong>Question 17. How will you distinguish between acetylene and ethylene?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>Acetylene forms a precipitate with ammoniacal silver nitrate solution, ethylene does not react with these reagents.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-18-what-happens-when-benzene-is-treated-with-acetyl-chloride-in-the-presence-of-alcl3\"><\/span><strong>Question 18. What happens when benzene is treated with acetyl chloride in the presence of AlCl<sub>3<\/sub>?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0Acetophenone is formed.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-19-which-type-of-isomerism-is-exhibited-by-but-l-one-and-but-2-one\"><\/span><strong>Question 19. Which type of isomerism is exhibited by but-l-one and but-2-one?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>Position isomerism.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-20-what-is-electrophile-in-sulphonation\"><\/span><strong>Question 20. What is electrophile in sulphonation?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>SO<sub>3<\/sub>.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-21-what-is-the-hybridization-of-central-carbon-in-12-propadiene-ch2cch2\"><\/span><strong>Question 21. What is the hybridization of central carbon in 1,2-propadiene (CH<sub>2<\/sub>=C=CH<sub>2<\/sub>)?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0sp.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-22-what-are-arenes\"><\/span><strong>Question 22. What are Arenes?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>Arenes are aromatic hydrocarbons.<\/p>\n<p>We have covered the complete guide on\u00a0<a href=\"http:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener noreferrer\">CBSE<\/a>\u00a0NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons Structure Of Atom. Feel free to ask us any questions in the comment section below.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"faq-ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons-structure-of-atom\"><\/span>FAQ: NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons Structure Of Atom<span class=\"ez-toc-section-end\"><\/span><\/h3>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1627561279348\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-download-ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons-structure-of-atom-pdf-for-free\"><\/span>Can I download NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons Structure Of Atom PDF for free? <span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, you can download NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons Structure Of Atom PDF free. <\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1627561298697\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-are-aromatic-hydrocarbons\"><\/span>What are aromatic hydrocarbons? <span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Those hydrocarbons formed by Benzene and its derivatives are known as aromatic hydrocarbons.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1627561299874\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-are-the-benefits-of-studying-from-ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons\"><\/span>What are the <strong>Benefits of Studying from NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons<\/strong>? <span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can refer to the above article to get the Benefits of Studying from NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons. <\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1627561305449\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-will-i-learn-in-ncert-solutions-for-class-11-chemistry-chapter-13-hydrocarbons\"><\/span>What will I learn in NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can refer to the above article to know the learnings of NCERT Solutions for Class 11 Chemistry Chapter 13\u00a0Hydrocarbons.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 11 Chemistry Chapter 13 Hydrocarbons: NCERT solutions help students understand complex concepts in a better way. NCERT Solutions for Class 11 Chemistry Chapter 13 is Hydrocarbons. And NCERT solutions include all the topics in the chapter with in-depth explanations for the same. So, going through the solutions will help you to &#8230; <a title=\"Class 11 Chemistry NCERT Solutions 2023 for Chapter 13\u00a0Hydrocarbons\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-class-11-chemistry-chapter-13\/\" aria-label=\"More on Class 11 Chemistry NCERT Solutions 2023 for Chapter 13\u00a0Hydrocarbons\">Read more<\/a><\/p>\n","protected":false},"author":249,"featured_media":109997,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73413,73694],"tags":[3428,76512,76520],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/55750"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/249"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=55750"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/55750\/revisions"}],"predecessor-version":[{"id":376863,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/55750\/revisions\/376863"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/109997"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=55750"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=55750"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=55750"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}