{"id":55572,"date":"2023-05-13T18:14:00","date_gmt":"2023-05-13T12:44:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=55572"},"modified":"2025-07-12T12:15:16","modified_gmt":"2025-07-12T06:45:16","slug":"ncert-solutions-for-chemistry-chapter-4","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/","title":{"rendered":"Class 11 Chemistry NCERT Solutions 2026 For Chapter 4 Chemical Bonding And Molecular Structure"},"content":{"rendered":"\n<p>\u00a0<\/p>\n<p><img class=\"alignnone size-full wp-image-109911\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure.jpg\" alt=\"NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure:\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/> <strong>NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure<\/strong>: Students often feel overwhelmed when they start with their chemistry textbook at the beginning of their session. The chapters and syllabus might sound familiar with the previous class\u2019s curriculum, however, the concepts get elaborate descriptions thus making the topics more complicated isn\u2019t it? Seeking out the references book is the best thing that you can do. So we bring you the best choice here that is the NCERT Solutions For Chemistry Chapter 4.<\/p>\n<ul>\n<li><a href=\"https:\/\/www.kopykitab.com\/blog\/cbse-class-11-chemistry-ncert-solutions\/\" target=\"_blank\" rel=\"noopener noreferrer\">NCERT Solutions For 11th Chemistry All Chapters<\/a><\/li>\n<\/ul>\n<p>Chemistry is a pretty important subject that determines your robust future for an aspiring goal ahead. Therefore taking note down from classroom lectures and reading the only textbook prescribed by your school won\u2019t help you that much. Additionally, class 11 is the initial level to begin your ultimate preparation for your 12th grade. If students pass their 11th standard effortlessly, then there are high chances of scoring excellently in their 12th boards. Therefore taking guidance from a solid reference book is your conclusive solution.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69ead0c0511f0\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69ead0c0511f0\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#ncert-solutions-for-chemistry-chapter-4-chemical-bonding-and-molecular-structure\" title=\"NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure\">NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#what-will-you-learn-in-ncert-solutions-for-chemistry-chapter-4\" title=\"What will you learn in NCERT Solutions For Chemistry Chapter 4?\">What will you learn in NCERT Solutions For Chemistry Chapter 4?<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#ncert-solutions-for-chemistry-chapter-4-chemical-bonding-and-molecular-structure-subtopics-that-are-followed-in-this-chapter-are\" title=\"NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure Subtopics that are followed in this chapter are-\">NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure Subtopics that are followed in this chapter are-<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#benefits-of-ncert-solutions-for-chemistry-chapter-4\" title=\"Benefits of NCERT Solutions For Chemistry Chapter 4\">Benefits of NCERT Solutions For Chemistry Chapter 4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#access-ncert-solutions-for-chemistry-chapter-4\" title=\"Access NCERT Solutions For Chemistry Chapter 4\">Access NCERT Solutions For Chemistry Chapter 4<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-1-explain-the-formation-of-a-chemical-bond\" title=\"Question 1. Explain the formation of a chemical bond.\">Question 1. Explain the formation of a chemical bond.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-2write-lewis-dot-symbols-for-atoms-of-the-following-elements-mg-na-b-o-n-br\" title=\"Question 2.Write Lewis dot symbols for atoms of the following elements: Mg, Na, B, O, N, Br.\">Question 2.Write Lewis dot symbols for atoms of the following elements: Mg, Na, B, O, N, Br.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-3-write-lewis-symbols-for-the-following-atoms-and-ions-s-and-s2%e2%80%93-al-and-al3-h-and-h%e2%80%93\" title=\"Question 3. Write Lewis symbols for the following atoms and ions: S and\u00a0S2\u2013 ; Al and\u00a0Al3+; H and H\u2013\">Question 3. Write Lewis symbols for the following atoms and ions: S and\u00a0S2\u2013 ; Al and\u00a0Al3+; H and H\u2013<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-4-draw-the-lewis-structures-for-the-following-molecules-and-ions-h2s-sicl4-bef2-c032-hcooh\" title=\"Question 4. Draw the Lewis structures for the following molecules and ions: H2S, SiCl4 ,\u00a0BeF2, C032-, HCOOH\">Question 4. Draw the Lewis structures for the following molecules and ions: H2S, SiCl4 ,\u00a0BeF2, C032-, HCOOH<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-5-define-octet-rule-write-its-significance-and-limitations\" title=\"Question 5. Define Octet rule. Write its significance and limitations.\">Question 5. Define Octet rule. Write its significance and limitations.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-6-write-the-favourable-factors-for-the-formation-of-ionic-bond\" title=\"Question 6. Write the favourable factors for the formation of ionic bond.\">Question 6. Write the favourable factors for the formation of ionic bond.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-7-discuss-the-shape-of-the-following-molecules-using-the-vsepr-model-becl2-bcl3-sicl4-asf5-h2s-ph3\" title=\"Question 7. Discuss the shape of the following molecules using the VSEPR model: BeCl2, BCl3\u00a0, SiCl4, AsF5, H2S, PH3\">Question 7. Discuss the shape of the following molecules using the VSEPR model: BeCl2, BCl3\u00a0, SiCl4, AsF5, H2S, PH3<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-8-although-geometries-of-nh3-and-h20-molecules-are-distorted-tetrahedral-bond-angle-in-water-is-less-than-that-of-ammonia-discuss\" title=\"Question 8. Although geometries of NH3\u00a0and H20 molecules are distorted tetrahedral, bond angle in water is less than that of ammonia. Discuss.\">Question 8. Although geometries of NH3\u00a0and H20 molecules are distorted tetrahedral, bond angle in water is less than that of ammonia. Discuss.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-9-how-do-you-express-the-bond-strength-in-terms-of-bond-order\" title=\"Question 9. How do you express the bond strength in terms of bond order?\">Question 9. How do you express the bond strength in terms of bond order?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-10-define-the-bond-length\" title=\"Question 10. Define the bond-length.\">Question 10. Define the bond-length.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-11-explain-the-important-aspects-of-resonance-with-reference-to-the-c032-ion\" title=\"Question 11. Explain the important aspects of resonance with reference to the\u00a0C032-ion.\">Question 11. Explain the important aspects of resonance with reference to the\u00a0C032-ion.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-17\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-12-h3po3-can-be-represented-by-structures-1-and-2-shown-below-can-these-two-structures-be-taken-as-the-canonical-forms-of-the-resonance-hybrid-representing-h3po3-if-not-give-reasons-for-the-same\" title=\"Question 12. H3PO3\u00a0can be represented by structures 1 and 2 shown below. Can these two structures be taken as the canonical forms of the resonance hybrid representing\u00a0H3PO3? If not, give reasons for the same. \">Question 12. H3PO3\u00a0can be represented by structures 1 and 2 shown below. Can these two structures be taken as the canonical forms of the resonance hybrid representing\u00a0H3PO3? If not, give reasons for the same. <\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-18\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-13-write-the-resonance-structures-for-so3no2-and-no3\" title=\"Question 13. Write the resonance structures for SO3,NO2\u00a0and NO3\">Question 13. Write the resonance structures for SO3,NO2\u00a0and NO3<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-19\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-14-use-lewis-symbols-to-show-electron-transfer-between-the-following-atoms-to-form-cations-and-anions-a-k-and-s-b-ca-and-o-c-al-and-n\" title=\"Question 14. Use Lewis symbols to show electron transfer between the following atoms to form cations and anions (a) K and S (b) Ca and O (c) Al and N.\">Question 14. Use Lewis symbols to show electron transfer between the following atoms to form cations and anions (a) K and S (b) Ca and O (c) Al and N.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-20\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-15-although-both-co2-and-h2o-are-triatomic-molecules-the-shape-of-h2o-molecule-is-bent-while-that-of-co2-is-linear-explain-this-on-the-basis-of-dipole-moment\" title=\"Question 15. Although both CO2\u00a0and H2O are triatomic molecules, the shape of H2O molecule is bent while that of CO2\u00a0is linear. Explain this on the basis of dipole moment.\">Question 15. Although both CO2\u00a0and H2O are triatomic molecules, the shape of H2O molecule is bent while that of CO2\u00a0is linear. Explain this on the basis of dipole moment.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-21\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-16-write-the-significanceapplications-of-dipole-moment\" title=\"Question 16. Write the significance\/applications of dipole moment.\">Question 16. Write the significance\/applications of dipole moment.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-22\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-17-define-electronegativity-how-does-it-differ-from-electron-gain-enthalpy\" title=\"Question 17. Define electronegativity. How does it differ from electron gain enthalpy?\">Question 17. Define electronegativity. How does it differ from electron gain enthalpy?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-23\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-18-explain-with-the-help-of-suitable-example-polar-covalent-bond\" title=\"Question 18. Explain with the help of suitable example polar covalent bond.\">Question 18. Explain with the help of suitable example polar covalent bond.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-24\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-19-arrange-the-bonds-in-order-of-increasing-ionic-character-in-the-molecules-lif-k2o-n2-so2-and-clf3\" title=\"Question 19. Arrange the bonds in order of increasing ionic character in the molecules: LiF, K2O, N2, SO2\u00a0and ClF3.\">Question 19. Arrange the bonds in order of increasing ionic character in the molecules: LiF, K2O, N2, SO2\u00a0and ClF3.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-25\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-20-the-skeletal-structure-of-ch3cooh-as-shown-below-is-correct-but-some-of-the-bonds-are-shown-incorrectly-write-the-correct-lewis-structure-for-acetic-acid\" title=\"Question 20. The skeletal structure of\u00a0CH3COOH\u00a0as shown below is correct, but some of the bonds are shown incorrectly. Write the correct Lewis structure for acetic acid. \">Question 20. The skeletal structure of\u00a0CH3COOH\u00a0as shown below is correct, but some of the bonds are shown incorrectly. Write the correct Lewis structure for acetic acid. <\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-26\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-21-apart-from-tetrahedral-geometry-another-possible-geometry-for-ch4-is-square-planar-with-the-four-h-atoms-at-the-comers-of-the-square-and-the-c-atom-at-its-centre-explain-why-ch4-is-not-square-planar\" title=\"Question 21. Apart from tetrahedral geometry, another possible geometry for CH4\u00a0is square planar with the four H atoms at the comers of the square and the C atom at its centre. Explain why CH4\u00a0is not square planar?\">Question 21. Apart from tetrahedral geometry, another possible geometry for CH4\u00a0is square planar with the four H atoms at the comers of the square and the C atom at its centre. Explain why CH4\u00a0is not square planar?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-27\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-22-explain-why-beh2-molecule-has-a-zero-dipole-moment-although-the-be%e2%80%94h-bonds-are-polar\" title=\"Question 22. Explain why BeH2\u00a0molecule has a zero dipole moment although the Be\u2014H bonds are polar.\">Question 22. Explain why BeH2\u00a0molecule has a zero dipole moment although the Be\u2014H bonds are polar.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-28\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-23-which-out-of-nh3-and-nf3-has-higher-dipole-moment-and-why\" title=\"Question 23. Which out of NH3\u00a0and NF3\u00a0has higher dipole moment and why?\">Question 23. Which out of NH3\u00a0and NF3\u00a0has higher dipole moment and why?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-29\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-24-what-is-meant-by-hybridisation-of-atomic-orbitals-describe-the-shapes-of-sp-sp2-sp3-hybrid-orbitals\" title=\"Question 24. What is meant by hybridisation of atomic orbitals? Describe the shapes of sp, sp2, sp3\u00a0hybrid orbitals.\">Question 24. What is meant by hybridisation of atomic orbitals? Describe the shapes of sp, sp2, sp3\u00a0hybrid orbitals.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-30\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-25-describe-the-change-in-hybridisation-if-any-of-the-al-atom-in-the-following-reaction-alcl3-cl%e2%80%93-%e2%80%94%e2%80%94%3e-alcl4\" title=\"Question 25. Describe the change in hybridisation (if any) of the Al atom in the following reaction. AlCl3\u00a0+ Cl\u2013\u00a0\u2014\u2014&gt; AlCl4-\u00a0.\">Question 25. Describe the change in hybridisation (if any) of the Al atom in the following reaction. AlCl3\u00a0+ Cl\u2013\u00a0\u2014\u2014&gt; AlCl4-\u00a0.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-31\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-26-is-there-any-change-in-the-hybridisation-of-b-and-n-atoms-as-a-result-of-the-following-reaction-bf3-nh3-%e2%80%94%e2%80%94-%3e-f3-bnh3\" title=\"Question 26. Is there any change in the hybridisation of B and N atoms as a result of the following reaction ? BF3\u00a0+ NH3\u00a0\u2014\u2014-&gt; F3\u00a0B.NH3\">Question 26. Is there any change in the hybridisation of B and N atoms as a result of the following reaction ? BF3\u00a0+ NH3\u00a0\u2014\u2014-&gt; F3\u00a0B.NH3<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-32\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-27-draw-diagrams-showing-the-formation-of-a-double-bond-and-a-triple-bond-between-carbon-atoms-in-c2-h4-and-c2-h2-molecules\" title=\"Question 27. Draw diagrams showing the formation of a double bond and a triple bond between carbon atoms in\u00a0C2\u00a0H4\u00a0and\u00a0C2\u00a0H2\u00a0molecules.\">Question 27. Draw diagrams showing the formation of a double bond and a triple bond between carbon atoms in\u00a0C2\u00a0H4\u00a0and\u00a0C2\u00a0H2\u00a0molecules.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-33\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-28-what-is-the-total-number-of-sigma-and-pi-bonds-in-the-following-molecules-a-c2-h2-b-c2-h4\" title=\"Question 28. What is the total number of sigma and pi bonds in the following molecules? (a) C2\u00a0H2\u00a0(b) C2\u00a0H4\">Question 28. What is the total number of sigma and pi bonds in the following molecules? (a) C2\u00a0H2\u00a0(b) C2\u00a0H4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-34\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-29-considering-x-axis-as-the-intemuclear-axis-which-out-of-the-following-will-not-form-a-sigma-bond-and-why-a-is-and-is-b-is-and-2px-c-2py-and-2py-d-is-and-2s\" title=\"Question 29. Considering X-axis as the intemuclear axis which out of the following will not form a sigma bond and why? (a) Is and Is (b) Is and\u00a02px\u00a0(c)\u00a02py\u00a0and 2py\u00a0(d) Is and 2s\">Question 29. Considering X-axis as the intemuclear axis which out of the following will not form a sigma bond and why? (a) Is and Is (b) Is and\u00a02px\u00a0(c)\u00a02py\u00a0and 2py\u00a0(d) Is and 2s<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-35\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-30-which-hybrid-orbitals-are-used-by-carbon-atoms-in-the-following-molecules-a-ch3-ch3-b-ch3-ch-ch2-c-ch3-ch2-oh-d-ch3-cho-e-ch3cooh\" title=\"Question 30. Which hybrid orbitals are used by carbon atoms in the following molecules? (a) CH3-CH3\u00a0(b) CH3-CH = CH2\u00a0(c) CH3-CH2-OH (d) CH3-CHO (e) CH3COOH.\">Question 30. Which hybrid orbitals are used by carbon atoms in the following molecules? (a) CH3-CH3\u00a0(b) CH3-CH = CH2\u00a0(c) CH3-CH2-OH (d) CH3-CHO (e) CH3COOH.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-36\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-31-what-do-you-understand-by-bond-pairs-and-lone-pairs-of-electrons-illustrate-by-giving-one-example-of-each-type\" title=\"Question 31. What do you understand by bond pairs and lone pairs of electrons? Illustrate by giving one example of each type.\">Question 31. What do you understand by bond pairs and lone pairs of electrons? Illustrate by giving one example of each type.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-37\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-32-distinguish-between-a-sigma-bond-and-a-pi-bond\" title=\"Question 32. Distinguish between a sigma bond and a pi bond.\">Question 32. Distinguish between a sigma bond and a pi bond.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-38\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-33-explain-the-formation-of-h2-molecule-on-the-basis-of-valence-bond-theory\" title=\"Question 33. Explain the formation of\u00a0H2\u00a0molecule on the basis of valence bond theory.\">Question 33. Explain the formation of\u00a0H2\u00a0molecule on the basis of valence bond theory.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-39\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-34-write-the-important-conditions-required-for-the-linear-combination-of-atomic-orbitals-to-form-molecular-orbitals\" title=\"Question 34. Write the important conditions required for the linear combination of atomic orbitals to form molecular orbitals.\">Question 34. Write the important conditions required for the linear combination of atomic orbitals to form molecular orbitals.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-40\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-35-use-molecular-orbital-theory-to-explain-why-the-be2-molecule-does-not-exist\" title=\"Question 35. Use molecular orbital theory to explain why the Be2\u00a0molecule does not exist.\">Question 35. Use molecular orbital theory to explain why the Be2\u00a0molecule does not exist.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-41\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-36-compare-the-relative-stability-of-the-following-species-and-indicate-their-magnetic-properties-o2-o2-o2%e2%80%93-superoxideo22-peroxide\" title=\"Question 36. Compare the relative stability of the following species and indicate their magnetic properties: O2, O2, O2\u2013\u00a0(Superoxide),O22-\u00a0(peroxide)\">Question 36. Compare the relative stability of the following species and indicate their magnetic properties: O2, O2, O2\u2013\u00a0(Superoxide),O22-\u00a0(peroxide)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-42\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-37-write-the-significance-of-plus-and-minus-sign-in-representing-the-orbitals\" title=\"Question 37. Write the significance of plus and minus sign in representing the orbitals,\">Question 37. Write the significance of plus and minus sign in representing the orbitals,<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-43\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-38-describe-the-hybridisation-in-case-of-pcl5-why-are-the-axial-bonds-longer-as-compared-to-equatorial-bonds\" title=\"Question 38. Describe the hybridisation in case of\u00a0PCl5. Why are the axial bonds longer as compared to equatorial bonds?\">Question 38. Describe the hybridisation in case of\u00a0PCl5. Why are the axial bonds longer as compared to equatorial bonds?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-44\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-39-define-hydrogen-bonds-is-it-weaker-or-stronger-than-the-van-der-waals-forces\" title=\"Question 39. Define hydrogen bonds. Is it weaker or stronger than the van der Waals forces?\">Question 39. Define hydrogen bonds. Is it weaker or stronger than the van der Waals forces?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-45\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-40-what-is-meant-by-the-term-bond-order-calculate-the-bond-order-of-n2-o2-o2o2%e2%80%93\" title=\"Question 40. What is meant by the term bond order? Calculate the bond order of N2, O2, O2+,O2\u2013\">Question 40. What is meant by the term bond order? Calculate the bond order of N2, O2, O2+,O2\u2013<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-46\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#more-questions-solved\" title=\"MORE QUESTIONS SOLVED\">MORE QUESTIONS SOLVED<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-47\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#i-very-short-answer-type-questions-question-1-how-is-bond-order-related-to-the-stability-of-a-molecule\" title=\"I. Very Short Answer Type Questions Question 1. How is bond order related to the stability of a molecule?\">I. Very Short Answer Type Questions Question 1. How is bond order related to the stability of a molecule?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-48\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-2-write-the-type-of-hybridisation-involved-in-ch4c2h4-and-c2h2\" title=\"Question 2. Write the type of hybridisation involved in\u00a0CH4,C2H4\u00a0and C2H2.\">Question 2. Write the type of hybridisation involved in\u00a0CH4,C2H4\u00a0and C2H2.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-49\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-3-out-of-sigma-and-%ce%a0-bonds-which-one-is-stronger-and-why\" title=\"Question 3. Out of sigma and \u03a0 bonds, which one is stronger and why?\">Question 3. Out of sigma and \u03a0 bonds, which one is stronger and why?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-50\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-4-write-the-lewis-dot-symbols-of-the-following-elements-and-predict-their-valences-i-cl-ii-p\" title=\"Question 4. Write the Lewis dot symbols of the following elements and predict their valences. (i) Cl (ii) P\">Question 4. Write the Lewis dot symbols of the following elements and predict their valences. (i) Cl (ii) P<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-51\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-5-predict-the-shapes-of-the-following-molecules-using-vsepr-theory-i-becl2ii-sicl4\" title=\"Question 5. Predict the shapes of the following molecules using VSEPR theory? (i) BeCl2(ii) SiCl4\">Question 5. Predict the shapes of the following molecules using VSEPR theory? (i) BeCl2(ii) SiCl4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-52\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-6-write-the-state-of-hybridisation-of-boron-in-bf3\" title=\"Question 6. Write the state of hybridisation of boron in\u00a0BF3.\">Question 6. Write the state of hybridisation of boron in\u00a0BF3.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-53\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-7-arrange-o2o2%e2%80%93o22-o2in-increasing-order-of-bond-energy\" title=\"Question 7. Arrange\u00a0O2,O2\u2013,O22-, O2+in increasing order of bond energy.\u00a0\">Question 7. Arrange\u00a0O2,O2\u2013,O22-, O2+in increasing order of bond energy.\u00a0<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-54\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-8-what-is-meant-by-bond-pairs-of-electrons\" title=\"Question 8. What is meant by bond pairs of electrons?\">Question 8. What is meant by bond pairs of electrons?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-55\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-9-which-of-the-following-has-larger-bond-angle-in-each-pair-i-co2-bf3-ii-nh3-ch4\" title=\"Question 9. Which of the following has larger bond angle in each pair? (i) CO2, BF3\u00a0(ii) NH3,\u00a0CH4\">Question 9. Which of the following has larger bond angle in each pair? (i) CO2, BF3\u00a0(ii) NH3,\u00a0CH4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-56\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-11-define-covalent-bond-according-to-orbital-concept\" title=\"Question 11. Define covalent bond according to orbital concept?\">Question 11. Define covalent bond according to orbital concept?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-57\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-12-why-b2-is-paramagnetic-in-nature-while-c2-is-not\" title=\"Question 12. Why\u00a0B2\u00a0is paramagnetic in nature while C2\u00a0is not?\">Question 12. Why\u00a0B2\u00a0is paramagnetic in nature while C2\u00a0is not?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-58\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-13-why-ethyl-alcohol-is-completely-miscible-with-water\" title=\"Question 13. Why ethyl alcohol is completely miscible with water?\">Question 13. Why ethyl alcohol is completely miscible with water?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-59\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-14-which-is-more-polar-co2-or-n2o-give-reason\" title=\"Question 14. Which is more polar CO2\u00a0or\u00a0N2O? Give reason.\">Question 14. Which is more polar CO2\u00a0or\u00a0N2O? Give reason.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-60\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-15-state-the-types-of-hybrid-orbitals-associated-with-i-p-in-pcl5-and-ii-s-in-sf6\" title=\"Question 15. State the types of hybrid orbitals associated with (i) P in PCl5\u00a0and (ii) S in\u00a0SF6\">Question 15. State the types of hybrid orbitals associated with (i) P in PCl5\u00a0and (ii) S in\u00a0SF6<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-61\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-16-why-n2-is-more-stable-than-o2-explain-on-the-basis-of-molecular-orbital-theory\" title=\"Question 16. Why\u00a0N2\u00a0is more stable than O2? Explain on the basis of molecular orbital theory.\">Question 16. Why\u00a0N2\u00a0is more stable than O2? Explain on the basis of molecular orbital theory.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-62\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-17-how-is-bond-order-related-to-bond-length-of-a-molecule\" title=\"Question 17. How is bond order related to bond length of a molecule?\">Question 17. How is bond order related to bond length of a molecule?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-63\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-18-out-of-bonding-and-antibonding-molecular-orbitals-which-one-has-lower-energy-and-which-one-has-higher-stability\" title=\"Question 18. Out of bonding and antibonding molecular orbitals, which one has lower energy and which one has higher stability?\">Question 18. Out of bonding and antibonding molecular orbitals, which one has lower energy and which one has higher stability?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-64\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-19-define-antibonding-molecular-orbital\" title=\"Question 19. Define antibonding molecular orbital.\">Question 19. Define antibonding molecular orbital.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-65\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-20-name-the-two-conditions-which-must-be-satisfied-for-hydrogen-bonding-to-take-place-in-a-molecule\" title=\"Question 20. Name the two conditions which must be satisfied for hydrogen bonding to take place in a molecule.\">Question 20. Name the two conditions which must be satisfied for hydrogen bonding to take place in a molecule.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-66\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#ii-short-answer-type-questions-question-1what-is-an-electrovalent-or-ionic-bond-explain-its-formation-with-two-examples\" title=\"II. Short Answer Type Questions Question\u00a01.What is an electrovalent (or ionic) bond? Explain its formation with two examples.\">II. Short Answer Type Questions Question\u00a01.What is an electrovalent (or ionic) bond? Explain its formation with two examples.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-67\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-2-what-are-lewis-structures-write-the-lewis-structure-of-h2-bef2-and-h2o\" title=\"Question 2. What are Lewis structures? Write the Lewis structure of\u00a0H2, BeF2\u00a0and\u00a0H2O.\">Question 2. What are Lewis structures? Write the Lewis structure of\u00a0H2, BeF2\u00a0and\u00a0H2O.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-68\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-3-define-lattice-energy-how-is-lattice-energy-influenced-by-i-charge-on-the-ions-ii-size-of-the-ions\" title=\"Question 3. Define Lattice energy. How is Lattice energy influenced by (i) Charge on the ions (ii) Size of the ions?\">Question 3. Define Lattice energy. How is Lattice energy influenced by (i) Charge on the ions (ii) Size of the ions?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-69\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-4-give-the-shapes-of-the-following-molecules-i-ab3-ii-ab4\" title=\"Question 4. Give the shapes of the following molecules: (i) AB3 (ii) AB4\">Question 4. Give the shapes of the following molecules: (i) AB3 (ii) AB4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-70\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-5-define-hybridisation-explain-sp-hybridisation-with-suitable-example\" title=\"Question 5. Define Hybridisation. Explain sp hybridisation with suitable example.\">Question 5. Define Hybridisation. Explain sp hybridisation with suitable example.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-71\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-6-account-for-the-following-i-water-is-a-liquid-while-h2s-is-a-gas-ii-nh3-has-higher-boiling-point-than-ph3\" title=\"Question 6. Account for the following: (i) Water is a liquid while H2S is a gas (ii) NH3\u00a0has higher boiling point than PH3.\">Question 6. Account for the following: (i) Water is a liquid while H2S is a gas (ii) NH3\u00a0has higher boiling point than PH3.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-72\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-7-what-do-you-mean-by-dipole-moment-draw-the-dipole-diagram-of-h2o\" title=\"Question 7. What do you mean by Dipole moment? Draw the dipole diagram of H2O.\">Question 7. What do you mean by Dipole moment? Draw the dipole diagram of H2O.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-73\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-8-what-are-the-main-postulates-of-valence-shell-electron-pair-repulsion-vsepr-theory\" title=\"Question 8. What are the main postulates of Valence Shell Electron Pair Repulsion (VSEPR) theory?\">Question 8. What are the main postulates of Valence Shell Electron Pair Repulsion (VSEPR) theory?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-74\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-9-define-bond-order-how-is-it-related-to-the-stability-of-a-molecule\" title=\"Question 9. Define bond order. How is it related to the stability of a molecule?\">Question 9. Define bond order. How is it related to the stability of a molecule?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-75\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-10-explain-the-diamagnetic-behaviour-of-p2-molecule-on-the-basis-of-molecular-orbital-theory\" title=\"Question 10. Explain the diamagnetic behaviour of\u00a0P2\u00a0molecule on the basis of molecular orbital theory.\">Question 10. Explain the diamagnetic behaviour of\u00a0P2\u00a0molecule on the basis of molecular orbital theory.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-76\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#iii-long-answer-type-questions-question-1-a-explain-the-formation-of-ionic-bond-with-two-examples-b-discuss-the-conditions-which-favour-the-formation-of-ionic-bond\" title=\"III. Long Answer Type Questions Question 1. (a) Explain the formation of ionic bond with two examples. (b) Discuss the conditions which favour the formation of ionic bond.\">III. Long Answer Type Questions Question 1. (a) Explain the formation of ionic bond with two examples. (b) Discuss the conditions which favour the formation of ionic bond.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-77\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-2-a-define-dipole-moment-what-are-the-units-of-dipole-moment-b-dipole-moment-values-help-in-predicting-the-shapes-of-covalent-molecules-explain\" title=\"Question 2. (a) Define dipole moment. What are the units of dipole moment? (b) Dipole moment values help in predicting the shapes of covalent molecules. Explain.\">Question 2. (a) Define dipole moment. What are the units of dipole moment? (b) Dipole moment values help in predicting the shapes of covalent molecules. Explain.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-78\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-3-discuss-the-orbital-structures-of-the-following-molecules-on-the-basis-of-hybridisation-i-bh3-ii-c2h2\" title=\"Question 3. Discuss the orbital structures of the following molecules on the basis of hybridisation, (i) BH3\u00a0(ii) C2H2\">Question 3. Discuss the orbital structures of the following molecules on the basis of hybridisation, (i) BH3\u00a0(ii) C2H2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-79\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#question-4-a-how-many-a-and-n-bonds-are-present-in-b-why-hf-is-more-stable-than-h2-c-why-is-b2-molecule-paramagnetic\" title=\"Question 4. (a) How many a and n bonds are present in  (b) Why Hf is more stable than H2? (c) Why is B2\u00a0molecule paramagnetic?\">Question 4. (a) How many a and n bonds are present in  (b) Why Hf is more stable than H2? (c) Why is B2\u00a0molecule paramagnetic?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-80\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#iv-multiple-choice-questions-question-1-a-co-ordinate-bond-is-formed-by-asharing-of-electrons-contributed-by-both-the-atoms-bcomplete-transfer-of-electrons-csharing-of-electrons-contributed-by-one-atom-only-d-none-of-these-question-2-the-species-co-cn%e2%80%93and-n2are-a-isoelectronic-b-having-coordinated-bond-chaving-polar-bond-d-having-low-bond-energies-question-3-the-axial-overlap-between-the-two-orbitals-leads-to-the-formation-of-a-a-sigma-bond-b-pi-bond-c-multiple-bond-d-none-of-these-question-4-in-s02-molecule-s-atom-is-asp3-hybridized-b-sp-hybridized-c-sp2-hybridized-d-d-sp2-hybridized-question-5-a-molecule-or-ion-is-stable-if-a-nb-na-b-nb-%3c-na-c-na-%3c-nb-d-na-%e2%80%93-nb-ve-question-6-the-molecule-ne2-does-not-exist-because-a-nb-%3e-na-b-nb-na-c-nb-%3c-na-d-none-of-these-question-7-which-one-is-diamagnetic-among-no-no-and-no-anob-no-c-no%e2%80%93d-none-of-these-question-8-in-sp3-sp2-and-sp-hybridized-carbon-atom-the-p-character-is-maximum-in-a-sp3-b-sp2-c-sp-d-all-of-the-above-have-same-p-character-question-9-out-of-the-following-intramolecular-hydrogen-bonding-exists-in-a-water-bh2s-c-4-nitrophenol-d-2-nitrophenol\" title=\"IV. Multiple Choice Questions Question 1. A co-ordinate bond is formed by: (a)sharing of electrons contributed by both the atoms (b)complete transfer of electrons (c)sharing of electrons contributed by one atom only (d) none of these Question 2. The species CO, CN\u2013and N2are: (a) isoelectronic (b) having coordinated bond (c)having polar bond (d) having low bond energies Question 3. The axial overlap between the two orbitals leads to the formation of a: (a) sigma bond (b) pi bond (c) multiple bond (d) none of these Question 4. In\u00a0S02\u00a0molecule, S atom is: (a)sp3\u00a0hybridized (b) sp hybridized (c) sp2\u00a0hybridized (d) d\u00a0sp2\u00a0hybridized Question 5. A molecule or ion is stable if: (a) Nb = Na (b) Nb &lt; Na (c) Na &lt; Nb (d) Na \u2013 Nb = + ve Question 6. The molecule Ne2 does not exist because (a) Nb &gt; Na (b) Nb = Na + (c) Nb &lt; Na (d) None of these Question 7. Which one is diamagnetic among NO+, NO and NO ? (a)NO+(b) NO (c)\u00a0NO\u2013(d) None of these Question 8. In sp3, sp2\u00a0and sp hybridized carbon atom, the p character is maximum in: (a) sp3\u00a0(b) sp2 (c) sp (d) all of the above have same p-character Question 9. Out of the following, intramolecular hydrogen bonding exists in: (a) water (b)H2S\u00a0(c) 4-nitrophenol (d) 2-nitrophenol\">IV. Multiple Choice Questions Question 1. A co-ordinate bond is formed by: (a)sharing of electrons contributed by both the atoms (b)complete transfer of electrons (c)sharing of electrons contributed by one atom only (d) none of these Question 2. The species CO, CN\u2013and N2are: (a) isoelectronic (b) having coordinated bond (c)having polar bond (d) having low bond energies Question 3. The axial overlap between the two orbitals leads to the formation of a: (a) sigma bond (b) pi bond (c) multiple bond (d) none of these Question 4. In\u00a0S02\u00a0molecule, S atom is: (a)sp3\u00a0hybridized (b) sp hybridized (c) sp2\u00a0hybridized (d) d\u00a0sp2\u00a0hybridized Question 5. A molecule or ion is stable if: (a) Nb = Na (b) Nb &lt; Na (c) Na &lt; Nb (d) Na \u2013 Nb = + ve Question 6. The molecule Ne2 does not exist because (a) Nb &gt; Na (b) Nb = Na + (c) Nb &lt; Na (d) None of these Question 7. Which one is diamagnetic among NO+, NO and NO ? (a)NO+(b) NO (c)\u00a0NO\u2013(d) None of these Question 8. In sp3, sp2\u00a0and sp hybridized carbon atom, the p character is maximum in: (a) sp3\u00a0(b) sp2 (c) sp (d) all of the above have same p-character Question 9. Out of the following, intramolecular hydrogen bonding exists in: (a) water (b)H2S\u00a0(c) 4-nitrophenol (d) 2-nitrophenol<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-81\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#faq-ncert-solutions-for-chemistry-chapter-4\" title=\"FAQ: NCERT Solutions For Chemistry Chapter 4\">FAQ: NCERT Solutions For Chemistry Chapter 4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-82\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#are-ncert-solutions-for-chemistry-chapter-4-difficult-to-understand\" title=\"Are NCERT Solutions For Chemistry Chapter 4 difficult to understand?\">Are NCERT Solutions For Chemistry Chapter 4 difficult to understand?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-83\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#can-i-download-ncert-solutions-for-class-11-chemistry-chapter-4-pdf-for-free\" title=\"Can I download NCERT Solutions for Class 11 Chemistry Chapter 4 PDF for free? \">Can I download NCERT Solutions for Class 11 Chemistry Chapter 4 PDF for free? <\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-84\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#what-is-the-name-of-ncert-solutions-for-chemistry-chapter-4\" title=\"What is the name of NCERT Solutions For Chemistry Chapter 4? \">What is the name of NCERT Solutions For Chemistry Chapter 4? <\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-85\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#what-are-the-topics-included-in-ncert-solutions-for-chemistry-chapter-4\" title=\"What are the topics included in NCERT Solutions For Chemistry Chapter 4? \">What are the topics included in NCERT Solutions For Chemistry Chapter 4? <\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-86\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/#what-are-the-ncert-solutions-for-chemistry-chapter-4-chemical-bonding-and-molecular-structure-subtopics\" title=\"What are the NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure Subtopics? \">What are the NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure Subtopics? <\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"ncert-solutions-for-chemistry-chapter-4-chemical-bonding-and-molecular-structure\"><\/span><strong>NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>So to begin with an easy exposition, start with our NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure right now. The easy language study material from NCERT help you learn the topic with dexterity thus getting the concept clearly in no time. Additionally referring to NCERT solutions will help you prepare for a golden future. With NCERT guide books in hand, you can start preparing for JEE and NEET from 11th class itself thus increasing your possibility of scoring competent marks to build your own path.<\/p>\n<p>And nothing can beat the approach of incorporating digital learning. Just have your copy of NCERT Solutions For Chemistry Chapter 4 Solutions pdf from here and start with your study session right now. Yes, it is that simple. Just Download NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure pdf in your portable device like your smartphone or laptop whichever is convenient for you, then get ready with your study time in your own space. Students who will appear for their exam in Hindi mode make sure to have NCERT Solutions For Chemistry Chapter 4 pdf download in Hindi.<\/p>\n<p>You can download CBSE NCERT Solutions For Chemistry Chapter 4 from below.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/chapter_4_chemical_bonding_and_molecular_structure.pdf\">NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"what-will-you-learn-in-ncert-solutions-for-chemistry-chapter-4\"><\/span>What will you learn in NCERT Solutions For Chemistry Chapter 4?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Chemical bonding and molecular structure are rudimentary to topics that you learned in the previous class. Now you are about to experience an elaborate explanations of the concepts in this chapter. Topics that students will learn in the chapters are as follows-<\/p>\n<ol>\n<li>VSEPR theory<\/li>\n<li>Lewis structures<\/li>\n<li>Valence bond theory<\/li>\n<li>The polar character of covalent bonds<\/li>\n<li>The concept of hybridization<\/li>\n<li>The molecular orbital theory of homonuclear diatomic molecules<\/li>\n<li>Hydrogen bonding<\/li>\n<\/ol>\n<p><strong>Types of question they generally come from NCERT Solutions For Chemistry Chapter 4 chapter are as follows-<\/strong><\/p>\n<ol>\n<li>Students will get to draw diagrams of Lewis Dot symbols of the atom, molecules and polyatomic ions.<\/li>\n<li>Then there will be questions on bond parameters and expressing resonance in reference to Lewis structure.<\/li>\n<li>Students will also get questions from dipole moment, bond polarity, covalent bonds, hybridization, VBT, MOT and lastly there is VSERP theory.<\/li>\n<\/ol>\n<h3><span class=\"ez-toc-section\" id=\"ncert-solutions-for-chemistry-chapter-4-chemical-bonding-and-molecular-structure-subtopics-that-are-followed-in-this-chapter-are\"><\/span><strong>NCERT Solutions For Chemistry Chapter 4 <\/strong><strong>Chemical Bonding And Molecular Structure Subtopics that are followed in this chapter are-<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul>\n<li>Octet Rule\n<ul>\n<li>Covalent Bond<\/li>\n<li>Lewis Representation Of Simple Molecules (The Lewis Structures)<\/li>\n<li>Formal Charge<\/li>\n<li>Limitations Of The Octet Rule<\/li>\n<\/ul>\n<\/li>\n<li>Ionic Or Electrovalent Bond\n<ul>\n<li>Lattice Enthalpy<\/li>\n<\/ul>\n<\/li>\n<li>Bond Parameters\n<ul>\n<li>Bond Length<\/li>\n<li>Bond Angle<\/li>\n<li>Bond Enthalpy<\/li>\n<li>Bond Order<\/li>\n<li>Resonance Structures<\/li>\n<li>Polarity Of Bonds<\/li>\n<\/ul>\n<\/li>\n<li>The Valence Shell Electron Pair Repulsion (VSEPR) Theory<\/li>\n<li>Valence Bond Theory\n<ul>\n<li>Orbital Overlap Concept<\/li>\n<li>Directional Properties Of Bonds<\/li>\n<li>Overlapping Of Atomic Orbitals<\/li>\n<li>Types Of Overlapping And Nature Of Covalent Bonds<\/li>\n<li>The Strength Of Sigma And Pi Bonds<\/li>\n<\/ul>\n<\/li>\n<li>Hybridisation\n<ul>\n<li>Types Of Hybridisation<\/li>\n<li>Other Examples Of Sp3, Sp2 And Sp Hybridisation<\/li>\n<li>The Hybridisation Of Elements Involving D Orbitals<\/li>\n<\/ul>\n<\/li>\n<li>Molecular Orbital Theory\n<ul>\n<li>Formation Of Molecular Orbitals Linear Combination Of Atomic Orbitals (Lcao)<\/li>\n<li>Conditions For The Combination Of Atomic Orbitals<\/li>\n<li>Types Of Molecular Orbitals<\/li>\n<li>Energy Level Diagram For Molecular Orbitals<\/li>\n<li>Electronic Configuration And Molecular Behaviour<\/li>\n<\/ul>\n<\/li>\n<li>Bonding In Some Homonuclear Diatomic Molecules<\/li>\n<li>Hydrogen Bonding\n<ul>\n<li>Cause Of Formation Of Hydrogen Bond<\/li>\n<li>Types Of H-bonds.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<h2><span class=\"ez-toc-section\" id=\"benefits-of-ncert-solutions-for-chemistry-chapter-4\"><\/span><strong>Benefits of NCERT Solutions For Chemistry Chapter 4<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ol>\n<li>One of the most promising benefits of the chemistry solution of class 11 is that NCERT comes up with easy language base. Therefore students will learn the subject with ease thus finishing the subject on time.<\/li>\n<li>Additionally, when you get to finish the chapter on time, you get to enjoy a rigorous revision session, thus having a solid base for each of the topics discussed in your syllabus.<\/li>\n<li>This ultimately will help you solve the question bank, previous year question paper and sample papers thus letting you stand on the grounds of your strength and weakness and hence working on the same as required.<\/li>\n<li>Moreover, NCERT solutions are the best guide to complete your exam prep fast and better.<\/li>\n<\/ol>\n<h2><span class=\"ez-toc-section\" id=\"access-ncert-solutions-for-chemistry-chapter-4\"><\/span>Access <strong>NCERT Solutions For Chemistry Chapter 4<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"question-1-explain-the-formation-of-a-chemical-bond\"><\/span><strong>Question 1. Explain the formation of a chemical bond.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0According to Kossel and Lewis, atoms combine together in order to complete their respective octets so as to acquire the stable inert gas configuration. This can occur in two ways; by transfer of one or more electrons from one atom to other or by sharing of electrons between two or more atoms.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-2write-lewis-dot-symbols-for-atoms-of-the-following-elements-mg-na-b-o-n-br\"><\/span><strong>Question 2.Write Lewis dot symbols for atoms of the following elements: Mg, Na, B, O, N, Br.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><\/p>\n<p><img class=\"alignnone size-full wp-image-117459\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/1-2.png\" alt=\"1\" width=\"390\" height=\"211\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-3-write-lewis-symbols-for-the-following-atoms-and-ions-s-and-s2%e2%80%93-al-and-al3-h-and-h%e2%80%93\"><\/span><strong>Question 3. Write Lewis symbols for the following atoms and ions: S and\u00a0S<sup>2<\/sup>\u2013 ; Al and\u00a0Al<sup>3+<\/sup>; H and H<sup>\u2013<\/sup><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117460\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/2-1.png\" alt=\"2\" width=\"457\" height=\"100\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-4-draw-the-lewis-structures-for-the-following-molecules-and-ions-h2s-sicl4-bef2-c032-hcooh\"><\/span><strong>Question 4. Draw the Lewis structures for the following molecules and ions:<\/strong><br \/><strong>H<sub>2<\/sub>S, SiCl<sub>4 ,\u00a0<\/sub>BeF<sub>2<\/sub>, C0<sub>3<\/sub><sup>2-<\/sup>, HCOOH<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117461\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/3-1.png\" alt=\"3\" width=\"519\" height=\"242\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-5-define-octet-rule-write-its-significance-and-limitations\"><\/span><strong>Question 5. Define Octet rule. Write its significance and limitations.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0<strong>Octet rule:<\/strong>\u00a0Atoms of elements combine with each other in order to complete their respective octets so as to acquire the stable gas configuration.<br \/><strong>Significance:<\/strong>\u00a0It helps to explain why different atoms combine with each other to form ionic compounds or covalent compounds.<br \/><strong>Limitations of Octet rule:<\/strong><\/p>\n<ul>\n<li>According to Octet rule, atoms take part in chemical combination to achieve the configuration of nearest noble gas elements. However, some of noble gas elements like Xenon have formed compounds with fluorine and oxygen. For example: XeF<sub>2<\/sub>, XeF<sub>4\u00a0<\/sub>etc.<br \/>Therefore, validity of the octet rule has been challenged.<\/li>\n<li>This theory does not account for shape of molecules.<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"question-6-write-the-favourable-factors-for-the-formation-of-ionic-bond\"><\/span><strong>Question 6. Write the favourable factors for the formation of ionic bond.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><\/p>\n<ol>\n<li>Low ionization enthalpy of metal atoms<\/li>\n<li>High electron gain enthalpy of non-metal atoms<\/li>\n<li>High lattice enthalpy of compound formed.<\/li>\n<\/ol>\n<h3><span class=\"ez-toc-section\" id=\"question-7-discuss-the-shape-of-the-following-molecules-using-the-vsepr-model-becl2-bcl3-sicl4-asf5-h2s-ph3\"><\/span><strong>Question 7. Discuss the shape of the following molecules using the VSEPR model:<\/strong><br \/><strong>BeCl<sub>2<\/sub>, BCl<sub>3<\/sub>\u00a0, SiCl<sub>4<\/sub>, AsF<sub>5<\/sub>, H<sub>2<\/sub>S, PH<sub>3<\/sub><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117462\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/4.png\" alt=\"4\" width=\"684\" height=\"544\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-8-although-geometries-of-nh3-and-h20-molecules-are-distorted-tetrahedral-bond-angle-in-water-is-less-than-that-of-ammonia-discuss\"><\/span><strong>Question 8. Although geometries of NH<sub>3\u00a0<\/sub>and H<sub>2<\/sub>0 molecules are distorted tetrahedral, bond angle in water is less than that of ammonia. Discuss.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-Q8.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure Q8\" width=\"125\" height=\"57\" \/><br \/>Because of two lone pairs of electrons on O-atom, repulsion on bond pairs is greater in H<sub>2<\/sub>0 in comparison to NH<sub>3\u00a0<\/sub>. Thus, the bond angle is less in H<sub>2<\/sub>0 molecules.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-9-how-do-you-express-the-bond-strength-in-terms-of-bond-order\"><\/span><strong>Question 9. How do you express the bond strength in terms of bond order?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Bond strength is directly proportional to the bond order. Greater the bond order, more is the bond strength.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-10-define-the-bond-length\"><\/span><strong>Question 10. Define the bond-length.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0Bond-length: It is the equilibrium distance between the nuclei of two bonded atoms in a molecule. Bond-lengths are measured by spectroscopic methods.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-11-explain-the-important-aspects-of-resonance-with-reference-to-the-c032-ion\"><\/span><strong>Question 11. Explain the important aspects of resonance with reference to the\u00a0C0<sub>3<\/sub><sup>2-<\/sup>ion.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117463\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/5.png\" alt=\"5\" width=\"373\" height=\"123\" \/><br \/>Resonance in C0<sub>3<\/sub><sup>2-<\/sup>, I, II and III represent the three canonical forms.<\/p>\n<ul>\n<li>In these structures, the position of nuclei are same.<\/li>\n<li>All three forms have almost equal energy.<\/li>\n<li>Same number of paired and impaired electrons, they differ only in their position.<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"question-12-h3po3-can-be-represented-by-structures-1-and-2-shown-below-can-these-two-structures-be-taken-as-the-canonical-forms-of-the-resonance-hybrid-representing-h3po3-if-not-give-reasons-for-the-same\"><\/span><strong>Question 12. H<sub>3<\/sub>PO<sub>3\u00a0<\/sub>can be represented by structures 1 and 2 shown below. Can these two structures be taken as the canonical forms of the resonance hybrid representing\u00a0H<sub>3<\/sub>PO<sub>3<\/sub>? If not, give reasons for the same.<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-Q12.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure Q12\" width=\"211\" height=\"106\" \/><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>No, these cannot be taken as canonical forms because the positions of atoms have been changed.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-13-write-the-resonance-structures-for-so3no2-and-no3\"><\/span><strong>Question 13. Write the resonance structures for SO<sub>3<\/sub>,NO<sub>2<\/sub>\u00a0and NO<sub>3<\/sub><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117464\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/6.png\" alt=\"6\" width=\"691\" height=\"337\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-14-use-lewis-symbols-to-show-electron-transfer-between-the-following-atoms-to-form-cations-and-anions-a-k-and-s-b-ca-and-o-c-al-and-n\"><\/span><strong>Question 14. Use Lewis symbols to show electron transfer between the following atoms to form cations and anions (a) K and S (b) Ca and O (c) Al and N.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-Q14.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure Q14\" width=\"418\" height=\"78\" \/><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-Q14.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure Q14.1\" width=\"438\" height=\"108\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-15-although-both-co2-and-h2o-are-triatomic-molecules-the-shape-of-h2o-molecule-is-bent-while-that-of-co2-is-linear-explain-this-on-the-basis-of-dipole-moment\"><\/span><strong>Question 15. Although both CO<sub>2<\/sub>\u00a0and H<sub>2<\/sub>O are triatomic molecules, the shape of H<sub>2<\/sub>O molecule is bent while that of CO<sub>2<\/sub>\u00a0is linear. Explain this on the basis of dipole moment.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0In CO<sub>2<\/sub>, there are two C=O bonds. Each C=O bond is a polar bond.<br \/>The net dipole moment of CO<sub>2<\/sub>\u00a0molecule is zero. This is possible only if CO<sub>2<\/sub>\u00a0is a linear molecule. (O=C=O). The bond dipoles of two C=O bonds cancel the moment of each other.<br \/>Whereas, H<sub>2<\/sub>O molecule has a net dipole moment (1.84 D). H<sub>2<\/sub>O molecule has a bent structure because here the O\u2014H bonds are oriented at an angle of 104.5\u00b0 and do not cancel the bond moments of each other.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-16-write-the-significanceapplications-of-dipole-moment\"><\/span><strong>Question 16. Write the significance\/applications of dipole moment.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0<\/p>\n<ul>\n<li>In predicting the nature of the molecules: Molecules with specific dipole moments are polar in nature and those of zero dipole moments are non-polar in nature.<\/li>\n<li>In the determination of shapes of molecules.<\/li>\n<li>In calculating the percentage ionic character.<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"question-17-define-electronegativity-how-does-it-differ-from-electron-gain-enthalpy\"><\/span><strong>Question 17. Define electronegativity. How does it differ from electron gain enthalpy?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer: Electronegativity:<\/strong>\u00a0Electronegativity is the tendency of an atom to attract shared pair of electrons. It is the property of bonded atom.<br \/>Whereas, electron gain enthalpy is the tendency of an atom to attract outside electron. It is the property of an isolated atom.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-18-explain-with-the-help-of-suitable-example-polar-covalent-bond\"><\/span><strong>Question 18. Explain with the help of suitable example polar covalent bond.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong> When two atoms with different electronegativity are linked to each other by covalent bond, the shared electron pair will not in the centre because of the difference in electronegativity. For example, in hydrogen flouride molecule, flouride has greater electronegativity than hydrogen.<\/p>\n<p>Thus, the shared electron pair is displaced more towards flourine atom, the later will acquire a partial negative charge (\u2202<sup>\u2013<\/sup>). At the same time hydrogen atom will have a partial positive charge (\u2202<sup>+<\/sup>). Such a covalent bond is known as polar covalent bond or simply polar bond.<br \/>It is represented as<br \/><img class=\"alignnone size-full wp-image-117465\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/7.png\" alt=\"7\" width=\"114\" height=\"67\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-19-arrange-the-bonds-in-order-of-increasing-ionic-character-in-the-molecules-lif-k2o-n2-so2-and-clf3\"><\/span><strong>Question 19. Arrange the bonds in order of increasing ionic character in the molecules: LiF, K<sub>2<\/sub>O, N<sub>2<\/sub>, SO<sub>2<\/sub>\u00a0and ClF<sub>3<\/sub>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>N<sub>2<\/sub>\u00a0&lt; SO<sub>2<\/sub>\u00a0&lt; ClF<sub>3<\/sub>\u00a0&lt; K<sub>2<\/sub>O &lt; LiF<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-20-the-skeletal-structure-of-ch3cooh-as-shown-below-is-correct-but-some-of-the-bonds-are-shown-incorrectly-write-the-correct-lewis-structure-for-acetic-acid\"><\/span><strong>Question 20. The skeletal structure of\u00a0CH<sub>3<\/sub>COOH\u00a0as shown below is correct, but some of the bonds are shown incorrectly. Write the correct Lewis structure for acetic acid.<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-Q20.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure Q20\" width=\"189\" height=\"108\" \/><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-Q20.1.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure Q20.1\" width=\"179\" height=\"104\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-21-apart-from-tetrahedral-geometry-another-possible-geometry-for-ch4-is-square-planar-with-the-four-h-atoms-at-the-comers-of-the-square-and-the-c-atom-at-its-centre-explain-why-ch4-is-not-square-planar\"><\/span><strong>Question 21. Apart from tetrahedral geometry, another possible geometry for CH<sub>4<\/sub>\u00a0is square planar with the four H atoms at the comers of the square and the C atom at its centre. Explain why CH<sub>4<\/sub>\u00a0is not square planar?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>According to VSEPR theory, if CH<sub>4<\/sub>were square planar, the bond angle would be 90\u00b0. For tetrahedral structure, the bond angle is 109\u00b028\u2032. Therefore, in square planar structure, repulsion between bond pairs would be more and thus the stability will be less.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-22-explain-why-beh2-molecule-has-a-zero-dipole-moment-although-the-be%e2%80%94h-bonds-are-polar\"><\/span><strong>Question 22. Explain why BeH<sub>2<\/sub>\u00a0molecule has a zero dipole moment although the Be\u2014H bonds are polar.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0BeH<sub>2<\/sub>is a linear molecular (H\u2014Be\u2014H), the bond angle = 180\u00b0.<br \/>Be\u2014H bonds are polar due to difference in their electronegativity but the bond polarities cancel each other. Thus, molecule has resultant dipole moment of zero.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-23-which-out-of-nh3-and-nf3-has-higher-dipole-moment-and-why\"><\/span><strong>Question 23. Which out of NH<sub>3<\/sub>\u00a0and NF<sub>3<\/sub>\u00a0has higher dipole moment and why?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>In NH<sub>3<\/sub>\u00a0and NF<sub>3<\/sub>, the difference in electronegativity is nearly same but the dipole moment of NH<sub>3<\/sub>\u00a0= (1.46D)\u00a0For Example, NH<sub>3<\/sub>\u00a0= (0.24D)<br \/>In NH3, the dipole moments of the three N\u2014H bonds are in the same direction as the lone pair of electron. But in NF<sub>3<\/sub>, the dipole moments of the three N\u2014F bonds are in the direction opposite to that of the lone pair. Therefore, the resultant dipole moment in NH<sub>3<\/sub>\u00a0is more than in NF<sub>3<\/sub>.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-24-what-is-meant-by-hybridisation-of-atomic-orbitals-describe-the-shapes-of-sp-sp2-sp3-hybrid-orbitals\"><\/span><strong>Question 24. What is meant by hybridisation of atomic orbitals? Describe the shapes of sp, sp<sup>2<\/sup>, sp<sup>3<\/sup>\u00a0hybrid orbitals.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0<strong>Hybridisation:<\/strong>\u00a0It is defined as the process of intermixing of atomic oribitals of slightly different energies to give rise to new hybridized orbitals having equivalent energy and identical shapes.<br \/><strong>Shapes of Orbitals:<\/strong><br \/><strong>sp hybridisation:<\/strong>\u00a0When one s-and one p-orbital, intermix then it is called sp-hybridisation. For example, in BeF2, Be atom undergoes sp-hybridisation. It has linear shape. Bond angle is 180\u00b0.<br \/><strong>sp<sup>2\u00a0<\/sup>hybridisation:<\/strong>\u00a0One s-and two p-orbitals get hybridised to form three equivalent hybrid orbitals. The three hybrid orbitals directed towards three corners of an equilateral triangle. It is, therefore, known as trigonal hybridisation.<br \/><strong>sp<sup>3<\/sup>\u00a0hybridisation:<\/strong>\u00a0One s-and three p-orbitals get hybridised to form four equivalent hybrid orbitals. These orbitals are directed towards the four corners of a regular tetrahedron.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-25-describe-the-change-in-hybridisation-if-any-of-the-al-atom-in-the-following-reaction-alcl3-cl%e2%80%93-%e2%80%94%e2%80%94%3e-alcl4\"><\/span><strong>Question 25. Describe the change in hybridisation (if any) of the Al atom in the following reaction. <\/strong><strong>AlCl<sub>3<\/sub>\u00a0+ Cl<sup>\u2013<\/sup>\u00a0\u2014\u2014&gt; AlCl<sup>4-<\/sup>\u00a0.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Electronic configuration of\u00a0<sub>13<\/sub>Al = 1s<sup>2<\/sup>\u00a02s<sup>2<\/sup>\u00a02p<sup>6<\/sup>\u00a03s<sup>1<\/sup>\u00a03p<sub>x<\/sub><sup>1<\/sup>3p<sub>y<\/sub><sup>1<\/sup><br \/>(excited state)<br \/>Hence, hybridisation will be SP<sup>2<\/sup><br \/>In AlCl<sup>\u2013<\/sup><sub>4<\/sub>, the empty\u00a03p<sub>z\u00a0<\/sub>orbital is also involved. So, the hybridisation is sp<sup>3<\/sup>\u00a0and the shape is tetrahedral.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-26-is-there-any-change-in-the-hybridisation-of-b-and-n-atoms-as-a-result-of-the-following-reaction-bf3-nh3-%e2%80%94%e2%80%94-%3e-f3-bnh3\"><\/span><strong>Question 26. Is there any change in the hybridisation of B and N atoms as a result of the following reaction ? <\/strong><strong>BF<sub>3<\/sub>\u00a0+ NH<sub>3<\/sub>\u00a0\u2014\u2014-&gt; F<sub>3<\/sub>\u00a0B.NH<sub>3<\/sub><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0In BF<sub>3<\/sub>, B atom is sp<sup>2<\/sup>\u00a0hybridised. In NH<sub>3<\/sub>, N is sp<sup>3\u00a0<\/sup>hybridised.<br \/>After the reaction, hybridisation of B changes from sp<sup>2<\/sup>\u00a0to sp<sup>3<\/sup>.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-27-draw-diagrams-showing-the-formation-of-a-double-bond-and-a-triple-bond-between-carbon-atoms-in-c2-h4-and-c2-h2-molecules\"><\/span><strong>Question 27. Draw diagrams showing the formation of a double bond and a triple bond between carbon atoms in\u00a0<\/strong><strong>C<sub>2<\/sub>\u00a0H<sub>4<\/sub>\u00a0and\u00a0C<sub>2<\/sub>\u00a0H<sub>2\u00a0<\/sub>molecules.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117466\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/8.png\" alt=\"8\" width=\"677\" height=\"430\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-28-what-is-the-total-number-of-sigma-and-pi-bonds-in-the-following-molecules-a-c2-h2-b-c2-h4\"><\/span><strong>Question 28. What is the total number of sigma and pi bonds in the following molecules?<\/strong><br \/><strong>(a) C<sub>2<\/sub>\u00a0H<sub>2<\/sub>\u00a0(b) C<sub>2<\/sub>\u00a0H<sub>4<\/sub><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0(a) H\u2014C = C\u2014H<br \/>Sigma bond = 3\u00a0\u03a0\u00a0bonds = 2<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-Q28.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure Q28\" width=\"247\" height=\"132\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-29-considering-x-axis-as-the-intemuclear-axis-which-out-of-the-following-will-not-form-a-sigma-bond-and-why-a-is-and-is-b-is-and-2px-c-2py-and-2py-d-is-and-2s\"><\/span><strong>Question 29. Considering X-axis as the intemuclear axis which out of the following will not form a sigma bond and why? (a) Is and Is (b) Is and\u00a02p<sub>x\u00a0<\/sub>(c)\u00a02p<sub>y\u00a0<\/sub>and 2p<sub>y<\/sub>\u00a0(d) Is and 2s<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0(c) It will not form a s-bond because taking x-axis as the intemuclear axis, there will be lateral overlap between the two 2p<sub>y<\/sub>\u00a0orbitals forming a \u03a0\u00a0-bond.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-30-which-hybrid-orbitals-are-used-by-carbon-atoms-in-the-following-molecules-a-ch3-ch3-b-ch3-ch-ch2-c-ch3-ch2-oh-d-ch3-cho-e-ch3cooh\"><\/span><strong>Question 30. Which hybrid orbitals are used by carbon atoms in the following molecules?<\/strong><br \/><strong>(a) CH<sub>3<\/sub>-CH<sub>3<\/sub>\u00a0(b) CH<sub>3<\/sub>-CH = CH<sub>2<\/sub>\u00a0(c) CH<sub>3<\/sub>-CH<sub>2<\/sub>-OH (d) CH<sub>3<\/sub>-CHO (e) CH<sub>3<\/sub>COOH.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117467\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/9.png\" alt=\"9\" width=\"597\" height=\"447\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-31-what-do-you-understand-by-bond-pairs-and-lone-pairs-of-electrons-illustrate-by-giving-one-example-of-each-type\"><\/span><strong>Question 31. What do you understand by bond pairs and lone pairs of electrons? Illustrate by giving one example of each type.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0The electron pair involved in sharing between two atoms during covalent bonding is called shared pair or bond pair. At the same time, the electron pair which is not involved in sharing is called lone pair of electrons.<br \/><img class=\"alignnone size-full wp-image-117468\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/10.png\" alt=\"10\" width=\"665\" height=\"128\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-32-distinguish-between-a-sigma-bond-and-a-pi-bond\"><\/span><strong>Question 32. Distinguish between a sigma bond and a pi bond.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117469\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/11.png\" alt=\"11\" width=\"739\" height=\"211\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-33-explain-the-formation-of-h2-molecule-on-the-basis-of-valence-bond-theory\"><\/span><strong>Question 33. Explain the formation of\u00a0H<sub>2<\/sub>\u00a0molecule on the basis of valence bond theory.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Let us consider the combination between atoms of hydrogen H<sub>A<\/sub>\u00a0and H<sub>B<\/sub> and eA and eB be their respective electrons.<br \/>As they tend to come closer, two different forces operate between the nucleus and the electron of the other and vice versa. The nuclei of the atoms as well as their electrons repel each other. Energy is needed to overcome the force of repulsion.<\/p>\n<p>Although the number of new attractive and repulsive forces is the same, but the magnitude of the attractive forces is more. Thus, when two hydrogen atoms approach each other, the overall potential energy of the system decreases. Thus, a stable molecule of hydrogen is formed.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-34-write-the-important-conditions-required-for-the-linear-combination-of-atomic-orbitals-to-form-molecular-orbitals\"><\/span><strong>Question 34. Write the important conditions required for the linear combination of atomic orbitals to form molecular orbitals.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><\/p>\n<ul>\n<li>The combining atomic orbitals should have comparable energies.<br \/>For example, Is orbital of one atom can combine with Is atomic orbital of another atom, 2s can combine with 2s.<\/li>\n<li>The combining atomic orbitals must have proper orientations. So that they are able to overlap to a considerable extent.<\/li>\n<li>The extent of overlapping should be large.<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"question-35-use-molecular-orbital-theory-to-explain-why-the-be2-molecule-does-not-exist\"><\/span><strong>Question 35. Use molecular orbital theory to explain why the Be<sub>2<\/sub>\u00a0molecule does not exist.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117470\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/12.png\" alt=\"12\" width=\"392\" height=\"152\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-36-compare-the-relative-stability-of-the-following-species-and-indicate-their-magnetic-properties-o2-o2-o2%e2%80%93-superoxideo22-peroxide\"><\/span><strong>Question 36. Compare the relative stability of the following species and indicate their magnetic properties: O<sub>2<\/sub>, O<sub>2<\/sub>, O<sub>2<\/sub><sup>\u2013<\/sup>\u00a0(Superoxide),O<sub>2<\/sub><sup>2-<\/sup>\u00a0(peroxide)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer: <\/strong>O<sub>2<\/sub>\u2014 Bond order = 2, paramagnetic<br \/>O<sub>2<\/sub><sup>+<\/sup>\u2014 Bond order = 2.5, paramagnetic<br \/>O<sub>2<\/sub><sup>\u2013<\/sup>\u2014 Bond order = 1.5, paramagnetic<br \/>O<sub>2<\/sub><sup>2-<\/sup>\u00a0\u2014 Bond order = 1, diamagnetic<br \/>Order of relative stability is<br \/>O<sub>2<\/sub><sup>+<\/sup>\u00a0&gt; O<sub>2\u00a0<\/sub>&gt; O<sub>2<\/sub><sup>\u2013<\/sup>\u00a0&gt; O<sub>2<\/sub><sup>2-<\/sup><br \/>(2.5) (2.0) (1.5) (1.0)<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-37-write-the-significance-of-plus-and-minus-sign-in-representing-the-orbitals\"><\/span><strong>Question 37. Write the significance of plus and minus sign in representing the orbitals,<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0Plus and minus sign is used to indentify the nature of electrons wave. Plus (+ve) sign denotes crest, while (-ve) sign denotes trough.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-38-describe-the-hybridisation-in-case-of-pcl5-why-are-the-axial-bonds-longer-as-compared-to-equatorial-bonds\"><\/span><strong>Question 38. Describe the hybridisation in case of\u00a0PCl<sub>5<\/sub>. Why are the axial bonds longer as compared to equatorial bonds?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0The ground state E.C. and the excited state E.C. of phosphorus are represented as:<br \/><img class=\"alignnone size-full wp-image-117471\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/13.png\" alt=\"13\" width=\"527\" height=\"240\" \/><br \/>The one s, three-p and one d-orbitals hybridise to yield five sets of SP<sup>3\u00a0<\/sup>d hybrid orbitals which are directed towards the five corners of a trigonal bipyramidal as in Fig.<br \/><img class=\"alignnone size-full wp-image-117473\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/14.png\" alt=\"14\" width=\"357\" height=\"256\" \/><br \/>Because axial bond pairs suffer more repulsive interaction from the equatorial bond pairs, therefore axial bonds have been found to be slightly longer and hence slightly weaker than equatorial bonds.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-39-define-hydrogen-bonds-is-it-weaker-or-stronger-than-the-van-der-waals-forces\"><\/span><strong>Question 39. Define hydrogen bonds. Is it weaker or stronger than the van der Waals forces?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0When hydrogen is attached with highly electronegative element in a covalent bonding the electrons of the covalent bond are shifted towards the more electronegative atom. Thus, a partially positively charged hydrogen atom forms a bond with the other more electronegative atom. This bond is known as a hydrogen bond. Hydrogen bond is stronger than the van der Waals forces.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-40-what-is-meant-by-the-term-bond-order-calculate-the-bond-order-of-n2-o2-o2o2%e2%80%93\"><\/span><strong>Question 40. What is meant by the term bond order? Calculate the bond order of N<sub>2<\/sub>, O<sub>2<\/sub>, O<sub>2<\/sub><sup>+<\/sup>,O<sub>2<\/sub><sup>\u2013<\/sup><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0Bond order is defined as the half of the difference between the number of electrons present in bonding and antibonding molecular orbitals.<br \/><img class=\"alignnone size-full wp-image-117474\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/15.png\" alt=\"15\" width=\"673\" height=\"637\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"more-questions-solved\"><\/span><strong>MORE QUESTIONS SOLVED<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<h3><span class=\"ez-toc-section\" id=\"i-very-short-answer-type-questions-question-1-how-is-bond-order-related-to-the-stability-of-a-molecule\"><\/span><strong>I. Very Short Answer Type Questions<\/strong><br \/><strong>Question 1. How is bond order related to the stability of a molecule?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Higher the bond order, greater is the stability.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-2-write-the-type-of-hybridisation-involved-in-ch4c2h4-and-c2h2\"><\/span><strong>Question 2. Write the type of hybridisation involved in\u00a0CH<sub>4<\/sub>,C<sub>2<\/sub>H<sub>4\u00a0<\/sub>and C<sub>2<\/sub>H<sub>2<\/sub>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0CH<sub>4<\/sub>= sp<sup>3<\/sup><br \/>C<sub>2<\/sub>H<sub>4<\/sub>\u00a0= sp<sup>2<\/sup><br \/>C<sub>2<\/sub>H<sub>2<\/sub>\u00a0= sp<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-3-out-of-sigma-and-%ce%a0-bonds-which-one-is-stronger-and-why\"><\/span><strong>Question 3. Out of sigma and \u03a0 bonds, which one is stronger and why?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0sigma-bond is stronger. This is because sigma-bond is formed by head-on overlapping of atomic orbitals and \u03a0 bond is formed by side wise overlapping.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-4-write-the-lewis-dot-symbols-of-the-following-elements-and-predict-their-valences-i-cl-ii-p\"><\/span><b>Question 4. Write the Lewis dot symbols of the following elements and predict their valences. <\/b><strong>(i) Cl (ii) P<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-VSAQ-Q4.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure VSAQ Q4\" width=\"286\" height=\"132\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-5-predict-the-shapes-of-the-following-molecules-using-vsepr-theory-i-becl2ii-sicl4\"><\/span><strong>Question 5. Predict the shapes of the following molecules using VSEPR theory?<\/strong><br \/><strong>(i) BeCl<sub>2<\/sub>(ii) SiCl<sub>4<\/sub><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0(i) Linear<br \/>(ii) Tetrahedral<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-6-write-the-state-of-hybridisation-of-boron-in-bf3\"><\/span><strong>Question 6. Write the state of hybridisation of boron in\u00a0BF<sub>3<\/sub>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0SP<sup>2<\/sup><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-7-arrange-o2o2%e2%80%93o22-o2in-increasing-order-of-bond-energy\"><\/span><strong>Question 7. Arrange\u00a0O<sub>2<\/sub>,O<sub>2<\/sub><sup>\u2013<\/sup>,O<sub>2<\/sub><sup>2-<\/sup>, O<sub>2<\/sub><sup>+<\/sup>in increasing order of bond energy.\u00a0<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0O<sub>2<\/sub><sup>2-<\/sup>&lt; O<sub>2<\/sub><sup>\u2013<\/sup>\u00a0&lt; O<sub>2<\/sub><sup>2-<\/sup>&lt; O<sub>2<\/sub><sup>+<\/sup><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-8-what-is-meant-by-bond-pairs-of-electrons\"><\/span><strong>Question 8. What is meant by bond pairs of electrons?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>The electron pairs involved in the bond formation are known as bond pairs or shared pairs.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-9-which-of-the-following-has-larger-bond-angle-in-each-pair-i-co2-bf3-ii-nh3-ch4\"><\/span><strong>Question 9. Which of the following has larger bond angle in each pair?<\/strong><br \/><strong>(i) CO<sub>2<\/sub>, BF<sub>3<\/sub>\u00a0(ii) NH<sub>3,<\/sub>\u00a0CH<sub>4<\/sub><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0(i) CO<sub>2<\/sub>\u00a0(ii) CH<sub>4<\/sub><\/p>\n<p><strong>Question 10. Arrange the following, according to increasing covalent nature.<\/strong><br \/><strong>NaCl, MgCl<sub>2<\/sub>, AlCl<sub>3<\/sub><\/strong><br \/><strong>Answer:<\/strong>\u00a0NaCl &lt; MgCl<sub>2<\/sub>\u00a0&lt; AlCl<sub>3<\/sub><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-11-define-covalent-bond-according-to-orbital-concept\"><\/span><strong>Question 11. Define covalent bond according to orbital concept?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Covalent bond can be formed by the overlap of the orbitals belonging to the two atoms having opposite spins of electrons.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-12-why-b2-is-paramagnetic-in-nature-while-c2-is-not\"><\/span><strong>Question 12. Why\u00a0B<sub>2\u00a0<\/sub>is paramagnetic in nature while C<sub>2<\/sub>\u00a0is not?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0The molecular orbital electronic configuration of both B<sub>2<\/sub>\u00a0and C<sub>2<\/sub>\u00a0are.<br \/><img class=\"alignnone size-full wp-image-117476\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/16.png\" alt=\"16\" width=\"365\" height=\"91\" \/><br \/>Since, B<sub>2<\/sub>has two impaired electrons, B<sub>2<\/sub>\u00a0is paramagnetic.<br \/>C<sub>2<\/sub>\u00a0has no unpaired electron. Thus, C<sub>2<\/sub>\u00a0is diamagnetic.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-13-why-ethyl-alcohol-is-completely-miscible-with-water\"><\/span><strong>Question 13. Why ethyl alcohol is completely miscible with water?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0This is because ethyl alcohol forms H-bonds witfi water.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-14-which-is-more-polar-co2-or-n2o-give-reason\"><\/span><strong>Question 14. Which is more polar CO<sub>2\u00a0<\/sub>or\u00a0N<sub>2<\/sub>O? Give reason.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0N<sub>2<\/sub>O is more polar than CO<sub>2<\/sub>.<br \/>This is \u201cbecause CO<sub>2<\/sub>\u00a0is linear and symmetrical. Its net dipole moment is zero.<br \/>N<sub>2<\/sub>O is linear but not symmetrical. It has a net dipole moment of sigma II6D.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-15-state-the-types-of-hybrid-orbitals-associated-with-i-p-in-pcl5-and-ii-s-in-sf6\"><\/span><strong>Question 15. State the types of hybrid orbitals associated with (i) P in PCl<sub>5\u00a0<\/sub>and (ii) S in\u00a0SF<sub>6<\/sub><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0(i) sp<sup>3<\/sup>d\u00a0of P in PCl<sub>5<\/sub>\u00a0(ii)\u00a0sp<sup>3<\/sup>d<sup>2\u00a0<\/sup>of S in\u00a0SF<sub>6<\/sub><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-16-why-n2-is-more-stable-than-o2-explain-on-the-basis-of-molecular-orbital-theory\"><\/span><strong>Question 16. Why\u00a0N<sub>2\u00a0<\/sub>is more stable than O<sub>2<\/sub>? Explain on the basis of molecular orbital theory.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Bond order of\u00a0N<sub>2<\/sub>\u00a0(= 3) is greater than that of O<sub>2<\/sub>\u00a0(= 2).<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-17-how-is-bond-order-related-to-bond-length-of-a-molecule\"><\/span><strong>Question 17. How is bond order related to bond length of a molecule?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0Bond length is inversely proportional to bond order.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-18-out-of-bonding-and-antibonding-molecular-orbitals-which-one-has-lower-energy-and-which-one-has-higher-stability\"><\/span><strong>Question 18. Out of bonding and antibonding molecular orbitals, which one has lower energy and which one has higher stability?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Bonding molecular orbital has lower energy and higher stability.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-19-define-antibonding-molecular-orbital\"><\/span><strong>Question 19. Define antibonding molecular orbital.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0The molecular orbital formed by the subtractive effect of the electron waves of the combining atomic orbitals, is called antibonding molecular orbital.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-20-name-the-two-conditions-which-must-be-satisfied-for-hydrogen-bonding-to-take-place-in-a-molecule\"><\/span><strong>Question 20. Name the two conditions which must be satisfied for hydrogen bonding to take place in a molecule.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0(i) The molecule should contain highly electronegative atom like hydrogen atom. (ii) The size of electronegative atom should be small.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"ii-short-answer-type-questions-question-1what-is-an-electrovalent-or-ionic-bond-explain-its-formation-with-two-examples\"><\/span><strong>II. Short Answer Type Questions<\/strong><br \/><strong>Question\u00a0<\/strong><strong>1.What is an electrovalent (or ionic) bond? Explain its formation with two examples.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0When a chemical bond is formed by the complete transfer of electrons from one atom to another, so as to complete their outermost shell and therefore, aquire the stable noble gas configuration, the bond formed is called ionic bond or electrovalent bond. \u2018<br \/>For Example,<br \/><img class=\"alignnone size-full wp-image-117477\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/17.png\" alt=\"17\" width=\"525\" height=\"315\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-2-what-are-lewis-structures-write-the-lewis-structure-of-h2-bef2-and-h2o\"><\/span><strong>Question 2. What are Lewis structures? Write the Lewis structure of\u00a0H<sub>2<\/sub>, BeF<sub>2<\/sub>\u00a0and\u00a0H<sub>2<\/sub>O.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0The outer shell electrons are shown as dots surrounding the symbol of the atom. These symbols are known as Lewis symbols or Lewis structures.<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-SAQ-Q2.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure SAQ Q2\" width=\"189\" height=\"154\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-3-define-lattice-energy-how-is-lattice-energy-influenced-by-i-charge-on-the-ions-ii-size-of-the-ions\"><\/span><strong>Question 3. Define Lattice energy. How is Lattice energy influenced by (i) Charge on the ions (ii) Size of the ions?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>Lattice energy is defined as the energy released when one mole of crystalline solid is formed by the combination of oppositely charged ions.<br \/>(i)As the magnitude of charge on an ion increases there will be greater force of interionic attraction and hence greater will be the value of Lattice energy,<br \/>(ii)Smaller the. size of the ions&gt; lower will be the intemuclear distance and thus greater will be the Lattice energy,<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-4-give-the-shapes-of-the-following-molecules-i-ab3-ii-ab4\"><\/span><strong>Question 4. Give the shapes of the following molecules:<\/strong><br \/><strong>(i) AB<sub>3 <\/sub>(ii) AB<sub>4<\/sub><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-SAQ-Q4.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure SAQ Q4\" width=\"540\" height=\"141\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-5-define-hybridisation-explain-sp-hybridisation-with-suitable-example\"><\/span><strong>Question 5. Define Hybridisation. Explain sp hybridisation with suitable example.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer: <\/strong>Hybridisation: It is the phenomenon of intermixing of atomic orbitals of slightly different energies to form new hybrid orbitals of equivalent energy,<br \/>Formation of water. In water (H<sub>2<\/sub>0)&gt; the atomic number of oxygen is 8 and its orbitals electronic configuration is\u00a01s<sup>2<\/sup>\u00a02s<sup>2<\/sup>\u00a02p<sub>x<\/sub><sup>2<\/sup>\u00a02p<sub>y<\/sub><sup>1<\/sup>\u00a02p<sub>z<\/sub><sup>1<\/sup>.The oxygen atom is also SP<sup>3\u00a0<\/sup>hybridised. However, in this case, the two orbitals with one electron each (half filled) are involved in overlap With the hydrogen orbitals.<br \/><img class=\"alignnone size-full wp-image-117478\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/18.png\" alt=\"18\" width=\"524\" height=\"237\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-6-account-for-the-following-i-water-is-a-liquid-while-h2s-is-a-gas-ii-nh3-has-higher-boiling-point-than-ph3\"><\/span><strong>Question 6. Account for the following:<\/strong><br \/><strong>(i) Water is a liquid while H<sub>2<\/sub>S is a gas<\/strong><br \/><strong>(ii) NH<sub>3<\/sub>\u00a0has higher boiling point than PH<sub>3<\/sub>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>(i) In case of water hydrogen bonding causes association of the H<sub>2<\/sub>O molecules. There is no such hydrogen bonding in H<sub>2<\/sub>S, that\u2019s why it is a gas.<br \/>(ii) There is hydrogen bonding in NH<sub>3<\/sub>\u00a0but not in PH<sub>3<\/sub>.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-7-what-do-you-mean-by-dipole-moment-draw-the-dipole-diagram-of-h2o\"><\/span><strong>Question 7. What do you mean by Dipole moment? Draw the dipole diagram of H<sub>2<\/sub>O.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>The product of magnitude of charges (+ve, or -ve) and distance between them is called dipole moment. It is usually denoted by\u00a0\u00b5.<br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-SAQ-Q7.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure SAQ Q7\" width=\"362\" height=\"194\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-8-what-are-the-main-postulates-of-valence-shell-electron-pair-repulsion-vsepr-theory\"><\/span><strong>Question 8. What are the main postulates of Valence Shell Electron Pair Repulsion (VSEPR) theory?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0<\/p>\n<ul>\n<li>\u00a0The shape of a molecule depends upon the no. of electron pairs around the central atom.<\/li>\n<li>There is a repulsive force between the electron pairs, which tend to repel one another.<\/li>\n<li>The electron pairs in space tend to occupy such positions that they are at maximum distance so, that the repulsive force will be minimum.<\/li>\n<li>A multiple bond is treated as if it is single bond and the remaining electron pairs which constitute the bond may be regarded as single super pair.<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"question-9-define-bond-order-how-is-it-related-to-the-stability-of-a-molecule\"><\/span><strong>Question 9. Define bond order. How is it related to the stability of a molecule?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0Bond order is defined as half of the difference between the number of electrons present in bonding and antibonding molecular orbitals.<br \/>Bond order (B.O.) = 1\/2[N<sub>b<\/sub>\u00a0\u2013 N<sub>a<\/sub>\u00a0] z<br \/>If the bond order is positive (N<sub>b<\/sub>\u00a0&gt; N<sub>a<\/sub>), the molecule or ion will be stable. If it is negative (N<sub>b<\/sub>\u00a0&lt; N<sub>a)<\/sub>the molecule or ion will be unstable.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-10-explain-the-diamagnetic-behaviour-of-p2-molecule-on-the-basis-of-molecular-orbital-theory\"><\/span><strong>Question 10. Explain the diamagnetic behaviour of\u00a0P<sub>2\u00a0<\/sub>molecule on the basis of molecular orbital theory.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117479\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/19.png\" alt=\"19\" width=\"660\" height=\"131\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"iii-long-answer-type-questions-question-1-a-explain-the-formation-of-ionic-bond-with-two-examples-b-discuss-the-conditions-which-favour-the-formation-of-ionic-bond\"><\/span><strong>III. Long Answer Type Questions<\/strong><br \/><strong>Question 1. (a) Explain the formation of ionic bond with two examples.<\/strong><br \/><strong>(b) Discuss the conditions which favour the formation of ionic bond.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong>\u00a0<strong>(a) An ionic or electrovalent bond is formed by the complete transference of one or more electrons from one atom to another.<\/strong><br \/><img class=\"alignnone size-full wp-image-117480\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/20.png\" alt=\"20\" width=\"603\" height=\"313\" \/><br \/><strong>(b) Conditions favourable for the formation of ionic bond:<\/strong><br \/>(i)Lesser the ionization enthalpy, easier will be the removal of an electron i.e., formation of a positive ion and hence greater the chances of formation of ionic bond.<br \/>(ii)Higher is the electron affinity, more is the energy released and stabler will be the negative ion produced. Consequently, the probability of formation of ionic bond will be enhanced.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-2-a-define-dipole-moment-what-are-the-units-of-dipole-moment-b-dipole-moment-values-help-in-predicting-the-shapes-of-covalent-molecules-explain\"><\/span><strong>Question 2. (a) Define dipole moment. What are the units of dipole moment?<\/strong><br \/><strong>(b) Dipole moment values help in predicting the shapes of covalent molecules. Explain.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong><strong>(a)Dipole moment:<\/strong>\u00a0In a polar molecule, one end bears a positive charge and the other has a negative charge. Thus, the molecule has two poles with equal magnitude of the charges.<\/p>\n<p>The molecule is known as dipolar molecule and possesses dipole moment.<br \/>It is defined as the product of the magnitude of the positive or negative charge and the distance between the charges.\u00a0\u00b5 (dipole moment) = q x d<br \/>SI unit of dipole moment is coulomb metre (m) or Debye.<\/p>\n<p><strong>(<\/strong><strong>b)The dipole moment values<\/strong>\u00a0are quite helpful in determining the general shapes of molecules.<br \/>For molecules with zero dipole moment, shapes will be either linear or symmetrical. For Example. BeF<sub>2<\/sub>\u00a0CO<sub>2<\/sub>etc. Molecules that possess dipole moments, their shape will not be symmetrical.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-3-discuss-the-orbital-structures-of-the-following-molecules-on-the-basis-of-hybridisation-i-bh3-ii-c2h2\"><\/span><strong>Question 3. Discuss the orbital structures of the following molecules on the basis of hybridisation, (i) BH<sub>3\u00a0<\/sub><\/strong><strong>(ii) C<sub>2<\/sub>H<sub>2<\/sub><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:<\/strong><br \/><img class=\"alignnone size-full wp-image-117481\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/21.png\" alt=\"21\" width=\"657\" height=\"298\" \/><br \/>B atom gets hybridised to form three equivalent hybrid orbitals directed towards three comers of equilateral triangle with B atoms in the centre. Bond angle = 120\u00b0.<br \/><img class=\"alignnone size-full wp-image-117482\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/22.png\" alt=\"22\" width=\"647\" height=\"232\" \/><br \/>Both the carbon atoms are sp hybridised. Both the carbon atoms have also two unhybridized orbitals which overlap sidewise with the similar orbitals of the other carbon atom to form two Jt bonds.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"question-4-a-how-many-a-and-n-bonds-are-present-in-b-why-hf-is-more-stable-than-h2-c-why-is-b2-molecule-paramagnetic\"><\/span><strong>Question 4. (a) How many a and n bonds are present in<\/strong><br \/><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-LAQ-Q4.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure LAQ Q4\" width=\"173\" height=\"26\" \/><br \/><strong>(b) Why Hf is more stable than H<sub>2<\/sub>?<\/strong><br \/><strong>(c) Why is B<sub>2<\/sub>\u00a0molecule paramagnetic?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a0(a) No. of c bonds = 7<br \/><img class=\"alignnone size-full wp-image-117483\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/07\/23.png\" alt=\"23\" width=\"681\" height=\"116\" \/><\/p>\n<p><img src=\"https:\/\/www.learncbse.in\/wp-content\/uploads\/2020\/11\/NCERT-Solutions-for-Class-11-Chemistry-Chapter-4-Chemical-Bonding-and-Molecular-Structure-LAQ-Q4.2.png\" alt=\"NCERT Solutions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure LAQ Q4.2\" width=\"500\" height=\"98\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"iv-multiple-choice-questions-question-1-a-co-ordinate-bond-is-formed-by-asharing-of-electrons-contributed-by-both-the-atoms-bcomplete-transfer-of-electrons-csharing-of-electrons-contributed-by-one-atom-only-d-none-of-these-question-2-the-species-co-cn%e2%80%93and-n2are-a-isoelectronic-b-having-coordinated-bond-chaving-polar-bond-d-having-low-bond-energies-question-3-the-axial-overlap-between-the-two-orbitals-leads-to-the-formation-of-a-a-sigma-bond-b-pi-bond-c-multiple-bond-d-none-of-these-question-4-in-s02-molecule-s-atom-is-asp3-hybridized-b-sp-hybridized-c-sp2-hybridized-d-d-sp2-hybridized-question-5-a-molecule-or-ion-is-stable-if-a-nb-na-b-nb-%3c-na-c-na-%3c-nb-d-na-%e2%80%93-nb-ve-question-6-the-molecule-ne2-does-not-exist-because-a-nb-%3e-na-b-nb-na-c-nb-%3c-na-d-none-of-these-question-7-which-one-is-diamagnetic-among-no-no-and-no-anob-no-c-no%e2%80%93d-none-of-these-question-8-in-sp3-sp2-and-sp-hybridized-carbon-atom-the-p-character-is-maximum-in-a-sp3-b-sp2-c-sp-d-all-of-the-above-have-same-p-character-question-9-out-of-the-following-intramolecular-hydrogen-bonding-exists-in-a-water-bh2s-c-4-nitrophenol-d-2-nitrophenol\"><\/span><strong>IV. Multiple Choice Questions<\/strong><br \/><strong>Question 1. A co-ordinate bond is formed by:<\/strong><br \/><strong>(a)sharing of electrons contributed by both the atoms<\/strong><br \/><strong>(b)complete transfer of electrons<\/strong><br \/><strong>(c)sharing of electrons contributed by one atom only (d) none of these<\/strong><br \/><strong>Question 2. The species CO, CN<sup>\u2013<\/sup>and N<sub>2<\/sub>are:<\/strong><br \/><strong>(a) isoelectronic (b) having coordinated bond<\/strong><br \/><strong>(c)having polar bond (d) having low bond energies<\/strong><br \/><strong>Question 3. The axial overlap between the two orbitals leads to the formation of a:<\/strong><br \/><strong>(a) sigma bond (b) pi bond (c) multiple bond (d) none of these<\/strong><br \/><strong>Question 4. In\u00a0S0<sub>2\u00a0<\/sub>molecule, S atom is:<\/strong><br \/><strong>(a)sp<sup>3\u00a0<\/sup>hybridized (b) sp hybridized (c) sp<sup>2\u00a0<\/sup>hybridized (d) d\u00a0sp<sup>2\u00a0<\/sup>hybridized<\/strong><br \/><strong>Question 5. A molecule or ion is stable if:<\/strong><br \/><strong>(a) Nb = Na (b) Nb &lt; Na (c) Na &lt; Nb (d) Na \u2013 Nb = + ve<\/strong><br \/><strong>Question 6. The molecule Ne2 does not exist because<\/strong><br \/><strong>(a) Nb &gt; Na (b) Nb = Na + (c) Nb &lt; Na (d) None of these<\/strong><br \/><strong>Question 7. Which one is diamagnetic among NO<sup>+<\/sup>, NO and NO ?<\/strong><br \/><strong>(a)NO<sup>+<\/sup>(b) NO (c)\u00a0NO<sup>\u2013<\/sup>(d) None of these<\/strong><br \/><strong>Question 8. In sp<sup>3<\/sup>, sp<sup>2<\/sup>\u00a0and sp hybridized carbon atom, the p character is maximum in:<\/strong><br \/><strong>(a) sp<sup>3<\/sup>\u00a0(b) sp<sup>2<\/sup><\/strong><br \/><strong>(c) sp (d) all of the above have same p-character<\/strong><br \/><strong>Question 9. Out of the following, intramolecular hydrogen bonding exists in:<\/strong><br \/><strong>(a) water (b)H<sub>2<\/sub>S\u00a0(c) 4-nitrophenol (d) 2-nitrophenol<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Answer:\u00a0<\/strong>\u00a01. (c) 2. (a) 3. (a) 4. (c) 5. (c)<br \/>6. (b) 7. (a) 8. (a) 9. (d)<\/p>\n<p>Here we presented you everything about <a href=\"http:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener noreferrer\">CBSE\u00a0<\/a><span data-sheets-value=\"{&quot;1&quot;:2,&quot;2&quot;:&quot;NCERT Solutions For Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry&quot;}\" data-sheets-userformat=\"{&quot;2&quot;:15235,&quot;3&quot;:{&quot;1&quot;:0},&quot;4&quot;:[null,2,16167531],&quot;10&quot;:2,&quot;11&quot;:0,&quot;12&quot;:0,&quot;14&quot;:[null,2,0],&quot;15&quot;:&quot;Calibri, sans-serif&quot;,&quot;16&quot;:11}\">NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure<\/span>. Still, if you find any sort of doubts make sure to ask us since are always here to help you out.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"faq-ncert-solutions-for-chemistry-chapter-4\"><\/span>FAQ: NCERT Solutions For Chemistry Chapter 4<span class=\"ez-toc-section-end\"><\/span><\/h3>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1627389445262\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"are-ncert-solutions-for-chemistry-chapter-4-difficult-to-understand\"><\/span>Are NCERT Solutions For Chemistry Chapter 4 difficult to understand?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>No not at all, if you practice regularly NCERT Solutions For Chemistry Chapter 4 is not much difficult to understand.\u00a0<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1627389488194\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-download-ncert-solutions-for-class-11-chemistry-chapter-4-pdf-for-free\"><\/span>Can I download NCERT Solutions for Class 11 Chemistry Chapter 4 PDF for free? <span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, you can download NCERT Solutions for Class 11 Chemistry Chapter 4 PDF For free. <\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1627389489776\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-is-the-name-of-ncert-solutions-for-chemistry-chapter-4\"><\/span>What is the name of NCERT Solutions For Chemistry Chapter 4? <span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>The name of NCERT Solutions For Chemistry Chapter 4 is Chemical Bonding And Molecular Structure<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1627389574448\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-are-the-topics-included-in-ncert-solutions-for-chemistry-chapter-4\"><\/span>What are the topics included in NCERT Solutions For Chemistry Chapter 4? <span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>VSEPR theory<br \/>Lewis structures<br \/>Valence bond theory<br \/>The polar character of covalent bonds<br \/>The concept of hybridization<br \/>The molecular orbital theory of homonuclear diatomic molecules<br \/>Hydrogen bonding<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1627389699592\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-are-the-ncert-solutions-for-chemistry-chapter-4-chemical-bonding-and-molecular-structure-subtopics\"><\/span>What are the NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure Subtopics? <span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can refer to the above article to know about the subtopics for NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>\u00a0 NCERT Solutions For Chemistry Chapter 4 Chemical Bonding And Molecular Structure: Students often feel overwhelmed when they start with their chemistry textbook at the beginning of their session. The chapters and syllabus might sound familiar with the previous class\u2019s curriculum, however, the concepts get elaborate descriptions thus making the topics more complicated isn\u2019t it? &#8230; <a title=\"Class 11 Chemistry NCERT Solutions 2026 For Chapter 4 Chemical Bonding And Molecular Structure\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/ncert-solutions-for-chemistry-chapter-4\/\" aria-label=\"More on Class 11 Chemistry NCERT Solutions 2026 For Chapter 4 Chemical Bonding And Molecular Structure\">Read more<\/a><\/p>\n","protected":false},"author":249,"featured_media":109911,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[2934],"tags":[3428,76474,76475],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/55572"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/249"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=55572"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/55572\/revisions"}],"predecessor-version":[{"id":574327,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/55572\/revisions\/574327"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/109911"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=55572"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=55572"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=55572"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}