{"id":126858,"date":"2023-04-24T05:12:00","date_gmt":"2023-04-23T23:42:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=126858"},"modified":"2023-04-24T14:17:07","modified_gmt":"2023-04-24T08:47:07","slug":"rd-sharma-class-10-solutions-chapter-8-exercise-8-5","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-exercise-8-5\/","title":{"rendered":"RD Sharma Class 10 Solutions Chapter 8 Quadratic Equations Exercise 8.5 (Updated for 2023)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-126883\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-8-Exercise-8.5.jpg\" alt=\"RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-8-Exercise-8.5.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-8-Exercise-8.5-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5:\u00a0<\/strong>In this exercise, the main focus is on another method known as the Quadratic formula. The Shreedharacharya&#8217;s rule is another name for it. This approach solves some of the drawbacks of factorization. Students can refer to the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-for-maths\/\"><strong>RD Sharma Solutions Class 10<\/strong><\/a> prepared by experts at Kopykitab for a more in-depth study of this concept. Below you will get the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-quadratic-equations\/\"><strong>RD Sharma Solutions for Class 10 Maths Chapter 8<\/strong><\/a> Exercise 8.5 PDF.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e75343cea76\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 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href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-exercise-8-5\/#download-rd-sharma-class-10-solutions-chapter-8-exercise-85-free-pdf\" title=\"Download RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5 Free PDF\">Download RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5 Free PDF<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-exercise-8-5\/#access-answers-to-rd-sharma-solutions-class-10-maths-chapter-8-exercise-85-important-question-with-answers\" title=\"Access answers to RD Sharma Solutions Class 10 Maths Chapter 8 Exercise 8.5- Important Question with Answers\">Access answers to RD Sharma Solutions Class 10 Maths Chapter 8 Exercise 8.5- Important Question with Answers<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-exercise-8-5\/#faqs-on-rd-sharma-class-10-solutions-chapter-8-exercise-85\" title=\"FAQs on RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5\">FAQs on RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-exercise-8-5\/#how-is-rd-sharma-class-10-solutions-chapter-8-exercise-85-helpful-for-board-exams\" title=\"How is RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5 helpful for board exams?\">How is RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5 helpful for board exams?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-exercise-8-5\/#is-the-rd-sharma-class-10-maths-solutions-chapter-8-exercise-85-available-on-the-kopykitab-website\" title=\"Is the RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 available on the Kopykitab website?\">Is the RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 available on the Kopykitab website?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-exercise-8-5\/#where-can-i-get-rd-sharma-class-10-maths-solutions-chapter-8-exercise-85-free-pdf\" title=\"Where can I get RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 Free PDF?\">Where can I get RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 Free PDF?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-exercise-8-5\/#from-where-can-i-find-the-download-link-for-rd-sharma-class-10-maths-solutions-chapter-8-exercise-85-pdf\" title=\"From where can I find the download link for RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 PDF?\">From where can I find the download link for RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 PDF?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-exercise-8-5\/#can-i-access-the-rd-sharma-class-10-maths-solutions-chapter-8-exercise-85-offline\" title=\"Can I access the RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 offline?\">Can I access the RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 offline?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-class-10-solutions-chapter-8-exercise-85-free-pdf\"><\/span>Download RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5 Free PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 800px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Solution-Class-10-Chapter-8-Exercise-8.5.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Solution-Class-10-Chapter-8-Exercise-8.5.pdf\">RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5<\/a><\/p>\n<h3><span class=\"ez-toc-section\" id=\"access-answers-to-rd-sharma-solutions-class-10-maths-chapter-8-exercise-85-important-question-with-answers\"><\/span>Access answers to RD Sharma Solutions Class 10 Maths Chapter 8 Exercise 8.5- Important Question with Answers<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>1. Write the discriminant of the following quadratic equations:<\/strong><\/p>\n<p><strong>(i) 2x<sup>2<\/sup>\u00a0\u2013 5x + 3 = 0<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given equation,<\/p>\n<p>2x<sup>2<\/sup>\u00a0\u2013 5x + 3 = 0<\/p>\n<p>It is in the form of ax<sup>2<\/sup>\u00a0+ bx + c = 0<\/p>\n<p>Where, a = 2, b = -5 and c = 3<\/p>\n<p>So, the discriminant is given by D = b<sup>2<\/sup>\u00a0\u2013 4ac<\/p>\n<p>D = (-5)<sup>2<\/sup>\u00a0\u2013 4 x 2 x 3<\/p>\n<p>D =\u00a025 \u2013 24 = 1<\/p>\n<p>Hence, the discriminant of the given quadratic equation is 1.<\/p>\n<p><strong>(ii) x<sup>2<\/sup>\u00a0+ 2x + 4 = 0<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given equation,<\/p>\n<p>x<sup>2<\/sup>\u00a0+ 2x + 4 = 0<\/p>\n<p>It is in the form of ax<sup>2<\/sup>\u00a0+ bx + c = 0<\/p>\n<p>Where, a = 1, b = 2 and c = 4<\/p>\n<p>So, the discriminant is given by D = b<sup>2<\/sup>\u00a0\u2013 4ac<\/p>\n<p>D = (2)<sup>2<\/sup>\u00a0\u2013 4 x 1 x 4<\/p>\n<p>D = 4 \u2013 16 = \u2013 12<\/p>\n<p>Hence, the discriminant of the given quadratic equation is \u2013 12.<\/p>\n<p><strong>(iii) (x \u2013 1)(2x \u2013 1) = 0<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given equation,<\/p>\n<p>(x -1) (2x -1) = 0<\/p>\n<p>On expanding it, we get<\/p>\n<p>2x<sup>2<\/sup>\u00a0\u2013 3x + 1 = 0<\/p>\n<p>It is in the form of ax<sup>2<\/sup>\u00a0+ bx + c = 0<\/p>\n<p>Where,\u00a0a = 2, b = -3, c = 1<\/p>\n<p>So, the discriminant is given by D = b<sup>2<\/sup>\u00a0\u2013 4ac<\/p>\n<p>D = (-3)<sup>2<\/sup>\u00a0\u2013 4 x 2 x 1<\/p>\n<p>D = 9 \u2013 8 = 1<\/p>\n<p>Hence, the discriminant of the given quadratic equation is 1.<\/p>\n<p><strong>(iv) x<sup>2<\/sup>\u00a0-2x + k = 0, k\u00a0<\/strong>\u2208 R<\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given equation,<\/p>\n<p>x<sup>2\u00a0<\/sup>\u2013 2x + k = 0<\/p>\n<p>It is in the form of ax<sup>2<\/sup>\u00a0+ bx + c = 0<\/p>\n<p>Where, a = 1, b = -2, and c = k<\/p>\n<p>So, the discriminant is given by D = b<sup>2<\/sup>\u00a0\u2013 4ac<\/p>\n<p>D = (-2)<sup>2<\/sup>\u00a0\u2013\u00a04(1)(k)<\/p>\n<p>= 4 \u2013 4k<\/p>\n<p>Hence, the discriminant of the given equation is (4 \u2013 4k).<\/p>\n<p><img title=\"RD Sharma Solutions for Class 10 Maths Chapter 8 Quadratic Equations\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/11\/r-d-sharma-solutions-for-class-10-maths-chapter-8-46.png\" alt=\"R D Sharma Solutions For Class 10 Maths Chapter 8 Quadratic Equations ex 8.5 - 1\" \/><\/p>\n<p><strong>(vi) x<sup>2<\/sup>\u00a0\u2013 x + 1 = 0<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given equation,<\/p>\n<p>x<sup>2<\/sup>\u00a0\u2013 x + 1 = 0 It is in the form of ax<sup>2<\/sup>\u00a0+ bx + c = 0<\/p>\n<p>Where, a = 1, b = -1 and c = 1<\/p>\n<p>So, the discriminant is given by D = b<sup>2<\/sup>\u00a0\u2013 4ac<\/p>\n<p>D = (-1)<sup>2<\/sup>\u00a0\u2013 4 \u00d7 1 \u00d7 1<\/p>\n<p>D = 1 \u2013 4 = \u2013 3<\/p>\n<p>Thus, the discriminant of the given equation is -3.<\/p>\n<p><span style=\"font-size: inherit; background-color: initial;\">We have provided complete details of RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5. If you have any queries related to <\/span><a style=\"font-size: inherit; background-color: initial;\" href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\"><strong>CBSE<\/strong><\/a><span style=\"font-size: inherit; background-color: initial;\">\u00a0Class 10, feel free to ask us in the comment section below.<\/span><\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-10-solutions-chapter-8-exercise-85\"><\/span>FAQs on RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631524561620\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-is-rd-sharma-class-10-solutions-chapter-8-exercise-85-helpful-for-board-exams\"><\/span>How is RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5 helpful for board exams?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>For self-evaluation, RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 provides solutions with thorough descriptions as per term limits specified by the Board. Students will gain valuable experience solving these problems, allowing them to complete the assignment on time.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631526265021\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-the-rd-sharma-class-10-maths-solutions-chapter-8-exercise-85-available-on-the-kopykitab-website\"><\/span>Is the RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 available on the Kopykitab website?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, the PDFs of RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 are available. These solutions are created in a unique method by Kopykitab\u2019s expert faculty.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631526480503\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"where-can-i-get-rd-sharma-class-10-maths-solutions-chapter-8-exercise-85-free-pdf\"><\/span>Where can I get RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 Free PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can get RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 Free PDF from the above article.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1682319437590\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"from-where-can-i-find-the-download-link-for-rd-sharma-class-10-maths-solutions-chapter-8-exercise-85-pdf\"><\/span>From where can I find the download link for RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can find the download link of the RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 PDF in the above blog.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1682319473069\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-access-the-rd-sharma-class-10-maths-solutions-chapter-8-exercise-85-offline\"><\/span>Can I access the RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 offline?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Once you have downloaded the RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 PDF online, you can access it offline whenever you want.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5:\u00a0In this exercise, the main focus is on another method known as the Quadratic formula. The Shreedharacharya&#8217;s rule is another name for it. This approach solves some of the drawbacks of factorization. Students can refer to the RD Sharma Solutions Class 10 prepared by experts at Kopykitab &#8230; <a title=\"RD Sharma Class 10 Solutions Chapter 8 Quadratic Equations Exercise 8.5 (Updated for 2023)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-8-exercise-8-5\/\" aria-label=\"More on RD Sharma Class 10 Solutions Chapter 8 Quadratic Equations Exercise 8.5 (Updated for 2023)\">Read more<\/a><\/p>\n","protected":false},"author":238,"featured_media":126883,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411,2985,73410],"tags":[3243,9206,73520,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126858"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/238"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=126858"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126858\/revisions"}],"predecessor-version":[{"id":356194,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126858\/revisions\/356194"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/126883"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=126858"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=126858"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=126858"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}