{"id":126721,"date":"2023-09-13T13:37:00","date_gmt":"2023-09-13T08:07:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=126721"},"modified":"2023-11-14T10:07:46","modified_gmt":"2023-11-14T04:37:46","slug":"rd-sharma-class-9-solutions-chapter-12-exercise-12-2","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-12-exercise-12-2\/","title":{"rendered":"RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2 (Updated for 2024)"},"content":{"rendered":"\n<p><strong style=\"font-size: inherit; background-color: initial;\">RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2: <\/strong><span style=\"font-size: inherit; background-color: initial;\">We have the perfect Maths guide for all the Class 9 students, i.e., <\/span><a style=\"font-size: inherit; background-color: initial;\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-for-maths\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 9 Maths.<\/a><span style=\"font-size: inherit; background-color: initial;\"> You can practice the questions and clear all your doubts. <\/span><a style=\"font-size: inherit; background-color: initial;\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-12-herons-formula\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 12<\/a><span style=\"font-size: inherit; background-color: initial;\"> Exercise 12.2 solutions are designed as per the current CBSE Syllabus by our subject matter experts. To know more, read the whole blog.\u00a0<\/span><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69da60538fcbc\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69da60538fcbc\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-12-exercise-12-2\/#download-rd-sharma-class-9-solutions-chapter-12-exercise-122-pdf\" title=\"Download RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2 PDF\">Download RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2 PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-12-exercise-12-2\/#access-answers-of-rd-sharma-class-9-solutions-chapter-12-exercise-122\" title=\"Access answers of RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2\">Access answers of RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-12-exercise-12-2\/#faqs-on-rd-sharma-class-9-solutions-chapter-12-exercise-122\" title=\"FAQs on RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2\u00a0\">FAQs on RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2\u00a0<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-12-exercise-12-2\/#from-where-can-i-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-12-exercise-122\" title=\"From where can I download the PDF of RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2?\">From where can I download the PDF of RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-12-exercise-12-2\/#how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-12-exercise-122\" title=\"How much does it cost to download the PDF of RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2?\">How much does it cost to download the PDF of RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-12-exercise-12-2\/#can-i-access-the-rd-sharma-class-9-solutions-chapter-12-exercise-122-pdf-offline\" title=\"Can I access the RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2\u00a0PDF offline?\">Can I access the RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2\u00a0PDF offline?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-class-9-solutions-chapter-12-exercise-122-pdf\"><\/span><strong>Download RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2 PDF<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-SHARMA-Solutions-Class-9-Maths-Chapter-12-Ex-12.2.pdf\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-SHARMA-Solutions-Class-9-Maths-Chapter-12-Ex-12.2.pdf\", \"#example1\");<\/script><\/p>\n<h2><span class=\"ez-toc-section\" id=\"access-answers-of-rd-sharma-class-9-solutions-chapter-12-exercise-122\"><\/span><strong>Access answers of RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\"><strong style=\"box-sizing: border-box;\">Question 1: Find the area of the quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.<\/strong><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\"><strong style=\"box-sizing: border-box;\">Solution:<\/strong><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Area of the quadrilateral ABCD = Area of \u25b3ABC + Area of \u25b3ADC \u2026.(1)<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">\u25b3ABC is a right-angled triangle, which is right-angled at B.<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Area of \u25b3ABC = 1\/2 x Base x Height<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 1\/2\u00d7AB\u00d7BC<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 1\/2\u00d73\u00d74<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 6<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Area of \u25b3ABC = 6 cm<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span>\u00a0\u2026\u2026(2)<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Now, In \u25b3CAD,<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Sides are given, apply Heron\u2019s Formula.<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\"><img style=\"box-sizing: border-box; border-width: 1px; border-style: solid; border-color: rgba(255, 255, 255, 0.95); vertical-align: middle; box-shadow: rgba(0, 0, 0, 0.05) 0px 3px 3px; padding: 5px; background: rgba(255, 255, 255, 0.8);\" title=\"RD Sharma Class 9 Maths chapter 12 ex 12.2 question 1 Solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-12-ex-12-2-questio-1.png\" alt=\"RD Sharma Class 9 Maths chapter 12 ex 12.2 question 1 Solution\" \/><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Perimeter = 2s = AC + CD + DA<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">2s = 5 cm + 4 cm + 5 cm<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">2s = 14 cm<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">s = 7 cm<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">\u00a0<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Area of the \u25b3CAD = 9.16 cm<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span>\u00a0\u2026(3)<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Using equations (2) and (3) in (1), we get<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Area of quadrilateral ABCD = (6 + 9.16) cm<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 15.16 cm<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span>.<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\"><strong style=\"box-sizing: border-box;\">Question 2: The sides of a quadrilateral field, taken in order, are 26 m, 27 m, 7 m, and 24 m, respectively. The angle contained by the last two sides is a right angle. Find its area.<\/strong><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\"><strong style=\"box-sizing: border-box;\">Solution:<\/strong><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">\u00a0<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Here,<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">AB = 26 m, BC = 27 m, CD = 7 m, DA = 24 m<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">AC is the diagonal joined at A to C point.<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Now, in \u25b3ADC,<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">From the Pythagoras theorem,<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">AC<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span>\u00a0= AD<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span>\u00a0+ CD<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">AC<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2\u00a0<\/span>= 14<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2\u00a0<\/span>+ 7<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">AC = 25<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Now, the area of \u25b3ABC<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">All the sides are known, Apply Heron\u2019s Formula.<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\"><img style=\"box-sizing: border-box; border-width: 1px; border-style: solid; border-color: rgba(255, 255, 255, 0.95); vertical-align: middle; box-shadow: rgba(0, 0, 0, 0.05) 0px 3px 3px; padding: 5px; background: rgba(255, 255, 255, 0.8);\" title=\"RD Sharma Class 9 Maths chapter 12 ex 12.2 question 2 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-12-ex-12-2-questio-4.png\" alt=\"RD Sharma Class 9 Maths chapter 12 ex 12.2 question 2 solution\" \/><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Perimeter of \u25b3ABC= 2s = AB + BC + CA<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">2s = 26 m + 27 m + 25 m<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">s = 39 m<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\"><img style=\"box-sizing: border-box; border-width: 1px; border-style: solid; border-color: rgba(255, 255, 255, 0.95); vertical-align: middle; box-shadow: rgba(0, 0, 0, 0.05) 0px 3px 3px; padding: 5px; background: rgba(255, 255, 255, 0.8);\" title=\"RD Sharma Class 9 Maths chapter 12 ex 12.2 question 1 solutions\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-12-ex-12-2-questio-5.png\" alt=\"RD Sharma Class 9 Maths chapter 12 ex 12.2 question 1 solutions\" \/><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 291.84<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Area of a triangle ABC = 291.84 m<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Now, for the area of \u25b3ADC, (Right angle triangle)<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Area = 1\/2 x Base X Height<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 1\/2 x 7 x 24<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 84<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Thus, the area of a \u25b3ADC is 84 m<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Therefore, the area of rectangular field ABCD = Area of \u25b3ABC + Area of \u25b3ADC<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 291.84 m<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span>\u00a0+ 84 m<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 375.8 m<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\"><strong style=\"box-sizing: border-box;\">Question 3: The sides of a quadrilateral, taken in order as 5, 12, 14, and 15 meters, respectively, and the angle contained by the first two sides is a right angle. Find its area.<\/strong><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\"><strong style=\"box-sizing: border-box;\">Solution:<\/strong><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">\u00a0<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Here, AB = 5 m, BC = 12 m, CD =14 m and DA = 15 m<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Join the diagonal AC.<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Now, the area of \u25b3ABC = 1\/2 \u00d7AB\u00d7BC<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 1\/2\u00d75\u00d712 = 30<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">The area of \u25b3ABC is 30 m<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">In \u25b3ABC (right triangle),<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">From the Pythagoras theorem,<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">AC<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span>\u00a0= AB<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span>\u00a0+ BC<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">AC<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span>\u00a0= 5<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2\u00a0<\/span>+ 12<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">AC<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span>\u00a0= 25 + 144 = 169<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">or AC = 13<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Now in \u25b3ADC,<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">All sides are known, apply Heron\u2019s Formula:<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\"><img style=\"box-sizing: border-box; border-width: 1px; border-style: solid; border-color: rgba(255, 255, 255, 0.95); vertical-align: middle; box-shadow: rgba(0, 0, 0, 0.05) 0px 3px 3px; padding: 5px; background: rgba(255, 255, 255, 0.8);\" title=\"RD Sharma Class 9 Maths chapter 12 ex 12.2 question 3 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-12-ex-12-2-questio-7.png\" alt=\"RD Sharma Class 9 Maths chapter 12 ex 12.2 question 3 solution\" \/><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Perimeter of \u25b3ADC = 2s = AD + DC + AC<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">2s = 15 m +14 m +13 m<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">s = 21 m<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">\u00a0<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 84<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Area of \u25b3ADC = 84 m<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">Area of quadrilateral ABCD = Area of \u25b3ABC + Area of \u25b3ADC<\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= (30 + 84) m<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p style=\"box-sizing: border-box; margin-bottom: 16px; font-size: 16px; line-height: 24px; color: #444444; font-family: Poppins, sans-serif; background-color: #ffffff;\">= 114 m<span style=\"box-sizing: border-box; font-size: 12px; line-height: 0; position: relative; vertical-align: baseline; top: -0.5em;\">2<\/span><\/p>\n<p>This is the complete blog on RD Sharma for Class 9 Solutions Chapter 12 Exercise 12.2. To know more about the <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 9 Maths exam, ask in the comments.\u00a0<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-9-solutions-chapter-12-exercise-122\"><\/span><strong>FAQs on RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2<\/strong>\u00a0<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631294768075\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"from-where-can-i-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-12-exercise-122\"><\/span>From where can I download the PDF of RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can find the download link from the above blog.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631294831951\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-12-exercise-122\"><\/span>How much does it cost to download the PDF of RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download it for free.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631294865130\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-access-the-rd-sharma-class-9-solutions-chapter-12-exercise-122-pdf-offline\"><\/span>Can I access the RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2\u00a0PDF offline?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Once you have downloaded the PDF online, you can access it offline as well.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2: We have the perfect Maths guide for all the Class 9 students, i.e., RD Sharma Solutions Class 9 Maths. You can practice the questions and clear all your doubts. RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2 solutions are designed as per the current CBSE &#8230; <a title=\"RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2 (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-12-exercise-12-2\/\" aria-label=\"More on RD Sharma Class 9 Solutions Chapter 12 Exercise 12.2 (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":126723,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411],"tags":[3086,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126721"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=126721"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126721\/revisions"}],"predecessor-version":[{"id":506792,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126721\/revisions\/506792"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/126723"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=126721"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=126721"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=126721"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}