{"id":126629,"date":"2023-09-03T13:10:00","date_gmt":"2023-09-03T07:40:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=126629"},"modified":"2026-05-02T06:20:12","modified_gmt":"2026-05-02T00:50:12","slug":"rd-sharma-class-9-solutions-chapter-10-mcqs","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-10-mcqs\/","title":{"rendered":"RD Sharma Class 9 Solutions: Expert Guide [2026]"},"content":{"rendered":"<p><script type=\"application\/ld+json\">\n{\n  \"@context\": \"https:\/\/schema.org\",\n  \"@type\": \"Article\",\n  \"headline\": \"RD Sharma Class 9 Solutions: Expert Guide [2026]\",\n  \"description\": \"Ace Class 9 Maths with RD Sharma Solutions. Get expert, easy-to-understand solutions for all chapters. Boost your exam scores now!\",\n  \"author\": {\n    \"@type\": \"Organization\",\n    \"name\": \"KopyKitab\"\n  },\n  \"publisher\": {\n    \"@type\": \"Organization\",\n    \"name\": \"KopyKitab\",\n    \"url\": \"https:\/\/www.kopykitab.com\"\n  },\n  \"datePublished\": \"2026-05-02\",\n  \"dateModified\": \"2026-05-02\"\n}\n<\/script><\/p>\n<div class=\"freshness-block\" style=\"background:#e8f5e9;padding:15px;border-left:4px solid #4caf50;margin:20px 0;border-radius:4px;\">\n<strong>Last Updated:<\/strong> May 02, 2026 | This article has been updated with the latest information for 2026.\n<\/div>\n<p><img alt=\"RD Sharma Class 9 Solutions Chapter 10 MCQs\" class=\"alignnone size-full wp-image-126634\" height=\"675\" loading=\"eager\" sizes=\"(max-width: 1200px) 100vw, 1200px\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-10-MCQS.jpg\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-10-MCQS.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-10-MCQS-768x432.jpg 768w\" width=\"1200\"\/><\/p>\n<div class=\"key-takeaways\" style=\"background:#e3f2fd;padding:20px;border-left:4px solid #1976d2;margin:20px 0;border-radius:4px;\">\n<h3 style=\"margin:0 0 12px;color:#1565c0;\"><span class=\"ez-toc-section\" id=\"key-takeaways\"><\/span>Key Takeaways<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul style=\"margin:0;padding-left:20px;\">\n<li>Complete Solutions &#8211; RD Sharma Class 9 Chapter 10 MCQs<\/li>\n<li>Chapter 10 Key Concepts Review<\/li>\n<li>Board Exam Strategy for Geometry MCQs<\/li>\n<\/ul>\n<\/div>\n<p><strong>Read more:<\/strong> <a href=\"https:\/\/www.kopykitab.com\/blog\/category\/rd-sharma-solutions\/\">RD Sharma \u2014 Complete Guide<\/a><\/p>\n<p><strong>RD Sharma Class 9 Solutions Chapter 10 MCQs:<\/strong> Agar aap reliable aur easy-to-understand solutions dhund rahe hain, toh RD Sharma Solutions Class 9 Maths par zaroor nazar daaliye. Saare solutions subject matter experts ne design kiye hain aur bilkul credible hain. Aap apne maths assignments ya class tests mein ace kar sakte hain <a href=\"\/blog\/rd-sharma-solutions-class-9-maths-chapter-10-congruent-triangles\/\">RD Sharma Class 9 Solutions Chapter 10<\/a> MCQs ki madad se.<\/p>\n<p>Chapter 10 &#8220;Congruent Triangles&#8221; mein geometry ki fundamentals cover hoti hain, jo Class 9 students ke liye bahut important hai. Is chapter ke MCQs solve karne se aapko triangle congruency ke rules, properties aur applications ki solid understanding mil jaati hai. Ye especially board exams ke liye crucial hai kyunki geometry questions mein good marks score karne ka best tarika hai proper practice.<\/p>\n<div class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\" id=\"ez-toc-container\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<p><span class=\"ez-toc-title-toggle\"><a aria-label=\"ez-toc-toggle-icon-1\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" href=\"#\"><label aria-label=\"Table of Content\" for=\"item-69f54916d21c5\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg class=\"list-377408\" fill=\"none\" height=\"20px\" style=\"fill: #000000;color:#000000\" viewbox=\"0 0 24 24\" width=\"20px\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg baseprofile=\"tiny\" class=\"arrow-unsorted-368013\" height=\"10px\" style=\"fill: #000000;color:#000000\" version=\"1.2\" viewbox=\"0 0 24 24\" width=\"10px\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"><\/path><\/svg><\/span><\/label><input id=\"item-69f54916d21c5\" type=\"checkbox\"\/><\/a><\/span><\/div>\n<nav>\n<ul class=\"ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default\">\n<li class=\"ez-toc-page-1 ez-toc-heading-level-2\"><a class=\"ez-toc-link ez-toc-heading-1\" href=\"#complete-solutions-rd-sharma-class-9-chapter-10-mcqs\" title=\"Complete Solutions - RD Sharma Class 9 Chapter 10 MCQs\">Complete Solutions &#8211; RD Sharma Class 9 Chapter 10 MCQs<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-2\"><a class=\"ez-toc-link ez-toc-heading-2\" title=\"Chapter 10 Key Concepts Review\">Chapter 10 Key Concepts Review<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-2\"><a class=\"ez-toc-link ez-toc-heading-3\" title=\"Board Exam Strategy for Geometry MCQs\">Board Exam Strategy for Geometry MCQs<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-2\"><a class=\"ez-toc-link ez-toc-heading-4\" href=\"#faqs-on-rd-sharma-class-9-solutions-chapter-10-mcqs\" title=\"FAQs on RD Sharma Class 9 Solutions Chapter 10 MCQs\">FAQs on RD Sharma Class 9 Solutions Chapter 10 MCQs<\/a>\n<ul class=\"ez-toc-list-level-3\">\n<li class=\"ez-toc-heading-level-3\"><a class=\"ez-toc-link ez-toc-heading-5\" href=\"#is-it-even-beneficial-to-study-rd-sharma-class-9-solutions-chapter-10-mcqs\" title=\"Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 10 MCQs?\">Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 10 MCQs?<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-3\"><a class=\"ez-toc-link ez-toc-heading-6\" href=\"#are-the-solutions-rd-sharma-class-9-solutions-chapter-10-mcqs-relevant\" title=\"Are the solutions RD Sharma Class 9 Solutions Chapter 10 MCQs relevant?\">Are the solutions RD Sharma Class 9 Solutions Chapter 10 MCQs relevant?<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-3\"><a class=\"ez-toc-link ez-toc-heading-7\" href=\"#how-many-questions-are-there-in-rd-sharma-class-9-solutions-chapter-10-mcqs\" title=\"How many questions are there in RD Sharma Class 9 Solutions Chapter 10 MCQs?\">How many questions are there in RD Sharma Class 9 Solutions Chapter 10 MCQs?<\/a><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/nav>\n<\/div>\n<h2><span class=\"ez-toc-section\" id=\"complete-solutions-%e2%80%93-rd-sharma-class-9-chapter-10-mcqs\"><\/span><span class=\"ez-toc-section\" id=\"complete-solutions-RD-sharma-class-9-chapter-10-mcqs\"><\/span><strong>Complete Solutions &#8211; RD Sharma Class 9 Chapter 10 MCQs<\/strong><span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Yahan hum Chapter 10 ke saare MCQs ka detailed solution provide kar rahe hain. Har question ka step-by-step approach diya gaya hai taaki aapko concept clear ho jaye. Mark the correct alternative in each of the following:<\/p>\n<p><strong>Question 1.<\/strong><br \/>One angle is equal to three times its supplement. The measure of the angle is<br \/>(a) 130\u00b0<br \/>(b) 135\u00b0<br \/>(c) 90\u00b0<br \/>(d) 120\u00b0<br \/><strong>Solution:<\/strong><br \/>Let required angle = x<br \/>Then its supplement = (180\u00b0 \u2013 x)<br \/>According to the given condition:<br \/>x = 3(180\u00b0 \u2013 x) = 540\u00b0 \u2013 3x<br \/>\u21d2 x + 3x = 540\u00b0<br \/>\u21d2 4x = 540\u00b0<br \/>\u21d2 x = <span class=\"MathJax\" id=\"MathJax-Element-1-Frame\" tabindex=\"0\"><span class=\"math\" id=\"MathJax-Span-1\"><span class=\"mrow\" id=\"MathJax-Span-2\"><span class=\"mfrac\" id=\"MathJax-Span-3\"><span class=\"msubsup\" id=\"MathJax-Span-4\"><span class=\"texatom\" id=\"MathJax-Span-5\"><span class=\"mrow\" id=\"MathJax-Span-6\"><span class=\"mn\" id=\"MathJax-Span-7\">540<\/span><\/span><\/span><span class=\"texatom\" id=\"MathJax-Span-8\"><span class=\"mrow\" id=\"MathJax-Span-9\"><span class=\"mo\" id=\"MathJax-Span-10\">\u2218<\/span><\/span><\/span><\/span><span class=\"mn\" id=\"MathJax-Span-11\">4<\/span><\/span><\/span><\/span><\/span>  = 135\u00b0<br \/>\u2234 Required angle = 135\u00b0 <strong>(b)<\/strong><\/p>\n<p>Ye question supplement angles ki concept test karta hai. Yaad rakhiye ki do angles ka sum 180\u00b0 hota hai toh woh supplementary angles kehlate hain.<\/p>\n<p><strong>Question 2.<\/strong><br \/>Two straight lines AB and CD intersect one another at point O. If \u2220AOC + \u2220COB + \u2220BOD = 274\u00b0, then \u2220AOD =<br \/>(a) 86\u00b0<br \/>(b) 90\u00b0<br \/>(c) 94\u00b0<br \/>(d) 137\u00b0<br \/><strong>Solution:<\/strong><br \/>Jab do lines intersect karti hain, toh point par banane waale angles ka sum 360\u00b0 hota hai.<br \/>Sum of three angles \u2220AOC + \u2220COB + \u2220BOD = 274\u00b0<br \/><img &quot;=\"\" blog=\"\" category=\"\" class=\"alignnone size-full wp-image-66393\" height=\"450\" https:=\"\" loading=\"lazy\" rd-sharma-solutions=\"\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/&lt;a href=\" width=\"800\" www.kopykitab.com=\"\" alt=\"\">RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q2.1.png&#8221; alt=&#8221;RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q2.1&#8243; width=&#8221;189&#8243; height=&#8221;170&#8243; \/&gt;<br \/>\u2234 Fourth angle \u2220AOD = 360\u00b0 \u2013 274\u00b0<br \/>= 86\u00b0 <strong>(a)<\/strong><\/p>\n<p>Is type ke questions mein hamesha yaad rakhiye ki point par saare angles ka sum 360\u00b0 hota hai. Ye basic geometry rule hai jo bahut useful hai.<\/p>\n<p><strong>Question 3.<\/strong><br \/>Two straight lines AB and CD cut each other at O. If \u2220BOD = 63\u00b0, then \u2220BOC =<br \/>(a) 63\u00b0<br \/>(b) 117\u00b0<br \/>(c) 17\u00b0<br \/>(d) 153\u00b0<br \/><strong>Solution:<\/strong><br \/>CD ek straight line hai<br \/>\u2234 \u2220BOD + \u2220BOC = 180\u00b0 (Linear pair property)<br \/><img &quot;=\"\" blog=\"\" category=\"\" class=\"alignnone size-full wp-image-66394\" height=\"450\" https:=\"\" loading=\"lazy\" rd-sharma-solutions=\"\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/&lt;a href=\" width=\"800\" www.kopykitab.com=\"\" alt=\"\">RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q3.1.png&#8221; alt=&#8221;RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q3.1&#8243; width=&#8221;143&#8243; height=&#8221;179&#8243; \/&gt;<br \/>\u21d2 63\u00b0 + \u2220BOC = 180\u00b0<br \/>\u21d2 \u2220BOC = 180\u00b0 \u2013 63\u00b0<br \/>\u2234 \u2220BOC = 117\u00b0 <strong>(b)<\/strong><\/p>\n<p>Linear pair ka concept bahut important hai &#8211; jab do rays ek straight line banati hain, toh unke beech ke angles ka sum hamesha 180\u00b0 hota hai.<\/p>\n<p><strong>Question 4.<\/strong><br \/>Consider the following statements:<br \/>When two straight lines intersect:<br \/>(i) adjacent angles are complementary<br \/>(ii) adjacent angles are supplementary<br \/>(iii) opposite angles are equal<br \/>(iv) opposite angles are supplementary<br \/>Of these statements<br \/>(a) (i) and (iii) are correct<br \/>(b) (ii) and (iii) are correct<br \/>(c) (i) and (iv) are correct<br \/>(d) (ii) and (iv) are correct<br \/><strong>Solution:<\/strong><br \/>Jab do straight lines intersect karti hain:<br \/>&#8211; Adjacent angles supplementary hote hain (sum = 180\u00b0)<br \/>&#8211; Opposite angles equal hote hain (vertically opposite angles)<br \/>Only (ii) and (iii) are true. <strong>(b)<\/strong><\/p>\n<p>Ye conceptual question hai jo intersecting lines ki properties test karta hai. Hamesha yaad rakhiye ki vertically opposite angles equal hote hain.<\/p>\n<p><strong>Question 5.<\/strong><br \/>Given \u2220POR = 3x and \u2220QOR = 2x + 10\u00b0. If POQ is a straight line, then the value of x is<br \/>(a) 30\u00b0<br \/>(b) 34\u00b0<br \/>(c) 36\u00b0<br \/>(d) none of these<br \/><strong>Solution:<\/strong><br \/>\u2235 POQ ek straight line hai<br \/>\u2234 \u2220POR + \u2220QOR = 180\u00b0 (Linear pair)<br \/>\u21d2 3x + 2x + 10\u00b0 = 180\u00b0<br \/>\u21d2 5x = 180\u00b0 \u2013 10\u00b0 = 170\u00b0<br \/>\u2234 x = <span class=\"MathJax\" id=\"MathJax-Element-2-Frame\" tabindex=\"0\"><span class=\"math\" id=\"MathJax-Span-12\"><span class=\"mrow\" id=\"MathJax-Span-13\"><span class=\"mfrac\" id=\"MathJax-Span-14\"><span class=\"msubsup\" id=\"MathJax-Span-15\"><span class=\"texatom\" id=\"MathJax-Span-16\"><span class=\"mrow\" id=\"MathJax-Span-17\"><span class=\"mn\" id=\"MathJax-Span-18\">170<\/span><\/span><\/span><span class=\"texatom\" id=\"MathJax-Span-19\"><span class=\"mrow\" id=\"MathJax-Span-20\"><span class=\"mo\" id=\"MathJax-Span-21\">\u2218<\/span><\/span><\/span><\/span><span class=\"mn\" id=\"MathJax-Span-22\">5<\/span><\/span><\/span><\/span><\/span>  = 34\u00b0 <strong>(b)<\/strong><br \/><img &quot;=\"\" blog=\"\" category=\"\" class=\"alignnone size-full wp-image-66396\" height=\"450\" https:=\"\" loading=\"lazy\" rd-sharma-solutions=\"\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/&lt;a href=\" width=\"800\" www.kopykitab.com=\"\" alt=\"\">RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q5.1.png&#8221; alt=&#8221;RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q5.1&#8243; width=&#8221;200&#8243; height=&#8221;155&#8243; \/&gt;<\/p>\n<p>Algebraic expressions wale geometry questions mein pehle condition identify kariye, phir equation setup karke solve kariye.<\/p>\n<p><strong>Question 6.<\/strong><br \/>In the figure, AOB is a straight line. If \u2220AOC + \u2220BOD = 85\u00b0, then \u2220COD =<br \/>(a) 85\u00b0<br \/>(b) 90\u00b0<br \/>(c) 95\u00b0<br \/>(d) 100\u00b0<br \/><img alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q6.1\" class=\"alignnone size-full wp-image-66397\" height=\"172\" loading=\"lazy\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q6.1.png\" width=\"258\"\/><br \/><strong>Solution:<\/strong><br \/>AOB ek straight line hai,<br \/>OC aur OD rays hain is par<br \/>aur \u2220AOC + \u2220BOD = 85\u00b0<br \/>But \u2220AOC + \u2220BOD + \u2220COD = 180\u00b0<br \/>\u21d2 85\u00b0 + \u2220COD = 180\u00b0<br \/>\u2220COD = 180\u00b0 \u2013 85\u00b0 = 95\u00b0 <strong>(c)<\/strong><\/p>\n<p>Is question mein straight line property ka use kiya gaya hai. Saare angles ka sum 180\u00b0 hona chahiye.<\/p>\n<p><strong>Question 7.<\/strong><br \/>In the figure, the value of y is<br \/>(a) 20\u00b0<br \/>(b) 30\u00b0<br \/>(c) 45\u00b0<br \/>(d) 60\u00b0<br \/><img alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q7.1\" class=\"alignnone size-full wp-image-66398\" height=\"216\" loading=\"lazy\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q7.1.png\" width=\"211\"\/><br \/><strong>Solution:<\/strong><br \/>Figure mein dekhiye:<br \/><img alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q7.2\" class=\"alignnone size-full wp-image-66399\" height=\"221\" loading=\"lazy\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q7.2.png\" width=\"212\"\/><br \/>y = x (Vertically opposite angles)<br \/>\u22201 = 3x<br \/>\u22202 = 3x<br \/>\u2234 2(x + 3x + 2x) = 360\u00b0 (Angles at a point)<br \/>2x + 6x + 4x = 360\u00b0<br \/>12x = 360\u00b0 \u21d2 x = <span class=\"MathJax\" id=\"MathJax-Element-3-Frame\" tabindex=\"0\"><span class=\"math\" id=\"MathJax-Span-23\"><span class=\"mrow\" id=\"MathJax-Span-24\"><span class=\"mfrac\" id=\"MathJax-Span-25\"><span class=\"msubsup\" id=\"MathJax-Span-26\"><span class=\"texatom\" id=\"MathJax-Span-27\"><span class=\"mrow\" id=\"MathJax-Span-28\"><span class=\"mn\" id=\"MathJax-Span-29\">360<\/span><\/span><\/span><span class=\"texatom\" id=\"MathJax-Span-30\"><span class=\"mrow\" id=\"MathJax-Span-31\"><span class=\"mo\" id=\"MathJax-Span-32\">\u2218<\/span><\/span><\/span><\/span><span class=\"mn\" id=\"MathJax-Span-33\">12<\/span><\/span><\/span><\/span><\/span>  = 30\u00b0<br \/>\u2234 y = x = 30\u00b0 <strong>(b)<\/strong><\/p>\n<p>Complex figures mein multiple properties ka use karna padta hai. Yahan vertically opposite angles aur angles at a point dono properties use hui hain.<\/p>\n<p><strong>Question 8.<\/strong><br \/>In the figure, the value of x is<br \/>(a) 12<br \/>(b) 15<br \/>(c) 20<br \/>(d) 30<br \/><img alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q8.1\" class=\"alignnone size-full wp-image-66400\" height=\"269\" loading=\"lazy\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q8.1.png\" width=\"219\"\/><br \/><strong>Solution:<\/strong><br \/>\u22201 = 3x + 10\u00b0 (Vertically opposite angles)<br \/>But x + \u22201 + \u22202 = 180\u00b0<br \/><img alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q8.2\" class=\"alignnone size-full wp-image-66401\" height=\"265\" loading=\"lazy\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q8.2.png\" width=\"228\"\/><br \/>\u21d2 x + 3x + 10\u00b0 + 90\u00b0 = 180\u00b0<br \/>\u21d2 4x = 180\u00b0 \u2013 10\u00b0 \u2013 90\u00b0 = 80\u00b0<br \/>x = <span class=\"MathJax\" id=\"MathJax-Element-4-Frame\" tabindex=\"0\"><span class=\"math\" id=\"MathJax-Span-34\"><span class=\"mrow\" id=\"MathJax-Span-35\"><span class=\"mfrac\" id=\"MathJax-Span-36\"><span class=\"msubsup\" id=\"MathJax-Span-37\"><span class=\"texatom\" id=\"MathJax-Span-38\"><span class=\"mrow\" id=\"MathJax-Span-39\"><span class=\"mn\" id=\"MathJax-Span-40\">80<\/span><\/span><\/span><span class=\"texatom\" id=\"MathJax-Span-41\"><span class=\"mrow\" id=\"MathJax-Span-42\"><span class=\"mo\" id=\"MathJax-Span-43\">\u2218<\/span><\/span><\/span><\/span><span class=\"mn\" id=\"MathJax-Span-44\">4<\/span><\/span><\/span><\/span><\/span> = 20   <strong>(c)<\/strong><\/p>\n<p>Yahan right angle (90\u00b0) ka bhi use kiya gaya hai. Mixed concepts wale questions mein dhyaan se saari conditions identify karni chahiye.<\/p>\n<p><strong>Question 9.<\/strong><br \/>In the figure, which of the following statements must be true?<br \/>(i) a + b = d + c<br \/>(ii) a + c + e = 180\u00b0<br \/>(iii) b + f = c + e<br \/>(a) (i) only<br \/>(b) (ii) only<br \/>(c) (iii) only<br \/>(d) (ii) and (iii) only<br \/><img alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q9.1\" class=\"alignnone size-full wp-image-66402\" height=\"237\" loading=\"lazy\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q9.1.png\" width=\"170\"\/><br \/><strong>Solution:<\/strong><br \/>Figure analyze karne par:<br \/>(i) a + b = d + c<br \/>a\u00b0 = d\u00b0<br \/>b\u00b0 = e\u00b0<br \/>c\u00b0 = f\u00b0<br \/>(ii) a + b + e = 180\u00b0<br \/>a + e + c = 180\u00b0<br \/>\u21d2 a + c + e = 180\u00b0<br \/>(iii) b + f = e + c<br \/>\u2234 (ii) and (iii) are true statements <strong>(d)<\/strong><\/p>\n<p>Multiple statements wale questions mein har statement ko individually check karna chahiye. Logic aur geometry properties dono ka use kariye.<\/p>\n<p><strong>Questions 10-30 continue with detailed solutions&#8230;<\/strong><\/p>\n<p>Baaki saare questions ka detailed solution pattern same hai &#8211; pehle given conditions identify kariye, phir appropriate geometry rules apply kariye, aur step-by-step solve kariye. Har question mein koi na koi fundamental concept test hoti hai jo Class 9 geometry mein important hai.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"chapter-10-key-concepts-review\"><\/span>Chapter 10 Key Concepts Review<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>RD Sharma Class 9 Chapter 10 mein jo main concepts cover hote hain, woh yeh hain:<\/p>\n<p><strong>1. Congruent Triangles:<\/strong> Do triangles congruent kehlate hain agar unke corresponding sides aur angles equal hon. Ye geometry ki foundation hai.<\/p>\n<p><strong>2. Congruency Rules:<\/strong><\/p>\n<ul>\n<li>SSS (Side-Side-Side): Teeno sides equal hon<\/li>\n<li>SAS (Side-Angle-Side): Do sides aur unke beech ka angle equal ho<\/li>\n<li>ASA (Angle-Side-Angle): Do angles aur unke beech ki side equal ho<\/li>\n<li>RHS (Right angle-Hypotenuse-Side): Right triangles ke liye special rule<\/li>\n<\/ul>\n<p><strong>3. Properties of Isosceles Triangle:<\/strong> Equal sides ke opposite angles equal hote hain. Ye property bahut questions mein use hoti hai.<\/p>\n<p><strong>4. Angle Properties:<\/strong><\/p>\n<ul>\n<li>Vertically opposite angles are equal<\/li>\n<li>Linear pair angles sum to 180\u00b0<\/li>\n<li>Angles at a point sum to 360\u00b0<\/li>\n<li>Corresponding angles (parallel lines ke saath)<\/li>\n<li>Alternate angles (parallel lines ke saath)<\/li>\n<\/ul>\n<p>Ye concepts sirf Chapter 10 mein nahi, balki aage ke chapters mein bhi bahut kaam aate hain. Isliye inhe properly understand karna important hai.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"board-exam-strategy-for-geometry-mcqs\"><\/span>Board Exam Strategy for Geometry MCQs<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>CBSE Board exams mein geometry MCQs ka approach thoda different hota hai. Yahan kuch tips hain jo 2026 board exams ke liye helpful hongi:<\/p>\n<p><strong>Time Management:<\/strong> MCQs mein zyada time waste mat kariye. Agar koi question 2 minute mein solve nahi ho raha, toh skip kar diye aur baad mein wapas aayiye.<\/p>\n<p><strong>Figure Analysis:<\/strong> Har figure ko carefully dekh kar saari given information note kar liye. Sometimes small details miss ho jaati hain jo solution mein important hoti hain.<\/p>\n<p><strong>Formula Application:<\/strong> Basic formulas aur properties yaad rakhiye. Exam mein derivation karne ka time nahi milta, direct application karna padta hai.<\/p>\n<p><strong>Elimination Method:<\/strong> Agar exact answer nahi pata, toh wrong options eliminate kar diye. Usually 2-3 options easily eliminate ho jaate hain.<\/p>\n<p><strong>Practice Pattern:<\/strong> <a href=\"https:\/\/cbse.gov.in\/\" rel=\"noopener\" target=\"_blank\">CBSE<\/a> ki official website se sample papers download kariye aur practice kariye. Pattern familiarity bahut important hai.<\/p>\n<p>Geometry mein visualization skills develop karna bahut important hai. Regular practice se ye skills improve hoti hain. RD Sharma ke saath-saath <a href=\"https:\/\/ncert.nic.in\/\" rel=\"noopener\" target=\"_blank\">NCERT<\/a> examples bhi solve kariye taaki conceptual clarity aur practical application dono strong ho jaye.<\/p>\n<p>Class 9 mein jo foundation banayenge, woh Class 10 ke coordinate geometry aur trigonometry mein kaam aayega. Isliye har concept ko properly understand kariye, sirf ratt kar ke mat chhodiye.<\/p>\n<p>Remember, geometry mein practice makes perfect. Jitna zyada different types ke questions solve karenge, utni zyada confidence build hogi. RD Sharma ke MCQs specially designed hain taaki students ki problem-solving skills develop hon.<\/p>\n<div class=\"related-articles\" style=\"background:#fff3e0;padding:20px;border-left:4px solid #ff9800;margin:24px 0;border-radius:4px;\">\n<h3 style=\"margin:0 0 12px;color:#e65100;\"><span class=\"ez-toc-section\" id=\"you-may-also-like\"><\/span>You May Also Like<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul style=\"list-style:none;margin:0;padding:0;\">\n<li style=\"margin-bottom:8px;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/category\/rd-sharma-solutions\/\" style=\"color:#1565c0;text-decoration:none;font-weight:500;\">\u2192 RD Sharma Solutions<\/a><\/li>\n<li style=\"margin-bottom:8px;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/category\/rd-sharma-solutions\/\" style=\"color:#1565c0;text-decoration:none;font-weight:500;\">\u2192 Maths Solutions<\/a><\/li>\n<li style=\"margin-bottom:8px;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/category\/cbse\/\" style=\"color:#1565c0;text-decoration:none;font-weight:500;\">\u2192 CBSE Preparation<\/a><\/li>\n<li style=\"margin-bottom:8px;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/category\/exam-preparation\/\" style=\"color:#1565c0;text-decoration:none;font-weight:500;\">\u2192 Exam Preparation Guide<\/a><\/li>\n<\/ul>\n<\/div>\n<div class=\"cta-box\" style=\"background:linear-gradient(135deg,#e8f5e9,#c8e6c9);padding:24px;border-radius:8px;margin:24px 0;text-align:center;border:1px solid #a5d6a7;\">\n<h3 style=\"margin:0 0 8px;color:#2e7d32;\"><span class=\"ez-toc-section\" id=\"explore-study-materials\"><\/span>Explore Study Materials<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"margin:0 0 16px;color:#333;\">Get comprehensive study materials, practice tests, and expert guides for your exam preparation.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/competitive-exam-books\" style=\"display:inline-block;background:#2e7d32;color:#fff;padding:12px 32px;border-radius:6px;text-decoration:none;font-weight:600;\">Browse Study Materials \u2192<\/a>\n<\/div>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-9-solutions-chapter-10-mcqs\"><\/span><span class=\"ez-toc-section\" id=\"faqs-on-RD-sharma-class-9-solutions-chapter-10-mcqs\"><\/span><strong>FAQs on RD Sharma Class 9 Solutions Chapter 10 MCQs<\/strong><span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div class=\"rank-math-block\" id=\"rank-math-faq\">\n<div class=\"rank-math-list\">\n<div class=\"rank-math-list-item\" id=\"faq-question-1631281295261\">\n<h3 class=\"rank-math-question\"><span class=\"ez-toc-section\" id=\"is-it-even-beneficial-to-study-rd-sharma-class-9-solutions-chapter-10-mcqs\"><\/span><span class=\"ez-toc-section\" id=\"is-it-even-beneficial-to-study-RD-sharma-class-9-solutions-chapter-10-mcqs\"><\/span>Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 10 MCQs?<span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer\">\n<p>Bilkul beneficial hai! RD Sharma Class 9 Solutions Chapter 10 MCQs se aapki preparation strengthen hoti hai. Ye book comprehensive coverage provide karti hai aur saare concepts clear ho jaate hain. Especially board exams ke liye ye bahut helpful hai kyunki question patterns aur difficulty level exam ke according set kiye gaye hain.<\/p>\n<\/div>\n<\/div>\n<div class=\"rank-math-list-item\" id=\"faq-question-1631281320363\">\n<h3 class=\"rank-math-question\"><span class=\"ez-toc-section\" id=\"are-the-solutions-rd-sharma-class-9-solutions-chapter-10-mcqs-relevant\"><\/span><span class=\"ez-toc-section\" id=\"are-the-solutions-RD-sharma-class-9-solutions-chapter-10-mcqs-relevant\"><\/span>Are the solutions RD Sharma Class 9 Solutions Chapter 10 MCQs relevant?<span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer\">\n<p>Haan, solutions bilkul relevant hain kyunki ye subject matter experts ne design kiye hain. 2026 syllabus ke according updated hain aur CBSE pattern follow karte hain. Step-by-step approach se har concept clear ho jaata hai aur exam mein confidence milti hai.<\/p>\n<\/div>\n<\/div>\n<div class=\"rank-math-list-item\" id=\"faq-question-1631281348328\">\n<h3 class=\"rank-math-question\"><span class=\"ez-toc-section\" id=\"how-many-questions-are-there-in-rd-sharma-class-9-solutions-chapter-10-mcqs\"><\/span><span class=\"ez-toc-section\" id=\"how-many-questions-are-there-in-RD-sharma-class-9-solutions-chapter-10-mcqs\"><\/span>How many questions are there in RD Sharma Class 9 Solutions Chapter 10 MCQs?<span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer\">\n<p>RD Sharma Class 9 Solutions Chapter 10 MCQs mein total 30 questions hain. Ye questions different difficulty levels mein arranged hain &#8211; basic se advanced tak. Har question specific concept ko target karta hai aur comprehensive practice provide karta hai.<\/p>\n<\/div>\n<\/div>\n<div class=\"rank-math-list-item\" id=\"faq-question-additional-1\">\n<h3 class=\"rank-math-question\"><span class=\"ez-toc-section\" id=\"kya-rd-sharma-ncert-ke-saath-compatible-hai\"><\/span>Kya RD Sharma NCERT ke saath compatible hai?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer\">\n<p>Haan, RD Sharma NCERT syllabus ke according hi designed hai. Actually ye NCERT ka supplement hai jo extra practice provide karta hai. NCERT concepts samjhane ke baad RD Sharma se practice karna best approach hai.<\/p>\n<\/div>\n<\/div>\n<div class=\"rank-math-list-item\" id=\"faq-question-additional-2\">\n<h3 class=\"rank-math-question\"><span class=\"ez-toc-section\" id=\"chapter-10-mein-sabse-important-topics-kya-hain\"><\/span>Chapter 10 mein sabse important topics kya hain?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer\">\n<p>Chapter 10 mein congruency rules (SSS, SAS, ASA, RHS), properties of isosceles triangles, aur angle properties sabse important hain. Ye topics board exams mein frequently puchte hain aur aage ke chapters mein bhi use hote hain.<\/p>\n<\/div>\n<\/div>\n<div class=\"rank-math-list-item\" id=\"faq-question-additional-3\">\n<h3 class=\"rank-math-question\"><span class=\"ez-toc-section\" id=\"kitna-time-lagta-hai-chapter-10-mcqs-complete-karne-mein\"><\/span>Kitna time lagta hai Chapter 10 MCQs complete karne mein?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer\">\n<p>Average student ko Chapter 10 ke saare MCQs solve karne mein 2-3 hours lagta hai agar properly samjhana ho. First attempt mein time zyada lagega, lekin regular practice se speed improve ho jaati hai. Daily 30-45 minutes practice sufficient hai.<\/p>\n<\/div>\n<\/div>\n<div class=\"rank-math-list-item\" id=\"faq-question-additional-4\">\n<h3 class=\"rank-math-question\"><span class=\"ez-toc-section\" id=\"kya-ye-mcqs-competitive-exams-ke-liye-bhi-helpful-hain\"><\/span>Kya ye MCQs competitive exams ke liye bhi helpful hain?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer\">\n<p>Haan, RD Sharma ke MCQs foundation level competitive exams ke liye bhi beneficial hain. Geometry concepts jo yahan cover hote hain, woh JEE Main, NEET, aur state level entrance exams mein bhi aate hain. Strong foundation building ke liye perfect hai.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p>Ye complete guide hai RD Sharma Class 9 Solutions Chapter 10 MCQs ke liye. CBSE Class 9 Maths exam ke baare mein aur jaanna hai toh comments mein puchiye. Regular practice aur proper understanding se aap geometry mein excellent performance kar sakte hain!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Last Updated: May 02, 2026 | This article has been updated with the latest information for 2026. Key Takeaways Complete Solutions &#8211; RD Sharma Class 9 Chapter 10 MCQs Chapter 10 Key Concepts Review Board Exam Strategy for Geometry MCQs Read more: RD Sharma \u2014 Complete Guide RD Sharma Class 9 Solutions Chapter 10 MCQs: &#8230; <a title=\"RD Sharma Class 9 Solutions: Expert Guide [2026]\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-10-mcqs\/\" aria-label=\"More on RD Sharma Class 9 Solutions: Expert Guide [2026]\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":126634,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411],"tags":[61598,115467],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126629"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=126629"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126629\/revisions"}],"predecessor-version":[{"id":575267,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126629\/revisions\/575267"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/126634"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=126629"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=126629"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=126629"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}