{"id":126629,"date":"2023-09-03T13:10:00","date_gmt":"2023-09-03T07:40:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=126629"},"modified":"2023-12-19T10:29:20","modified_gmt":"2023-12-19T04:59:20","slug":"rd-sharma-class-9-solutions-chapter-10-mcqs","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-10-mcqs\/","title":{"rendered":"RD Sharma Class 9 Solutions Chapter 10 MCQs (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-126634\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-10-MCQS.jpg\" alt=\"RD Sharma Class 9 Solutions Chapter 10 MCQs\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-10-MCQS.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-10-MCQS-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Class 9 Solutions Chapter 10 MCQs:<\/strong> If you are looking for reliable and easy-to-understand solutions then you must have a look at RD Sharma Solutions Class 9 Maths. All the solutions are designed by subject matter experts and are very credible. You can make your maths assignments or even ace your class tests with the help of <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-10-congruent-triangles\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 10<\/a> MCQs.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e73ff17ef5f\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e73ff17ef5f\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-10-mcqs\/#access-answers-of-rd-sharma-class-9-solutions-chapter-10-mcqs\" title=\"Access answers of RD Sharma Class 9 Solutions Chapter 10 MCQs\">Access answers of RD Sharma Class 9 Solutions Chapter 10 MCQs<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-10-mcqs\/#faqs-on-rd-sharma-class-9-solutions-chapter-10-mcqs\" title=\"FAQs on RD Sharma Class 9 Solutions Chapter 10 MCQs\">FAQs on RD Sharma Class 9 Solutions Chapter 10 MCQs<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-10-mcqs\/#is-it-even-beneficial-to-study-rd-sharma-class-9-solutions-chapter-10-mcqs\" title=\"Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 10 MCQs?\">Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 10 MCQs?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-10-mcqs\/#are-the-solutions-rd-sharma-class-9-solutions-chapter-10-mcqs-relevant\" title=\"Are the solutions RD Sharma Class 9 Solutions Chapter 10\u00a0MCQs\u00a0relevant?\">Are the solutions RD Sharma Class 9 Solutions Chapter 10\u00a0MCQs\u00a0relevant?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-10-mcqs\/#how-many-questions-are-there-in-rd-sharma-class-9-solutions-chapter-10-mcqs\" title=\"How many questions are there in RD Sharma Class 9 Solutions Chapter 10 MCQs?\">How many questions are there in RD Sharma Class 9 Solutions Chapter 10 MCQs?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"access-answers-of-rd-sharma-class-9-solutions-chapter-10-mcqs\"><\/span><strong>Access answers of RD Sharma Class 9 Solutions Chapter 10 MCQs<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Mark the correct alternative in each of the following:<\/p>\n<p>Question 1.<br \/>One angle is equal to three times its supplement. The measure of the angle is<br \/>(a) 130\u00b0<br \/>(b) 135\u00b0<br \/>(c) 90\u00b0<br \/>(d) 120\u00b0<br \/>Solution:<br \/>Let required angle = x<br \/>Then its supplement = (180\u00b0 \u2013 x)<br \/>x = 3(180\u00b0 \u2013 x) = 540\u00b0 \u2013 3x<br \/>\u21d2 x + 3x = 540\u00b0<br \/>\u21d2 4x = 540\u00b0<br \/>\u21d2 x =\u00a0<span id=\"MathJax-Element-1-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-1\" class=\"math\"><span id=\"MathJax-Span-2\" class=\"mrow\"><span id=\"MathJax-Span-3\" class=\"mfrac\"><span id=\"MathJax-Span-4\" class=\"msubsup\"><span id=\"MathJax-Span-5\" class=\"texatom\"><span id=\"MathJax-Span-6\" class=\"mrow\"><span id=\"MathJax-Span-7\" class=\"mn\">540<\/span><\/span><\/span><span id=\"MathJax-Span-8\" class=\"texatom\"><span id=\"MathJax-Span-9\" class=\"mrow\"><span id=\"MathJax-Span-10\" class=\"mo\">\u2218<\/span><\/span><\/span><\/span><span id=\"MathJax-Span-11\" class=\"mn\">4<\/span><\/span><\/span><\/span><\/span>\u00a0 = 135\u00b0<br \/>\u2234 Required angle = 135\u00b0 (b)<\/p>\n<p>Question 2.<br \/>Two straight lines AB and CD intersect one another at point O. If \u2220AOC + \u2220COB + \u2220BOD = 274\u00b0, then \u2220AOD =<br \/>(a) 86\u00b0<br \/>(b) 90\u00b0<br \/>(c) 94\u00b0<br \/>(d) 137\u00b0<br \/>Solution:<br \/>Sum of angles at a point O = 360\u00b0<br \/>Sum of three angles \u2220AOC + \u2220COB + \u2220BOD = 274\u00b0<br \/><img class=\"alignnone size-full wp-image-66393\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q2.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q2.1\" width=\"189\" height=\"170\" \/><br \/>\u2234 Fourth angle \u2220AOD = 360\u00b0 \u2013 274\u00b0<br \/>= 86\u00b0 (a)<\/p>\n<p>Question 3.<br \/>Two straight lines AB and CD cut each other at O. If \u2220BOD = 63\u00b0, then \u2220BOC =<br \/>(a) 63\u00b0<br \/>(b) 117\u00b0<br \/>(c) 17\u00b0<br \/>(d) 153\u00b0<br \/>Solution:<br \/>CD is a line<br \/>\u2234 \u2220BOD + \u2220BOC = 180\u00b0 (Linear pair)<br \/><img class=\"alignnone size-full wp-image-66394\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q3.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q3.1\" width=\"143\" height=\"179\" \/><br \/>\u21d2 63\u00b0 + \u2220BOC = 180\u00b0<br \/>\u21d2 \u2220BOC = 180\u00b0 \u2013 63\u00b0<br \/>\u2234 \u2220BOC =117\u00b0 (b)<\/p>\n<p>Question 4.<br \/>Consider the following statements:<br \/>When two straight lines intersect:<br \/>(i) adjacent angles are complementary<br \/>(ii) adjacent angles are supplementary<br \/>(iii) opposite angles are equal<br \/>(iv) opposite angles are supplementary Of these statements<br \/>(a) (i) and (iii) are correct<br \/>(b) (ii) and (iii) are correct<br \/>(c) (i) and (iv) are correct<br \/>(d) (ii) and (iv) are correct<br \/>Solution:<br \/>Only (ii) and (iii) arc true. (b)<\/p>\n<p>Question 5.<br \/>Given \u2220POR = 3x and \u2220QOR = 2x + 10\u00b0. If POQ is a striaght line, then the value of x is<br \/>(a) 30\u00b0<br \/>(b) 34\u00b0<br \/>(c) 36\u00b0<br \/>(d) none of these<br \/>Solution:<br \/>\u2235 POQ is a straight line<br \/>\u2234 \u2220POR + \u2220QOR = 180\u00b0 (Linear pair)<br \/>\u21d2 3x + 2x + 10\u00b0 = 180\u00b0<br \/>\u21d2 5x = 180 \u2013 10\u00b0 = 170\u00b0<br \/>\u2234 x =\u00a0<span id=\"MathJax-Element-2-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-12\" class=\"math\"><span id=\"MathJax-Span-13\" class=\"mrow\"><span id=\"MathJax-Span-14\" class=\"mfrac\"><span id=\"MathJax-Span-15\" class=\"msubsup\"><span id=\"MathJax-Span-16\" class=\"texatom\"><span id=\"MathJax-Span-17\" class=\"mrow\"><span id=\"MathJax-Span-18\" class=\"mn\">170<\/span><\/span><\/span><span id=\"MathJax-Span-19\" class=\"texatom\"><span id=\"MathJax-Span-20\" class=\"mrow\"><span id=\"MathJax-Span-21\" class=\"mo\">\u2218<\/span><\/span><\/span><\/span><span id=\"MathJax-Span-22\" class=\"mn\">5<\/span><\/span><\/span><\/span><\/span>\u00a0 = 34\u00b0 (b)<br \/><img class=\"alignnone size-full wp-image-66396\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q5.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q5.1\" width=\"200\" height=\"155\" \/><\/p>\n<p>Question 6.<br \/>In the figure, AOB is a straight line. If \u2220AOC + \u2220BOD = 85\u00b0, then \u2220COD =<br \/>(a) 85\u00b0<br \/>(b) 90\u00b0<br \/>(c) 95\u00b0<br \/>(d) 100\u00b0<br \/><img class=\"alignnone size-full wp-image-66397\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q6.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q6.1\" width=\"258\" height=\"172\" \/><br \/>Solution:<br \/>AOB is a straight line,<br \/>OC and OD are rays on it<br \/>and \u2220AOC + \u2220BOD = 85\u00b0<br \/>But \u2220AOC + \u2220BOD + \u2220COD = 180\u00b0<br \/>\u21d2 85\u00b0 + \u2220COD = 180\u00b0<br \/>\u2220COD = 180\u00b0 \u2013 85\u00b0 = 95\u00b0 (c)<\/p>\n<p>Question 7.<br \/>In the figure, the value of y is<br \/>(a) 20\u00b0<br \/>(b) 30\u00b0<br \/>(c) 45\u00b0<br \/>(d) 60\u00b0<br \/><img class=\"alignnone size-full wp-image-66398\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q7.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q7.1\" width=\"211\" height=\"216\" \/><br \/>Solution:<br \/>In the figure,<br \/><img class=\"alignnone size-full wp-image-66399\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q7.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q7.2\" width=\"212\" height=\"221\" \/><br \/>y = x (Vertically opposite angles)<br \/>\u22201 = 3x<br \/>\u22202 = 3x<br \/>\u2234 2(x + 3x + 2x) = 360\u00b0 (Angles at a point)<br \/>2x + 6x + 4x = 360\u00b0<br \/>12x = 360\u00b0 \u21d2 x =\u00a0<span id=\"MathJax-Element-3-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-23\" class=\"math\"><span id=\"MathJax-Span-24\" class=\"mrow\"><span id=\"MathJax-Span-25\" class=\"mfrac\"><span id=\"MathJax-Span-26\" class=\"msubsup\"><span id=\"MathJax-Span-27\" class=\"texatom\"><span id=\"MathJax-Span-28\" class=\"mrow\"><span id=\"MathJax-Span-29\" class=\"mn\">360<\/span><\/span><\/span><span id=\"MathJax-Span-30\" class=\"texatom\"><span id=\"MathJax-Span-31\" class=\"mrow\"><span id=\"MathJax-Span-32\" class=\"mo\">\u2218<\/span><\/span><\/span><\/span><span id=\"MathJax-Span-33\" class=\"mn\">12<\/span><\/span><\/span><\/span><\/span>\u00a0 = 30\u00b0<br \/>\u2234 y = x = 30\u00b0 (b)<\/p>\n<p>Question 8.<br \/>In the figure, the value of x is<br \/>(a) 12<br \/>(b) 15<br \/>(c) 20<br \/>(d) 30<br \/><img class=\"alignnone size-full wp-image-66400\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q8.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q8.1\" width=\"219\" height=\"269\" \/><br \/>Solution:<br \/>\u22201 = 3x+ 10 (Vertically opposite angles)<br \/>But x + \u22201 + \u22202 = 180\u00b0<br \/><img class=\"alignnone size-full wp-image-66401\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q8.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q8.2\" width=\"228\" height=\"265\" \/><br \/>\u21d2 x + 3x + 10\u00b0 + 90\u00b0 = 180\u00b0<br \/>\u21d2 4x = 180\u00b0 \u2013 10\u00b0 \u2013 90\u00b0 = 80\u00b0<br \/>x =\u00a0<span id=\"MathJax-Element-4-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-34\" class=\"math\"><span id=\"MathJax-Span-35\" class=\"mrow\"><span id=\"MathJax-Span-36\" class=\"mfrac\"><span id=\"MathJax-Span-37\" class=\"msubsup\"><span id=\"MathJax-Span-38\" class=\"texatom\"><span id=\"MathJax-Span-39\" class=\"mrow\"><span id=\"MathJax-Span-40\" class=\"mn\">80<\/span><\/span><\/span><span id=\"MathJax-Span-41\" class=\"texatom\"><span id=\"MathJax-Span-42\" class=\"mrow\"><span id=\"MathJax-Span-43\" class=\"mo\">\u2218<\/span><\/span><\/span><\/span><span id=\"MathJax-Span-44\" class=\"mn\">4<\/span><\/span><\/span><\/span><\/span> = 20\u00a0 \u00a0(c)<\/p>\n<p>Question 9.<br \/>In the figure, which of the following statements must be true?<br \/>(i) a + b = d + c<br \/>(ii) a + c + e = 180\u00b0<br \/>(iii) b + f= c + e<br \/>(a) (i) only<br \/>(b) (ii) only<br \/>(c) (iii) only<br \/>(d) (ii) and (iii) only<br \/><img class=\"alignnone size-full wp-image-66402\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q9.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q9.1\" width=\"170\" height=\"237\" \/><br \/>Solution:<br \/>In the figure,<br \/>(i) a + b = d + c<br \/>a\u00b0 = d\u00b0<br \/>b\u00b0 = e\u00b0<br \/>c\u00b0= f\u00b0<br \/>(ii) a + b + e = 180\u00b0<br \/>a + e + c = 180\u00b0<br \/>\u21d2 a + c + e = 180\u00b0<br \/>(iii) b + f= e + c<br \/>\u2234 (ii) and (iii) are true statements (d)<\/p>\n<p>Question 10.<br \/>If two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio 2:3, then the measure of the larger angle is<br \/>(a) 54\u00b0<br \/>(b) 120\u00b0<br \/>(c) 108\u00b0<br \/>(d) 136\u00b0<br \/>Solution:<br \/>In figure, l || m and p is transversal<br \/><img class=\"alignnone size-full wp-image-66403\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q10.1.png\" sizes=\"(max-width: 311px) 100vw, 311px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q10.1.png 311w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q10.1-298x300.png 298w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q10.1-150x150.png 150w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q10.1-100x100.png 100w\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q10.1\" width=\"311\" height=\"313\" \/><br \/>=\u00a0<span id=\"MathJax-Element-5-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-45\" class=\"math\"><span id=\"MathJax-Span-46\" class=\"mrow\"><span id=\"MathJax-Span-47\" class=\"mfrac\"><span id=\"MathJax-Span-48\" class=\"mn\">3<\/span><span id=\"MathJax-Span-49\" class=\"mn\">5<\/span><\/span><\/span><\/span><\/span> x 180\u00b0 = 108\u00b0 (c)<\/p>\n<p>Question 11.<br \/>In the figure, if AB || CD, then the value of x is<br \/>(a) 20\u00b0<br \/>(b) 30\u00b0<br \/>(c) 45\u00b0<br \/>(d) 60\u00b0<br \/><img class=\"alignnone size-full wp-image-66404\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q11.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q11.1\" width=\"251\" height=\"265\" \/><br \/>Solution:<br \/>In the figure, AB || CD,<br \/>and \/ is transversal<br \/>\u22201 = x (Vertically opposite angles)<br \/>and 120\u00b0 + x + \u22201 = 180\u00b0 (Co-interior angles)<br \/><img class=\"alignnone size-full wp-image-66405\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q11.2.png\" sizes=\"(max-width: 361px) 100vw, 361px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q11.2.png 361w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q11.2-276x300.png 276w\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q11.2\" width=\"361\" height=\"392\" \/><\/p>\n<p>Question 12.<br \/>Two lines AB and CD intersect at O. If \u2220AOC + \u2220COB + \u2220BOD = 270\u00b0, then \u2220AOC =<br \/>(a) 70\u00b0<br \/>(b) 80\u00b0<br \/>(c) 90\u00b0<br \/>(d) 180\u00b0<br \/>Solution:<br \/>Two lines AB and CD intersect at O<br \/><img class=\"alignnone size-full wp-image-66406\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q12.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q12.1\" width=\"176\" height=\"197\" \/><br \/>\u2220AOC + \u2220COB + \u2220BOD = 270\u00b0 \u2026(i)<br \/>But \u2220AOC + \u2220COB + \u2220BOD + \u2220DOA = 360\u00b0 \u2026(ii)<br \/>Subtracting (i) from (ii),<br \/>\u2220DOA = 360\u00b0 \u2013 270\u00b0 = 90\u00b0<br \/>But \u2220DOA + \u2220AOC = 180\u00b0<br \/>\u2234 \u2220AOC = 180\u00b0 \u2013 90\u00b0 = 90\u00b0 (c)<\/p>\n<p>Question 13.<br \/>In the figure, PQ || RS, \u2220AEF = 95\u00b0, \u2220BHS = 110\u00b0 and \u2220ABC = x\u00b0. Then the value of x is<br \/>(a) 15\u00b0<br \/>(b) 25\u00b0<br \/>(c) 70\u00b0<br \/>(d) 35\u00b0<br \/><img class=\"alignnone size-full wp-image-66407\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q13.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q13.1\" width=\"266\" height=\"243\" \/><br \/>Solution:<br \/>In the figure,<br \/><img class=\"alignnone size-full wp-image-66408\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q13.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q13.2\" width=\"253\" height=\"237\" \/><br \/>PQ || RS, \u2220AEF = 95\u00b0<br \/>\u2220BHS = 110\u00b0, \u2220ABC = x<br \/>\u2235 PQ || RS,<br \/>\u2234 \u2220AEF = \u22201 = 95\u00b0 (Corresponding anlges)<br \/>But \u22201 + \u22202 = 180\u00b0 (Linear pair)<br \/>\u21d2 \u22202 = 180\u00b0 \u2013 \u22201 = 180\u00b0 \u2013 95\u00b0 = 85\u00b0<br \/>In \u2206AGH,<br \/>Ext. \u2220BHS = \u22202 +x<br \/>\u21d2 110\u00b0 = 85\u00b0 + x<br \/>\u21d2 x= 110\u00b0-85\u00b0 = 25\u00b0 (b)<\/p>\n<p>Question 14.<br \/>In the figure, if l1 || l2, what is the value of x?<br \/>(a) 90\u00b0<br \/>(b) 85\u00b0<br \/>(c) 75\u00b0<br \/>(d) 70\u00b0<br \/><img class=\"alignnone size-full wp-image-66409\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q14.1.png\" sizes=\"(max-width: 303px) 100vw, 303px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q14.1.png 303w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q14.1-300x168.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q14.1\" width=\"303\" height=\"170\" \/><br \/>Solution:<br \/>In the figure,<br \/><img class=\"alignnone size-full wp-image-66410\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q14.2.png\" sizes=\"(max-width: 309px) 100vw, 309px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q14.2.png 309w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q14.2-300x190.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q14.2\" width=\"309\" height=\"196\" \/><br \/>\u22201 = 58\u00b0 (Vertically opposite angles)<br \/>Similarly, \u22202 = 37\u00b0<br \/>\u2235 l<sub>1<\/sub>\u00a0|| l<sub>2<\/sub>, EF is transversal<br \/>\u2220GEF + EFD = 180\u00b0 (Co-interior angles)<br \/>\u21d2 \u22202 + \u2220l +x = 180\u00b0<br \/>\u21d2 37\u00b0 + 58\u00b0 + x = 180\u00b0<br \/>\u21d2 95\u00b0 + x= 180\u00b0<br \/>x = 180\u00b0-95\u00b0 = 85\u00b0 (b)<\/p>\n<p>Question 15.<br \/>In the figure, if l<sub>1<\/sub>\u00a0|| l<sub>2<\/sub>, what is x + y in terms of w and z?<br \/>(a) 180-w + z<br \/>(b) 180\u00b0 + w- z<br \/>(c) 180 -w- z<br \/>(d) 180 + w + z<br \/><img class=\"alignnone size-full wp-image-66411\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q15.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q15.1\" width=\"233\" height=\"222\" \/><br \/>Solution:<br \/>In the figure, l<sub>1<\/sub>\u00a0|| l<sub>2<\/sub><br \/><img class=\"alignnone size-full wp-image-66412\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q15.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q15.2\" width=\"253\" height=\"220\" \/><br \/>p and q are transversals<br \/>\u2234 w + x = 180\u00b0 \u21d2 x = 180\u00b0 \u2013 w (Co-interior angle)<br \/>z = y (Alternate angles)<br \/>\u2234 x + y = 180\u00b0 \u2013 w + z (a)<\/p>\n<p>Question 16.<br \/>In the figure, if l<sub>1<\/sub>\u00a0|| l<sub>2<\/sub>, what is the value of y?<br \/>(a) 100<br \/>(b) 120<br \/>(c) 135<br \/>(d) 150<br \/><img class=\"alignnone size-full wp-image-66413\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q16.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q16.1\" width=\"262\" height=\"149\" \/><br \/>Solution:<br \/>In the figure, l<sub>1<\/sub>\u00a0|| l<sub>2<\/sub>\u00a0and l<sub>3<\/sub>\u00a0is the transversal<br \/><img class=\"alignnone size-full wp-image-66414\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q16.2.png\" sizes=\"(max-width: 381px) 100vw, 381px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q16.2.png 381w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q16.2-228x300.png 228w\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q16.2\" width=\"381\" height=\"501\" \/><\/p>\n<p>Question 17.<br \/>In the figure, if l1 || l2 and l3 || l4 what is y in terms of x?<br \/>(a) 90 + x<br \/>(b) 90 + 2x<br \/>(c) 90 \u2013\u00a0<span id=\"MathJax-Element-6-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-50\" class=\"math\"><span id=\"MathJax-Span-51\" class=\"mrow\"><span id=\"MathJax-Span-52\" class=\"mfrac\"><span id=\"MathJax-Span-53\" class=\"mi\">x<\/span><span id=\"MathJax-Span-54\" class=\"mn\">2<\/span><\/span><\/span><\/span><\/span><br \/>(d) 90 \u2013 2x<br \/><img class=\"alignnone size-full wp-image-66415\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q17.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q17.1\" width=\"264\" height=\"259\" \/><br \/>Solution:<br \/>In the figure,<br \/><img class=\"alignnone size-full wp-image-66416\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q17.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q17.2\" width=\"274\" height=\"255\" \/><br \/>l<sub>1<\/sub>\u00a0|| l<sub>2<\/sub>\u00a0and l<sub>3<\/sub>\u00a0|| l<sub>4<\/sub>\u00a0and m is the angle bisector<br \/>\u2234 \u22202 = \u22203 = y<br \/>\u2235 l<sub>1<\/sub>\u00a0|| l<sub>2<\/sub><br \/>\u22201 = x (Corresponding angles)<br \/>\u2235 l<sub>3<\/sub>\u00a0|| l<sub>4<\/sub><br \/>\u2234 \u22201 + (\u22202 + \u22203) = 180\u00b0 (Co-interior angles)<br \/>\u21d2 x + 2y= 180\u00b0<br \/>\u21d2 2y= 180\u00b0-x<br \/>\u21d2 y =\u00a0<span id=\"MathJax-Element-7-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-55\" class=\"math\"><span id=\"MathJax-Span-56\" class=\"mrow\"><span id=\"MathJax-Span-57\" class=\"mfrac\"><span id=\"MathJax-Span-58\" class=\"mrow\"><span id=\"MathJax-Span-59\" class=\"msubsup\"><span id=\"MathJax-Span-60\" class=\"texatom\"><span id=\"MathJax-Span-61\" class=\"mrow\"><span id=\"MathJax-Span-62\" class=\"mn\">540<\/span><\/span><\/span><span id=\"MathJax-Span-63\" class=\"texatom\"><span id=\"MathJax-Span-64\" class=\"mrow\"><span id=\"MathJax-Span-65\" class=\"mo\">\u2218<\/span><\/span><\/span><\/span><span id=\"MathJax-Span-66\" class=\"mo\">\u2212<\/span><span id=\"MathJax-Span-67\" class=\"mi\">x<\/span><\/span><span id=\"MathJax-Span-68\" class=\"mn\">4<\/span><\/span><\/span><\/span><\/span><br \/>= 90\u00b0 \u2013\u00a0<span id=\"MathJax-Element-8-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-69\" class=\"math\"><span id=\"MathJax-Span-70\" class=\"mrow\"><span id=\"MathJax-Span-71\" class=\"mfrac\"><span id=\"MathJax-Span-72\" class=\"mi\">x<\/span><span id=\"MathJax-Span-73\" class=\"mn\">2<\/span><\/span><\/span><\/span><\/span>\u00a0(c)<\/p>\n<p>Question 18.<br \/>In the figure, if 11| m, what is the value of x?<br \/>(a) 60<br \/>(b) 50<br \/>(c) 45<br \/>d) 30<br \/><img class=\"alignnone size-full wp-image-66417\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q18.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q18.1\" width=\"296\" height=\"214\" \/><br \/>Solution:<br \/>In the figure, l || m and n is the transversal<br \/><img class=\"alignnone size-full wp-image-66418\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q18.2.png\" sizes=\"(max-width: 380px) 100vw, 380px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q18.2.png 380w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q18.2-270x300.png 270w\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q18.2\" width=\"380\" height=\"423\" \/><br \/>\u21d2 y = 25\u00b0<br \/>But 2y + 25\u00b0 = x+ 15\u00b0<br \/>(Vertically opposite angles) \u21d2 x = 2y + 25\u00b0 \u2013 15\u00b0 = 2y+ 10\u00b0<br \/>= 2 x 25\u00b0+10\u00b0 = 50\u00b0+10\u00b0 = 60\u00b0 (a)<\/p>\n<p>Question 19.<br \/>In the figure, if AB || HF and DE || FG, then the measure of \u2220FDE is<br \/>(a) 108\u00b0<br \/>(b) 80\u00b0<br \/>(c) 100\u00b0<br \/>(d) 90\u00b0<br \/><img class=\"alignnone size-full wp-image-66419\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q19.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q19.1\" width=\"272\" height=\"181\" \/><br \/>Solution:<br \/>In the figure,<br \/>AB || HF, DE || FG<br \/><img class=\"alignnone size-full wp-image-66420\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q19.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q19.2\" width=\"267\" height=\"175\" \/><br \/>\u2234 HF || AB<br \/>\u22201 =28\u00b0 (Corresponding angles)<br \/>But \u22201 + \u2220FDE + 72\u00b0 \u2013 180\u00b0 (Angles of a straight line)<br \/>\u21d2 28\u00b0 + \u2220FDE + 72\u00b0 = 180\u00b0<br \/>\u21d2 \u2220FDE + 100\u00b0 = 180\u00b0<br \/>\u21d2 \u2220FDE = 180\u00b0 \u2013 100 = 80\u00b0 (b)<\/p>\n<p>Question 20.<br \/>In the figure, if lines l and m are parallel, then x =<br \/>(a) 20\u00b0<br \/>(b) 45\u00b0<br \/>(c) 65\u00b0<br \/>(d) 85\u00b0<br \/><img class=\"alignnone size-full wp-image-66421\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q20.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q20.1\" width=\"232\" height=\"152\" \/><br \/>Solution:<br \/>In the figure, l || m<br \/><img class=\"alignnone size-full wp-image-66422\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q20.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q20.2\" width=\"260\" height=\"172\" \/><br \/>\u2234 \u22201 =65\u00b0 (Corresponding angles)<br \/>In \u2206BCD,<br \/>Ext. \u22201 = x + 20\u00b0<br \/>\u21d2 65\u00b0 = x + 20\u00b0<br \/>\u21d2 x = 65\u00b0 \u2013 20\u00b0<br \/>\u21d2 x = 45\u00b0 (b)<\/p>\n<p>Question 21.<br \/>In the figure, if AB || CD, then x =<br \/>(a) 100\u00b0<br \/>(b) 105\u00b0<br \/>(c) 110\u00b0<br \/>(d) 115\u00b0<br \/><img class=\"alignnone size-full wp-image-66423\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q21.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q21.1\" width=\"264\" height=\"141\" \/><br \/>Solution:<br \/>In the figure, AB || CD<br \/>Through P, draw PQ || AB or CD<br \/><img class=\"alignnone size-full wp-image-66424\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q21.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q21.2\" width=\"279\" height=\"159\" \/><br \/>\u2220A + \u22201 = 180\u00b0 (Co-interior angles)<br \/>\u21d2 132\u00b0 + \u22201 = 180\u00b0<br \/>\u21d2 \u22201 = 180\u00b0- 132\u00b0 = 48\u00b0<br \/>\u2234 \u22202 = 148\u00b0 \u2013 \u22201 = 148\u00b0 \u2013 48\u00b0 = 100\u00b0<br \/>\u2235 DQ || CP<br \/>\u2234 \u22202 = x (Corresponding angles)<br \/>\u2234 x = 100\u00b0 (a)<\/p>\n<p>Question 22.<br \/>In tlie figure, if lines l and in are parallel lines, then x =<br \/>(a) 70\u00b0<br \/>(b) 100\u00b0<br \/>(c) 40\u00b0<br \/>(d) 30\u00b0<br \/><img class=\"alignnone size-full wp-image-66425\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q22.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q22.1\" width=\"191\" height=\"246\" \/><br \/>Solution:<br \/>In the figure, l || m<br \/><img class=\"alignnone size-full wp-image-66426\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q22.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q22.2\" width=\"202\" height=\"261\" \/><br \/>\u2220l =70\u00b0 (Corresponding angles)<br \/>In \u2206DEF,<br \/>Ext. \u2220l = x + 30\u00b0<br \/>\u21d2 70\u00b0 = x + 30\u00b0<br \/>\u21d2 x = 70\u00b0 \u2013 30\u00b0 = 40\u00b0 (c)<\/p>\n<p>Question 23.<br \/>In the figure, if l || m, then x =<br \/>(a) 105\u00b0<br \/>(b) 65\u00b0<br \/>(c) 40\u00b0<br \/>(d) 25\u00b0<br \/><img class=\"alignnone size-full wp-image-66427\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q23.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q23.1\" width=\"250\" height=\"191\" \/><br \/>Solution:<br \/>In the figure,<br \/>l || m and n is the transversal<br \/><img class=\"alignnone size-full wp-image-66428\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q23.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q23.2\" width=\"256\" height=\"208\" \/><br \/>\u22201 = 65\u00b0 (Alternate angles)<br \/>In \u2206GHF,<br \/>Ext. x = \u22201 + 40\u00b0 = 65\u00b0 + 40\u00b0<br \/>\u21d2 x = 105\u00b0<br \/>\u2234 x = 105\u00b0 (a)<\/p>\n<p>Question 24.<br \/>In the figure, if lines l and m are parallel, then the value of x is<br \/>(a) 35\u00b0<br \/>(b) 55\u00b0<br \/>(c) 65\u00b0<br \/>(d) 75\u00b0<br \/><img class=\"alignnone size-full wp-image-66429\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q24.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q24.1\" width=\"235\" height=\"153\" \/><br \/>Solution:<br \/>In the figure, l || m<br \/>and PQ is the transversal<br \/><img class=\"alignnone size-full wp-image-66430\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q24.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q24.2\" width=\"238\" height=\"178\" \/><br \/>\u22201 = 90\u00b0<br \/>In \u2206EFG,<br \/>Ext. \u2220G = \u2220E + \u2220F<br \/>\u21d2 125\u00b0 = x + \u22201 = x + 90\u00b0<br \/>\u21d2 x = 125\u00b0 \u2013 90\u00b0 = 35\u00b0 (a)<\/p>\n<p>Question 25.<br \/>Two complementary angles are such that two times the measure of one is equal to three times the measure of the other. The measure of the smaller angle is<br \/>(a) 45\u00b0<br \/>(b) 30\u00b0<br \/>(c) 36\u00b0<br \/>(d) none of these<br \/>Solution:<br \/>Let first angle = x<br \/>Then its complementary angle = 90\u00b0 \u2013 x<br \/>\u2234 2x = 3(90\u00b0 \u2013 x)<br \/>\u21d2 2x = 270\u00b0 \u2013 3x<br \/>\u21d2 2x + 3x = 270\u00b0<br \/>\u21d2 5x = 270\u00b0<br \/>\u21d2 x =\u00a0<span id=\"MathJax-Element-9-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-74\" class=\"math\"><span id=\"MathJax-Span-75\" class=\"mrow\"><span id=\"MathJax-Span-76\" class=\"mfrac\"><span id=\"MathJax-Span-77\" class=\"msubsup\"><span id=\"MathJax-Span-78\" class=\"texatom\"><span id=\"MathJax-Span-79\" class=\"mrow\"><span id=\"MathJax-Span-80\" class=\"mn\">270<\/span><\/span><\/span><span id=\"MathJax-Span-81\" class=\"texatom\"><span id=\"MathJax-Span-82\" class=\"mrow\"><span id=\"MathJax-Span-83\" class=\"mo\">\u2218<\/span><\/span><\/span><\/span><span id=\"MathJax-Span-84\" class=\"mn\">5<\/span><\/span><\/span><\/span><\/span>\u00a0 = 54\u00b0<br \/>\u2234 second angle = 90\u00b0 \u2013 54\u00b0 = 36\u00b0<br \/>\u2234 smaller angle = 36\u00b0 (c)<\/p>\n<p>Question 26.<br \/><img class=\"alignnone size-full wp-image-66431\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q26.1.png\" sizes=\"(max-width: 373px) 100vw, 373px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q26.1.png 373w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q26.1-300x224.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q26.1\" width=\"373\" height=\"278\" \/><br \/>Solution:<br \/><img class=\"alignnone size-full wp-image-66432\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q26.2.png\" sizes=\"(max-width: 368px) 100vw, 368px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q26.2.png 368w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q26.2-237x300.png 237w\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q26.2\" width=\"368\" height=\"466\" \/><\/p>\n<p>Question 27.<br \/>In the figure, AB || CD || EF and GH || KL.<br \/>The measure of \u2220HKL is<br \/>(a) 85\u00b0<br \/>(b) 135\u00b0<br \/>(c) 145\u00b0<br \/>(d) 215\u00b0<br \/><img class=\"alignnone size-full wp-image-66433\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q27.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q27.1\" width=\"264\" height=\"223\" \/><br \/>Solution:<br \/>In the figure, AB || CD || EF and GH || KL and GH is product to meet AB in L.<br \/><img class=\"alignnone size-full wp-image-66434\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q27.2.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q27.2\" width=\"266\" height=\"220\" \/><br \/>\u2235 AB || CD<br \/>\u2234 \u22201 = 25\u00b0 (Alternate angle)<br \/>and GH || KL<br \/>\u2234 \u22204 = 60\u00b0 (Corresponding angles)<br \/>\u22205 = \u22204 = 60\u00b0 (Vertically opposite angle)<br \/>\u22205 + \u22202 = 180\u00b0 (Co-interior anlges)<br \/>\u2234 \u21d2 60\u00b0 + \u22202 = 180\u00b0<br \/>\u22202 = 180\u00b0 \u2013 60\u00b0 = 120\u00b0<br \/>Now \u2220HKL = \u22201 + \u22202 = 25\u00b0 + 120\u00b0<br \/>= 145\u00b0 (c)<\/p>\n<p>Question 28.<br \/>AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of \u2220FEB. If \u2220LEB = 35\u00b0, then \u2220CFQ will be<br \/>(a) 55\u00b0<br \/>(b) 70\u00b0<br \/>(c) 110\u00b0<br \/>(d) 130\u00b0<br \/>Solution:<br \/>AB || CD and PQ is the transversal EL is the bisector of \u2220FEB and \u2220LEB = 35\u00b0<br \/><img class=\"alignnone size-full wp-image-66435\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q28.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q28.1\" width=\"261\" height=\"213\" \/><br \/>\u2234 \u2220FEB = 2 x 35\u00b0 = 70\u00b0<br \/>\u2235 AB || CD<br \/>\u2234 \u2220FEB + \u2220EFD = 180\u00b0<br \/>(Co-interior angles)<br \/>70\u00b0 + \u2220EFD = 180\u00b0<br \/>\u2234 \u2220EFD = 180\u00b0-70\u00b0= 110\u00b0<br \/>But \u2220CFQ = \u2220EFD<br \/>(Vertically opposite angles)<br \/>\u2234 \u2220CFQ =110\u00b0 (c)<\/p>\n<p>Question 29.<br \/>In the figure, if line segment AB is parallel to the line segment CD, what is the value of y?<br \/>(a) 12<br \/>(b) 15<br \/>(c) 18<br \/>(d) 20<br \/><img class=\"alignnone size-full wp-image-66436\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q29.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q29.1\" width=\"267\" height=\"146\" \/><br \/>Solution:<br \/>In the figure, AB || CD<br \/>BD is transversal<br \/>\u2234 \u2220ABD + \u2220BDC = 180\u00b0 (Co-interior angles)<br \/>\u21d2y + 2y+y + 5y = 180\u00b0<br \/>\u21d2 9y = 180\u00b0 \u21d2 y =\u00a0<span id=\"MathJax-Element-10-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-85\" class=\"math\"><span id=\"MathJax-Span-86\" class=\"mrow\"><span id=\"MathJax-Span-87\" class=\"mfrac\"><span id=\"MathJax-Span-88\" class=\"msubsup\"><span id=\"MathJax-Span-89\" class=\"texatom\"><span id=\"MathJax-Span-90\" class=\"mrow\"><span id=\"MathJax-Span-91\" class=\"mn\">180<\/span><\/span><\/span><span id=\"MathJax-Span-92\" class=\"texatom\"><span id=\"MathJax-Span-93\" class=\"mrow\"><span id=\"MathJax-Span-94\" class=\"mo\">\u2218<\/span><\/span><\/span><\/span><span id=\"MathJax-Span-95\" class=\"mn\">9<\/span><\/span><\/span><\/span><\/span>\u00a0 = 20\u00b0 (d)<\/p>\n<p>Question 30.<br \/>In the figure, if CP || DQ, then the measure of x is<br \/>(a) 130\u00b0<br \/>(b) 105\u00b0<br \/>(c) 175\u00b0<br \/>(d) 125\u00b0<br \/><img class=\"alignnone size-full wp-image-66437\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q30.1.png\" sizes=\"(max-width: 317px) 100vw, 317px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q30.1.png 317w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q30.1-300x175.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q30.1\" width=\"317\" height=\"185\" \/><br \/>Solution:<br \/>In the figure, CP || DQ<br \/>BA is transversal<br \/>Produce PC to meet BA at D<br \/><img class=\"alignnone size-full wp-image-66438\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q30.2.png\" sizes=\"(max-width: 323px) 100vw, 323px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q30.2.png 323w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-10-Congruent-Triangles-MCQS-Q30.2-300x182.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS Q30.2\" width=\"323\" height=\"196\" \/><br \/>\u2235 QB || PD<br \/>\u2234 \u2220D = 105\u00b0 (Corresponding angles)<br \/>In \u2206ADC,<br \/>Ext. \u2220ACP = \u2220CDA + \u2220DAC<br \/>\u21d2 x = \u22201 + 25\u00b0<br \/>= 105\u00b0 + 25\u00b0 = 130\u00b0 (a)<\/p>\n<p>This is the complete blog on RD Sharma Class 9 Solutions Chapter 10 MCQs. To know more about the <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 9 Maths exam, ask in the comments.\u00a0<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-9-solutions-chapter-10-mcqs\"><\/span><strong>FAQs on RD Sharma Class 9 Solutions Chapter 10 MCQs<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631281295261\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-it-even-beneficial-to-study-rd-sharma-class-9-solutions-chapter-10-mcqs\"><\/span>Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 10 MCQs?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, your preparation will be strengthened with RD Sharma Class 9 Solutions Chapter 10 MCQs. All your questions will be answered by this book.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631281320363\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"are-the-solutions-rd-sharma-class-9-solutions-chapter-10-mcqs-relevant\"><\/span>Are the solutions RD Sharma Class 9 Solutions Chapter 10\u00a0MCQs\u00a0relevant?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>The solutions are relevant as they are designed by the subject matter experts. \u00a0<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631281348328\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-many-questions-are-there-in-rd-sharma-class-9-solutions-chapter-10-mcqs\"><\/span>How many questions are there in RD Sharma Class 9 Solutions Chapter 10 MCQs?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>There are 30 questions in\u00a0RD Sharma Class 9 Solutions for Chapter 10 MCQs.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 9 Solutions Chapter 10 MCQs: If you are looking for reliable and easy-to-understand solutions then you must have a look at RD Sharma Solutions Class 9 Maths. All the solutions are designed by subject matter experts and are very credible. You can make your maths assignments or even ace your class tests &#8230; <a title=\"RD Sharma Class 9 Solutions Chapter 10 MCQs (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-10-mcqs\/\" aria-label=\"More on RD Sharma Class 9 Solutions Chapter 10 MCQs (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":126634,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411],"tags":[3086,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126629"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=126629"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126629\/revisions"}],"predecessor-version":[{"id":524546,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126629\/revisions\/524546"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/126634"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=126629"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=126629"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=126629"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}