{"id":126433,"date":"2023-09-11T12:15:00","date_gmt":"2023-09-11T06:45:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=126433"},"modified":"2023-11-24T11:11:31","modified_gmt":"2023-11-24T05:41:31","slug":"rd-sharma-class-9-solutions-chapter-9-exercise-9-1","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-9-exercise-9-1\/","title":{"rendered":"RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1 (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-126436\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-9-Exercise-9.1.jpg\" alt=\"RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-9-Exercise-9.1.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-9-Exercise-9.1-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1:&nbsp;<\/strong>You can become the top scorer in your Maths class really easily by preparing the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-for-maths\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 9 Maths<\/a>. All the solutions in this are well designed and explained by our subject matter experts. You can download the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-9-triangle-and-its-angles\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 9<\/a> Exercise 9.1 PDF for free and even access it without the internet once downloaded. To know more, read the whole blog.&nbsp;<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e85bb8b2fb5\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e85bb8b2fb5\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-9-exercise-9-1\/#download-rd-sharma-class-9-solutions-chapter-9-exercise-91-pdf\" title=\"Download RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1 PDF\">Download RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1 PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-9-exercise-9-1\/#access-answers-of-rd-sharma-class-9-solutions-chapter-9-exercise-91\" title=\"Access answers of RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1\">Access answers of RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-9-exercise-9-1\/#faqs-on-rd-sharma-class-9-solutions-chapter-9exercise-91\" title=\"FAQs on RD Sharma Class 9 Solutions Chapter 9Exercise 9.1\">FAQs on RD Sharma Class 9 Solutions Chapter 9Exercise 9.1<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-9-exercise-9-1\/#how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-9-exercise-91\" title=\"How much does it cost to download the PDF of RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1?\">How much does it cost to download the PDF of RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-9-exercise-9-1\/#can-i-access-the-rd-sharma-class-9-solutions-chapter-9-exercise-91-pdf-offline\" title=\"Can I access the RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1\u00a0PDF offline?\">Can I access the RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1\u00a0PDF offline?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-9-exercise-9-1\/#from-where-can-i-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-9-exercise-91\" title=\"From where can I download the PDF of RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1?\">From where can I download the PDF of RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-class-9-solutions-chapter-9-exercise-91-pdf\"><\/span><strong>Download RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1 PDF<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/9.1.pdf\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">&nbsp;<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/9.1.pdf\", \"#example1\");<\/script><\/p>\n<h2><span class=\"ez-toc-section\" id=\"access-answers-of-rd-sharma-class-9-solutions-chapter-9-exercise-91\"><\/span><strong>Access answers of RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>Question 1: In a \u0394ABC, if \u2220A = 55<sup>0<\/sup>, \u2220B = 40<sup>0<\/sup>, find \u2220C.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Given: \u2220A = 55<sup>0<\/sup>, \u2220B = 40<sup>0<\/sup><\/p>\n<p>We know, the sum of all angles of a triangle is 180<sup>0<\/sup><\/p>\n<p>\u2220A + \u2220B + \u2220C = 180<sup>0<\/sup><\/p>\n<p>55<sup>0&nbsp;<\/sup>+ 40<sup>0&nbsp;<\/sup>+ \u2220C=180<sup>0<\/sup><\/p>\n<p>95<sup>0&nbsp;<\/sup>+ \u2220C = 180<sup>0<\/sup><\/p>\n<p>\u2220C = 180<sup>0<\/sup>&nbsp;\u2212 95<sup>0<\/sup><\/p>\n<p>\u2220C = 85<sup>0<\/sup><\/p>\n<p><strong>Question 2: If the angles of a triangle are in the ratio 1:2:3, determine three angles.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Angles of a triangle are in the ratio 1:2:3 (Given)<\/p>\n<p>Let the angles be x, 2x, 3x<\/p>\n<p>The sum of all angles of triangles = 180<sup>0<\/sup><\/p>\n<p>x + 2x + 3x = 180<sup>0<\/sup><\/p>\n<p>6x = 180<sup>0<\/sup><\/p>\n<p>x = 180<sup>0<\/sup>\/6<\/p>\n<p>x = 30<sup>0<\/sup><\/p>\n<p>Answer:<\/p>\n<p>x = 30<sup>0<\/sup><\/p>\n<p>2x = 2(30)<sup>0<\/sup>&nbsp;= 60<sup>0<\/sup><\/p>\n<p>3x = 3(30)<sup>&nbsp;0<\/sup>&nbsp;= 90<sup>0<\/sup><\/p>\n<p><strong>Question 3: The angles of a triangle are (x \u2212 40)<sup>0<\/sup>, (x \u2212 20)<sup> 0,&nbsp;<\/sup>and (1\/2 x \u2212 10)<sup>&nbsp;0<\/sup>. Find the value of x.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>The angles of a triangle are (x \u2212 40)<sup>0<\/sup>, (x \u2212 20)<sup>&nbsp;0&nbsp;<\/sup>and (1\/2 x \u2212 10)<sup>&nbsp;0<\/sup><\/p>\n<p>The sum of all angles of triangle = 180<sup>0<\/sup><\/p>\n<p>(x \u2212 40)<sup>0<\/sup>&nbsp;+ (x \u2212 20)<sup>&nbsp;0&nbsp;<\/sup>+ (1\/2 x \u2212 10)<sup>&nbsp;0<\/sup>&nbsp;= 180<sup>0<\/sup><\/p>\n<p>5\/2 x \u2013 70<sup>0<\/sup>&nbsp;= 1800<\/p>\n<p>5\/2 x = 180<sup>0<\/sup>&nbsp;+ 70<sup>0<\/sup><\/p>\n<p>5x = 2(250)<sup>&nbsp;0<\/sup><\/p>\n<p>x = 500<sup>0<\/sup>\/5<\/p>\n<p>x = 100<sup>0<\/sup><\/p>\n<p><strong>Question 4: The angles of a triangle are arranged in ascending order of magnitude. If the difference between two consecutive angles is 10<sup>0<\/sup>, find the three angles.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>The difference between two consecutive angles is 10<sup>0<\/sup>&nbsp;(given)<\/p>\n<p>Let x, x + 10<sup>0<\/sup>, x + 20<sup>0<\/sup>&nbsp;be the consecutive angles<\/p>\n<p>x + x + 10<sup>0<\/sup>&nbsp;+ x + 20<sup>0<\/sup>&nbsp;= 180<sup>0<\/sup><\/p>\n<p>3x + 30<sup>0<\/sup>&nbsp;= 180<sup>0<\/sup><\/p>\n<p>3x = 180<sup>0<\/sup>\u2013 30<sup>0<\/sup><\/p>\n<p>3x = 150<sup>0<\/sup><\/p>\n<p>or x = 50<sup>0<\/sup><\/p>\n<p>Again,<\/p>\n<p>x + 10<sup>0<\/sup>&nbsp;= 50<sup>0<\/sup>&nbsp;+ 10<sup>0<\/sup>&nbsp;= 60<sup>0<\/sup><\/p>\n<p>x+20<sup>0<\/sup>&nbsp;= 50<sup>0<\/sup>&nbsp;+ 20<sup>0<\/sup>&nbsp;= 70<sup>0<\/sup><\/p>\n<p>Answer: Three angles are 50<sup>0<\/sup>,60<sup>0<\/sup>&nbsp;and 70<sup>0<\/sup>.<\/p>\n<p><strong>Question 5: Two angles of a triangle are equal, and the third angle is greater than each of those angles by 30<sup>0<\/sup>. Determine all the angles of the triangle.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Two angles of a triangle are equal, and the third angle is greater than each of those angles by 30<sup>0<\/sup>. (Given)<\/p>\n<p>Let x, x, x + 30<sup>0<\/sup>&nbsp;be the angles of a triangle.<\/p>\n<p>The sum of all angles in a triangle = 180<sup>0<\/sup><\/p>\n<p>x + x + x + 30<sup>0<\/sup>&nbsp;= 180<sup>0<\/sup><\/p>\n<p>3x + 30<sup>0<\/sup>&nbsp;= 180<sup>0<\/sup><\/p>\n<p>3x = 150<sup>0<\/sup><\/p>\n<p>or x = 50<sup>0<\/sup><\/p>\n<p>And x + 30<sup>0<\/sup>&nbsp;= 50<sup>0<\/sup>&nbsp;+ 30<sup>0<\/sup>&nbsp;= 80<sup>0<\/sup><\/p>\n<p>Answer: Three angles are 50<sup>0<\/sup>, 50<sup>0,<\/sup>&nbsp;and 80<sup>0<\/sup>.<\/p>\n<p><strong>Question 6: If one angle of a triangle is equal to the sum of the other two, show that the triangle is a right-angle triangle.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>One angle of a triangle is equal to the sum of the other two angles (given)<\/p>\n<p>To Prove: One of the angles is 90<sup>0<\/sup><\/p>\n<p>Let x, y and z are three angles of a triangle, where<\/p>\n<p>z = x + y \u2026(1)<\/p>\n<p>The sum of all angles of a triangle = 180<sup>0<\/sup><\/p>\n<p>x + y + z = 180<sup>0<\/sup><\/p>\n<p>z + z = 180<sup>0<\/sup>&nbsp;(Using equation (1))<\/p>\n<p>2z = 180<sup>0<\/sup><\/p>\n<p>z = 90<sup>0<\/sup>&nbsp;(Proved)<\/p>\n<p>Therefore, the triangle is a right-angled triangle.<\/p>\n<p>This is the complete blog on RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1. To know more about the <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 9 Maths, ask in the comments.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-9-solutions-chapter-9exercise-91\"><\/span><strong>FAQs on RD Sharma Class 9 Solutions Chapter 9Exercise 9.1<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631259882376\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-9-exercise-91\"><\/span>How much does it cost to download the PDF of RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download it for free.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631259976738\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-access-the-rd-sharma-class-9-solutions-chapter-9-exercise-91-pdf-offline\"><\/span>Can I access the RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1\u00a0PDF offline?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Once you have downloaded the PDF online, you can access it offline as well.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631259999833\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"from-where-can-i-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-9-exercise-91\"><\/span>From where can I download the PDF of RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can find the download link from the above blog.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1:&nbsp;You can become the top scorer in your Maths class really easily by preparing the RD Sharma Solutions Class 9 Maths. All the solutions in this are well designed and explained by our subject matter experts. You can download the RD Sharma Class 9 Solutions Chapter 9 &#8230; <a title=\"RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1 (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-9-exercise-9-1\/\" aria-label=\"More on RD Sharma Class 9 Solutions Chapter 9 Exercise 9.1 (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":126436,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411],"tags":[3086,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126433"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=126433"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126433\/revisions"}],"predecessor-version":[{"id":511918,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126433\/revisions\/511918"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/126436"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=126433"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=126433"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=126433"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}