<\/span><\/h2>\nQuestion 1.
The opposite sides of a quadrilateral have
(a) no common point
(b) one common point
(c) two common points
(d) infinitely many common points
Solution:
The opposite sides of a quadrilateral have no common point. (a)<\/p>\n
Question 2.
The consecutive sides of a quadrilateral have
(a) no common point
(b) one common point
(c) two common points
(d) infinitely many common points
Solution:
The consecutive sides of a quadrilateral have one common point. (b)<\/p>\n
Question 3.
PQRS is a quadrilateral, PR and QS intersect each other at O. In which of the following cases, PQRS is a parallelogram?
(a) \u2220P = 100\u00b0, \u2220Q = 80\u00b0, \u2220R = 100\u00b0
(b) \u2220P = 85\u00b0, \u2220Q = 85\u00b0, \u2220R = 95\u00b0
(c) PQ = 7 cm, QR = 7 cm, RS = 8 cm, SP = 8 cm
(d) OP = 6.5 cm, OQ = 6.5 cm, OR = 5.2 cm, OS = 5.2 cm
Solution:
PQRS is a quadrilateral, PR and QS intersect each other at O. PQRS is a parallelogram if \u2220P = 100\u00b0, \u2220Q = 80\u00b0, \u2220R = 100\u00b0 (a)<\/p>\n
Question 4.
Which of the following quadrilateral is not a rhombus?
(a) All four sides are equal
(b) Diagonals bisect each other
(c) Diagonals bisect opposite angles
(d) One angle between the diagonals is 60\u00b0
Solution:
A quadrilateral is not a rhombus if one angle between the diagonals is 60\u00b0. (d)<\/p>\n
Question 5.
Diagonals necessarily bisect opposite angles in a
(a) rectangle
(b) parallelogram
(c) isosceles trapezium
(d) square
Solution:
Diagonals necessarily bisect opposite angles in a square. (d)<\/p>\n
Question 6.
The two diagonals are equal in a
(a) parallelogram
(b) rhombus
(c) rectangle
(d) trapezium
Solution:
The two diagonals are equal in a rectangle. (c)<\/p>\n
Question 7.
We get a rhombus by joining the mid-points of the sides of a
(a) parallelogram
(b) rhombus
(c) rectangle
(d) triangle
Solution:
We get a rhombus by joining the midpoints of the sides of a rectangle. (c)<\/p>\n
Question 8.
The bisectors of any two adjacent angles of a parallelogram intersect at
(a) 30\u00b0
(b) 45\u00b0
(c) 60\u00b0
(d) 90\u00b0
Solution:
The bisectors of any two adjacent angles of a parallelogram intersect at 90\u00b0. (d)<\/p>\n
Question 9.
The bisectors of the angle of a parallelogram enclose a
(a) parallelogram
(b) rhombus
(c) rectangle
(d) square
Solution:
The bisectors of the angles of a parallelogram enclose a rectangle. (c)<\/p>\n
Question 10.
The figure formed by joining the mid-points of the adjacent sides of a quadrilateral is a
(a) parallelogram
(b) rectangle
(c) square
(d) rhombus
Solution:
The figure formed by joining the mid-points of the adjacent sides of a quadrilateral is a parallelogram. (a)<\/p>\n
Question 11.
The figure formed by joining the mid-points of the adjacent sides of a rectangle is a
(a) square
(b) rhombus
(c) trapezium
(d) none of these
Solution:
The figure formed by joining the mid-points of the adjacent sides of a rectangle is a rhombus. (b)<\/p>\n
Question 12.
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a
(a) square
(b) rectangle
(c) trapezium
(d) none of these
Solution:
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a rectangle. (b)<\/p>\n
Question 13.
The figure formed by joining the mid-points of the adjacent sides of a square is a
(a) rhombus
(b) square
(c) rectangle
(d) parallelogram
Solution:
A tire figure formed by joining the mid-points of the adjacent sides of a square is a square. (b)<\/p>\n
Question 14.
The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a
(a) rectangle
(b) parallelogram
(b) rhombus
(d) square
Solution:
The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a parallelogram. (b)<\/p>\n
We have included all the information regarding\u00a0CBSE<\/a> RD Sharma Class 9 Solutions Chapter 13 MCQS. If you have any queries feel free to ask in the comment section.\u00a0<\/span><\/p>\n
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