{"id":126355,"date":"2023-09-04T10:51:00","date_gmt":"2023-09-04T05:21:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=126355"},"modified":"2023-12-08T10:18:42","modified_gmt":"2023-12-08T04:48:42","slug":"rd-sharma-class-10-solutions-chapter-6-trigonometric-identities","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-trigonometric-identities\/","title":{"rendered":"RD Sharma Class 10 Solutions Chapter 6- Trigonometric Identities (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-126358\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-6-Trigonometric-Identities.jpg\" alt=\"RD Sharma Class 10 Solutions Chapter 6\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-6-Trigonometric-Identities.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-6-Trigonometric-Identities-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Class 10 Solutions Chapter 6 Trigonometric Identities\u00a0<\/strong>are provided in this article. The 6th Chapter of RD Sharma Class 10 is Trigonometric Identities, which has two exercises and is solved with thorough explanations here <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-for-maths\/\"><strong>RD Sharma Solutions for Class 10<\/strong><\/a>. The preceding chapter discussed trigonometric ratios and their relationships. This chapter, on the other hand, will focus on establishing some trigonometric identities and applying them to the derivation of other relevant trigonometric identities.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69ea5a1f23751\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69ea5a1f23751\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-trigonometric-identities\/#download-rd-sharma-class-10-solutions-chapter-6-trigonometric-identities-pdf\" title=\"Download RD Sharma Class 10 Solutions Chapter 6 Trigonometric Identities PDF\">Download RD Sharma Class 10 Solutions Chapter 6 Trigonometric Identities PDF<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-trigonometric-identities\/#access-the-rd-sharma-solutions-for-class-10-maths-chapter-6-%e2%80%93-trigonometric-identities\" title=\"Access the RD Sharma Solutions for Class 10 Maths Chapter 6 \u2013 Trigonometric Identities\">Access the RD Sharma Solutions for Class 10 Maths Chapter 6 \u2013 Trigonometric Identities<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-trigonometric-identities\/#rd-sharma-solutions-for-class-10-maths-chapter-6-exercise-61-page-no-643\" title=\"RD Sharma Solutions for Class 10 Maths Chapter 6 Exercise 6.1 Page No: 6.43\">RD Sharma Solutions for Class 10 Maths Chapter 6 Exercise 6.1 Page No: 6.43<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-trigonometric-identities\/#exercise-wise-rd-sharma-class-10-maths-chapter-6-%e2%80%93-trigonometric-identities\" title=\"Exercise-Wise RD Sharma Class 10 Maths Chapter 6 \u2013 Trigonometric Identities\">Exercise-Wise RD Sharma Class 10 Maths Chapter 6 \u2013 Trigonometric Identities<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-trigonometric-identities\/#frequently-asked-questions-on-rd-sharma-class-10-maths-solutions-chapter-6\" title=\"Frequently Asked Questions on RD Sharma Class 10 Maths Solutions Chapter 6\">Frequently Asked Questions on RD Sharma Class 10 Maths Solutions Chapter 6<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-trigonometric-identities\/#where-can-i-get-rd-sharma-solutions-class-10-maths-chapter-6-free-pdf\" title=\"Where can I get RD Sharma Solutions Class 10 Maths Chapter 6 Free PDF?\">Where can I get RD Sharma Solutions Class 10 Maths Chapter 6 Free PDF?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-trigonometric-identities\/#is-it-necessary-to-study-rd-sharma-solutions-for-class-10-maths-chapter-6-for-the-exam\" title=\"Is it necessary to study RD Sharma Solutions for Class 10 Maths Chapter 6 for the exam?\">Is it necessary to study RD Sharma Solutions for Class 10 Maths Chapter 6 for the exam?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-trigonometric-identities\/#why-should-we-use-kopykitab-to-get-rd-sharma-solutions-for-class-10-maths-chapter-6\" title=\"Why should we use Kopykitab to get RD Sharma Solutions for Class 10 Maths Chapter 6?\">Why should we use Kopykitab to get RD Sharma Solutions for Class 10 Maths Chapter 6?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-class-10-solutions-chapter-6-trigonometric-identities-pdf\"><\/span>Download RD Sharma Class 10 Solutions Chapter 6 Trigonometric Identities PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 800px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/586a1491e4b0df1c027b639e_5e9a08fd97915e738f25d9ed_1587578990815.pdf\", \"#example1\");<\/script><\/p>\n<p>\u00a0<\/p>\n<h3><span class=\"ez-toc-section\" id=\"access-the-rd-sharma-solutions-for-class-10-maths-chapter-6-%e2%80%93-trigonometric-identities\"><\/span>Access the RD Sharma Solutions for Class 10 Maths Chapter 6 \u2013 Trigonometric Identities<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<h3><span class=\"ez-toc-section\" id=\"rd-sharma-solutions-for-class-10-maths-chapter-6-exercise-61-page-no-643\"><\/span>RD Sharma Solutions for Class 10 Maths Chapter 6 Exercise 6.1 Page No: 6.43<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Prove the following trigonometric identities:<\/strong><\/p>\n<p><strong>1. (1 \u2013 cos<sup>2<\/sup>\u00a0A) cosec<sup>2<\/sup>\u00a0A = 1<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Taking the L.H.S.,<\/p>\n<p>(1 \u2013 cos<sup>2<\/sup>\u00a0A) cosec<sup>2<\/sup>\u00a0A<\/p>\n<p>= (sin<sup>2<\/sup>\u00a0A) cosec<sup>2<\/sup>\u00a0A [\u2235 sin<sup>2<\/sup>\u00a0A + cos<sup>2\u00a0<\/sup>A = 1 \u21d21 \u2013 sin<sup>2<\/sup>\u00a0A = cos<sup>2<\/sup>\u00a0A]<\/p>\n<p>= 1<sup>2<\/sup><\/p>\n<p><strong><em>= 1 = R.H.S.<\/em><\/strong><\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>2. (1 + cot<sup>2<\/sup>\u00a0A) sin<sup>2<\/sup>\u00a0A = 1\u00a0<\/strong><\/p>\n<p><strong>Solution:\u00a0<\/strong><\/p>\n<p>By using the identity,<\/p>\n<p><strong>cosec<sup>2\u00a0<\/sup>A \u2013 cot<sup>2<\/sup>\u00a0A = 1 \u21d2 cosec<sup>2\u00a0<\/sup>A = cot<sup>2<\/sup>\u00a0A + 1<\/strong><\/p>\n<p>Taking,<\/p>\n<p>L.H.S. = (1 + cot<sup>2<\/sup>\u00a0A) sin<sup>2<\/sup>\u00a0A<\/p>\n<p>= cosec<sup>2<\/sup>\u00a0A sin<sup>2<\/sup>\u00a0A<\/p>\n<p>= (cosec A sin A)<sup>2<\/sup><\/p>\n<p>= ((1\/sin A) \u00d7 sin A)<sup>2<\/sup><\/p>\n<p>= (1)<sup>2<\/sup><\/p>\n<p><strong><em>= 1<\/em><\/strong><\/p>\n<p>= R.H.S.<\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>3. tan<sup>2\u00a0<\/sup>\u03b8 cos<sup>2\u00a0<\/sup>\u03b8 =\u00a01 \u2212 cos<sup>2\u00a0<\/sup>\u03b8\u00a0<\/strong><\/p>\n<p><strong>Solution:\u00a0<\/strong><\/p>\n<p>We know that,<\/p>\n<p><strong>sin<sup>2\u00a0<\/sup>\u03b8 + cos<sup>2\u00a0<\/sup>\u03b8 = 1<\/strong><\/p>\n<p>Taking,<\/p>\n<p>L.H.S. = tan<sup>2\u00a0<\/sup>\u03b8 cos<sup>2\u00a0<\/sup>\u03b8<\/p>\n<p>= (tan \u03b8 \u00d7 cos \u03b8)<sup>2<\/sup><\/p>\n<p>= (sin \u03b8)<sup>2<\/sup><\/p>\n<p>= sin<sup>2\u00a0<\/sup>\u03b8<\/p>\n<p><strong><em>= 1 \u2013 cos<sup>2\u00a0<\/sup>\u03b8<\/em><\/strong><\/p>\n<p>= R.H.S.<\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>4. cosec \u03b8 \u221a(1 \u2013 cos<sup>2<\/sup>\u00a0\u03b8) = 1<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Using identity,<\/p>\n<p><strong>sin<sup>2\u00a0<\/sup>\u03b8 + cos<sup>2\u00a0<\/sup>\u03b8 = 1\u00a0 \u21d2 sin<sup>2\u00a0<\/sup>\u03b8 = 1 \u2013 cos<sup>2\u00a0<\/sup>\u03b8<\/strong><\/p>\n<p>Taking L.H.S.,<\/p>\n<p>L.H.S = cosec \u03b8 \u221a(1 \u2013 cos<sup>2<\/sup>\u00a0\u03b8)<\/p>\n<p>= cosec \u03b8 \u221a( sin<sup>2\u00a0<\/sup>\u03b8)<\/p>\n<p>= cosec \u03b8 x sin<sup>\u00a0<\/sup>\u03b8<\/p>\n<p><strong><em>= 1<\/em><\/strong><\/p>\n<p>= R.H.S.<\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>5. (sec<sup>2\u00a0<\/sup>\u03b8 \u2212 1)(cosec<sup>2\u00a0<\/sup>\u03b8 \u2212 1) = 1\u00a0<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>Using identities,<\/p>\n<p><strong>(sec<sup>2\u00a0<\/sup>\u03b8 \u2212 tan<sup>2\u00a0<\/sup>\u03b8) = 1\u00a0and (cosec<sup>2\u00a0<\/sup>\u03b8 \u2212 cot<sup>2\u00a0<\/sup>\u03b8) = 1<\/strong><\/p>\n<p>We have,<\/p>\n<p>L.H.S. = (sec<sup>2\u00a0<\/sup>\u03b8 \u2013 1)(cosec<sup>2<\/sup>\u03b8 \u2013 1)<\/p>\n<p>= tan<sup>2<\/sup>\u03b8 \u00d7 cot<sup>2<\/sup>\u03b8<\/p>\n<p>= (tan \u03b8 \u00d7 cot \u03b8)<sup>2<\/sup><\/p>\n<p>= (tan \u03b8 \u00d7 1\/tan \u03b8)<sup>2<\/sup><\/p>\n<p>= 1<sup>2<\/sup><\/p>\n<p><strong><em>= 1<\/em><\/strong><\/p>\n<p>= R.H.S.<\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>6. tan \u03b8 + 1\/ tan \u03b8 = sec \u03b8 cosec \u03b8<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>We have,<\/p>\n<p>L.H.S. = tan \u03b8 + 1\/ tan \u03b8<\/p>\n<p>= (tan<sup>2<\/sup>\u00a0\u03b8 + 1)\/ tan \u03b8<\/p>\n<p>= sec<sup>2<\/sup>\u00a0\u03b8 \/ tan \u03b8\u00a0<strong>[\u2235 sec<sup>2\u00a0<\/sup>\u03b8 \u2212 tan<sup>2\u00a0<\/sup>\u03b8 = 1]<\/strong><\/p>\n<p>= (1\/cos<sup>2<\/sup>\u00a0\u03b8) x 1\/ (sin \u03b8\/cos \u03b8) [\u2235 tan \u03b8 = sin \u03b8 \/ cos \u03b8]<\/p>\n<p>= cos \u03b8\/ (sin \u03b8 x cos<sup>2<\/sup>\u00a0\u03b8)<\/p>\n<p>= 1\/ cos \u03b8 x 1\/ sin \u03b8<\/p>\n<p>= sec \u03b8 x cosec \u03b8<\/p>\n<p><strong><em>= sec \u03b8 cosec \u03b8<\/em><\/strong><\/p>\n<p>= R.H.S.<\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>7. cos \u03b8\/ (1 \u2013 sin \u03b8) = (1 + sin \u03b8)\/ cos \u03b8<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>We know that,<\/p>\n<p><strong>sin<sup>2\u00a0<\/sup>\u03b8 + cos<sup>2\u00a0<\/sup>\u03b8 = 1<\/strong><\/p>\n<p>So, by multiplying both the numerator and the denominator by (1+ sin \u03b8), we get<\/p>\n<p><img title=\"RD Sharma Solutions for Class 10 Maths Chapter 6 Trigonometric Identities\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/11\/r-d-sharma-solutions-for-class-10-maths-chapter-6.png\" alt=\"R D Sharma Solutions For Class 10 Maths Chapter 6 Trigonometric Identities ex 6.1 - 1\" \/><\/p>\n<p><em><strong>L.H.S. = R.H.S.<\/strong><\/em><\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>8. cos \u03b8\/ (1 + sin \u03b8) = (1 \u2013 sin \u03b8)\/ cos \u03b8<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>We know that,<\/p>\n<p>sin<sup>2\u00a0<\/sup>\u03b8 + cos<sup>2\u00a0<\/sup>\u03b8 = 1<\/p>\n<p>So, by multiplying both the numerator and the denominator by (1- sin \u03b8), we get<\/p>\n<p><img title=\"RD Sharma Solutions for Class 10 Maths Chapter 6 Trigonometric Identities\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/11\/r-d-sharma-solutions-for-class-10-maths-chapter-6-1.png\" alt=\"R D Sharma Solutions For Class 10 Maths Chapter 6 Trigonometric Identities ex 6.1 - 2\" \/><\/p>\n<p><strong><em>L.H.S. = R.H.S.<\/em><\/strong><\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>9. cos<sup>2\u00a0<\/sup>\u03b8 + 1\/(1 + cot<sup>2\u00a0<\/sup>\u03b8) = 1<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>We already know that,<\/p>\n<p><strong>cosec<sup>2\u00a0<\/sup>\u03b8 \u2212 cot<sup>2\u00a0<\/sup>\u03b8 = 1 and sin<sup>2\u00a0<\/sup>\u03b8 + cos<sup>2\u00a0<\/sup>\u03b8 = 1<\/strong><\/p>\n<p>Taking L.H.S.,<\/p>\n<p><strong><img title=\"RD Sharma Solutions for Class 10 Maths Chapter 6 Trigonometric Identities\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/11\/r-d-sharma-solutions-for-class-10-maths-chapter-6-2.png\" alt=\"R D Sharma Solutions For Class 10 Maths Chapter 6 Trigonometric Identities ex 6.1 - 3\" \/><\/strong><\/p>\n<p>= cos<sup>2<\/sup>\u00a0A + sin<sup>2<\/sup>\u00a0A<\/p>\n<p><strong><em>= 1<\/em><\/strong><\/p>\n<p>= R.H.S.<\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>10. sin<sup>2\u00a0<\/sup>A + 1\/(1 + tan\u00a0<sup>2\u00a0<\/sup>A) = 1<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>We already know that,<\/p>\n<p><strong>sec<sup>2\u00a0<\/sup>\u03b8 \u2212 tan<sup>2\u00a0<\/sup>\u03b8 = 1\u00a0and sin<sup>2\u00a0<\/sup>\u03b8 + cos<sup>2\u00a0<\/sup>\u03b8 = 1<\/strong><\/p>\n<p>Taking L.H.S.,<\/p>\n<p><img title=\"RD Sharma Solutions for Class 10 Maths Chapter 6 Trigonometric Identities\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/11\/r-d-sharma-solutions-for-class-10-maths-chapter-6-3.png\" alt=\"R D Sharma Solutions For Class 10 Maths Chapter 6 Trigonometric Identities ex 6.1 - 4\" \/><\/p>\n<p>= sin<sup>2<\/sup>\u00a0A + cos<sup>2<\/sup>\u00a0A<\/p>\n<p><strong><em>= 1<\/em><\/strong><\/p>\n<p>= R.H.S.<\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>11.<\/strong><br \/><img title=\"RD Sharma Solutions for Class 10 Maths Chapter 6 Trigonometric Identities\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/11\/r-d-sharma-solutions-for-class-10-maths-chapter-6-4.png\" alt=\"R D Sharma Solutions For Class 10 Maths Chapter 6 Trigonometric Identities ex 6.1 - 5\" \/><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>We know that,<\/p>\n<p><strong>sin<sup>2\u00a0<\/sup>\u03b8 + cos<sup>2\u00a0<\/sup>\u03b8 = 1<\/strong><\/p>\n<p>Taking the L.H.S.,<\/p>\n<p><img title=\"RD Sharma Solutions for Class 10 Maths Chapter 6 Trigonometric Identities\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/11\/r-d-sharma-solutions-for-class-10-maths-chapter-6-5.png\" alt=\"R D Sharma Solutions For Class 10 Maths Chapter 6 Trigonometric Identities ex 6.1 - 6\" \/><\/p>\n<p><strong><em>= cosec \u03b8 \u2013 cot\u00a0\u03b8<\/em><\/strong><\/p>\n<p>= R.H.S.<\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>12. 1 \u2013 cos \u03b8\/ sin \u03b8 = sin \u03b8\/ 1 + cos \u03b8<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>We know that,<\/p>\n<p><strong>sin<sup>2\u00a0<\/sup>\u03b8 + cos<sup>2\u00a0<\/sup>\u03b8 = 1<\/strong><\/p>\n<p>So, by multiplying both the numerator and the denominator by (1+ cos \u03b8), we get<\/p>\n<p><img title=\"RD Sharma Solutions for Class 10 Maths Chapter 6 Trigonometric Identities\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/11\/r-d-sharma-solutions-for-class-10-maths-chapter-6-6.png\" alt=\"R D Sharma Solutions For Class 10 Maths Chapter 6 Trigonometric Identities ex 6.1 - 7\" \/><\/p>\n<p><strong><em>= R.H.S.<\/em><\/strong><\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p><strong>13.<\/strong>\u00a0<strong>sin \u03b8\/ (1 \u2013 cos \u03b8) = cosec \u03b8 + cot \u03b8<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>\u00a0<\/p>\n<p>Taking L.H.S.,<\/p>\n<p><img title=\"RD Sharma Solutions for Class 10 Maths Chapter 6 Trigonometric Identities\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/11\/r-d-sharma-solutions-for-class-10-maths-chapter-6-7.png\" alt=\"R D Sharma Solutions For Class 10 Maths Chapter 6 Trigonometric Identities ex 6.1 - 8\" \/><\/p>\n<p><strong><em>= cosec \u03b8 + cot \u03b8<\/em><\/strong><\/p>\n<p>= R.H.S.<\/p>\n<p>\u2013 Hence, proved.<\/p>\n<p style=\"text-align: center;\"><a style=\"display: inline-block; width: auto; padding: 18px; cursor: pointer; font-weight: bold; border-radius: 40px; text-decoration: none; color: #fff; background: #ff4500; -webkit-box-shadow: 0px 2px 6px 0px rgba(0, 0, 0, 0.25); -moz-box-shadow: 0px 2px 6px 0px rgba(0, 0, 0, 0.25); box-shadow: 0px 2px 6px 0px rgba(0, 0, 0, 0.25);\" href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/586a1491e4b0df1c027b639e_5e9a08fd97915e738f25d9ed_1587578990815.pdf\" target=\"_blank\" rel=\"noopener noreferrer\">RD Sharma Class 10 Solutions Chapter 6 PDF- Direct LiNK<\/a><\/p>\n<h2><span class=\"ez-toc-section\" id=\"exercise-wise-rd-sharma-class-10-maths-chapter-6-%e2%80%93-trigonometric-identities\"><\/span>Exercise-Wise RD Sharma Class 10 Maths Chapter 6 \u2013 Trigonometric Identities<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<table>\n<tbody>\n<tr>\n<td style=\"text-align: center;\"><strong>RD Sharma Class 10 Solutions Chapter 6 Exercises<\/strong><\/td>\n<\/tr>\n<tr>\n<td><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-exercise-6-1\/\">RD Sharma Solutions for Class 10 Chapter 6 Exercise 6.1<\/a><\/td>\n<\/tr>\n<tr>\n<td><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-exercise-6-2\/\">RD Sharma Solutions for Class 10 Chapter 6 Exercise 6.2<\/a><\/td>\n<\/tr>\n<tr>\n<td><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-vsaqs\/\">RD Sharma Solutions for Class 10 Chapter 6 VSAQs<\/a><\/td>\n<\/tr>\n<tr>\n<td><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-mcqs\/\">RD Sharma Solutions for Class 10 Chapter 6 MCQs<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Download RD Sharma\u00a0<a href=\"http:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 10 Maths Chapter 6 Solutions to boost your preparations for the exam. If you have any queries, feel free to ask us in the comment section.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"frequently-asked-questions-on-rd-sharma-class-10-maths-solutions-chapter-6\"><\/span>Frequently Asked Questions on RD Sharma Class 10 Maths Solutions Chapter 6<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631251060686\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"where-can-i-get-rd-sharma-solutions-class-10-maths-chapter-6-free-pdf\"><\/span>Where can I get RD Sharma Solutions Class 10 Maths Chapter 6 Free PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can get RD Sharma for Class 10 Maths Solutions Chapter 6 Free PDF from the above article.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631251072127\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-it-necessary-to-study-rd-sharma-solutions-for-class-10-maths-chapter-6-for-the-exam\"><\/span>Is it necessary to study RD Sharma Solutions for Class 10 Maths Chapter 6 for the exam?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, all of the chapters in RD Sharma Solutions for Class 10 Maths are important for both board exams and better marks. To get good grades, students should practice all of the questions in RD Sharma Solutions for Class 10 Maths Chapter 6.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631251149608\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"why-should-we-use-kopykitab-to-get-rd-sharma-solutions-for-class-10-maths-chapter-6\"><\/span>Why should we use Kopykitab to get RD Sharma Solutions for Class 10 Maths Chapter 6?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>For the questions in RD Sharma Solutions for Class 10 Maths Chapter 6, Kopykitab delivers the most precise answers. These solutions are available in PDF format and can be viewed online. Experts describe the solutions to this chapter&#8217;s problems in detail, with neat diagrams whenever applicable.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 10 Solutions Chapter 6 Trigonometric Identities\u00a0are provided in this article. The 6th Chapter of RD Sharma Class 10 is Trigonometric Identities, which has two exercises and is solved with thorough explanations here RD Sharma Solutions for Class 10. The preceding chapter discussed trigonometric ratios and their relationships. This chapter, on the other &#8230; <a title=\"RD Sharma Class 10 Solutions Chapter 6- Trigonometric Identities (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-6-trigonometric-identities\/\" aria-label=\"More on RD Sharma Class 10 Solutions Chapter 6- Trigonometric Identities (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":238,"featured_media":126358,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411,2985,73410],"tags":[3243,9206,73520,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126355"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/238"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=126355"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126355\/revisions"}],"predecessor-version":[{"id":518930,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/126355\/revisions\/518930"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/126358"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=126355"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=126355"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=126355"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}