<\/span><\/h2>\nQuestion 1.
<\/strong>Write the equation representing x-axis.
<\/strong>Solution:
<\/strong>The equation of x-axis is, y = 0.<\/p>\nQuestion 2.
<\/strong>Write the equation representing y-axis.
<\/strong>Solution:
<\/strong>The equation of y-axis is, x = 0.<\/p>\n <\/div>\n
Question 3.
<\/strong>Write the equation of a line passing through the point (0, 4) and parallel to x-axis.
<\/strong>Solution:
<\/strong>The equation of the line passing through the point (0,4) and parallel to x-axis will be y = 4.<\/p>\nQuestion 4.
<\/strong>Write the equation of a line passing through the point (3, 5) and parallel to x-axis.
<\/strong>Solution:
<\/strong>The equation of the line passing through the point (3, 5) and parallel to x-axis will be y = 5.<\/p>\nQuestion 5.
<\/strong>Write the equation of a line parallel toy-axis and passing through the point (-3, -7).
<\/strong>Solution:
<\/strong>The equations of the line passing through the point (-3, -7) and parallel to y-axis will be x = -3.<\/p>\nQuestion 6.
<\/strong>A line passes through the point (-4, 6) and is parallel to x-axis. Find its equation. A line passes through the point (-4, 6) and is parallel to x-axis. Find its equation.
<\/strong>Solution:
<\/strong>A line parallel to x-axis and passing through the point (-4, 6) will be y = 6.<\/p>\nQuestion 7.
<\/strong>Solve the equation 3x \u2013 2 = 2x + 3 and represent the solution on the number line.
<\/strong>Solution:
<\/strong>3x \u2013 2 = 2x + 3
\u21d2 3x \u2013 2x = 3 + 2 (By terms formation)
\u21d2 x = 5
\u2234 x = 5
Solution on the number line is
![\"RD](\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-7-Introduction-to-Euclid%E2%80%99s-Geometry-VSAQS-Q7.1.png\")
<\/p>\nQuestion 8.
<\/strong>Solve the equation 2y \u2013 1 = y + 1 and represent it graphically on the coordinate plane.
![\"RD](\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-7-Introduction-to-Euclid%E2%80%99s-Geometry-VSAQS-Q8.1.png\")
<\/strong>Solution:
<\/strong>2y \u2013 1 = y + 1
\u21d2 2y \u2013 y = 1 +1
\u21d2 y = 2
\u2234 It is a line parallel to x-axis at a distance of 2 units above the x-axis is y = 2.<\/p>\nQuestion 9.
<\/strong>If the point (a, 2) lies on the graph of the linear equation 2x \u2013 3y + 8 = 0, find the value of a.
<\/strong>Solution:
\u2235 <\/strong>Points (a, 2) lies on the equation
2x \u2013 3y + 8 = 0
\u2234 It will satisfy the equation,
Now substituting the value of x = a, y = 2 in the equation
\u21d2 2a \u2013 3 x 2+ 8= 0
\u21d2 2a + 2= 0
\u21d2 2a = -2
\u21d2 a = \u2212<\/span>2<\/span><\/span>2<\/span><\/span><\/span><\/span><\/span> = -1
\u2234 a = -1<\/p>\nQuestion 10.
<\/strong>Find the value of k for which the point (1, -2) lies on the graph of the linear equation, x \u2013 2y + k = 0.
<\/strong>Solution:
<\/strong>\u2235 Point (1, -2) lies on the graph of the equation x \u2013 2y + k = 0
\u2234 x = 1, y = -2 will satisfy the equation
Now substituting the value of x = 1, y = -2 in it
1-2 (-2) + k = 0
\u21d2 1 + 4 + k = 0
\u21d2 5+ k = 0 \u21d2 k =-5
\u2234 k = -5<\/p>\nThis is the complete blog on RD Sharma Class 9 Solutions Chapter 7 VSAQs. To know more about the CBSE<\/a> Class 9 Maths exam, ask in the comments.<\/p>\n
![\"RD](\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-7-VSAQS.jpg\")
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