{"id":125987,"date":"2023-09-09T16:24:00","date_gmt":"2023-09-09T10:54:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=125987"},"modified":"2023-09-15T19:36:15","modified_gmt":"2023-09-15T14:06:15","slug":"rd-sharma-class-9-solutions-chapter-6-vsaqs","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-vsaqs\/","title":{"rendered":"RD Sharma Class 9 Solutions Chapter 6 VSAQs"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-125996\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-6-VSAQS.jpg\" alt=\"RD Sharma Class 9 Solutions Chapter 6 VSAQS\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-6-VSAQS.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-6-VSAQS-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Class 9 Solutions Chapter 6 VSAQs:<\/strong> Clear your Class 9 Maths exams with flying colors by studying the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-for-maths\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 9 Maths<\/a>. It is important to clear your concepts before appearing for the exams. Hence you can give a try studying <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-6-factorization-of-polynomials\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 6<\/a> VSAQs. To now more, read the whole blog.&nbsp;<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e7675a68d5d\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e7675a68d5d\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-vsaqs\/#access-answers-of-rd-sharma-class-9-solutions-chapter-6-vsaqs\" title=\"Access answers of RD Sharma Class 9 Solutions Chapter 6 VSAQS\">Access answers of RD Sharma Class 9 Solutions Chapter 6 VSAQS<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-vsaqs\/#faqs-on-rd-sharma-class-9-solutions-chapter-6-vsaqs\" title=\"FAQs on RD Sharma Class 9 Solutions Chapter 6 VSAQS\">FAQs on RD Sharma Class 9 Solutions Chapter 6 VSAQS<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-vsaqs\/#how-many-questions-are-there-in-rd-sharma-class-9-solutions-chapter-6-vsaqs\" title=\"How many questions are there in RD Sharma Class 9 Solutions Chapter 6 VSAQs?\">How many questions are there in RD Sharma Class 9 Solutions Chapter 6 VSAQs?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-vsaqs\/#is-it-even-beneficial-to-study-rd-sharma-class-9-solutions-chapter-6-vsaqs\" title=\"Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 6 VSAQs?\">Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 6 VSAQs?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-vsaqs\/#are-the-solutions-rd-sharma-class-9-solutions-chapter-6-vsaqs-relevant\" title=\"Are the solutions RD Sharma Class 9 Solutions Chapter 6 VSAQs\u00a0relevant?\">Are the solutions RD Sharma Class 9 Solutions Chapter 6 VSAQs\u00a0relevant?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"access-answers-of-rd-sharma-class-9-solutions-chapter-6-vsaqs\"><\/span><strong>Access answers of RD Sharma Class 9 Solutions Chapter 6 VSAQS<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>Question 1.<br><\/strong><strong>Define zero or root of a polynomial.<br><\/strong><strong>Solution:<br><\/strong>A real number a is a zero or root of a polynomial f(x) if f(\u03b1) = 0<\/p>\n<p><strong>Question 2.<br><\/strong><strong>If x =&nbsp;<span id=\"MathJax-Element-1-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-1\" class=\"math\"><span id=\"MathJax-Span-2\" class=\"mrow\"><span id=\"MathJax-Span-3\" class=\"mfrac\"><span id=\"MathJax-Span-4\" class=\"mn\">1<\/span><span id=\"MathJax-Span-5\" class=\"mn\">2<\/span><\/span><\/span><\/span><\/span>&nbsp;is a zero of the polynomial f(x) =&nbsp; 8x<sup>3<\/sup>&nbsp;+ ax<sup>2<\/sup>&nbsp;\u2013 4x + 2, find the value of a.<br><\/strong><strong>Solution:<br><img class=\"alignnone size-full wp-image-66093\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-6-Factorisation-of-Polynomials-VSAQS-Q2.1.png\" sizes=\"(max-width: 341px) 100vw, 341px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-6-Factorisation-of-Polynomials-VSAQS-Q2.1.png 341w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-6-Factorisation-of-Polynomials-VSAQS-Q2.1-216x300.png 216w\" alt=\"RD Sharma Class 9 Solutions Chapter 6 Factorisation of Polynomials VSAQS Q2.1\" width=\"341\" height=\"473\"><br><\/strong><\/p>\n<div class=\"code-block code-block-2\">&nbsp;<\/div>\n<p><strong>Question 3.<br><\/strong><strong>Write the remainder when the polynomial f(x) = x<sup>3<\/sup>+x<sup>2<\/sup>-3x + 2is divided by x + 1.<\/strong><br><strong>Solution:<br><\/strong>f(x) = x<sup>3<\/sup>+x<sup>2<\/sup>-3x + 2<br>Let x + 1 = 0, then x = -1<br>\u2234 Remainder =(-1)<br>Now,f(-1) = (-1)<sup>3<\/sup>&nbsp;+ (-1)<sup>2<\/sup>&nbsp;\u2013 3(-1) + 2<br>= -1 + 1+ 3 + 2 = 5<br>\u2234 Remainder = 5<\/p>\n<p><strong>Question 4.<br><\/strong><strong>Find the remainder when x<sup>3<\/sup>&nbsp;+ 4x<sup>2<\/sup>&nbsp;+ 4x \u2013 3 is divided by x.<br><\/strong><strong>Solution:<br><\/strong>f(x) = x<sup>3<\/sup>&nbsp;+ 4x<sup>2<\/sup>&nbsp;+ 4x \u2013 3<br>Dividing f(x) by x, we get<br>Let x = 0, then<br>f(x) = 0 + 0 + 0 \u2013 3 = -3<br>\u2234&nbsp;&nbsp;Remainder = -3<\/p>\n<p><strong>Question 5.<br><\/strong><strong>If x + 1 is a factor of x<sup>3<\/sup>&nbsp;+ a, then write the value of a.<br><\/strong><strong>Solution:<br><\/strong>Let f(x) = x<sup>3<\/sup>&nbsp;+ a<br>\u2234 x + 1 is a factor of fx)<br>Let x + 1 = 0<br>\u21d2 x = -1<br>\u2234 f(-1) = x<sup>3<\/sup>&nbsp;+ a<br>= (-1)<sup>3<\/sup>&nbsp;+ a = -1 + a<br>\u2234&nbsp; x + 1 is a factor<br>\u2234&nbsp; Remainder = 0<br>\u2234&nbsp; -1 + a = 0 \u21d2&nbsp; a = 1<br>Hence a = 1<\/p>\n<p><strong>Question 6.<br><\/strong><strong>If f(x) = x<sup>4<\/sup>-2x<sup>3<\/sup>&nbsp;+ 3x<sup>2<\/sup>&nbsp;\u2013 ax \u2013 b when divided by x \u2013 1, the remainder is 6, then find the value of a + b.<br><\/strong><strong>Solution:<br><\/strong>f(x) = x<sup>4<\/sup>&nbsp;\u2013 2x<sup>3<\/sup>&nbsp;+ 3x<sup>2<\/sup>&nbsp;\u2013 ax \u2013 b<br>Dividing f(x) by x \u2013 1, the remainder = 6<br>Now let x \u2013 1 = 0, then x = 1<br>\u2234&nbsp; f(1) = (1)<sup>4<\/sup>&nbsp;\u2013 2(1)<sup>3<\/sup>&nbsp;+ 3(1)<sup>2<\/sup>&nbsp;-ax 1-b<br>= 1 -2 + 3-a-b = 2-a-b<br>\u2234 Remainder = 6<br>\u2234 2 \u2013 a \u2013 b = 6&nbsp; \u21d2 a + b = 2 \u2013 6 = -4<br>Hence a + b = -4<\/p>\n<p>This is the complete blog on RD Sharma Class 9 Solutions Chapter 6 VSAQS. To know more about the <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 9 Maths exam, ask in the comments.&nbsp;<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-9-solutions-chapter-6-vsaqs\"><\/span><strong>FAQs on RD Sharma Class 9 Solutions Chapter 6 VSAQS<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631184337969\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-many-questions-are-there-in-rd-sharma-class-9-solutions-chapter-6-vsaqs\"><\/span>How many questions are there in RD Sharma Class 9 Solutions Chapter 6 VSAQs?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>There are 6 questions in\u00a0RD Sharma Class 9 Solutions Chapter 6 VSAQs.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631184368299\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-it-even-beneficial-to-study-rd-sharma-class-9-solutions-chapter-6-vsaqs\"><\/span>Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 6 VSAQs?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, your preparation will be strengthened with this amazing help book. All your questions will be answered by this book.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631184431305\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"are-the-solutions-rd-sharma-class-9-solutions-chapter-6-vsaqs-relevant\"><\/span>Are the solutions RD Sharma Class 9 Solutions Chapter 6 VSAQs\u00a0relevant?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>The solutions are relevant as they are designed by the subject matter experts. \u00a0<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 9 Solutions Chapter 6 VSAQs: Clear your Class 9 Maths exams with flying colors by studying the RD Sharma Solutions Class 9 Maths. It is important to clear your concepts before appearing for the exams. Hence you can give a try studying RD Sharma Class 9 Solutions Chapter 6 VSAQs. To now &#8230; <a title=\"RD Sharma Class 9 Solutions Chapter 6 VSAQs\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-vsaqs\/\" aria-label=\"More on RD Sharma Class 9 Solutions Chapter 6 VSAQs\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":125996,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411],"tags":[3086,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125987"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=125987"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125987\/revisions"}],"predecessor-version":[{"id":473866,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125987\/revisions\/473866"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/125996"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=125987"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=125987"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=125987"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}