{"id":125886,"date":"2023-09-09T16:23:00","date_gmt":"2023-09-09T10:53:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=125886"},"modified":"2023-11-08T10:20:56","modified_gmt":"2023-11-08T04:50:56","slug":"rd-sharma-class-10-solutions-chapter-4-exercise-4-4","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-exercise-4-4\/","title":{"rendered":"RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4 (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-125911\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-4-Exercise-4.4-scaled.jpg\" alt=\"RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4\" width=\"2048\" height=\"1152\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-4-Exercise-4.4-scaled.jpg 2048w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-4-Exercise-4.4-768x432.jpg 768w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-4-Exercise-4.4-1536x864.jpg 1536w\" sizes=\"(max-width: 2048px) 100vw, 2048px\" \/><\/p>\n<p><strong>RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4:\u00a0<\/strong>This exercise delves deeper into the basic proportionality theorem. A few problems are solved in the proper manner to reinforce the fundamental principle. Students can use the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-for-maths\/\"><strong>RD Sharma Class 10 Solutions<\/strong><\/a> to learn how to present and make their solutions error-free. Students who want to get good grades in Class 10 Maths Chapter 4 Exercise 4.4 can download the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-triangles\/\"><strong>RD Sharma Solutions for Class 10 Maths Chapter 4<\/strong><\/a> Exercise 4.4 PDF.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e791d6655b3\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" 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href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-exercise-4-4\/#download-rd-sharma-class-10-solutions-chapter-4-exercise-44-free-pdf\" title=\"Download RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4 Free PDF\">Download RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4 Free PDF<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-exercise-4-4\/#access-answers-to-rd-sharma-solutions-class-10-maths-chapter-4-exercise-44-important-question-with-answers\" title=\"Access answers to RD Sharma Solutions Class 10 Maths Chapter 4 Exercise 4.4- Important Question with Answers\">Access answers to RD Sharma Solutions Class 10 Maths Chapter 4 Exercise 4.4- Important Question with Answers<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-exercise-4-4\/#faqs-on-rd-sharma-class-10-solutions-chapter-4-exercise-44\" title=\"FAQs on RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4\">FAQs on RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-exercise-4-4\/#is-it-important-to-study-all-of-the-concepts-included-in-rd-sharma-class-10-solutions-chapter-4-exercise-44\" title=\"Is it important to study all of the concepts included in RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4?\">Is it important to study all of the concepts included in RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-exercise-4-4\/#where-can-i-download-rd-sharma-class-10-maths-solutions-chapter-4-exercise-44-free-pdf\" title=\"Where can I download RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4 free PDF?\">Where can I download RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4 free PDF?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-exercise-4-4\/#what-are-the-benefits-of-using-rd-sharma-class-10-maths-solutions-chapter-4-exercise-44\" title=\"What are the benefits of using RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4?\">What are the benefits of using RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-class-10-solutions-chapter-4-exercise-44-free-pdf\"><\/span>Download RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4 Free PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 800px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Solution-Class-10-Chapter-4-Exercise-4.4.pdf\", \"#example1\");<\/script><\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Solution-Class-10-Chapter-4-Exercise-4.4.pdf\">RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4<\/a><\/p>\n<h3><span class=\"ez-toc-section\" id=\"access-answers-to-rd-sharma-solutions-class-10-maths-chapter-4-exercise-44-important-question-with-answers\"><\/span>Access answers to RD Sharma Solutions Class 10 Maths Chapter 4 Exercise 4.4- Important Question with Answers<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>1. (i)\u00a0In fig. 4.70, if\u00a0<\/strong>AB\u2225CD<strong>, find the value of x.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>It\u2019s given that\u00a0AB\u2225CD.<\/p>\n<p>Required to find the value of x.<\/p>\n<p><img class=\"\" title=\"R D Sharma Solutions For Class 10 Maths Chapter 4 Triangles ex 4.3 - 18\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/c-users-tnluser-downloads-extra-images-of-rd-shar.png\" alt=\"C:\\Users\\Tnluser\\Downloads\\extra-images-of-RD-Sharma-Chapter-4--ex-4.4-3.png\" width=\"299\" height=\"203\" \/><\/p>\n<p>We know that,<\/p>\n<p>Diagonals of a parallelogram bisect each other.<\/p>\n<p>So,<\/p>\n<p>AO\/ CO = BO\/ DO<\/p>\n<p>\u21d2 4\/ (4x \u2013 2) = (x +1)\/ (2x + 4)<\/p>\n<p>4(2x + 4) = (4x \u2013 2)(x +1)<\/p>\n<p>8x + 16 = x(4x \u2013 2) + 1(4x \u2013 2)<\/p>\n<p>8x + 16 = 4x<sup>2<\/sup>\u00a0\u2013 2x + 4x \u2013 2<\/p>\n<p>-4x<sup>2<\/sup>\u00a0+ 8x + 16 + 2 \u2013 2x = 0<\/p>\n<p>-4x<sup>2\u00a0<\/sup>+ 6x + 8 = 0<\/p>\n<p>4x<sup>2<\/sup>\u00a0\u2013 6x \u2013 18 = 0<\/p>\n<p>4x<sup>2<\/sup>\u00a0\u2013 12x + 6x \u2013 18 = 0<\/p>\n<p>4x(x \u2013 3) + 6(x \u2013 3) = 0<\/p>\n<p>(4x + 6) (x \u2013 3) = 0<\/p>\n<p>\u2234\u00a0<strong>x = \u2013 6\/4 or x = 3<\/strong><\/p>\n<p><strong>(ii)\u00a0 In fig. 4.71, if\u00a0<\/strong>AB\u2225CD<strong>, find the value of x.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>It\u2019s given that\u00a0AB\u2225CD.<\/p>\n<p>Required to find the value of x.<\/p>\n<p><img class=\"\" title=\"R D Sharma Solutions For Class 10 Maths Chapter 4 Triangles ex 4.3 - 19\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/c-users-tnluser-downloads-extra-images-of-rd-shar-1.png\" alt=\"C:\\Users\\Tnluser\\Downloads\\extra-images-of-RD-Sharma-Chapter-4--ex-4.4-1.png\" width=\"288\" height=\"195\" \/><\/p>\n<p>We know that,<\/p>\n<p>Diagonals of a parallelogram bisect each other<\/p>\n<p>So,<\/p>\n<p>AO\/ CO = BO\/ DO<\/p>\n<p>\u21d2 (6x \u2013 5)\/ (2x + 1) = (5x \u2013 3)\/ (3x \u2013 1)<\/p>\n<p>(6x \u2013 5)(3x \u2013 1) = (2x + 1)(5x \u2013 3)<\/p>\n<p>3x(6x \u2013 5) \u2013 1(6x \u2013 5) = 2x(5x \u2013 3) + 1(5x \u2013 3)<\/p>\n<p>18x<sup>2<\/sup>\u00a0\u2013 10x<sup>2<\/sup>\u00a0\u2013 21x + 5 + x +3 = 0<\/p>\n<p>8x<sup>2<\/sup>\u00a0\u2013 16x \u2013 4x + 8 = 0<\/p>\n<p>8x(x \u2013 2) \u2013 4(x \u2013 2) = 0<\/p>\n<p>(8x \u2013 4)(x \u2013 2) = 0<\/p>\n<p>x = 4\/8 = 1\/2\u00a0or\u00a0x = -2<\/p>\n<p>\u2234\u00a0<strong>x= 1\/2<\/strong><\/p>\n<p><strong>(iii) In fig. 4.72, if\u00a0<\/strong>AB \u2225 CD<strong>. If OA = 3x \u2013 19, OB = x \u2013 4, OC = x- 3 and OD = 4, find x.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>It\u2019s given that\u00a0AB\u2225CD.<\/p>\n<p>Required to find the value of x.<\/p>\n<p><img class=\"\" title=\"R D Sharma Solutions For Class 10 Maths Chapter 4 Triangles ex 4.4 - 20\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/c-users-tnluser-downloads-extra-images-of-rd-shar-2.png\" alt=\"C:\\Users\\Tnluser\\Downloads\\extra-images-of-RD-Sharma-Chapter-4--ex-4.4-2.png\" width=\"289\" height=\"196\" \/><\/p>\n<p>We know that,<\/p>\n<p>Diagonals of a parallelogram bisect each other<\/p>\n<p>So,<\/p>\n<p>AO\/ CO = BO\/ DO<\/p>\n<p>(3x \u2013 19)\/ (x \u2013 3) = (x\u20134)\/ 4<\/p>\n<p>4(3x \u2013 19) = (x \u2013 3) (x \u2013 4)<\/p>\n<p>12x \u2013 76 = x(x \u2013 4) -3(x \u2013 4)<\/p>\n<p>12x \u2013 76 = x<sup>2<\/sup>\u00a0\u2013 4x \u2013 3x + 12<\/p>\n<p>-x<sup>2<\/sup>\u00a0+ 7x \u2013 12 + 12x -76 = 0<\/p>\n<p>-x<sup>2\u00a0<\/sup>+ 19x \u2013 88 = 0<\/p>\n<p>x<sup>2\u00a0<\/sup>\u2013 19x + 88 = 0<\/p>\n<p>x<sup>2<\/sup>\u00a0\u2013 11x \u2013 8x + 88 = 0<\/p>\n<p>x(x \u2013 11) \u2013 8(x \u2013 11) = 0<\/p>\n<p>\u2234\u00a0<strong>x = 11 or x = 8<\/strong><\/p>\n<hr \/>\n<p>We have provided complete details of RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4. If you have any queries related to <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\"><strong>CBSE<\/strong><\/a>\u00a0Class 10, feel free to ask us in the comment section below.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-10-solutions-chapter-4-exercise-44\"><\/span>FAQs on RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631178071006\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-it-important-to-study-all-of-the-concepts-included-in-rd-sharma-class-10-solutions-chapter-4-exercise-44\"><\/span>Is it important to study all of the concepts included in RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, learning all of the concepts included in RD Sharma Solutions for Class 10 Maths Chapter 4 Exercise 4.4 is required in order to achieve high scores on the Class 10 board exams. These solutions were created by subject matter specialists who compiled model questions that covered all of the textbook&#8217;s exercise questions.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631178209888\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"where-can-i-download-rd-sharma-class-10-maths-solutions-chapter-4-exercise-44-free-pdf\"><\/span>Where can I download RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4 free PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4 free PDF from the above article.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631178341976\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-are-the-benefits-of-using-rd-sharma-class-10-maths-solutions-chapter-4-exercise-44\"><\/span>What are the benefits of using RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>1. Correct answers according to the latest CBSE guidelines and syllabus.<br \/>2. The RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4 is written in simple language to assist students in their board examination, &amp; competitive examination preparation.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4:\u00a0This exercise delves deeper into the basic proportionality theorem. A few problems are solved in the proper manner to reinforce the fundamental principle. Students can use the RD Sharma Class 10 Solutions to learn how to present and make their solutions error-free. Students who want to get &#8230; <a title=\"RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4 (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-exercise-4-4\/\" aria-label=\"More on RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4 (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":238,"featured_media":125911,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411,2985,73410],"tags":[3243,9206,73520,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125886"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/238"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=125886"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125886\/revisions"}],"predecessor-version":[{"id":504083,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125886\/revisions\/504083"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/125911"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=125886"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=125886"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=125886"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}