{"id":125882,"date":"2021-09-09T16:24:26","date_gmt":"2021-09-09T10:54:26","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=125882"},"modified":"2021-09-09T16:32:13","modified_gmt":"2021-09-09T11:02:13","slug":"rd-sharma-class-10-solutions-chapter-4-vsaqs","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-vsaqs\/","title":{"rendered":"RD Sharma Class 10 Solutions Chapter 4 VSAQs (Updated for 2021-22)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-125932\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-4-VSAQS.jpg\" alt=\"RD Sharma Class 10 Solutions Chapter 4 VSAQs\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-4-VSAQS.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-4-VSAQS-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Class 10 Solutions Chapter 4 VSAQs:\u00a0<\/strong>Students can download the\u00a0<a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-triangles\/\"><strong>RD Sharma Class 10 Solutions Chapter 4<\/strong><\/a> VSAQs PDF to learn how to solve the questions in this exercise correctly. Students wishing to brush up on their concepts can check the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-for-maths\/\"><strong>RD Sharma Class 10 Solutions<\/strong><\/a>.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-6a03a0878596a\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-6a03a0878596a\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-vsaqs\/#access-rd-sharma-class-10-solutions-chapter-4-vsaqs-pdf\" title=\"Access RD Sharma Class 10 Solutions Chapter 4 VSAQs PDF\">Access RD Sharma Class 10 Solutions Chapter 4 VSAQs PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-vsaqs\/#faqs-on-rd-sharma-class-10-solutions-chapter-4-vsaqs\" title=\"FAQs on RD Sharma Class 10 Solutions Chapter 4 VSAQs\">FAQs on RD Sharma Class 10 Solutions Chapter 4 VSAQs<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-vsaqs\/#is-it-important-to-study-all-of-the-concepts-included-in-rd-sharma-class-10-solutions-chapter-4-vsaqs\" title=\"Is it important to study all of the concepts included in RD Sharma Class 10 Solutions Chapter 4 VSAQs?\">Is it important to study all of the concepts included in RD Sharma Class 10 Solutions Chapter 4 VSAQs?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-vsaqs\/#where-can-i-download-rd-sharma-class-10-solutions-chapter-4-vsaqs-free-pdf\" title=\"Where can I download RD Sharma Class 10 Solutions Chapter 4 VSAQs free PDF?\">Where can I download RD Sharma Class 10 Solutions Chapter 4 VSAQs free PDF?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-vsaqs\/#what-are-the-benefits-of-using-rd-sharma-class-10-solutions-chapter-4-vsaqs\" title=\"What are the benefits of using RD Sharma Class 10 Solutions Chapter 4 VSAQs?\">What are the benefits of using RD Sharma Class 10 Solutions Chapter 4 VSAQs?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"access-rd-sharma-class-10-solutions-chapter-4-vsaqs-pdf\"><\/span>Access RD Sharma Class 10 Solutions Chapter 4 VSAQs PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>Answer each of the following questions either in one word or one sentence or as per the requirement of the questions :<\/strong><br \/><strong>Question 1.<\/strong><br \/>State basic proportionality theorem and its converse.<br \/><strong>Solution:<\/strong><br \/><strong>Basic Proportionality Theorem:<\/strong>\u00a0If a line is drawn parallel to one side of a triangle intersects the other two sides in distinct points, then the other two sides are divided in the same ratio.<br \/><strong>Conversely:<\/strong> In a line that divides any two sides of a triangle in the same ratio, then the line is parallel to the third side of the triangle.<\/p>\n<p><strong>Question 2.<\/strong><br \/>In the adjoining figure, find AC.<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-1.png\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 1\" width=\"265\" height=\"178\" \/><br \/><strong>Solution:<\/strong><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-2.png\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 2\" width=\"296\" height=\"185\" \/><\/p>\n<p><strong>Question 3.<\/strong><br \/>In the adjoining figure, if AD is the bisector of \u2220A, what is AC?<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-3.png\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 3\" width=\"247\" height=\"180\" \/><br \/><strong>Solution:<\/strong><br \/>In the figure, AD is the angle bisector of \u2220A of \u2206ABC<br \/>AB = 6 cm, BC = 3 cm, DC = 2 cm<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-4.png\" sizes=\"(max-width: 296px) 100vw, 296px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-4.png 296w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-4-242x300.png 242w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 4\" width=\"296\" height=\"367\" \/><\/p>\n<p><strong>Question 4.<\/strong><br \/>State AAA similarity criterion.<br \/><strong>Solution:<\/strong><br \/>If in two triangles, corresponding angles are respectively equal then the triangles are similar.<\/p>\n<p><strong>Question 5.<\/strong><br \/>State SSS similarity criterion.<br \/><strong>Solution:<\/strong><br \/>If in two triangles, corresponding sides are in the same ratio, then the two triangles are similar.<\/p>\n<p><strong>Question 6.<\/strong><br \/>State SAS similarity criterion.<br \/><strong>Solution:<\/strong><br \/>If one angle of a triangle is equal to one angle of another triangle and the sides including these angles are in the same ratio, then the triangles are similar.<\/p>\n<p><strong>Question 7.<\/strong><br \/>In the adjoining figure, DE is parallel to BC and AD = 1 cm, BD = 2 cm. What is the ratio of the area of \u2206ABC to the area of \u2206ADE?<br \/><strong>Solution:<\/strong><br \/>In \u2206ABC, DE || BC<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-5.png\" sizes=\"(max-width: 305px) 100vw, 305px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-5.png 305w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-5-233x300.png 233w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 5\" width=\"305\" height=\"393\" \/><\/p>\n<div><ins data-ad-format=\"auto\" data-ad-client=\"ca-pub-7601472013083661\" data-adsbygoogle-status=\"done\" data-ad-status=\"filled\"><ins tabindex=\"0\" title=\"Advertisement\" aria-label=\"Advertisement\"><ins><iframe src=\"https:\/\/googleads.g.doubleclick.net\/pagead\/ads?client=ca-pub-7601472013083661&amp;output=html&amp;h=280&amp;adk=2523109437&amp;adf=2199795995&amp;pi=t.aa~a.1381849204~i.22~rp.4&amp;w=750&amp;fwrn=4&amp;fwrnh=100&amp;lmt=1630769829&amp;num_ads=1&amp;rafmt=1&amp;armr=3&amp;sem=mc&amp;pwprc=1894297687&amp;psa=1&amp;ad_type=text_image&amp;format=750x280&amp;url=https%3A%2F%2Fwww.learninsta.com%2Frd-sharma-class-10-solutions-chapter-7-triangles-vsaqs%2F&amp;flash=0&amp;fwr=0&amp;pra=3&amp;rh=188&amp;rw=750&amp;rpe=1&amp;resp_fmts=3&amp;wgl=1&amp;fa=27&amp;adsid=ChAI8OHmiQYQkMCJsMKosN5ZEkgAU_BnjsRWYIHGoSml1N6lqgTOks-8D4kF9_LIqzby8zfKn6HVTNg3qiWMeLLIvHyt7ufsFx3w_X6A7DeTEOIjo292zL_k5Wg&amp;uach=WyJXaW5kb3dzIiwiMTAuMCIsIng4NiIsIiIsIjkyLjAuNDUxNS4xNTkiLFtdLG51bGwsbnVsbCxudWxsXQ..&amp;tt_state=W3siaXNzdWVyT3JpZ2luIjoiaHR0cHM6Ly9hdHRlc3RhdGlvbi5hbmRyb2lkLmNvbSIsInN0YXRlIjo3fV0.&amp;dt=1631177349223&amp;bpp=3&amp;bdt=5383&amp;idt=3&amp;shv=r20210901&amp;mjsv=m202109070201&amp;ptt=9&amp;saldr=aa&amp;abxe=1&amp;cookie=ID%3D8453b4fab91013b2-2212de3796cb004a%3AT%3D1629100192%3ART%3D1631170222%3AS%3DALNI_MaEH3cUJ5yJN_REvjVav6leNGZctw&amp;prev_fmts=0x0%2C750x280%2C750x280%2C1263x577&amp;nras=4&amp;correlator=1307529688593&amp;frm=20&amp;pv=1&amp;ga_vid=2075297474.1629100192&amp;ga_sid=1631177348&amp;ga_hid=1675950663&amp;ga_fc=0&amp;u_tz=330&amp;u_his=1&amp;u_java=0&amp;u_h=720&amp;u_w=1280&amp;u_ah=680&amp;u_aw=1280&amp;u_cd=24&amp;u_nplug=3&amp;u_nmime=4&amp;adx=62&amp;ady=4110&amp;biw=1263&amp;bih=577&amp;scr_x=0&amp;scr_y=1811&amp;eid=44747621%2C31062369%2C31062508%2C21065724%2C21067496%2C31062297&amp;oid=3&amp;psts=AGkb-H-E3UYOtBS3CmgHZAzpU6xTTD5HfBlKfKRKsfTXJGZuzkm_MHpKpR2KLBb5Nue-dexrSvkGReix0g%2CAGkb-H91t_wseOFW3OLbFFtl_Y8B6u-vegdriVic1jpS5JRIDOyMKYu0buRvjddoNSuwJuJphKsG_xNVmMfJ&amp;pvsid=3062918234020672&amp;pem=343&amp;ref=https%3A%2F%2Fwww.google.com%2F&amp;eae=0&amp;fc=1408&amp;brdim=0%2C0%2C0%2C0%2C1280%2C0%2C1280%2C680%2C1280%2C577&amp;vis=1&amp;rsz=%7C%7Cs%7C&amp;abl=NS&amp;fu=128&amp;bc=31&amp;jar=2021-09-09-08&amp;ifi=4&amp;uci=a!4&amp;btvi=3&amp;fsb=1&amp;xpc=4QhUJTQTn1&amp;p=https%3A\/\/www.learninsta.com&amp;dtd=4176\" name=\"aswift_3\" width=\"750\" height=\"345\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" sandbox=\"allow-forms allow-popups allow-popups-to-escape-sandbox allow-same-origin allow-scripts allow-top-navigation-by-user-activation\" allowfullscreen=\"allowfullscreen\" data-google-container-id=\"a!4\" data-google-query-id=\"CL_h5JXB8fICFReMYgodm54GlA\" data-load-complete=\"true\" data-mce-fragment=\"1\"><\/iframe><\/ins><\/ins><\/ins><\/div>\n<p><strong>Question 8.<\/strong><br \/>In the figure given below, DE || BC. If AD = 2.4 cm, DB = 3.6 cm and AC = 5 cm. Find AE.<br \/><strong>Solution:<\/strong><br \/>In \u2206ABC, DE || BC<br \/>AD = 2.4 cm, DB = 3.6 cm, AC = 5 cm<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-6.png\" sizes=\"(max-width: 278px) 100vw, 278px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-6.png 278w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-6-188x300.png 188w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 6\" width=\"278\" height=\"444\" \/><br \/>x = 2<br \/>AE = 2 cm<\/p>\n<p><strong>Question 9.<\/strong><br \/>If the areas of two similar triangles ABC and PQR are in the ratio 9: 16 and BC = 4.5 cm, what is the length of QR?<br \/><strong>Solution:<\/strong><br \/>\u2206ABC ~ \u2206PQR<br \/>Area of \u2206ABC : area of \u2206PQR = 9 : 16<br \/>BC = 4.5 cm<br \/>Let QR = A<br \/>The area of two similar triangles are in the ratio of the squares of their corresponding sides<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-7.png\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 7\" width=\"281\" height=\"197\" \/><\/p>\n<p><strong>Question 10.<\/strong><br \/>The areas of two similar triangles are 169 cm\u00b2 and 121 cm\u00b2 respectively. If the longest side of the larger triangle is 26 cm, what is the length of the longest side of the smaller triangle?<br \/><strong>Solution:<\/strong><br \/>Let \u2206ABC be the larger triangle and \u2206PQR<br \/>be the smaller triangle and their longest sides are BC and QR respectively<br \/>Area of \u2206ABC = 169 cm\u00b2<br \/>area of \u2206PQR = 121 cm\u00b2<br \/>BC = 26 cm<br \/>Let QR = x cm<br \/>\u2206ABC ~ \u2206PQR<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-8.png\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 8\" width=\"196\" height=\"122\" \/><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-9.png\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 9\" width=\"255\" height=\"157\" \/><\/p>\n<p><strong>Question 11.<\/strong><br \/>If ABC and DEF are similar triangles such that \u2220A = 57\u00b0 and \u2220E = 73\u00b0, what is the measure of \u2220C?<br \/><strong>Solution:<\/strong><br \/>\u2206ABC ~ \u2206DEF<br \/>Their corresponding angles are equal \u2220A = \u2220D, \u2220B = \u2220E and \u2220C = \u2220F<br \/>But \u2220A = 57\u00b0<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-10.png\" sizes=\"(max-width: 351px) 100vw, 351px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-10.png 351w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-10-170x300.png 170w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 10\" width=\"351\" height=\"620\" \/><\/p>\n<p><strong>Question 12.<\/strong><br \/>If the altitude of two similar triangles are in the ratio 2 : 3, what is the ratio of their areas?<br \/><strong>Solution:<\/strong><br \/>Let \u2206ABC ~ \u2206PQR<br \/>and let AL \u22a5 BC and PM \u22a5 QR<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-11.png\" sizes=\"(max-width: 350px) 100vw, 350px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-11.png 350w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-11-300x171.png 300w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 11\" width=\"350\" height=\"199\" \/><\/p>\n<p><strong>Question 13.<\/strong><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-12.png\" sizes=\"(max-width: 320px) 100vw, 320px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-12.png 320w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-12-300x98.png 300w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 12\" width=\"320\" height=\"105\" \/><br \/><strong>Solution:<\/strong><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-13.png\" sizes=\"(max-width: 346px) 100vw, 346px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-13.png 346w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-13-300x220.png 300w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 13\" width=\"346\" height=\"254\" \/><\/p>\n<p><strong>Question 14.<\/strong><br \/>If \u2206ABC and \u2206DEF are similar triangles such that AB = 3 cm, BC = 2 cm, CA = 2.5 cm and EF = 4 cm, write the perimeter of \u2206DEF.<br \/><strong>Solution:<\/strong><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-14.png\" sizes=\"(max-width: 353px) 100vw, 353px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-14.png 353w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-14-300x110.png 300w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 14\" width=\"353\" height=\"130\" \/><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-15.png\" sizes=\"(max-width: 250px) 100vw, 250px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-15.png 250w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-15-179x300.png 179w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 15\" width=\"250\" height=\"420\" \/><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-16.png\" sizes=\"(max-width: 334px) 100vw, 334px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-16.png 334w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-16-300x233.png 300w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 16\" width=\"334\" height=\"259\" \/><\/p>\n<p><strong>Question 15.<\/strong><br \/>State Pythagoras Theorem and its converse.<br \/><strong>Solution:<\/strong><br \/>In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.<br \/>Conversely: If in a triangle, the square of one side is equal to the sum of squares of the remaining two sides, then the angle opposite to the first side is a right angle.<\/p>\n<p><strong>Question 16.<\/strong><br \/>The lengths of the diagonals of a rhombus are 30 cm and 40 cm. Find the side of the rhombus.\u00a0<strong>(C.B.S.E. 2008)<\/strong><br \/><strong>Solution:<\/strong><br \/>In rhombus ABCD, BD = 30 cm, AC = 40 cm<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-17.png\" sizes=\"(max-width: 351px) 100vw, 351px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-17.png 351w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-17-224x300.png 224w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 17\" width=\"351\" height=\"471\" \/><\/p>\n<p><strong>Question 17.<\/strong><br \/>In figure, PQ || BC and AP : PB = 1 : 2.<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-18.png\" sizes=\"(max-width: 332px) 100vw, 332px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-18.png 332w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-18-300x264.png 300w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 18\" width=\"332\" height=\"292\" \/><br \/><strong>Solution:<\/strong><br \/>In \u2206ABC, PQ || BC<br \/>\u2206APQ ~ \u2206ABC<br \/>But AP : PB = 1 : 2<br \/>The ratio of the areas of two similar triangles are proportional to the square of their corresponding sides<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-19.png\" sizes=\"(max-width: 337px) 100vw, 337px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-19.png 337w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-19-300x143.png 300w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 19\" width=\"337\" height=\"161\" \/><\/p>\n<p><strong>Question 18.<\/strong><br \/>In the figure, S and T are points on the sides PQ and PR respectively of \u2206PQR such that PT = 2 cm, TR = 4 cm, and ST is parallel to QR. Find the ratio of the areas of \u2206PST and \u2206PQR. <strong>[CBSE 2010]<\/strong><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-20.png\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 20\" width=\"197\" height=\"175\" \/><br \/><strong>Solution:<\/strong><br \/>In \u2206PQR, ST || QR and PT = 2 cm, TR = 4 cm<br \/>PR = PT + TR = 2 + 4 = 6 cm<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-21.png\" sizes=\"(max-width: 345px) 100vw, 345px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-21.png 345w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-21-300x300.png 300w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-21-150x150.png 150w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-21-100x100.png 100w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 21\" width=\"345\" height=\"345\" \/><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-22.png\" sizes=\"(max-width: 348px) 100vw, 348px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-22.png 348w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-22-300x127.png 300w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 22\" width=\"348\" height=\"147\" \/><\/p>\n<p><strong>Question 19.<\/strong><br \/>In the figure, \u2206AHK is similar to \u2206ABC. If AK = 10 cm, BC = 3.5 cm and HK = 7 cm, find AC.\u00a0<strong>[CBSE 2010]<\/strong><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-23.png\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 23\" width=\"261\" height=\"192\" \/><br \/><strong>Solution:<\/strong><br \/>In the given figure, AK = 10 cm, BC = 3.5 cm, HK = 7 cm<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-24.png\" sizes=\"(max-width: 351px) 100vw, 351px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-24.png 351w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-24-235x300.png 235w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 24\" width=\"351\" height=\"448\" \/><\/p>\n<p><strong>Question 20.<\/strong><br \/>In the figure, DE || BC in \u2206ABC such that BC = 8 cm, AB = 6 cm and DA = 1.5 cm. Find DE.<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-25.png\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 25\" width=\"190\" height=\"155\" \/><br \/><strong>Solution:<\/strong><br \/>In the given figure,<br \/>DE || BC<br \/>BC = 8 cm, AB = 6 cm and DA = 1.5 cm<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-26.png\" sizes=\"(max-width: 353px) 100vw, 353px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-26.png 353w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-26-272x300.png 272w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 26\" width=\"353\" height=\"390\" \/><\/p>\n<p><strong>Question 21.<\/strong><br \/>In the figure, DE || BC and AD =\u00a012\u00a0BD. If BC = 4.5 cm, find DE.\u00a0<strong>[CBSE 2010]<\/strong><br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-27.png\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 27\" width=\"260\" height=\"167\" \/><br \/><strong>Solution:<\/strong><br \/>In the given figure,<br \/>DE || BC<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-28.png\" sizes=\"(max-width: 359px) 100vw, 359px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-28.png 359w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-28-191x300.png 191w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 28\" width=\"359\" height=\"563\" \/><\/p>\n<p><strong>Question 22.<\/strong><br \/>In the figure, \u2220M = \u2220N = 46\u00b0. Express x in terms of a, b, and c where a, b, c are lengths of LM, MN, and NK respectively.<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-29.png\" sizes=\"(max-width: 334px) 100vw, 334px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-29.png 334w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-29-300x242.png 300w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 29\" width=\"334\" height=\"269\" \/><br \/><strong>Solution:<\/strong><br \/>In the figure, \u2220M = \u2220N = 46\u00b0<br \/>\u2220M = a, PN = x, MN = b, NK = c<br \/>\u2220M = \u2220N = 46\u00b0<br \/>But there are corresponding angle<br \/>PN || ML<br \/>\u2206PKN ~ \u2206LKM<br \/><img src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-30.png\" sizes=\"(max-width: 358px) 100vw, 358px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-30.png 358w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-10-Solutions-Chapter-7-Triangles-VSAQS-30-300x189.png 300w\" alt=\"RD Sharma Class 10 Solutions Chapter 7 Triangles\u00a0VSAQS 30\" width=\"358\" height=\"226\" \/><\/p>\n<p>We have provided complete details of RD Sharma Class 10 Solutions Chapter 4 VSAQs. If you have any queries related to <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\"><strong>CBSE<\/strong><\/a>\u00a0Class 10, feel free to ask us in the comment section below.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-10-solutions-chapter-4-vsaqs\"><\/span>FAQs on RD Sharma Class 10 Solutions Chapter 4 VSAQs<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631178103800\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-it-important-to-study-all-of-the-concepts-included-in-rd-sharma-class-10-solutions-chapter-4-vsaqs\"><\/span>Is it important to study all of the concepts included in RD Sharma Class 10 Solutions Chapter 4 VSAQs?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, learning all of the concepts included in RD Sharma Class 10 Solutions Chapter 4 VSAQs is required in order to achieve high scores on the Class 10 board exams. These solutions were created by subject matter specialists who compiled model questions that covered all of the textbook&#8217;s exercise questions.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631178230277\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"where-can-i-download-rd-sharma-class-10-solutions-chapter-4-vsaqs-free-pdf\"><\/span>Where can I download RD Sharma Class 10 Solutions Chapter 4 VSAQs free PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download RD Sharma Class 10 Solutions Chapter 4 VSAQs free PDF from the above article.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631178373779\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-are-the-benefits-of-using-rd-sharma-class-10-solutions-chapter-4-vsaqs\"><\/span>What are the benefits of using RD Sharma Class 10 Solutions Chapter 4 VSAQs?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>1. Correct answers according to the latest CBSE guidelines and syllabus.<br \/>2. The RD Sharma Class 10 Solutions Chapter 4 VSAQs are written in simple language to assist students in their board examination, &amp; competitive examination preparation.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 10 Solutions Chapter 4 VSAQs:\u00a0Students can download the\u00a0RD Sharma Class 10 Solutions Chapter 4 VSAQs PDF to learn how to solve the questions in this exercise correctly. Students wishing to brush up on their concepts can check the RD Sharma Class 10 Solutions. Access RD Sharma Class 10 Solutions Chapter 4 VSAQs &#8230; <a title=\"RD Sharma Class 10 Solutions Chapter 4 VSAQs (Updated for 2021-22)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-4-vsaqs\/\" aria-label=\"More on RD Sharma Class 10 Solutions Chapter 4 VSAQs (Updated for 2021-22)\">Read more<\/a><\/p>\n","protected":false},"author":238,"featured_media":125932,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411,2985,73410],"tags":[3243,9206,73520,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125882"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/238"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=125882"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125882\/revisions"}],"predecessor-version":[{"id":126016,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125882\/revisions\/126016"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/125932"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=125882"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=125882"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=125882"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}